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Thank you so much sir.... After watching this video I am so much satisfied that I can't explain in words..... I found this video really helpful Sir... Thank you Sir
Sir why do we arrange the CH2OH group on top of the 5th carbon when we have a hydrgen group on the left side of 5th carbon in alpha fructose opn chain structure
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His handwriting is so soothing! Thank you so much this all made so much more sense wish my professor explained it this well.
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Thank you so much sir....
After watching this video I am so much satisfied that I can't explain in words.....
I found this video really helpful Sir...
Thank you Sir
Sir why do we arrange the CH2OH group on top of the 5th carbon when we have a hydrgen group on the left side of 5th carbon in alpha fructose opn chain structure
Just don't jhaddhing gyan here.....
You save time and give an authentic concept 🎉
This really help me because I can't get any good explaination from Google. And now , I feel very relieve.
Thank u soo much sir.....very helpful lecture😌
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Thank you 😊
Keep it up .....
Simple English and unique explanation 🇵🇰
Lots of prayers for u sirr🙌🏽💯👑
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Thnx ❤
Dear sir, can u pls tell like how to justify the open chain structure of fructose 👀
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@@Ekeeda thanks. Of course i will share🌼
Vey nicely explained, Thank you sir 😊
from where did the OH group came on the 2nd carbon atom? pls explain
Where did the H come from to make OH with the carbon 1
Loved the explanation, soothing,clear, properly professional, loved it sir 😌 tysm
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@@Ekeeda sure
Nicely explained. Keep up the good work. God bless
finally i understood it!!
thanks alot sir
Best wishes”
Thank you so much 🥰
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Ekeeda Team
thank you so much
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Thanks!!
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Ekeeda Team
Thanks man you helped me out a lot
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You cut the video in between couldn't understand it correctly.
Ya u explain well
Thank uu sm
bst way 🙂
Sooo satisfying
Thank you very much sir.
Your explanation was very clear.
Well explained ❤️
This was so helpful sir 😊
I want chair structure
Hi
Thank u sir
Nothing but nothing but nothing but what
Thank u sir
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Thank you sir
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Sure sir.