If anyone is confused with the school board questions. The first one is combination because it said "3 people" which is to say ANY 3 from the 8 will do. The next one says "3 DIFFERENT responsibilities" which is to say it matters which 3 from the 8 gets which unique responsibility. Essentially for these problems pay attention to wording.
Thank you! My takeaway: • Permutation: - arrangement - order matters, i.e., A, B ≠ B, A • Combination: - selection/choice - order doesn't matter, ie, A, B = B, A
FooBar Maximus shit you’re a genius just blame it on your proffessor and scientists. Its always not your fault but its always someone else fault. What a genius.
Too educational and the examples are understandable just goes in my mind this topic took my teachers 2 weeks to cover still can't get what my teachers thaught but ur 8 minutes videos just helped me out in the best way
@Daniel, Thank you so much!!! I figured it out, turns out that I didn't do 3.2.1 and ended up with 6 at the bottom, that's the only mistake I made. But I really appreciate your help!!! God Bless you!
Great Video 👍 Tip: Use "Universal Calculator"(formula mode) App to perform Permutation and Combination automatically, this helps to verify your answer, learn and understand quickly. Download from Play Store : play.google.com/store/apps/details?id=com.shahalam7862020.calculator
This is the second video that I watched so far in two hours about permutation and combination. I like how this video focuses on the differences between the two which helped me understand it a bit better. The number of examples also was very helpful. Thank you Jamie Toloa
You really answer my nagging question which is different between knowing combination and permutation from the term of Selecting*...if the selection is termed Different then use Permutation and if rephrased as Same then apply Combination
I still didn't get why you divided it by 6. You mentioned that we may have counted twice, but what's exactly the 'twice' thing ? Even though I tried it one by one and scrolled through people's explanation, I'd still scratch my head.
in permutation/arrangement (20$,10$, 5$ example)order is important i.e it matters to whom we give the first second and third prizes. But the order is not important in combination/selection(same 5$ prize example). so when he took 10*9*8 , he has also counted 3! (or 6) additional possibilities i.e 1st 2nd and 3rd person getting the same 5$ prize . Lets say the prizes are A,B and C(permutation). these can be arranged 3! ways that is ABC,ACB,BAC,BCA,CAB and CBA. but if these are all the same prizes i.e AAA they can be arranged only 1 way(combination).
@@rahulraveendran7200 Yeah, so basically he counted the 1st,2nd and 3rd prize twice so he divided it by 3! as there are three prizes and the order does not matter as the prizes are same.
thank you SAL i just randamly searched for difference i never thought that you would teach it because just before this video i had watched a video of yours at khan academy iam happy with the coincincedence
When the "bucket" is unique, you never double count. When the "bucket" is not unique, you have to account for double counting. Quick example. If A B C are receiving 2 x $5 dollar bills (bucket). You will end up with A and B , B and A, A and C , C and B. See how A and B is same as B and A since the $5 dollar bill isn't unique and you will need to remove this later. If A B C are receiving a 1 dollar bill and a 5 dollar bill you will end up with: A(1dollar) and B(5dollar), B(1dollar) and A(5dollar) in this scenario you don't have to worry about double counting.
Basically the difference is that in a Permutation, the order matters. In the first example in the video, 3 people were to be chosen out of 10 for 3 UNIQUE prizes (the $20, $10, and $5 prizes). Meaning that the same person who wins the $20 could not also win the $10 or the $5 prize, the prizes are unique. This question could have been made into a Combination problem (where order does NOT matter) by asking how many ways can 3 people out of 10 be selected for the SAME VALUE of prizes (three $5 for example). It doesn’t matter if you win the first $5, or the second $5, or the third $5... you’re getting the same prize. Basically it’s about whether what you’re calculating the probability is for a unique thing or just multiples of the same thing. I hope that helps somewhat.
I like the way of teaching except to those parts that you were using a calculator to solve it. Maybe you could help us more by trying to show us how to solve it in a practical way rather than using shortcuts. Because in exams, calculators are not allowed.
The first example could be a bit cleaner, cause the way it was expressed I could apply either permutation or combination, depending on the understand; In a group of 10 people, a $20, $10 and $5 prize will be given. How many ways can the prizes be distributed? In case I assume these three prizes are going to be distributed in a draw/lottery way, I would apply on it a combination (10 choose 3), but if it was said the context as a race for example, so I would understand it as an ordering thus applying the permutation (10 permute 3).
I see that a race would make it clearer. In my mind I am seeing who gets each prize like a first second third. $20 is first, $10 is second, $5 is third. Actually when I made this video, I thought it would get 10 views a year.... not 1000s per day...... it is a strange video to be my most popular. I though my Permutation video and my combination video would be more popular. Both use cleaner examples with cleaner explanations.
I’ve been stuck on this certain problem. 5 letters a,b,c,d,e. How many ways can we have a distinct sequence using 3 letters? A or b or both must be included. The answers is 54 ways but don’t know how they got there. Event 1 has a c d e because b is not included. There is 3 events each adds up to 18 for 18+18+18 = 54 ways
Give me a minute and I will post the problem and how I think of it. sorry had company all weekend so haven't had time to read comments. Will post something shortly. It will be in my channel as a new video.
i am really confused. Take the example "locker combo" firstly the point of this comment is not that locker combo should be locker perm i already got that cleared. Continuing, if your locker "combo" is 5432 and you enter 2345 it will not work, because order does matter in a permutation, right? Then why does a permutation have more results than a combination? If this locker would also open with 2345 then there should be more results, correct? And then I also don't understand why there's only 1 answer and how I'm supposed to plug in that for an equation nPr??? or for cPr? basically what im saying is why do permutations have more results than combinations if order is relevant in perms and certain options will be removed, where as in combination those options will be kept as choices? I can see it in the formulas, but I don't know truly know why perms have more results. also...for 4:45 and 6:00 why are they not the same answer? Can't you interpret the 3 people chosen as the ones with responsibilities? This makes my head hurt. please help i have a major test with probability being 1/4 of it and it is pretty soon.
Sorry I have not been replying in a short period of time. I have lots of excuses. Thank you for giving me such a well thought out question. This is a lot to unpack. In a locker combo where your have four combinations that can all be the same number, for example 0000 is a legitimate possibility. and there are 10 symbols that can go into each spot in the proper order from left to right.... Using fundamental theorem of counting we would have 10*10*10*10 possible combinations for this locker key. Or 10,000 possible values. This is neither a combination or permutation. It is a simpler problem of the fundamental counting theorem. I can see now how my video is confusing. A permutation means we pick the combination in order and then cannot reuse the thing we picked. So you would get 10*9*8*7. Or 10p4 or out of 10 things we choose 4 where order is important and we cannot repeat a symbol (so 0000 is no longer a possible locker combination) now we have 5040 ways to choose the locker combo and indeed 5432 would be different than 2345. In the case of the word combination. which should not be confused with something you do with your locker, as it depends on the devise you use.... In my mind the mathematical definition of a combination is a permutation where order is not important. In this case if you get any number correct in any order you will unlock the locker and again 0000 or 5555 is not a possibility. Which I am not sure of a mechanism in the physical world that would produce this..... an any rate 5432 and 2345 would be the same code and unlock the locker.... In this case you would divide 10*9*8*7 by the number of ways to rearrange the 4 numbers (4*3*2*1) so 5040/24 = 210 so now we are down to 240 possible values. I am not sure I am helping you here, but you have given me yet another angle to approach these problems. This is a great example to show the difference between the three things we are talking about. the fundamental counting Theorem, Permutation, and Combination. Those are the big 3, and in my experience the only way to truly understand them is to get down and dirty working tons of different types of problems and finding your own understanding. There are two things to avoid in this world and both lead to self destruction. Always avoid knowledge and money you didn't work your ass off for. Or in other words as a positive. Always work hard for your knowledge and money, so that they are truly yours and only one can be stolen from you. They have to kill you to steal the other, and it is not stolen, just lost.
i understand the multiplying part in the last question, what confuses me is why it was a combination and not a permutation. was it because they're all just in a committee, an all receiving the same position in the committee? and why it's choosing 2 girls out of 5 instead of 8..and same for the boys instead of 8 choosing 1 its 3 choosing 1
@@danielschaben Thnx for your prompt response Sir. Then for the 9th rank should there be 2 ways. Shall be grateful if any illustration is shown. Regards
if each person on the committee was assigned a different responsibility then it would be a permutation. like picking a president vice president and treasurer out of 10 people. if they all have the same responsibility.... then it is combination
sorry, just getting to replying 3 choose 1 is 3. you can look at it with the formula, but might be easier to thing about it.... if there are 3 things and we want to know all the possible ways we could choose one of those things, then there is only 3 ways because there are only 3 things to choose from. You can also see it in the second element of the 3rd row of pascals triangle (1,3,3,1) which also means there are 3 ways to select 2 things in a group of 3..... Anyway... thank you so much for the comment. So sorry it is taking so long to get responses to people... my day job is killing me...lol have a great one and if you have other questions please send them my way. Truly love helping out when I can... have a great one!!!!
Also thanks for watching to the end...Im not always the most excited speaker when I do these vids because I am alone speaking to a wall..... FML.... LOL
Well thank you. It has been a strange video. I remade it from comments that I received, but it remains incredibly popular for some reason. Thanks for the comment and I am so glad I was able to help you.
What is the total combination I will have if I have 13 kids and each kid has a choice to choose one of these 3 fruits apples pears and grapes........how do I calculate the number of combinations
THANKS man!! you help me a lot! this is why I love youtube than my lame college,,, becuz youtube has much more understanding and better education then my college lmao
in how many ways can we select three students from a group of five students to stand in line for a picture? Is it a permutation or a combination please?
The first question about the committee was incorrectly identified as a combination. It would be a permutation because they need 3 people and a person cannot be on the committee twice
In the last question the order matter since we are choosing a given no. Of girls and boys..... Please clear my doubt.. that how is it a combination....
It is a combination because it does not matter what order we choose the girls and it does not matter what order we choose the boy, but since we are just choosing one, it is irrelevant.
Can anyone explain me.. How to Solve this Problem...? In a cultural festival, 6 programmes are to be staged, 3 on a day for 2 days. In how many ways could the programmes be arranged?
For the last question, I believe there would be an extra 3! multiplied to the answer because the order of how you choose the 1 boy and 2 girls does not matter. You could choose G1 then G2 and then B1, or B1 then G1 then G2, etc...
Hello, great video! This really helped me for the online math course I'm taking since they don't exactly describe it in great detail. just one question, why do you multiply the two combinations in the last problem? Why not add? Thanks!
Short answer would be fundamental counting theorem......sorry my answer is late. I just know that is why we multiply. Watch some stuff on fundamental counting. And thanks for the comment, even though I am 7 months late. I will try and do better in the future
It could be the way you are using your calculator. That is why I like students to first learn these problems with the bins or fundamental counting property rather than the formula. Too easy to make mistakes and get discouraged with the formula.
In here the fact that they are all doing the same job means that order does not matter. If the three person committee had specific jobs to do. . . maybe one person was the data gatherer, another person is the recorder, and the final person compiles the data, then order would matter. The example at 4:50
I wish I was that popular. I have a few trillion views and several hundreds of millions of dollars to catch up with Sal... lol. thanks for the comment. You made my day. Have a great one.
thank u very much , i got it in few mins .u solved my doubts.But interesting fact is that can u provide website of probability calc?its easier way. i didnt used it before
Let me ask you this. Would it matter to you which prize you win? If the amount of money we have were meaningless, then no, order does not matter. But I want to win the bigger prize.
If anyone is confused with the school board questions. The first one is combination because it said "3 people" which is to say ANY 3 from the 8 will do. The next one says "3 DIFFERENT responsibilities" which is to say it matters which 3 from the 8 gets which unique responsibility. Essentially for these problems pay attention to wording.
Thanks because I had combination. I really over looked the word different.
Thanks
💀💀💀gonna have to take some time getting used to these
The video was helpful , but your comment was more helpful than the video ❤thank u
Can I send you a question on it
Thank you!
My takeaway:
• Permutation:
- arrangement
- order matters, i.e., A, B ≠ B, A
• Combination:
- selection/choice
- order doesn't matter, ie, A, B = B, A
Glad it was useful! Thanks for the comment.
Why these word problems are so easy while my teacher gives the most confusing ones. This is the only time i've predicted everything right 😂
Samedt HAHAHA ang hirap yawa may exam kame in 5 minutes zzzzz
😂😂
😂😂😂
Who else is here one night before the examm
Good Luck
One hour
so why is our locker code called locker COMBINATION and not locker PERMUTATION if the order matters? (this is what my math teacher said btw)
I will have to use that one. Thanks!!!!!!
jungkook i thought you graduated already? XD
Bangtan_Animegirl
Wrong sound
FooBar Maximus can you prove what you’re saying? sorry it’s just I’m a bit skeptical of what you’re saying
FooBar Maximus shit you’re a genius just blame it on your proffessor and scientists. Its always not your fault but its always someone else fault. What a genius.
Thank you for actually explaining how you do things and not just what to do. You are a God send.
Glad it was helpful
5 years ago and this is still gold! Thank you so so much for this. i understand the concept now
Too educational and the examples are understandable just goes in my mind this topic took my teachers 2 weeks to cover still can't get what my teachers thaught but ur 8 minutes videos just helped me out in the best way
@Daniel, Thank you so much!!! I figured it out, turns out that I didn't do 3.2.1 and ended up with 6 at the bottom, that's the only mistake I made. But I really appreciate your help!!! God Bless you!
Great Video 👍
Tip: Use "Universal Calculator"(formula mode) App to perform Permutation and Combination automatically, this helps to verify your answer, learn and understand quickly.
Download from Play Store : play.google.com/store/apps/details?id=com.shahalam7862020.calculator
@@intelilearning8341 I'm not
My kwo look ok l Ok I'll only usually,
Jesus Christ loves you
Thank you so much! I was having a bit of trouble with recognizing a permutation vs a combination, and this video cleared that up nicely!!
Glad it helped!
Jesus Christ loves you
@@ben2808 i do too
This is the second video that I watched so far in two hours about permutation and combination. I like how this video focuses on the differences between the two which helped me understand it a bit better. The number of examples also was very helpful. Thank you
Jamie Toloa
Hey Jamie
I will be regret if i dont watch this vid before answering my final exam..it helps A LOTTTT..likeeee it really make me understand the concepttr
I just had my Eureka moment! Thank you for this video!
This Last 2 questions is the one I have been struggling with from my textbook but u have done justice to it, thanks man👌
Watch more videos on Permutation and combination here ruclips.net/video/M-U-GFCVfD4/видео.html
You really answer my nagging question which is different between knowing combination and permutation from the term of Selecting*...if the selection is termed Different then use Permutation and if rephrased as Same then apply Combination
I still didn't get why you divided it by 6. You mentioned that we may have counted twice, but what's exactly the 'twice' thing ? Even though I tried it one by one and scrolled through people's explanation, I'd still scratch my head.
in permutation/arrangement (20$,10$, 5$ example)order is important i.e it matters to whom we give the first second and third prizes. But the order is not important in combination/selection(same 5$ prize example). so when he took 10*9*8 , he has also counted 3! (or 6) additional possibilities i.e 1st 2nd and 3rd person getting the same 5$ prize . Lets say the prizes are A,B and C(permutation). these can be arranged 3! ways that is ABC,ACB,BAC,BCA,CAB and CBA. but if these are all the same prizes i.e AAA they can be arranged only 1 way(combination).
@@rahulraveendran7200 Yeah, so basically he counted the 1st,2nd and 3rd prize twice so he divided it by 3! as there are three prizes and the order does not matter as the prizes are same.
The answer is simple. 3*2*1 is 6 Dumbo
thank you SAL
i just randamly searched for difference i never thought that you would teach it because just before this video i had watched a video of yours at khan academy
iam happy with the coincincedence
i feel like you couldve explained why it would be a permutation or a combination better... im still confused
Will do some work on this when I get my equipment replaced. I see that this is a topic that needs several clarifying videos for.
When the "bucket" is unique, you never double count. When the "bucket" is not unique, you have to account for double counting.
Quick example. If A B C are receiving 2 x $5 dollar bills (bucket). You will end up with A and B , B and A, A and C , C and B. See how A and B is same as B and A since the $5 dollar bill isn't unique and you will need to remove this later. If A B C are receiving a 1 dollar bill and a 5 dollar bill you will end up with: A(1dollar) and B(5dollar), B(1dollar) and A(5dollar) in this scenario you don't have to worry about double counting.
@@swallow1106 what?? Omg
Basically the difference is that in a Permutation, the order matters. In the first example in the video, 3 people were to be chosen out of 10 for 3 UNIQUE prizes (the $20, $10, and $5 prizes). Meaning that the same person who wins the $20 could not also win the $10 or the $5 prize, the prizes are unique. This question could have been made into a Combination problem (where order does NOT matter) by asking how many ways can 3 people out of 10 be selected for the SAME VALUE of prizes (three $5 for example). It doesn’t matter if you win the first $5, or the second $5, or the third $5... you’re getting the same prize. Basically it’s about whether what you’re calculating the probability is for a unique thing or just multiples of the same thing. I hope that helps somewhat.
@@ck4786 thank you
Finally!!! A video with my type of calculator
calculator app link please
My exam is today. This video explained the topic SO WELL. I'm finally looking forward to my exam.🎉
Just the refresher I needed before my finals
Thanks a million!
Even though I study Math in Arabic this video helped me to differentiate between Choose and Pick.
Glad it was helpful! The video in the discription is my remake of this video. It goes into more depth
A tip:
If you're shortcutting anything in a tutorial or shorthanding something, make sure you explain why you took certain steps (purpose).
I like the way of teaching except to those parts that you were using a calculator to solve it. Maybe you could help us more by trying to show us how to solve it in a practical way rather than using shortcuts. Because in exams, calculators are not allowed.
Julius Villanueva good to know. Will do one without a calc
no longer confused ..good job sir
thanks a bunch
thankss !! next tomorrow is my biggest exam in my life and i know how to solve it in additional mathematics exam !! thank :))
thank you! Have a test tomorrow on a bunch is stuff on probability, this is the one thing that confused me on identifying them but much more clear now
1 year later.. how did it go
Thank you! I’m trying to teach my students about this and it’s still hard for me to tell lol
One of the most difficult topics in math in my opinion
@@danielschaben thanks for relating lol its a relief for people
@@danielschaben This is harder than limits and derivatives
This video was very helpful I now know the differences between the two
The first example could be a bit cleaner, cause the way it was expressed I could apply either permutation or combination, depending on the understand;
In a group of 10 people, a $20, $10 and $5 prize will be given. How many ways can the prizes be distributed?
In case I assume these three prizes are going to be distributed in a draw/lottery way, I would apply on it a combination (10 choose 3), but if it was said the context as a race for example, so I would understand it as an ordering thus applying the permutation (10 permute 3).
I see that a race would make it clearer. In my mind I am seeing who gets each prize like a first second third. $20 is first, $10 is second, $5 is third. Actually when I made this video, I thought it would get 10 views a year.... not 1000s per day...... it is a strange video to be my most popular. I though my Permutation video and my combination video would be more popular. Both use cleaner examples with cleaner explanations.
I found it so helpful for my exams thanks
Thank you so much it was so clear i had problem with identifying the permutation and combination
damn thank you so much, i understand within the first two mins .
your example is on point !
Thanks!
Omg wish my math teacher had told me that earlier. Tysm!
thank you man unfortunately my professor likes to make up questions that are 50 x harder than this :(
I’ve been stuck on this certain problem. 5 letters a,b,c,d,e. How many ways can we have a distinct sequence using 3 letters? A or b or both must be included. The answers is 54 ways but don’t know how they got there. Event 1 has a c d e because b is not included. There is 3 events each adds up to 18 for 18+18+18 = 54 ways
Give me a minute and I will post the problem and how I think of it. sorry had company all weekend so haven't had time to read comments. Will post something shortly. It will be in my channel as a new video.
ruclips.net/video/P_CgxYHRphs/видео.html
searching4math thank you so much I really appreciate it
I have been trying to find something about permutations thank you so much.
glad I get help you. Sorry I am late replying
This video serves as a good revision of this topic.
Thank you so much! This is SO helpful, you have no idea!
Thank you sir ! great tutorial . This examples are very helpful to understand . :)
Great video. Btw, what software are you using for writing?
UPSC SSC GURUKUL smart notebook
my final is literally tomorrow freaking BLESS this video just saved my life
lmao. How did the Exam go?
@@kishanmehta1102 she died
Thanks for the video.You explained the difference quite well
In some ques (not in ur videos) , its difficult to guess orders matters or not? then how would v know that its permutation que or combn que?
i am really confused. Take the example "locker combo" firstly the point of this comment is not that locker combo should be locker perm i already got that cleared. Continuing, if your locker "combo" is 5432 and you enter 2345 it will not work, because order does matter in a permutation, right? Then why does a permutation have more results than a combination? If this locker would also open with 2345 then there should be more results, correct? And then I also don't understand why there's only 1 answer and how I'm supposed to plug in that for an equation nPr??? or for cPr?
basically what im saying is why do permutations have more results than combinations if order is relevant in perms and certain options will be removed, where as in combination those options will be kept as choices? I can see it in the formulas, but I don't know truly know why perms have more results.
also...for 4:45 and 6:00 why are they not the same answer? Can't you interpret the 3 people chosen as the ones with responsibilities? This makes my head hurt. please help i have a major test with probability being 1/4 of it and it is pretty soon.
Sorry I have not been replying in a short period of time. I have lots of excuses. Thank you for giving me such a well thought out question. This is a lot to unpack. In a locker combo where your have four combinations that can all be the same number, for example 0000 is a legitimate possibility. and there are 10 symbols that can go into each spot in the proper order from left to right.... Using fundamental theorem of counting we would have 10*10*10*10 possible combinations for this locker key. Or 10,000 possible values. This is neither a combination or permutation. It is a simpler problem of the fundamental counting theorem. I can see now how my video is confusing. A permutation means we pick the combination in order and then cannot reuse the thing we picked. So you would get 10*9*8*7. Or 10p4 or out of 10 things we choose 4 where order is important and we cannot repeat a symbol (so 0000 is no longer a possible locker combination) now we have 5040 ways to choose the locker combo and indeed 5432 would be different than 2345. In the case of the word combination. which should not be confused with something you do with your locker, as it depends on the devise you use.... In my mind the mathematical definition of a combination is a permutation where order is not important. In this case if you get any number correct in any order you will unlock the locker and again 0000 or 5555 is not a possibility. Which I am not sure of a mechanism in the physical world that would produce this..... an any rate 5432 and 2345 would be the same code and unlock the locker.... In this case you would divide 10*9*8*7 by the number of ways to rearrange the 4 numbers (4*3*2*1) so 5040/24 = 210 so now we are down to 240 possible values. I am not sure I am helping you here, but you have given me yet another angle to approach these problems. This is a great example to show the difference between the three things we are talking about. the fundamental counting Theorem, Permutation, and Combination. Those are the big 3, and in my experience the only way to truly understand them is to get down and dirty working tons of different types of problems and finding your own understanding. There are two things to avoid in this world and both lead to self destruction. Always avoid knowledge and money you didn't work your ass off for. Or in other words as a positive. Always work hard for your knowledge and money, so that they are truly yours and only one can be stolen from you. They have to kill you to steal the other, and it is not stolen, just lost.
i understand the multiplying part in the last question, what confuses me is why it was a combination and not a permutation. was it because they're all just in a committee, an all receiving the same position in the committee? and why it's choosing 2 girls out of 5 instead of 8..and same for the boys instead of 8 choosing 1 its 3 choosing 1
Thank you so much sir...... May God bless you... this is the video by the help of which i understood the concept....
You are Lord Hanuman , thanks for saving me 🙏👍
If there are 10 teams playing, what will be the formula to rank them 1 to 10 based on the scores if each team. Thnx
10!
Your placing them so order matters. 10 *9*8*7*6*5*4*3*2*1. 10 ways to pick first, 9 ways to pick 2nd...etc
@@danielschaben Thnx for your prompt response Sir. Then for the 9th rank should there be 2 ways. Shall be grateful if any illustration is shown. Regards
Thanks! I wished you would have spend a little more time on that last problem--it was a little harder!
Harold Thomas good to know. Thanks
Thank you. You really helped me understand this topic very well.
Glad it was helpful!
If the word "responsibilities" were to be included in the first sentence at 7:45, would that make it permutation?
if each person on the committee was assigned a different responsibility then it would be a permutation. like picking a president vice president and treasurer out of 10 people. if they all have the same responsibility.... then it is combination
In the last question you divide by 2 to get the number of combinations for the girls part without repetition, but where does the repetition come in?
in 8:40, why the answer is 3? isn’t it 6? correct me if I’m wrong huhu
sorry, just getting to replying 3 choose 1 is 3. you can look at it with the formula, but might be easier to thing about it.... if there are 3 things and we want to know all the possible ways we could choose one of those things, then there is only 3 ways because there are only 3 things to choose from. You can also see it in the second element of the 3rd row of pascals triangle (1,3,3,1) which also means there are 3 ways to select 2 things in a group of 3..... Anyway... thank you so much for the comment. So sorry it is taking so long to get responses to people... my day job is killing me...lol have a great one and if you have other questions please send them my way. Truly love helping out when I can... have a great one!!!!
Also thanks for watching to the end...Im not always the most excited speaker when I do these vids because I am alone speaking to a wall..... FML.... LOL
Great explanation.
Such a life-saving video!
Well thank you. It has been a strange video. I remade it from comments that I received, but it remains incredibly popular for some reason. Thanks for the comment and I am so glad I was able to help you.
What is the total combination I will have if I have 13 kids and each kid has a choice to choose one of these 3 fruits apples pears and grapes........how do I calculate the number of combinations
Very helpful, thank you!
THANKS man!! you help me a lot! this is why I love youtube than my lame college,,, becuz youtube has much more understanding and better education then my college lmao
Your welcome. Glad I could help
I love that the school board is downsizing itself!
in how many ways can we select three students from a group of five students to stand in line for a picture? Is it a permutation or a combination please?
After 8 months… the answer is combination. Maybe you passed the course already so do u need the answer anymore?
@@Al-Suzuki Yes passed, but thanks for answering :)
Thanks
You clarified my confusions
جزاك الله خيرا ❤❤❤وشكرا جدا ع شرحك الذى لايوصف 😊
I hope God rewards me as well. Glad it was useful. God Bless.
The first question about the committee was incorrectly identified as a combination. It would be a permutation because they need 3 people and a person cannot be on the committee twice
In the last question the order matter since we are choosing a given no. Of girls and boys.....
Please clear my doubt.. that how is it a combination....
It is a combination because it does not matter what order we choose the girls and it does not matter what order we choose the boy, but since we are just choosing one, it is irrelevant.
great video, but I dont understand on the last part why you multiplied by 3 not 3 factorial
Can anyone explain me.. How to Solve this Problem...?
In a cultural festival, 6 programmes are to be staged, 3 on a day for 2 days. In how many ways could the programmes be arranged?
That was really good video
wow this is great stuff.. thanks for sharing this.. love from indonesia
For the last question, I believe there would be an extra 3! multiplied to the answer because the order of how you choose the 1 boy and 2 girls does not matter. You could choose G1 then G2 and then B1, or B1 then G1 then G2, etc...
Rabeea Ahmad that is possible. I would look at it again. Nice thought.
thinking about it again, there would be no 3!, I was getting my permutations and combinations confused
@@rabeeaahmad875 But shouldn't the final answer 30 be divided by 8C3 since we are picking a committee of 3 from 8 people?
Lifesaver 🔥🔥🔥
Hello, great video! This really helped me for the online math course I'm taking since they don't exactly describe it in great detail. just one question, why do you multiply the two combinations in the last problem? Why not add? Thanks!
Short answer would be fundamental counting theorem......sorry my answer is late. I just know that is why we multiply. Watch some stuff on fundamental counting. And thanks for the comment, even though I am 7 months late. I will try and do better in the future
@@danielschaben Loll no worries--finished the course with an easy A, thanks to your vid! i really appreciate your reply though, don't sweat it !
THANKEWWWWW it helped a lot my whole concept is clear now😍
You are very welcome. Glad it was helpful!
@@danielschaben 😍❤️
Thank you so much!!!
You're welcome
Why did you get two different values on the first example with the $20, $20, $5 ...you got 720,and then 1098 using the formula. That makes no sense.
Make sure your plugging it into the formula correctly. 10!/(10 - 3 )! is 720
And thanks for the comment and question!!!!
It could be the way you are using your calculator. That is why I like students to first learn these problems with the bins or fundamental counting property rather than the formula. Too easy to make mistakes and get discouraged with the formula.
thank you!! An amazing explanation))
Thanks bro, it helped a lot
Thanx a lot... It really helped me...
Great help to my basics ... Thank you so much :)
Happy to help!
Thank you so much this really cleared my doubt
You're welcome
Is it (probabilistically) possible to do the last exercice if the question implied using permutations ?
If yes, how can we do it?
what clue tells us that order does not matter in the second exercise?
In here the fact that they are all doing the same job means that order does not matter. If the three person committee had specific jobs to do. . . maybe one person was the data gatherer, another person is the recorder, and the final person compiles the data, then order would matter. The example at 4:50
Just new to this topic, can someone explain to me why the last one is a combination?
So helpful! Thank you!!!
your welcome
Me watching night before the exam 💀
Good Luck
wow i understand so much
Lowkey thought this was Sal Khan for split sec
I wish I was that popular. I have a few trillion views and several hundreds of millions of dollars to catch up with Sal... lol. thanks for the comment. You made my day. Have a great one.
permutation and combination *questions* is just like sat
Really good video, thanks
Your welcome. So glad I could help
thank u very much , i got it in few mins .u solved my doubts.But interesting fact is that can u provide website of probability calc?its easier way. i didnt used it before
good video
Thanks for the visit
This is great thank you
Dude you helped so much
Ro _ ruclips.net/video/fD-a_YFuYU0/видео.html
You can watch it animated regarding permutations
I just had an Oooooh moment! Thanks so much!
You're welcome and thanks for the comment.
Thank you sir
Thank you so much 💕
I don't get why the order matters in the first question
Let me ask you this. Would it matter to you which prize you win? If the amount of money we have were meaningless, then no, order does not matter. But I want to win the bigger prize.
@@danielschaben thanks, I got it
thank you
You're welcome!
This was helpful ... Thank you!!