There's no greater feeling than clicking on a video and having all your doubts and questions washed away in one sitting. Thank you, this was extremely helpful!
There's no greater feeling than clicking on a video and having all your doubts and questions washed away in one sitting. Thank you, this was extremely helpful! Thank you sir!
I am watching this again and again.It is masterpiece,you explained everything in 20 munite that my prof. couldnt explain to me in 3 weeks.Thank you so much,Sir
Thank you so much! This video cleared the confusing I was having. My professor just threw the formula for rank nullity theorem and I couldnt understand why it was like that. This video explained it nicely and added a gag to it too. Wish I had you as my professor!
What a life saver! I wish i saw this video earlier,, I have my la exam tomorrow and i was still having hard time understanding all those concepts,, and this single video untangled everything in my brain:) You r not even explaining in my mother tongue but you got me better than my own professor who speaks the same language as me hahaha Thank u so much!!!!
4:17 - since those are 3 linearly independant vectors in R³, their span should be all of R³, so wouldn't the columns of the identity matrix also serve as a sufficient basis?
@@drpeyam and what about the 3 L.I. vectors of the row-reduced matrix? Shouldn't they span R3 as well? I didn't understand the "span non-preservation property" between the L.I. vectors in the original matrix vs the L.I. vectors in the row-reduced matrix
I like how two seemingly parallel lines in this video seem to intersect somewhere off screen to the right. Do the top and bottom of the whiteboard form a basis of the column space of the whiteboard from this angle?
If you imagine 2x1 matrix, the transformation takes 2D space to 1D space, meaning there exists a line in the 2D space that goes to origin after the transformation, meaning that it's the null space of the matrix. Since column space is the output span, and null space is in a sense number of dimensions lost, the N (original number of dimensions) becomes the sum of column space and null space.
4:04 Row reduction destroys span? Why, columns 1, 3 and 5 are Linear independent and span R3 just like before row reduction Is the span of the matrix all 5 columns?
Hi Dr Peyam! If you have time, I was wondering if you could help me prove two things regarding column spaces and null spaces. I’m supposed to prove Nul(B) ⊂ Nul(AB). Here’s my attempt at the proof: Nul(B) contains all the vectors x that make the homogeneous Bx=0. We are allowed to left-multiply both sides by the matrix A. ABx = A0 ABx = 0 So I think we can say that if Bx=0, then ABx=0. If x makes Bx = 0 true, then x makes ABx=0 true. If x belongs to the null space of B, then x belongs to the null space of AB. Thus, we have proven that Nul(B) ⊂ Nul(AB). Is this reasoning correct or flawed? I’m also supposed to prove Col(AB) ⊂ Col(A). This one is trickier for me. Col(AB) contains all the output vectors y such that (AB)x = y. By the property of associative matrix multiplication, we are allowed to shift the parenthesis to say A(Bx) = y. If (AB)x = y then A(Bx) = y. So I’m seeing that if we can use AB to obtain the image vector y, then we can use A to obtain the same image vector y. But does this demonstrate that Col(AB) is a subset of Col(A)? I’ve been so confused by this for a long time and was wondering if you would be able to help clear up the confusion for me. Thank you so much!
Thanks Dr Peyam, is there anyway you and your team will do a real analysis for those struggling in undergrad schools and introductions of proofs. Thanks as always, and it is a pleasure to watch your output.
Thanks, I am taking my linear algebra exam within an hour. I don’t want to say this video is helpful, but this video is super helpful!
Hahaha
I hope you already passed your LA exam years ago lol.
i m surprised that u could find time to take linear algebra despite ur busy schedule
wait, I thought you were a university professor? Why are you taking Linear Algebra ??
I actually have the exam in three hours 💀
There's no greater feeling than clicking on a video and having all your doubts and questions washed away in one sitting. Thank you, this was extremely helpful!
exactly
There's no greater feeling than clicking on a video and having all your doubts and questions washed away in one sitting. Thank you, this was extremely helpful!
Thank you sir!
Happy to help!
"every answer in linear algebra is row reduction"
Exactly what I was thinking! Thank you sir for making cramming fun and effective 👏
meat(A) + fat(A) = steak(A)
I am watching this again and again.It is masterpiece,you explained everything in 20 munite that my prof. couldnt explain to me in 3 weeks.Thank you so much,Sir
ı am here before the every linear algebra exam😂😂
Thank you so much! This video cleared the confusing I was having. My professor just threw the formula for rank nullity theorem and I couldnt understand why it was like that. This video explained it nicely and added a gag to it too. Wish I had you as my professor!
I liked the M and N acronyms rule. Thank you very much for this lecture.
thank you so much, you saved my life.
Honestly! This is so much helpful...I have my LA exam in an hour and with no preparation, I just watched this video now and gosh it felt good...
I actually do have an linear algebra exam in an hour and needed this video so badly !
😂😂😂 the way he began am literally two hours away from my exam
What a top G. Huge respect for you brother
Bro you’re too good at teaching this concept… I’m crystal clear now, thx a lot!
Thank you :3
Thank you so much! I love your energy and enthusiasm for math!
Thanks for posting this! I have a linear algebra final next week and I was stressing over this topic. Thank you!
+ Respect
Need more enthusiastic teachers/lecturers/professors like you
May Lord Shiva Bless you.
What a life saver! I wish i saw this video earlier,, I have my la exam tomorrow and i was still having hard time understanding all those concepts,, and this single video untangled everything in my brain:) You r not even explaining in my mother tongue but you got me better than my own professor who speaks the same language as me hahaha
Thank u so much!!!!
I don't know why his way of teaching makes me happy ...Anyways thanks for clear explanation of concepts .
you are the goat mate thank you so much your teaching is incredible
Thank you so much, sir! You clarified my confusion hell out of me!
Thanks for the amazing video ! I found hope in linear algebra again !
You are welcome!
So helpful sir. Thank you so much
Brilliant!! Absolutely Brilliant!
Thanks! explaining everything in very simple way
You're welcome!
u make maths so interesting. thanks Sir. it was so clear
Realy i like linear algebra because your explain is very very good thank y so much
your energyyyyy wake me up!!
Your way of teaching is so good👍
thank you so much, this was an eye opener.
You are so sweet...
You explained very easily, the most confusing topic for me in linear algebra.
This channel is soo underrated
Thank you!!!
Ooh I loved this algebra craziness ❤
Thank you for the video Dr. Peyam
OMG a lot of very useful things with only one example Thank you so much
Thanks so much...I am going to watch through all your videos
Thank you for this video!
Thank you very much for the video!
Thank you! Explained very well
THANK YOU SO MUCH! God bless you sir!
Wow, thanks for the video, your explanations helped me a lot.
hey sir thanks a lot you cleared any of my doubts
Thank you for this video😄This video make me pass the exam in linear algebra 😄I like it
well done and thank you. extremely clear information and process
Thank you!!!
You are a fantastic teacher :)
Amazing video. Thank you!
Ok, This was actually a Great video THANK A lot sir!!!!!
Wonderful video Professor.
super informative thank you!!
Great Examples
thank you sir...its really helpful 😊
4:17 - since those are 3 linearly independant vectors in R³, their span should be all of R³, so wouldn't the columns of the identity matrix also serve as a sufficient basis?
Or any other set of 3 independant vectors
Yes, of course!
@@drpeyam and what about the 3 L.I. vectors of the row-reduced matrix? Shouldn't they span R3 as well? I didn't understand the "span non-preservation property" between the L.I. vectors in the original matrix vs the L.I. vectors in the row-reduced matrix
you are the best ever.
You Made my day ❤
Thank you, you are excellent!
It's more than super helpful 🙂
I like how two seemingly parallel lines in this video seem to intersect somewhere off screen to the right. Do the top and bottom of the whiteboard form a basis of the column space of the whiteboard from this angle?
I have exactly one hour 2 minutes to take my linear algebra exam 😭
Thank you so much!
من طرف الدكتور عيسى قيقية , كل الدعم❤❤😘
Thank you so much sir
If you imagine 2x1 matrix, the transformation takes 2D space to 1D space, meaning there exists a line in the 2D space that goes to origin after the transformation, meaning that it's the null space of the matrix. Since column space is the output span, and null space is in a sense number of dimensions lost, the N (original number of dimensions) becomes the sum of column space and null space.
THANK YOU!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! so helpful!!!!
you are a great man
Awww we just learned rank recently, vector system's rank, rank of a linear function and ofc matrix rank. Also the Kronecker rank theorem and so on ^_^
Amazing sir..... thankyou 👍
Very helpful thanks!
You’re welcome!
thank you very much
thank you
RoWs and nOse
Columns Schmolumns 😂
00:13 I have the exam in an hour 😂😂
THank you for this vedio.... :)
Many thanks!!!
Thanks sir
Is there any video that explains these concepts and why row reduction works geometrically ?
You can check out the playlist!!
4:04 Row reduction destroys span? Why, columns 1, 3 and 5 are Linear independent and span R3 just like before row reduction
Is the span of the matrix all 5 columns?
Yeah but this example is just a coincidence
Dr. Peyam should get waves 🌊
First thanks it was very useful second I got headache for camera’s angle
lot of thanks🥰🥰
Thanku sir
How are you teaching sooo good sir
Awwwww thank you!!!
yea the video is super super good
Thanks so much!
sir , why didnt you wrote the simplified matrix in row space span ? u said it preserves the span .
very nice!
Tell you what. This video saved my test 2😂. Took something of 2 weeks into 20 minutes 😂
I was watching etc etc n etc then found it now I regret why didn't I found it earlier.
Hi Dr Peyam!
If you have time, I was wondering if you could help me prove two things regarding column spaces and null spaces.
I’m supposed to prove Nul(B) ⊂ Nul(AB).
Here’s my attempt at the proof:
Nul(B) contains all the vectors x that make the homogeneous Bx=0.
We are allowed to left-multiply both sides by the matrix A.
ABx = A0
ABx = 0
So I think we can say that if Bx=0, then ABx=0.
If x makes Bx = 0 true, then x makes ABx=0 true.
If x belongs to the null space of B, then x belongs to the null space of AB.
Thus, we have proven that Nul(B) ⊂ Nul(AB).
Is this reasoning correct or flawed?
I’m also supposed to prove Col(AB) ⊂ Col(A).
This one is trickier for me.
Col(AB) contains all the output vectors y such that (AB)x = y.
By the property of associative matrix multiplication, we are allowed to shift the parenthesis to say A(Bx) = y.
If (AB)x = y then A(Bx) = y.
So I’m seeing that if we can use AB to obtain the image vector y, then we can use A to obtain the same image vector y.
But does this demonstrate that Col(AB) is a subset of Col(A)?
I’ve been so confused by this for a long time and was wondering if you would be able to help clear up the confusion for me.
Thank you so much!
when you are finding the Col(A) can you use the RREF or do you have to use REF
REF is enough
@@drpeyam but can you do rref and the answer be the same?
Yes, since the pivots are still at the same positions
Heck, within 30 seconds I feel so called out lol
for the colspace of A. I think you needed to out "span" of such 3 vectors
I bet that when you play Super Smash Bros, you always go for linear combos.
These are the best ones :P
Hahaha, of course 😂
The negative nine and positive two... Shouldn't that be positive nine ? Kindly inquiring
I think so, see comments
Bro he is hacker 😮 🔥
valeu paee
how does -7 act as a pivot? Doesn't it need to be 1 to be a pivot?
No pivots can be not equal to 1
Row space and column space be like: I am inevitable.
Dr peyam: and I am......🤏 🤏Dr peyam.
Thanks for helping me sir.
wow this helped alot!!
“maybe you have an exam in an hour”
Me: 😳 he caught me
thanks xqcL
Thanks Dr Peyam, is there anyway you and your team will do a real analysis for those struggling in undergrad schools and introductions of proofs. Thanks as always, and it is a pleasure to watch your output.
Real Analysis ruclips.net/p/PLJb1qAQIrmmDs56gwp6yeytyy0wxWLac8