Possible set of values for x, y, z are, 1. (1,2,3) this we can arrange in 3! Ways = 6 2. (1,1,4) this we arrange in 3!/2! = 3 ways (since, there are two ‘1’) 3. (2,2,2) here two repeats thrice then, number of ways we can arrange these three numbers =3!/3!=1 Therefore total possible set of numbers which satisfies x +y+z=6 are 6+3+1=10.
thanks sir
Happy to share knowledge with you. Please like share and subscribe 😊
Great Job
Thanks for formula
Happy to share knowledge with you. Please like, share and subscribe 😊.
Why subtract the number one from n and r
Sir kindly solve any examples of permutations and combinations by formulae , I can't properly do it 🙏🙏🙏🙏🙏🙏🙏🙏
Please see the playlist, ask if you face any difficulties
Upsc key - option C).
Please explain the formula.
Possible set of values for x, y, z are, 1. (1,2,3) this we can arrange in 3! Ways = 6
2. (1,1,4) this we arrange in 3!/2! = 3 ways (since, there are two ‘1’)
3. (2,2,2) here two repeats thrice then, number of ways we can arrange these three numbers =3!/3!=1
Therefore total possible set of numbers which satisfies x +y+z=6 are 6+3+1=10.