Schrodingers Equation and the Infinite Potential Well

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  • Опубликовано: 8 ноя 2024

Комментарии • 69

  • @naumaniftikhar6397
    @naumaniftikhar6397 5 лет назад +132

    6:02 "If you are a math person I don't advocate you doing this because you might have an aneurysm. If you are an engineer like me you will have absolutely no trouble with this ..." lol that was hilarious

    • @friedrichbahk5675
      @friedrichbahk5675 4 года назад +5

      Mathmatic User : Minus, Why there your are?!?!?!?!
      Engineering User : Well! that's fine. Keep going, sir.

    • @PAA-ne3pc
      @PAA-ne3pc 3 года назад +9

      I wanted to add :if you're a physicist you are in a superposition between being confused and not

    • @xXEpicxManXx
      @xXEpicxManXx 3 года назад

      @@PAA-ne3pc ahh clever!

    • @LagDaemonProgramming
      @LagDaemonProgramming Год назад +2

      @@PAA-ne3pc If you are a physist your wave function shows a vary low probability of you being in the state "Nobel Laureate"

    • @PAA-ne3pc
      @PAA-ne3pc Год назад +1

      @@LagDaemonProgramming as long as it's not a zero I'm fine

  • @tumsum6945
    @tumsum6945 4 года назад +34

    These lectures are so beautifully and eloquently taught!!! Man I'm so happy I found them.

  • @vibing6378
    @vibing6378 3 года назад +10

    I normally don't comment on videos, but I have read every section in my textbook and attended every lecture, yet I get more out of this 14 minute video. Thanks for being so clear

  • @syedmuidalkais625
    @syedmuidalkais625 2 года назад +5

    Initial part of your lectures tells us the reason why we study Infinite Potential Well and I think that's the most important part may teachers skip. Thanks for this and best of luck.

  • @tonymagana6489
    @tonymagana6489 2 года назад +2

    I really appreciate this video explaining exactly what an infinite potential well is. Most college professors will just tell you there is an infinite potential well and expect you to conceptually understand what that is. Thank you!

  • @albertcamus7530
    @albertcamus7530 2 года назад +2

    Thank you! Finally an explanation of the "particle in the box" with an application.

  • @MohammadAliLatifi-y4t
    @MohammadAliLatifi-y4t Месяц назад

    wowwww! im speech less! this videos are great. in our university we have a course called electronic physic and i've always struggled to understand what our professor wants to say and these videos provides best way to understand these subjects

  • @omoshiroi2326
    @omoshiroi2326 6 месяцев назад

    This was the clearest explanation I've ever seen for the wave number! Thanks a ton for this video.

  • @ItamiPlaysGuitar
    @ItamiPlaysGuitar Год назад +1

    Four years later, still this man saves lives. What a legend

  • @treslineas2826
    @treslineas2826 5 лет назад +19

    You are very clear. I got every step of the way.

  • @aselim20.
    @aselim20. 7 месяцев назад +1

    I watched this twice and I took notes.

    • @noahvaillant8509
      @noahvaillant8509 6 месяцев назад +1

      Im on my fourth rewatch personally, no notes though.

    • @aselim20.
      @aselim20. 6 месяцев назад +1

      @@noahvaillant8509 I think after watching it, you should take notes.

  • @chipoostar8302
    @chipoostar8302 4 года назад +5

    Thank you so much !! Everything makes sense slowly and gets more clear

  • @李天翊-w5g
    @李天翊-w5g 3 года назад +1

    It's just so nice, clear, and useful, which saves me a large amount of time in comprehending, thanks soooooo much

  • @CogsofCogitation
    @CogsofCogitation 3 года назад +2

    Thanks, been searching all over for this, great explanation.

  • @nikhilpant2671
    @nikhilpant2671 4 года назад +5

    Sir, please continue this series I have to learn semiconductor physics.. My college have gross teacher, u r the only hope now and please recommend me some books too

    • @rorytobin1492
      @rorytobin1492 2 года назад +1

      Dear Nikhil, in a similar situation here my brother. Did you make it through and if so would you care to impart some advice on us

    • @greatwhite8412
      @greatwhite8412 Год назад +1

      Yes, Hey!!! Tell us how it went???

    • @greatwhite8412
      @greatwhite8412 Год назад +1

      ​@@rorytobin1492I'm curious myself 🤔🤔

  • @SomeshRajvlogs
    @SomeshRajvlogs 3 года назад +1

    Thanks Sir.
    I was Struggling with these concepts.

  • @dusanlazic7112
    @dusanlazic7112 3 года назад +1

    Thank you for your explanations. I finally understood some things.

  • @rajaumairkhan7765
    @rajaumairkhan7765 3 года назад

    I have seen this video, it's so much helpful that i pressed the Bell icon, thank you sir.. 💕

  • @ahmetfurkankula337
    @ahmetfurkankula337 3 года назад +1

    It was a very neat explanation. Thank you, Sir!

  • @biswajeetpatro9990
    @biswajeetpatro9990 5 лет назад +4

    The explanations are just Awesome

  • @gomemego3417
    @gomemego3417 4 года назад +3

    Thanks for this deep explanation

  • @ajitzote6103
    @ajitzote6103 4 года назад

    I'm in love with your teaching sir!

  • @MM-ei7xv
    @MM-ei7xv 5 лет назад +4

    honestly, you're awesome! thank you!

  • @TheGroundskeeper
    @TheGroundskeeper 2 года назад +3

    Dude, a math person might have an aneurysm for plugging infinity in but a word nerd would point out an aneurysm is only a bulge of a blood vessel; what I had is closer to a hemorrhage

  • @andonghuang1215
    @andonghuang1215 4 года назад +2

    Hi Edmunds, may I know what software are you using for the vedio?

  • @LagDaemonProgramming
    @LagDaemonProgramming Год назад +1

    When you said it takes 5ev for an electron to escape, did you mean 5Mev?

  • @ira9186
    @ira9186 5 лет назад +4

    Explained well, thank you.

  • @bogdansofalca6946
    @bogdansofalca6946 3 года назад +1

    Dear Mr. Edmunds,
    First thank you very much for all your videos.
    I have a question about A1 term calculation: solving for it at 13:30
    shouldn't it be sqrt(2/(L-sin(2kL))). Is there a reason why the sin(2kL) from the denominator reduces to 0? Thank you again.

    • @JordanEdmundsEECS
      @JordanEdmundsEECS  3 года назад +3

      Great question! Sin(kL) needs to be zero because from our underlying model we've said the electron is confined to the box. In other words, the wavefunction must be zero everywhere outside the box, and since the wavefunction has to be continuous (you can get this just from the structure of the Schrodinger equation), this means it must be zero at the boundaries (x=L and x=0 being the two boundaries).

    • @bogdansofalca6946
      @bogdansofalca6946 3 года назад

      @@JordanEdmundsEECS Very clear. many thanks again!

    • @bogdansofalca6946
      @bogdansofalca6946 3 года назад +1

      @@JordanEdmundsEECS Maybe additional question: this means wave function is equal to 0 fot all x > L or < 0? If true, I struglgle to see it from the final formula you derived at 14:00. Is there something I am missing again :).
      Thank you in advance.

    • @JordanEdmundsEECS
      @JordanEdmundsEECS  3 года назад +2

      Yup! It’s not in the formula, because the formula only applies from 0 to L. Outside that region the potential is infinite and the wavefunction must be zero.

  • @eeejay235
    @eeejay235 Год назад

    I LOVE THIS!

  • @mab7727
    @mab7727 2 года назад

    Bless you man, you are so awesome!

  • @jimitsoni18
    @jimitsoni18 4 года назад +2

    Schrödinger's equation is a wave equation but it defines the probability of existence of matter in space. Please help me connect that... How is the range of a sine wave function [0,1]...

    • @JordanEdmundsEECS
      @JordanEdmundsEECS  4 года назад

      It's the magnitude squared of the wavefunction that corresponds to probability, not just the wavefunction (and really probability *density*, or probability per unit space).

    • @feiwang9892
      @feiwang9892 4 года назад

      @@JordanEdmundsEECS So, If I want to know the reason.... must I learn quantum physics first?

  • @AliAkbar-bv7zp
    @AliAkbar-bv7zp 4 года назад +2

    I need the link of previous video

  • @fancybluepen3489
    @fancybluepen3489 2 года назад +1

    I had a question about 6:55. I'm still lost on how the second equation leads to the conclusion about the wave function not existing outside of the range of x=0 to x=L. Like I understand why that makes sense physically but I don't understand how the 2nd equation describes this.

    • @fancybluepen3489
      @fancybluepen3489 2 года назад

      Oh wait! Is it because When U(x) = infinity, then x ≠ 0 to L and when U(x) = 0, then x = 0 to L?

    • @LagDaemonProgramming
      @LagDaemonProgramming Год назад +1

      @@fancybluepen3489 It's because the electron cannot exist outside he well, so the function must be 0 outside the well. It is something just set to 0. Then, since the function must be continuous from -inf to inf, then the function must also be 0 at the lower and upper bounds.

  • @selinsamyeli797
    @selinsamyeli797 8 месяцев назад

    great great teacher!!

  • @DW-iq8lt
    @DW-iq8lt 4 года назад +4

    5:46 why is there no negative sign in front of the term?

  • @islacasey839
    @islacasey839 4 года назад +6

    "We're done".
    Me:
    Then why do you still have SIX MINUETS LEFT IN THE VIDEO HMMMMM????

  • @tanyouzi8610
    @tanyouzi8610 2 года назад

    really good.

  • @kevinsweeney2809
    @kevinsweeney2809 2 года назад

    Thank you!

  • @lafaci3788
    @lafaci3788 5 лет назад +2

    thank you

  • @barsilgen120
    @barsilgen120 2 года назад

    Thanks a lot.

  • @hyspipyle
    @hyspipyle 3 года назад +1

    Can n=0 however?

  • @NinjaLLR
    @NinjaLLR 5 лет назад +1

    So is k^2=2m(E-V)/hbar^2 or 2mE/hbar^2 ?

    • @JordanEdmundsEECS
      @JordanEdmundsEECS  5 лет назад +1

      If you have a potential, then you’ll want to include the V. Otherwise, you can just go with the E. In this case, V=0 inside the well.

    • @NinjaLLR
      @NinjaLLR 5 лет назад +1

      @@JordanEdmundsEECS ok thanks

  • @murfoll__3074
    @murfoll__3074 4 года назад +2

    I have an aneurysm now omg...

  • @user-ge8hj9br6w
    @user-ge8hj9br6w 3 года назад +1

    actually U varies between -infinity and 0, not 0 and +infinity. That should correct your maths.

    • @JordanEdmundsEECS
      @JordanEdmundsEECS  3 года назад +5

      Nope, it’s zero to infinity. If it were negative infinity the electron would want to jump down there and would release infinite energy in doing so - it wouldn’t be bound.