Difference Between Permutations and Combinations | Discrete Math Exercises

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  • Опубликовано: 4 ноя 2024

Комментарии • 13

  • @WrathofMath
    @WrathofMath  Год назад +10

    CORRECTION AT 13:51 - I accidentally added 4 twice. Sorry about that. n + r - 1 is 8 + 4 -1 = 11. It should be 11C4 = 330.
    Thanks @Sport Master for pointing this out.

    • @dquixal77
      @dquixal77 Год назад

      Seven people in a room. How many handshakes are made? 7! / 2!5!
      person A handshakes the others and go out the room (6)
      person B handshakes the others and go out the room (6+5)
      At the end we have 6 + 5 + 4 + 3 + 2 + 1. A triangular number! isn't that beautiful, considering that factorials are the same but with multiplication? In fact, 6! is 6 * 5 * 4 * 3 * 2 * 1 and sixth triangular number is 6 + 5 + ... + 1.
      this problem is a combination poblem. But it's a permutation problem as well. It's a permutation of two groups of letters: YYNNNNN
      And combination with repetition is a permutation of bars and stars. Everything is a permutation! Combinatorics is beautiful

  • @gulamnabikagathala3762
    @gulamnabikagathala3762 Год назад +6

    Just sees you 2 years old video power set very help full thx
    Form India

  • @rubym420
    @rubym420 5 месяцев назад +1

    I have a test tomorrow and this helped so much!

  • @karthik6178
    @karthik6178 3 месяца назад +2

    I like your videos ❤ from india ❤

  • @sportmaster2586
    @sportmaster2586 Год назад +2

    Mistake in the final example Sir. Should be 11C4 I think. Great video!

    • @WrathofMath
      @WrathofMath  Год назад +1

      Drats, can't believe I missed that in editing! Thanks!

  • @firstname4337
    @firstname4337 Год назад +1

    combinations always confused me because "order does not matter" -- but for combination locks order DOES matter

    • @WrathofMath
      @WrathofMath  Год назад

      Yeah they should definitely be called permutation locks! Oh well.

  • @rubym420
    @rubym420 5 месяцев назад

    You look a lot like Freddie Highmore!