Finding Basis for Column Space, Row Space, and Null Space - Linear Algebra

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  • Опубликовано: 28 окт 2024

Комментарии • 65

  • @tony-hz4gg
    @tony-hz4gg 7 месяцев назад +21

    Bro you're a goat I never comment but u made everything so much easier to understand than the other tutors who just yap about definitions, but you explain the intuition. Love it def gonna start watching u more for linear.

    • @DrewWerbowski
      @DrewWerbowski  5 месяцев назад +2

      Thank you so much for your comment. Are there any linear algebra topics you would like to see?

    • @Ahmed-yo7gb
      @Ahmed-yo7gb 5 месяцев назад +2

      ​@@DrewWerbowski
      Determine if U is or not a subspace with justification.
      Finding eigenvectors and eigenvalues and diagonalization.
      Gram-Schmidt Orthogonalization Algorithm and computing a projection
      Finding a basis for a vector space
      Finding the matrix that describes the linear transformation (9.1).
      Least Squares Approximation
      Singular Value Decomposition
      Proof of an important Theorem

    • @DrewWerbowski
      @DrewWerbowski  5 месяцев назад +1

      @@Ahmed-yo7gb thank you for the comprehensive list! Many of those topics I already have videos on my channel, but I will add some of the others to my list

  • @hagopderghazarian326
    @hagopderghazarian326 10 месяцев назад +11

    I never comment on videos but you my friend just aced this chapter. Khan academy complicates it for no reasons. Great job

    • @DrewWerbowski
      @DrewWerbowski  10 месяцев назад +2

      Appreciate the support! Thank you!

  • @rustomcadet3533
    @rustomcadet3533 Год назад +17

    Thank you for this; you makes things much easier to understand.

  • @semkiz1133
    @semkiz1133 10 месяцев назад +1

    omg i literally have my final tmrw and u just explained the concepts i've been dreading the most in the most understandable way ever omfg ur the goat

    • @DrewWerbowski
      @DrewWerbowski  10 месяцев назад

      Thank you! Hope your final went well!

  • @pharaohscurse
    @pharaohscurse 10 месяцев назад +4

    Thank you so much. Finally understood the concept perfectly

  • @AdrenalStorm
    @AdrenalStorm Год назад +4

    OMG THANK YOU SO MUCH. You are a life saver. I was having so much trouble with a question on MyOpenMath and now I understand 😭

  • @volken54
    @volken54 Месяц назад

    Great! Thanks for this simple and intelligent explanation!

  • @FarheenQureshi-ei9jv
    @FarheenQureshi-ei9jv 5 месяцев назад

    best explanation of topic .... finally i understood the topic ... it is simple but our teacher make it very hard.

  • @TumuhairwePeace-we6zd
    @TumuhairwePeace-we6zd Год назад +2

    Thanks for good explanation,may God bless you abandantly

  • @maxpercer7119
    @maxpercer7119 6 месяцев назад

    interesting you say that applying a linear transformation is 'shifting space'. So that is one way to think about it, as a mapping between two spaces , the departure space and the arrival space, or as transformation of the departure space.
    A linear transformation is equivalent to matrix multiplication, and for the null space we are looking for solutions to A*x = 0 , where x is an n x 1 matrix of "solutions" and A is a given m x n matrix. When x varies you have a map from R^n -> R^m , defined by x -> A * x .

  • @alexanderstrauss6282
    @alexanderstrauss6282 21 день назад

    needed this, thanks for creating this. :)

  • @moshiurrahman9677
    @moshiurrahman9677 2 года назад +10

    Excellent presentation. Thanks.
    You presented it in consideration of a homogenous system. Could you please add some explanation of this topics in a non-homogenous system? You are a great teacher!

  • @nattavich2780
    @nattavich2780 2 года назад +2

    Thank you for teaching. It helps me to solve my homework. And if you don’t mind,please you will suggest the book of Linear Algebra.

  • @ColeWagner-l5j
    @ColeWagner-l5j Год назад +1

    Hey thought the video was great but I think your definition on independence may be off. A matrix is independent if the subsets don’t contain other subset variables. Your first problem you said was independent was actually dependent even though it spanned

  • @cornmasterliao7080
    @cornmasterliao7080 Год назад +2

    so for column space I should use the corresponding column vectors in the original matrix. for row space I should use the row vectors in the RREF matrix?

  • @cerberuss8133
    @cerberuss8133 8 месяцев назад

    thank you! my endterm is tomorrow, u helped a lot!

  • @promilaize
    @promilaize Год назад

    Thanks for making it understand.

  • @mirmubasher9597
    @mirmubasher9597 4 года назад +2

    will the dimensions of basis of col(A) and row(A) always be the same?
    Does dimensions of basis of null(A) hold any significance with col(A) and row(A)?
    Thank you!
    you're blessed.

    • @natedominion5432
      @natedominion5432 2 года назад +6

      Dimensions of Row(A)=Col(A) and Dimensions of Row(A) + null(A) = # of columns

  • @maxpercer7119
    @maxpercer7119 6 месяцев назад

    11:22 I think there is a mistake, it should be the span of {v1, v2, v3, v3} = span {v1, v2} , not
    span {v1, v2, v3 } = span v1, v2, since there are four vectors we started with in Col(A).

    • @syedabubaker1389
      @syedabubaker1389 5 месяцев назад

      It was an example {v1, v2, v3, v3} = span {v1, v2} stands correct due to {v1, v2, v3 } = span {v1, v2} being correct

  • @henrytzuo8517
    @henrytzuo8517 7 месяцев назад

    THANK YOU!!😀😀😀

  • @ElifArslan-l9g
    @ElifArslan-l9g 2 года назад +2

    thank you so much! btw your voice is super cool

  • @sevdedundar2334
    @sevdedundar2334 3 месяца назад

    thank you so much.....

  • @AsandeGumede-yx9vc
    @AsandeGumede-yx9vc 5 месяцев назад

    youre so good man!

  • @matthiasd2023
    @matthiasd2023 Год назад +1

    you are a legend thank you so much

  • @sohamnandi5457
    @sohamnandi5457 9 месяцев назад

    If I perform row operations on a matrix, does it affect its column space? I am asking this because I used to perform row operations on the transposed matrix so that they are basically column operations.

    • @theultimate2345
      @theultimate2345 2 месяца назад

      On a matrix after application of row operation the row space stays the same while column space changes , and for application of row operation on its transpose keeps it's column space same but changes row space

    • @sohamnandi5457
      @sohamnandi5457 2 месяца назад

      @@theultimate2345 got it, thanks a lot!!

  • @AkashSingh-vm8rd
    @AkashSingh-vm8rd 2 года назад +1

    Thank you, buddy

  • @Kage1128
    @Kage1128 Год назад

    would be cool if you shared the onenote document so that we could save it for notes :)

    • @DrewWerbowski
      @DrewWerbowski  Год назад +5

      You'll learn more efficiently if you listen, understand, then write notes in your own way :) Good luck!

  • @titaniumx5471
    @titaniumx5471 7 месяцев назад

    explained it better than my prof and my textbook combined. appreciate it man thank you

  • @abdelazizamr33
    @abdelazizamr33 Год назад

    great video you deserve more likes and subscribes

  • @sachininirmani4791
    @sachininirmani4791 Год назад

    thank you!

  • @viral724pathak
    @viral724pathak 2 года назад

    please suggest any book from where i can get all these things. thnx

  • @briannguyen5057
    @briannguyen5057 2 года назад +1

    thanks!

  • @kaustubhlande5568
    @kaustubhlande5568 Год назад

    Can I write the basis row with the original matrix like we did with the columns ? Thanks

    • @armisol00
      @armisol00 Год назад

      I have the same question and exam in 5days

    • @kushaal1607
      @kushaal1607 7 месяцев назад

      no you can't, i don't know why, but i'm sure you can't write the basis row with the original matrix like we did with the columns

    • @rubengabeaditya598
      @rubengabeaditya598 7 месяцев назад

      @@kushaal1607 how about making the matrices to the transpose form and then you take the original vector as row space after finding the rref. Is it still wrong?

    • @theultimate2345
      @theultimate2345 2 месяца назад

      ​@@kushaal1607 you can write it that way thought

    • @DirkdeZwijger
      @DirkdeZwijger 6 дней назад

      @@kushaal1607 in the video (14:39) he says that row(A) of the original matrix A is equal to the row(A) of the RREF form, so you can use both. Only for columns it doesn't work, as you might end up the standard basis vectors, which is not per definition the same as the basis of col(A) of the original matrix A

  • @davlatbekkobiljonov911
    @davlatbekkobiljonov911 Год назад

    thanks

  • @aminamehboob4068
    @aminamehboob4068 2 года назад

    Thank you so much sir

  • @samueldarenskiy6893
    @samueldarenskiy6893 Год назад +9

    Wouldn't the column space be the set of all column vectors, so literally every column is in the span. Whereby the basis is all the literally independent columns

    • @prasanjeetnayak8253
      @prasanjeetnayak8253 11 месяцев назад +1

      Yes

    • @anirbandhar1
      @anirbandhar1 9 месяцев назад +1

      Column space is the linear span of all independent columns of the matrix. So sure, it contains all the columns in the matrix, however its not limited to it.

  • @Triadii
    @Triadii Месяц назад

    but the question is asking for a column space of a polynomial. There isn't even a matrix given in the question.

  • @abdur._.sharif
    @abdur._.sharif День назад

    i luv u

  • @advikace8847
    @advikace8847 Год назад

    Video was lil bit helpful

  • @abdur._.sharif
    @abdur._.sharif День назад

    plz replace my linear teacher 🙏🙏🙏

  • @ВикторияИльина-ю4з
    @ВикторияИльина-ю4з 2 года назад

    what is your instagram..

  • @daphneeroy6623
    @daphneeroy6623 Год назад

    Can I write the basis row with the original matrix like we did with the columns ? Thanks

  • @seacheuk5665
    @seacheuk5665 2 года назад

    thanks!