Thank you. I understand basic math. But, this is a bit more advanced for me. God bless you sir. You are a great math teacher. Your videos help me get me through some difficult times in my life right now until I get them straightened out. Hopefully will be practicing them with my scientific calculator on my laptop.
I am doing a math puzzle. There are 19 pieces, with numerical values from 1 to 19. (I have to arrange them in rows in such a way that every row adds up to 38,). I’m trying to find out how many possible combinations. I used to think it was 19 squared. Now I’m wondering if it’s 19x18x17….and so on. So it’s either 361. Or some astronomical number, or I’m wrong on both counts. It’s a Chinese puzzle call Lu’s Tshu, or something like that.
❗❗❗❗❗❗❗❗❗ URGENT PLEASE🙏🏽 There are 12 numbers and 12 Alphabets. And each number corresponds to an alphabet. Its in the form below. 1 A 2 B 3 C 4 D 5. E 6. F 7 G 8 H 9 I 10 J 11 K 12 L We are finding the combinations. 1. Find all the possible combination of these 24 entities in 12 groups. If number ( 1 ) occurs, it means alphabet ( A ) cannot occur . if ( 2 ) occurs, then alphabet ( B ) cannot occur. And so forth. How do you find such a combination ? 2. What are the list of all the combinations? Is there any machine or app that can list all those combinations ? Lemme know
Bravo Mr. Tecmath. you should publish books on these matters and they should be mandatory for school curriculum . Your examples take the fear out of mathematics.
THANK YOU! I am studying for the CLEP exam and the other sites I have found are so confusing and drawn out! You are straight to the point and easy to follow with the steps and rational you provide!!!!
Thank you very much, you have seriously helped out dramatically, I was afraid I would fail my test, but just like always, some dude on youtube who sounds like Bruce the shark from Finding Nemo always helps me more than my own school's lessons
This is selection combinations. Instead of having a number & taking away from it. It would be more accurate if for example you did "Its wacky t-shirt day at work. There are 15 employees that decided to participate, & each employee has has their own 7 shirts to choose from. How many different wacky t-shirt combinations could the employees show up to work in?". Can you figure it out??(I just thought of this, I don't even have an answer, or know how to figure this out 🤦♂️lol)
i was searching for a while but could not find any answers. basically what i was looking for was that there would be 4 people, 3 erasers, and 2 pencils. how many combinations would there be if i chose 1 from the people, 1 from the erasers, and 1 from the pencils.
That easy?! I leaned about permutations from Brilliant, it vaguely showed the algebra but didn't explain it. Kahn Academy uses a similar format and that works for me just fine,
What about if we are required to have a combination of 3 letters with 4 numbers? Like these : ABC 1234; BBC 4351; SSS 6666, etc. Condition 1: Numbers and letters may be repeated; Condition 2 : Numbers and letters may not be repeated. Numbers can be picked from 0 to 9 (10 numbers) and letters can be picked from A to Z (26 letters). Thanks in advance.
Thank you , thank you!! You have now helped me overcome the fear of permutations and combinations. I always loved the other maths like geometry, trigs, mechanics and calculus but when I had to deal with stats I had a some fear. Thanks again!
Not sure if it works if we have this an example like this. You have to get 6 snacks from the gasoline station and you have to choose from 10 different snacks. The same snack can be chosen. So you can have 1,1,1,1,1,1. It doesn't work with this example does it
If you are reading this comment I came across a problem that won’t work with the examples. I have a combination lock with 6 buttons but you need to press buttons 10 times to open it. So it is repetitive and you need to press the buttons in order.
How do you find permutation but if there are for example 10 numbers and out of them 4 numbers but the repetition is possible. The same number could repeat more than one time
Glad I found this, I didn't know how to ask for this lol so I couldn't find it for a long time! I was sure there was a short cut but I couldn't find it from my stats text book. They really want you to do it the long way.
What about combination, which involves letters as well? For example 2-9 and A-Z ? (26 letters in the alphabet) but the string is limited to 12 - so 12 spaces, mixed with letters and numbers.
Q: So if I got my answer but I only gave a partner the factorial of 9! / 6! 3! how would they find out the answer? They'd just say n is clearly 9 and r is clearly 3 so then they'd work out, like you did, that there's 84 combinations and check it by n-r?
I appreciate you for making videos to help us and it is so helpful to me bc of how many number and types of questions there are and your explanation. my intension here is to clarify some stuff for those who didnt get this vid contents (for those who watched this as 1st video to help them understand) I have watched and understood some of the very important concepts and then I watched this video so I could understand but some who watched this as beginning videos for practicing understanding the concept may not get the meaning/theory behind it. 5C3 = 5!/[(5-3)!(3!)] = 5 x 4 x 3 x 2 x 1 /2 x 1 x 3 x 2 x 1 = 10 5C3, or 5 choose 3, is *5*: number of total items to choose *from* and *3*: the number of items to *choose*. Meaning.... nCr = n: total number of items to choose from, r: the number of items to choose. back to (n-r)! is divided from total number of items to choose from because we are *not taking those items in to account*. r! is also divided because items to choose, themselves, have number of ways to arrange(since if it was 5!, which is permutation, it means all items are DISTINCT so the order matters and no need to cut down the number of ways to arrange those items; there is no overlap). Here is the part I wanted to clarify: the next moment he was calculating 10C4 = (10 x 9 x 8 x 7)/ (4 x 3 x 2 x 1). Why and how? This is because in ANY case where you come up with answer nCr, the whole calculation reduces to be (n, decreasing each time by 1 when it is multiplied, times the number of items selected / n!) when you feel comfortable in calculating nCr is a tip...... 5C3 is SAME as 5C2. you can check with any number as long as it follows the rule I stated in previous paragraph. (5 x 4 x 3)/(3 x 2 x 1) = (3 cancels, 4 is reduced) 2 is the answer. You'll see the pattern once you try both the way to do this is when your answer is 8C6, you just have to change the number r with (n-r) so it'd be 8C2 in this case. Much faster and efficient to calculate. disclaimer: as I am one who is still learning there maybe some mistake or unclear parts but I am confident enough to say above and tips. This is not meant to disrespect or so; just trying to add something to this vid since I honestly think this video was very helpful to me. I struggled so much when I first learned this so that's why I want to help
Man sounds Bruce the shark from Finding Nemo
J L oh yea
Where are you from ...my one of the friend look like you ...
That's why we all are here (explaination : no one care about maths )
@@Xeroffice I care…
Thats rude
Thank you. I understand basic math. But, this is a bit more advanced for me. God bless you sir. You are a great math teacher. Your videos help me get me through some difficult times in my life right now until I get them straightened out. Hopefully will be practicing them with my scientific calculator on my laptop.
Aghhhh thank you thank you I didn’t understand the formula just wanted to know what it meant
Thank you!
I am doing a math puzzle. There are 19 pieces, with numerical values from 1 to 19. (I have to arrange them in rows in such a way that every row adds up to 38,).
I’m trying to find out how many possible combinations. I used to think it was 19 squared. Now I’m wondering if it’s 19x18x17….and so on.
So it’s either 361. Or some astronomical number, or I’m wrong on both counts. It’s a Chinese puzzle call Lu’s Tshu, or something like that.
❗❗❗❗❗❗❗❗❗
URGENT PLEASE🙏🏽
There are 12 numbers and 12 Alphabets.
And each number corresponds to an alphabet.
Its in the form below.
1 A
2 B
3 C
4 D
5. E
6. F
7 G
8 H
9 I
10 J
11 K
12 L
We are finding the combinations.
1. Find all the possible combination of these 24 entities in 12 groups. If number ( 1 ) occurs, it means alphabet ( A ) cannot occur . if ( 2 ) occurs, then alphabet ( B ) cannot occur. And so forth. How do you find such a combination ?
2. What are the list of all the combinations?
Is there any machine or app that can list all those combinations ? Lemme know
I'm in 7th grade and don't know this is that good or bad
I suffered from the pronunciation of yours
how could anybody dislike this amazingly compassionate and clear presentation
Jealous perhaps 🤣😅
It might just be a misclick
they were holding their phone upside down
This is way easier than what I was taught in school!
MTMFan you are still a baby
Hehe
i had a really good teacher and still agree
460 views, 46 likes and 0 dislikes... I love how perfect the numbers are
Now its 570 virws and 57 likes
590 views, 59 likes 0 dislikes... What is this sorcery?
670 views, 67 likes and 0 dislikes
WazzupKMS now it's 790 views 79 likes and 0 dislike
I am for sure going to murder anyone who breaks the pattern
OMG! I'm studying for the GRE, and this is something I never learned... THANK YOU FROM THE BOTTOM OF MY HEART!!!
bad understanding ☹😵😵💫
Bravo Mr. Tecmath. you should publish books on these matters and they should be mandatory for school curriculum . Your examples take the fear out of mathematics.
Thank you mate !!!
Finally understand it
Way easier than what I’m being taught now. Thank you!
This made computer programming functions so much less complicated than what computer science circles Ex15b made it seem. Tysm
Dude totally agree man, this guy is such a genius
THANK YOU! I am studying for the CLEP exam and the other sites I have found are so confusing and drawn out! You are straight to the point and easy to follow with the steps and rational you provide!!!!
explained way better than my teachers. Thank you. I swear, school makes it out to be harder than it ACTUALLY is.
Thank you very much, you have seriously helped out dramatically, I was afraid I would fail my test, but just like always, some dude on youtube who sounds like Bruce the shark from Finding Nemo always helps me more than my own school's lessons
don't come to comments man, you're here to study and so am I. lmao
Nice video, very clearly explained, however you could've included combinations with repetition! Nevertheless, respect.
+cho_Oz thanks. Good luck on your exam tomorrow.
Bore
Much better than some of the complicated videos watched. Thanks mate.
Omg thanks alot😄. My school has scantron coming soon and these are the only questions that confused me😂. You really helped me lol
Are you Australian? I love your pronunciation hahahhh
Anyway I love your videos
Love from Italy
WHY DONT WE IS LIFE
PaulNerrumo iD He sounds like Daren Lehman, the former Australia cricket coach
He sounds normal
...then again I am Australian
@@leizhang7255 lool, why did you say you are austrialian? isnt your name zhiang? i think you must be chinese. thats for sure.
THANK YOU! 🙏 I just went through 5 videos and 2 books trying to figure this out.
better than my professor, thank you soooo much!!!!!
Legit😂😂
This is selection combinations. Instead of having a number & taking away from it. It would be more accurate if for example you did "Its wacky t-shirt day at work. There are 15 employees that decided to participate, & each employee has has their own 7 shirts to choose from. How many different wacky t-shirt combinations could the employees show up to work in?". Can you figure it out??(I just thought of this, I don't even have an answer, or know how to figure this out 🤦♂️lol)
You have a big pot of oatmeal and a choice of 18 toppings. How many combinations?
What if you want to select all the books?
Thanks really helpful
i was searching for a while but could not find any answers. basically what i was looking for was that there would be 4 people, 3 erasers, and 2 pencils. how many combinations would there be if i chose 1 from the people, 1 from the erasers, and 1 from the pencils.
nevermind! what i was looking for was possible outcomes probability.
Ok. i understand this explanation. So, good job.
Thank you so much for your excellent and simple explanation - I just couldn’t wrap my head around this problem on my own.
That easy?! I leaned about permutations from Brilliant, it vaguely showed the algebra but didn't explain it. Kahn Academy uses a similar format and that works for me just fine,
One step closer to counting cards 😏
What about if we are required to have a combination of 3 letters with 4 numbers? Like these : ABC 1234; BBC 4351; SSS 6666, etc. Condition 1: Numbers and letters may be repeated; Condition 2 : Numbers and letters may not be repeated. Numbers can be picked from 0 to 9 (10 numbers) and letters can be picked from A to Z (26 letters). Thanks in advance.
Thank you , thank you!! You have now helped me overcome the fear of permutations and combinations. I always loved the other maths like geometry, trigs, mechanics and calculus but when I had to deal with stats I had a some fear. Thanks again!
Insanly interesting and simple way you explained this concept! I would still be trying to remember the formula if it wasn't for you!
Not sure if it works if we have this an example like this.
You have to get 6 snacks from the gasoline station and you have to choose from 10 different snacks. The same snack can be chosen. So you can have 1,1,1,1,1,1. It doesn't work with this example does it
i think this is permutation not combination :)
Incredibly clear. You make it easy to digest and it seems so obvious once I grasped it.
Thank you so so much for this video it helps me a lot but I didn't get the last part where did you get the 3!5!?
If you are reading this comment I came across a problem that won’t work with the examples. I have a combination lock with 6 buttons but you need to press buttons 10 times to open it. So it is repetitive and you need to press the buttons in order.
Let A be a set containing 2023 elements. How many ways are there to choose two subsets of A (not necessarily distinct) whose union equals the set A
How do you find permutation but if there are for example 10 numbers and out of them 4 numbers but the repetition is possible. The same number could repeat more than one time
Your explanation made things sooooo much easier! Thank you!
Sir please can you teach time and work, AP - GP and calendar problems
oh my god he had such a bogan accent i didn't realise he was Australian at first haha
What happens when the boss is going to be going no matter what but he needs to take three out of five people how do you figure that out?
thank you so much for this .
If in people one particular person include how we will chose from that
Thank you bruh
His accent feels like a cold glass of water on a hot humid summer day
Im a kid so don’t judge but...i dont get it?!?!??!?!!!
this broke my brain in school but it seems so ridiculously easy now
This is much easier than making a chart thank you!!
Very intuitive explanation. Great video.
Nice.
In just under 9 minutes I went from having no f*ckin clue what I was doing to being able to solve these questions no problem.
THANKS
don't judge a book by its cover ;)
Too easy
3:17 formula
I gotta find out where your from, that accent is a turn on!
Glad I found this, I didn't know how to ask for this lol so I couldn't find it for a long time! I was sure there was a short cut but I couldn't find it from my stats text book. They really want you to do it the long way.
I like maths.
Sup, I love your vids.
What about combination, which involves letters as well? For example 2-9 and A-Z ? (26 letters in the alphabet) but the string is limited to 12 - so 12 spaces, mixed with letters and numbers.
I heard your voice somewherebut I can't remember where
Q: So if I got my answer but I only gave a partner the factorial of 9! / 6! 3! how would they find out the answer?
They'd just say n is clearly 9 and r is clearly 3 so then they'd work out, like you did, that there's 84 combinations and check it by n-r?
OMG thank you so much my GED prep book told me that I had to write out EVERY combination???
great teacher. you made it super easy
thank you so much I understand this now!!!
Hello, if an id has 8 numbers, how many can be made if the number can be repeated ?
And how many if it cant?
TYSM! finally I know how it works
Hey it’s the doctor from spongebob here to save my day :)
I've been going over and over this and thanks to tou I finally understand, Thank You...
Nice ! It is ok if I take your idea and translate it in another language (a new video) and put it in my channel?
Finally, a video I could understand to help make things easier. Many thanks!
This man is a total sadist.
how can i calculate the amount of possible bets on the euro million, 5 from 1 to 50 and 2 from 1 to 12
This video really really helped, I was so confused and now I feel really confident about my exam!
This was by far the best explanation I could understand. Thank you!
can you tell me how many combination there are if you use 1 and 0 for a 10 numbers password
wow- you summed that up perfectly! THANK YOU
Ok good explanation
I don’t know how can I say thank you professor ❤️ ❤️ I appreciate you so much
why his voice so deep.i wasn't easy for me to understand the English as I am not a native 😭😭😭😭😭
Dude sounded like corpsehusband
thank you it really helped me .
your a legend mate respond because you made me get 92 in maths for fraction all from the help of you
Great accent sir!
Thank you so easy
Thanks for making a tricky subject a little easier to understand Josh.
I love you man
I appreciate you for making videos to help us and it is so helpful to me bc of how many number and types of questions there are and your explanation.
my intension here is to clarify some stuff for those who didnt get this vid contents (for those who watched this as 1st video to help them understand)
I have watched and understood some of the very important concepts and then I watched this video so I could understand but some who watched this as beginning videos for practicing understanding the concept may not get the meaning/theory behind it.
5C3 = 5!/[(5-3)!(3!)] = 5 x 4 x 3 x 2 x 1 /2 x 1 x 3 x 2 x 1 = 10
5C3, or 5 choose 3, is *5*: number of total items to choose *from* and *3*: the number of items to *choose*. Meaning....
nCr = n: total number of items to choose from, r: the number of items to choose.
back to (n-r)! is divided from total number of items to choose from because we are *not taking those items in to account*. r! is also divided because items to choose, themselves, have number of ways to arrange(since if it was 5!, which is permutation, it means all items are DISTINCT so the order matters and no need to cut down the number of ways to arrange those items; there is no overlap).
Here is the part I wanted to clarify: the next moment he was calculating 10C4 = (10 x 9 x 8 x 7)/ (4 x 3 x 2 x 1). Why and how?
This is because in ANY case where you come up with answer nCr, the whole calculation reduces to be (n, decreasing each time by 1 when it is multiplied, times the number of items selected / n!)
when you feel comfortable in calculating nCr is a tip......
5C3 is SAME as 5C2. you can check with any number as long as it follows the rule I stated in previous paragraph.
(5 x 4 x 3)/(3 x 2 x 1) = (3 cancels, 4 is reduced) 2 is the answer. You'll see the pattern once you try both
the way to do this is when your answer is 8C6, you just have to change the number r with (n-r) so it'd be 8C2 in this case. Much faster and efficient to calculate.
disclaimer: as I am one who is still learning there maybe some mistake or unclear parts but I am confident enough to say above and tips. This is not meant to disrespect or so; just trying to add something to this vid since I honestly think this video was very helpful to me. I struggled so much when I first learned this so that's why I want to help
Thanks.
Extremely helpful. Thanks so much
Thanks Alan Moore
Thanks
you are so much better at explaining than my teacher.
What