Or you could add all lines to the first and you would get 1+2+3+4+5 on the first line,then just factor them and you would only have 1 s on the first line,make them 0 and you would get a 4x4
of course i'd start by subtracting the first row once from everything else, and then the second row X many times from all the rest to get [(1,2,3,4,5),(1,1,1,1,1),zero,zero,zero] it's as beautiful a reduction as the matrix
Because inverse of A = {1/|A|}{adjoint of A} Now if two rows are identical, then |A| (or determinant of A) would be zero and inverse of A would not be defined.
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You could also substract lines/columns to get 4 "11111" rows/columns and get 0 as det.
The columns are linearly dependant, so the determinant is 0
One mathematical meme mad-lad:
"We have better stuff to do. Ain't nobody got time for that"
Great vid!
What was the beginning step of multiplication of x-2 and x-3? How does this work or what is this called so I can find why this is done?
Its great that you upload this determinant videos, because in college in seeing this actually! Keep it up Dr Peyam!
Or you could add all lines to the first and you would get 1+2+3+4+5 on the first line,then just factor them and you would only have 1 s on the first line,make them 0 and you would get a 4x4
I love ur teaching ! Is there any video about dual space in future? :p
In a couple of months
Peyam: Alright thanks for watching
Me: But I haven't watched the video yet
of course i'd start by subtracting the first row once from everything else, and then the second row X many times from all the rest to get [(1,2,3,4,5),(1,1,1,1,1),zero,zero,zero] it's as beautiful a reduction as the matrix
R5-R4 , R3-R4
2 rows same so zero
1st comment
I thought the same :-)
Do you mean R4-R3?
Mohammed Sharukh whatever
Does it have something to do with the det being "symmetric", ie equal to its transposed, or just a coincidence ?
Just a coincidence :)
Thanks
Hahahahaha, I love this one!
Why matrix are not inversible when have two same line ?
because it results in the determinant being 0 thus not invertible
Because inverse of A = {1/|A|}{adjoint of A}
Now if two rows are identical, then |A| (or determinant of A) would be zero and inverse of A would not be defined.
Nice explantion sir
C2 - C1 + C3 = C4
The determinant is equal to 0
Thanks goodbye !
Upload the next for Gaussian Integral
Please, Dr. πm 😍😄
In 2 days
What is the Jordan form for this?
Good question, haha! Definitely an eigenvalue of 0 somewhere
Haha! Thanks for the video, it is one of the few videos I understand 100% :P
Hugs from Brazil
Wow realy beautiful det.D peyam