Bravo Mr. Tecmath. you should publish books on these matters and they should be mandatory for school curriculum . Your examples take the fear out of mathematics.
THANK YOU! I am studying for the CLEP exam and the other sites I have found are so confusing and drawn out! You are straight to the point and easy to follow with the steps and rational you provide!!!!
Thank you very much, you have seriously helped out dramatically, I was afraid I would fail my test, but just like always, some dude on youtube who sounds like Bruce the shark from Finding Nemo always helps me more than my own school's lessons
Thank you. I understand basic math. But, this is a bit more advanced for me. God bless you sir. You are a great math teacher. Your videos help me get me through some difficult times in my life right now until I get them straightened out. Hopefully will be practicing them with my scientific calculator on my laptop.
Thank you , thank you!! You have now helped me overcome the fear of permutations and combinations. I always loved the other maths like geometry, trigs, mechanics and calculus but when I had to deal with stats I had a some fear. Thanks again!
Glad I found this, I didn't know how to ask for this lol so I couldn't find it for a long time! I was sure there was a short cut but I couldn't find it from my stats text book. They really want you to do it the long way.
What about if we are required to have a combination of 3 letters with 4 numbers? Like these : ABC 1234; BBC 4351; SSS 6666, etc. Condition 1: Numbers and letters may be repeated; Condition 2 : Numbers and letters may not be repeated. Numbers can be picked from 0 to 9 (10 numbers) and letters can be picked from A to Z (26 letters). Thanks in advance.
I appreciate you for making videos to help us and it is so helpful to me bc of how many number and types of questions there are and your explanation. my intension here is to clarify some stuff for those who didnt get this vid contents (for those who watched this as 1st video to help them understand) I have watched and understood some of the very important concepts and then I watched this video so I could understand but some who watched this as beginning videos for practicing understanding the concept may not get the meaning/theory behind it. 5C3 = 5!/[(5-3)!(3!)] = 5 x 4 x 3 x 2 x 1 /2 x 1 x 3 x 2 x 1 = 10 5C3, or 5 choose 3, is *5*: number of total items to choose *from* and *3*: the number of items to *choose*. Meaning.... nCr = n: total number of items to choose from, r: the number of items to choose. back to (n-r)! is divided from total number of items to choose from because we are *not taking those items in to account*. r! is also divided because items to choose, themselves, have number of ways to arrange(since if it was 5!, which is permutation, it means all items are DISTINCT so the order matters and no need to cut down the number of ways to arrange those items; there is no overlap). Here is the part I wanted to clarify: the next moment he was calculating 10C4 = (10 x 9 x 8 x 7)/ (4 x 3 x 2 x 1). Why and how? This is because in ANY case where you come up with answer nCr, the whole calculation reduces to be (n, decreasing each time by 1 when it is multiplied, times the number of items selected / n!) when you feel comfortable in calculating nCr is a tip...... 5C3 is SAME as 5C2. you can check with any number as long as it follows the rule I stated in previous paragraph. (5 x 4 x 3)/(3 x 2 x 1) = (3 cancels, 4 is reduced) 2 is the answer. You'll see the pattern once you try both the way to do this is when your answer is 8C6, you just have to change the number r with (n-r) so it'd be 8C2 in this case. Much faster and efficient to calculate. disclaimer: as I am one who is still learning there maybe some mistake or unclear parts but I am confident enough to say above and tips. This is not meant to disrespect or so; just trying to add something to this vid since I honestly think this video was very helpful to me. I struggled so much when I first learned this so that's why I want to help
What about combination, which involves letters as well? For example 2-9 and A-Z ? (26 letters in the alphabet) but the string is limited to 12 - so 12 spaces, mixed with letters and numbers.
I am doing a math puzzle. There are 19 pieces, with numerical values from 1 to 19. (I have to arrange them in rows in such a way that every row adds up to 38,). I’m trying to find out how many possible combinations. I used to think it was 19 squared. Now I’m wondering if it’s 19x18x17….and so on. So it’s either 361. Or some astronomical number, or I’m wrong on both counts. It’s a Chinese puzzle call Lu’s Tshu, or something like that.
That easy?! I leaned about permutations from Brilliant, it vaguely showed the algebra but didn't explain it. Kahn Academy uses a similar format and that works for me just fine,
Not sure if it works if we have this an example like this. You have to get 6 snacks from the gasoline station and you have to choose from 10 different snacks. The same snack can be chosen. So you can have 1,1,1,1,1,1. It doesn't work with this example does it
This is selection combinations. Instead of having a number & taking away from it. It would be more accurate if for example you did "Its wacky t-shirt day at work. There are 15 employees that decided to participate, & each employee has has their own 7 shirts to choose from. How many different wacky t-shirt combinations could the employees show up to work in?". Can you figure it out??(I just thought of this, I don't even have an answer, or know how to figure this out 🤦♂️lol)
How do you find permutation but if there are for example 10 numbers and out of them 4 numbers but the repetition is possible. The same number could repeat more than one time
Q: So if I got my answer but I only gave a partner the factorial of 9! / 6! 3! how would they find out the answer? They'd just say n is clearly 9 and r is clearly 3 so then they'd work out, like you did, that there's 84 combinations and check it by n-r?
i was searching for a while but could not find any answers. basically what i was looking for was that there would be 4 people, 3 erasers, and 2 pencils. how many combinations would there be if i chose 1 from the people, 1 from the erasers, and 1 from the pencils.
how could anybody dislike this amazingly compassionate and clear presentation
Jealous perhaps 🤣😅
It might just be a misclick
they were holding their phone upside down
Man sounds Bruce the shark from Finding Nemo
J L oh yea
Where are you from ...my one of the friend look like you ...
That's why we all are here (explaination : no one care about maths )
@@Xeroffice I care…
Thats rude
OMG! I'm studying for the GRE, and this is something I never learned... THANK YOU FROM THE BOTTOM OF MY HEART!!!
This is way easier than what I was taught in school!
MTMFan you are still a baby
Hehe
i had a really good teacher and still agree
Bravo Mr. Tecmath. you should publish books on these matters and they should be mandatory for school curriculum . Your examples take the fear out of mathematics.
THANK YOU! I am studying for the CLEP exam and the other sites I have found are so confusing and drawn out! You are straight to the point and easy to follow with the steps and rational you provide!!!!
This made computer programming functions so much less complicated than what computer science circles Ex15b made it seem. Tysm
Dude totally agree man, this guy is such a genius
Way easier than what I’m being taught now. Thank you!
Much better than some of the complicated videos watched. Thanks mate.
Incredibly clear. You make it easy to digest and it seems so obvious once I grasped it.
explained way better than my teachers. Thank you. I swear, school makes it out to be harder than it ACTUALLY is.
Exactly!!!
Thank you very much, you have seriously helped out dramatically, I was afraid I would fail my test, but just like always, some dude on youtube who sounds like Bruce the shark from Finding Nemo always helps me more than my own school's lessons
THANK YOU! 🙏 I just went through 5 videos and 2 books trying to figure this out.
460 views, 46 likes and 0 dislikes... I love how perfect the numbers are
Now its 570 virws and 57 likes
590 views, 59 likes 0 dislikes... What is this sorcery?
670 views, 67 likes and 0 dislikes
WazzupKMS now it's 790 views 79 likes and 0 dislike
I am for sure going to murder anyone who breaks the pattern
Your explanation made things sooooo much easier! Thank you!
Thank you. I understand basic math. But, this is a bit more advanced for me. God bless you sir. You are a great math teacher. Your videos help me get me through some difficult times in my life right now until I get them straightened out. Hopefully will be practicing them with my scientific calculator on my laptop.
This was by far the best explanation I could understand. Thank you!
Thank you so much for your excellent and simple explanation - I just couldn’t wrap my head around this problem on my own.
Finally, a video I could understand to help make things easier. Many thanks!
Thanks for making a tricky subject a little easier to understand Josh.
Thank you , thank you!! You have now helped me overcome the fear of permutations and combinations. I always loved the other maths like geometry, trigs, mechanics and calculus but when I had to deal with stats I had a some fear. Thanks again!
better than my professor, thank you soooo much!!!!!
Legit😂😂
you are so much better at explaining than my teacher.
Thank you mate !!!
Finally understand it
This video really really helped, I was so confused and now I feel really confident about my exam!
OMG thank you so much my GED prep book told me that I had to write out EVERY combination???
Very intuitive explanation. Great video.
I've been going over and over this and thanks to tou I finally understand, Thank You...
This is much easier than making a chart thank you!!
Omg thanks alot😄. My school has scantron coming soon and these are the only questions that confused me😂. You really helped me lol
Glad I found this, I didn't know how to ask for this lol so I couldn't find it for a long time! I was sure there was a short cut but I couldn't find it from my stats text book. They really want you to do it the long way.
thank you sir From the bottom of my heart and top of my head
Insanly interesting and simple way you explained this concept! I would still be trying to remember the formula if it wasn't for you!
dude this guys a genius
u saved my grade thank u so much
wow- you summed that up perfectly! THANK YOU
most relaxed guy ever
Thank you bruh
I don’t know how can I say thank you professor ❤️ ❤️ I appreciate you so much
Extremely helpful. Thanks so much
Bro I love you so much you just made my day easy
OMG thank you so much. I could learn from you all day long. You make combinations so much easier.
great teacher. you made it super easy
your a legend mate respond because you made me get 92 in maths for fraction all from the help of you
Thanks Alan Moore
thank you so much for this .
Thanks really helpful
TYSM! finally I know how it works
thank you so much I understand this now!!!
thank you it really helped me .
What about if we are required to have a combination of 3 letters with 4 numbers? Like these : ABC 1234; BBC 4351; SSS 6666, etc. Condition 1: Numbers and letters may be repeated; Condition 2 : Numbers and letters may not be repeated. Numbers can be picked from 0 to 9 (10 numbers) and letters can be picked from A to Z (26 letters). Thanks in advance.
Aghhhh thank you thank you I didn’t understand the formula just wanted to know what it meant
I appreciate you for making videos to help us and it is so helpful to me bc of how many number and types of questions there are and your explanation.
my intension here is to clarify some stuff for those who didnt get this vid contents (for those who watched this as 1st video to help them understand)
I have watched and understood some of the very important concepts and then I watched this video so I could understand but some who watched this as beginning videos for practicing understanding the concept may not get the meaning/theory behind it.
5C3 = 5!/[(5-3)!(3!)] = 5 x 4 x 3 x 2 x 1 /2 x 1 x 3 x 2 x 1 = 10
5C3, or 5 choose 3, is *5*: number of total items to choose *from* and *3*: the number of items to *choose*. Meaning....
nCr = n: total number of items to choose from, r: the number of items to choose.
back to (n-r)! is divided from total number of items to choose from because we are *not taking those items in to account*. r! is also divided because items to choose, themselves, have number of ways to arrange(since if it was 5!, which is permutation, it means all items are DISTINCT so the order matters and no need to cut down the number of ways to arrange those items; there is no overlap).
Here is the part I wanted to clarify: the next moment he was calculating 10C4 = (10 x 9 x 8 x 7)/ (4 x 3 x 2 x 1). Why and how?
This is because in ANY case where you come up with answer nCr, the whole calculation reduces to be (n, decreasing each time by 1 when it is multiplied, times the number of items selected / n!)
when you feel comfortable in calculating nCr is a tip......
5C3 is SAME as 5C2. you can check with any number as long as it follows the rule I stated in previous paragraph.
(5 x 4 x 3)/(3 x 2 x 1) = (3 cancels, 4 is reduced) 2 is the answer. You'll see the pattern once you try both
the way to do this is when your answer is 8C6, you just have to change the number r with (n-r) so it'd be 8C2 in this case. Much faster and efficient to calculate.
disclaimer: as I am one who is still learning there maybe some mistake or unclear parts but I am confident enough to say above and tips. This is not meant to disrespect or so; just trying to add something to this vid since I honestly think this video was very helpful to me. I struggled so much when I first learned this so that's why I want to help
Thanks.
Ok. i understand this explanation. So, good job.
Let A be a set containing 2023 elements. How many ways are there to choose two subsets of A (not necessarily distinct) whose union equals the set A
Nice.
In just under 9 minutes I went from having no f*ckin clue what I was doing to being able to solve these questions no problem.
THANKS
Thanks a Million 🎉❤
THANK YOU MAGIC MAN
this man made weeks of studying to miniutes
What about combination, which involves letters as well? For example 2-9 and A-Z ? (26 letters in the alphabet) but the string is limited to 12 - so 12 spaces, mixed with letters and numbers.
THANK YOU SO MUCH!!!
Are you Australian? I love your pronunciation hahahhh
Anyway I love your videos
Love from Italy
WHY DONT WE IS LIFE
PaulNerrumo iD He sounds like Daren Lehman, the former Australia cricket coach
He sounds normal
...then again I am Australian
@@leizhang7255 lool, why did you say you are austrialian? isnt your name zhiang? i think you must be chinese. thats for sure.
Sup, I love your vids.
Thank you!
I am doing a math puzzle. There are 19 pieces, with numerical values from 1 to 19. (I have to arrange them in rows in such a way that every row adds up to 38,).
I’m trying to find out how many possible combinations. I used to think it was 19 squared. Now I’m wondering if it’s 19x18x17….and so on.
So it’s either 361. Or some astronomical number, or I’m wrong on both counts. It’s a Chinese puzzle call Lu’s Tshu, or something like that.
Thank you
this broke my brain in school but it seems so ridiculously easy now
You have a big pot of oatmeal and a choice of 18 toppings. How many combinations?
I gotta find out where your from, that accent is a turn on!
thank you bro
THANK YOU
That easy?! I leaned about permutations from Brilliant, it vaguely showed the algebra but didn't explain it. Kahn Academy uses a similar format and that works for me just fine,
Not sure if it works if we have this an example like this.
You have to get 6 snacks from the gasoline station and you have to choose from 10 different snacks. The same snack can be chosen. So you can have 1,1,1,1,1,1. It doesn't work with this example does it
Thank you so so much for this video it helps me a lot but I didn't get the last part where did you get the 3!5!?
Thank you so easy
Ok good explanation
Nice video, very clearly explained, however you could've included combinations with repetition! Nevertheless, respect.
+cho_Oz thanks. Good luck on your exam tomorrow.
Bore
thankyou so much.
Thanks for the lesson!
So good! Thank you so much!!
Great accent sir!
don't come to comments man, you're here to study and so am I. lmao
This is selection combinations. Instead of having a number & taking away from it. It would be more accurate if for example you did "Its wacky t-shirt day at work. There are 15 employees that decided to participate, & each employee has has their own 7 shirts to choose from. How many different wacky t-shirt combinations could the employees show up to work in?". Can you figure it out??(I just thought of this, I don't even have an answer, or know how to figure this out 🤦♂️lol)
thanks so much man
Nice ! It is ok if I take your idea and translate it in another language (a new video) and put it in my channel?
bloody legend
How do you find permutation but if there are for example 10 numbers and out of them 4 numbers but the repetition is possible. The same number could repeat more than one time
Q: So if I got my answer but I only gave a partner the factorial of 9! / 6! 3! how would they find out the answer?
They'd just say n is clearly 9 and r is clearly 3 so then they'd work out, like you did, that there's 84 combinations and check it by n-r?
THANK YOU SO MUCH
Thank you sm 🤩🥺❤️
Hey it’s the doctor from spongebob here to save my day :)
Yay now i understand it!
Sir please can you teach time and work, AP - GP and calendar problems
Thank You!!!!!!!!
I love you man
One step closer to counting cards 😏
i was searching for a while but could not find any answers. basically what i was looking for was that there would be 4 people, 3 erasers, and 2 pencils. how many combinations would there be if i chose 1 from the people, 1 from the erasers, and 1 from the pencils.
nevermind! what i was looking for was possible outcomes probability.
Hello, if an id has 8 numbers, how many can be made if the number can be repeated ?
And how many if it cant?
Thanks
What happens when the boss is going to be going no matter what but he needs to take three out of five people how do you figure that out?