Free radical substitution reactions

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  • Опубликовано: 6 окт 2024

Комментарии • 38

  • @ahmedal-saied211
    @ahmedal-saied211 7 лет назад +46

    These videos are really good ! I will definitely be spreading this over my entire college!

  • @megha.ks686
    @megha.ks686 3 года назад +8

    Saved my life! Thank You!!!!!!! I spent ages trying to understand it and you did it in 12 minutes!

  • @STICKY_
    @STICKY_ 4 года назад +26

    I understand it I just don't know how to answer exam questions on it ughhhh

  • @faizallimalia4986
    @faizallimalia4986 5 лет назад +3

    May God bless you Sir.

  • @farahhussain8484
    @farahhussain8484 8 лет назад +22

    This is so helpful!! :)

    • @AlleryChemistry
      @AlleryChemistry  8 лет назад +5

      +Farah Hussain Good good. Please spread the word about this video ☺

  • @deloresyan1363
    @deloresyan1363 5 лет назад +2

    this is super cool, I can totally understand it now

  • @alexiaplacinta5468
    @alexiaplacinta5468 3 года назад +3

    Your videos are very helpful

  • @LaurasLabyrinth
    @LaurasLabyrinth 3 года назад +3

    thank you, this made it a lot easier to understand!! You're a star :)

  • @y.mstizzy9179
    @y.mstizzy9179 2 года назад +3

    Great video

  • @rahihasan3670
    @rahihasan3670 4 года назад +3

    This is really so helpful thanks mate

  • @geotheomusic761
    @geotheomusic761 2 года назад +3

    THANK YOU!!!

  • @reptilected4097
    @reptilected4097 5 лет назад +3

    thank you, very helpful!

  • @LOVEAD2
    @LOVEAD2 2 года назад +2

    thank you for the video!

  • @fzahrab1
    @fzahrab1 9 лет назад +6

    Great video!!! :)

    • @AlleryChemistry
      @AlleryChemistry  9 лет назад +3

      Grapesand Snapple Thanks very much! Please share these videos to people you know who you think will also benefit too. If you are on twitter follow me @allerytutors to hear about what videos are being made before everyone else.

  • @user-or1tp5bo5q
    @user-or1tp5bo5q 4 года назад +2

    So helpfulll

  • @tahir4230
    @tahir4230 6 лет назад +1

    thank you

  • @salmanqureshi3361
    @salmanqureshi3361 6 лет назад +1

    yes! finally zoomed in!

  • @Andy-cx3iz
    @Andy-cx3iz 7 лет назад +8

    hey i have a question, when you do the second propagation reaction how do you which is the second reactant you should use other than the one that has a radical rom the first propagation reaction product? btw great video!

    • @mejiidowu7659
      @mejiidowu7659 4 года назад +4

      the second reactant is always the diatomic atom

  • @nomsy9279
    @nomsy9279 8 лет назад +4

    Cool video 👍🏻

    • @AlleryChemistry
      @AlleryChemistry  8 лет назад +1

      +Nneoma Uche Thanks very much! Please share this vid with others who may find it useful too! 😄

  • @freezerhythmsnevents5891
    @freezerhythmsnevents5891 7 лет назад +1

    Sir I have a doubt plz explain free radical mechanism of sulphonation

  • @malk5961
    @malk5961 3 месяца назад +1

    YAAAAAAAAAAAAAAAAAAS

  • @roshnyabraham7941
    @roshnyabraham7941 3 года назад +1

    Does the dot have to be on the C or near it 6:14

  • @ali-bb7so
    @ali-bb7so 8 лет назад +1

    How come in Cl. + O3 > clo. + o2 the radical group doesn't cross over giving the o2 as a radical

    • @JBCJackson
      @JBCJackson 8 лет назад +1

      +ali _r Thats what i was wondering

    • @AlleryChemistry
      @AlleryChemistry  8 лет назад +6

      +JBC Jackson +ali _r It is due to the structure of ozone. It has a single and double bond and has a positive and negative charge too. When bond fission occurs it is more energetically stable to form O2 and O radical which then bonds with Cl to form ClO radical. The explanation is simplified a lot as the actual reasoning is very complex and beyond A Level.

    • @ali-bb7so
      @ali-bb7so 8 лет назад

      +Allery Chemistry thanks very much your vids are helpful

    • @Michelle-hc5dp
      @Michelle-hc5dp Год назад

      @@AlleryChemistry when the O radical bonds to Cl wouldn’t it no longer have a radical because it shares an electron with Cl?

    • @Michelle-hc5dp
      @Michelle-hc5dp Год назад

      @@AlleryChemistry does this mean that when reactions happen the most likely outcome is the one that’s most stable like with markownikoff’s rule?

  • @ace1879
    @ace1879 7 лет назад +2

    What if they ask to represent without curly half headed arrows, they asked this in the October 2016 IAL Edexcel exam

    • @AlleryChemistry
      @AlleryChemistry  7 лет назад

      Yes you just set it up showing equations for the initiation, propagation and termination steps.