sir for problem 1 (analysis) bakit po rhomax transition parin ang ginamit nyo po (3/7).. kahit na state na sa problem is tension controlled? ano po gagamitin namin sa board exam 3/7 or 3/8
Ayon sa NSCP, minimum strain for SR condition is 0.004 (NSCP 409.3.3.1) (corresponding to c = 3/7 of effective depth). Tapos ang strain values between 0.004 and 0.005 ay transition region. Kaya by code, 3/7 talaga Pero kapag nagdedesign kasi, halimbawa may Mu ka tapos kailangan ng compression block. Ang unang gagawin ay mag aassume ng Φ. Kung tension controlled, 0.9 na agad. Kung transition yung mahaba pa. So yung ibang designers, ginagawa na nilang 3/8 yung pinakamalaki nilang "gustong" macompute para hindi na nila gamitin yung mahabang equation ng Φ kapag hahanap ng compression block. TLDR: 3/7 talaga sabi ng code pero mas gusto ng iba yung 3/8 kasi mas madali yung Φ
Kapag sinabi na use Φ = 0.9 dapat 3/8 para maging tension controlled talaga pero kung walang inespecify, kahit alin naman kasi di ganun kalaki effect niyan sa procedure most of the time
yung sa example 1 po, bakit po ang phi ay 0.9 kung ang tension bars ay nag yield pero ang compression bars ay hindi nag yield? Always po ba naka base sa tension bars ang reduction factor sa DRB?
@@KippapEducation sa 28:50 po, di po ba yan yung sagot sa steel area sa tension? sabi niyo po kasi yan yung sagot sa 2nd question, wherein yung tanong is steel area for compression. nalito lang po ako
@@JoshuaCedilla salamat po Engr pag actual designing po ba lalo po pag may contract project 10kn/m po kadalasan ang value ng w? salamat po sa sagot sir🤗
For design problems, yes tension controlled dapat. If analysis naman, you can do checks (strain of steel > 0.005) para malaman if tension controlled yung section.
I think G11 is the perfect time to master the foundational courses rather than design agad haha. Very impt ang basics sa engineering, mas nagiging intuitive ang formulas sayo in the long-term,, maybe look for statics muna before reinforced concrete design?
Hello, bat po 3/7 ginamit sa rho max instead na 3/8 since TC?
parang gusto kung makita mag publish yung kippap ng rcd book😌🔥
Seconding this sana may book na NSCP 2015 with past boards 😭 puro 2010 nahahanap ko
I tried c po in substituting for finding fs', in calculating it, it still did not exceed 420. why is this po?
tas if gamitin nating c=95.41 po, nagyield naman po siya sa tension side po at hindi nag yield sa compression side po
sir for problem 1 (analysis) bakit po rhomax transition parin ang ginamit nyo po (3/7).. kahit na state na sa problem is tension controlled? ano po gagamitin namin sa board exam 3/7 or 3/8
Ayon sa NSCP, minimum strain for SR condition is 0.004 (NSCP 409.3.3.1) (corresponding to c = 3/7 of effective depth). Tapos ang strain values between 0.004 and 0.005 ay transition region. Kaya by code, 3/7 talaga
Pero kapag nagdedesign kasi, halimbawa may Mu ka tapos kailangan ng compression block. Ang unang gagawin ay mag aassume ng Φ. Kung tension controlled, 0.9 na agad. Kung transition yung mahaba pa. So yung ibang designers, ginagawa na nilang 3/8 yung pinakamalaki nilang "gustong" macompute para hindi na nila gamitin yung mahabang equation ng Φ kapag hahanap ng compression block.
TLDR: 3/7 talaga sabi ng code pero mas gusto ng iba yung 3/8 kasi mas madali yung Φ
Kapag sinabi na use Φ = 0.9 dapat 3/8 para maging tension controlled talaga
pero kung walang inespecify, kahit alin naman kasi di ganun kalaki effect niyan sa procedure most of the time
32:16 Sir pag ni round up sa 2 bars yyng comp steel, hindi ba magiging over-reinforced yung beam?
sir baka may example kayo sa analysis na hindi sa midspan hinahanap ang factored concentrated load
hindi po ba ang C sa Problem 1 (analysis) is 154.5214?
May we know saang step naiba solution niyo?
@@KippapEducation sir 154.521 po nalabas for C. Yung step po after ma check if steel yields Cc + Cs = T. Hindi po nalabas 128.6727
@@nhojcapili8735 i tried it again, my full equation was
0.85(28)(0.85x)(350)+512pi*600((x-70)/x) = 1024pi*420
Ang lumabas sa calcu ay 128.67
@@KippapEducation ahhh okay na po sir salamat
Allowed po bang gumamit ng 12mm rebars for beams on two storey residential building?
yung sa example 1 po, bakit po ang phi ay 0.9 kung ang tension bars ay nag yield pero ang compression bars ay hindi nag yield? Always po ba naka base sa tension bars ang reduction factor sa DRB?
Yes, sa tension bars nakadepende ang phi
hello, di po ba opposite yung answers sa number 2 and 3 sa design?
Hello! Can you elaborate?
@@KippapEducation sa 28:50 po, di po ba yan yung sagot sa steel area sa tension? sabi niyo po kasi yan yung sagot sa 2nd question, wherein yung tanong is steel area for compression. nalito lang po ako
@@confeccti7100 ah yup. Nalito lang ako sa order ng questions haha, pero the compression and tension steel area are indicated naman sa pagsolve ko
Hindi po ba kasama sa pag compute ng moment capacity ang reduction factor (phi)?
Mentioned na sa both problems na tension-controlled (phi = 0.9)
Saan niyo po nakuha yunhlg value ng w=10?
Nasa problem po, Yan Yung uniform deadload
@@JoshuaCedilla salamat po Engr pag actual designing po ba lalo po pag may contract project 10kn/m po kadalasan ang value ng w? salamat po sa sagot sir🤗
Boss, kung ang gamitin pong rho-max is pang T.C? Pwede po?
For board exam mas maganda gamitin ang Rho Max na 3/8 para ma-ensure na tension controlled
Sir. What if negative po Yung excess moment?
That means hindi siya excess and baka singly reinforced beam lang ang analysis
tension controlled po lahat sa board exam?
For design problems, yes tension controlled dapat. If analysis naman, you can do checks (strain of steel > 0.005) para malaman if tension controlled yung section.
Hi Grade 11 student here, learning this para matop ko board in the future 🤩
😂
I think G11 is the perfect time to master the foundational courses rather than design agad haha. Very impt ang basics sa engineering, mas nagiging intuitive ang formulas sayo in the long-term,, maybe look for statics muna before reinforced concrete design?
Ano pangalan mo para matandaan hahaha
Nays 1 sir 😇
hoping you make episodes 4-11 of es 101 series available again!!! very helpful po for someone taking es 101 right now hehe
Salamat idol gawa ka pa Po more tutorial Pa sa RCD . T-beams , slab , foundation ,
💯
more topics pa sa concrete uwu
First
Nasaan ang mga answr sa question number 1 at 2 sa first situation?
Depth of compression block is 0.85(128.67). Moment capacity is at 15:20