Cantilevered Truss Analysis | Reaction Forces & Method of Joints
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- Опубликовано: 27 сен 2024
- Use the equations for static equilibrium to solve for the reaction forces on a cantilevered truss. This involves looking at both the net torque on the truss around each of the supports as well as looking at the net force on the truss in each axis.
Then having solved for the reaction forces by the pin and roller supports, we will use the Method of Joints to solve for the force in each beam or member of the truss.
After that we will determine whether each beam is under tension, or under compression.
Trusses are a fundamental part of the study of static structures and static equilibrium. Truss Analysis comes up in most courses that deal with statics. This includes introductory physics courses such as high school physics, AP Physics 1, AP Physics C Mechanics. As well as introductory engineering courses such as PLTW Principles of Engineering (POE).
This problem also serves as the foundation for more advanced statics engineering courses that appear at a college level in fields such as civil engineering.
As someone who only got a B In 8th grade algebra like 20+ years ago this is blowing me away. I want to be able to understand this kind of stuff better so thank you for putting content like this out.
This might be some confusion over terminology but i wanted to clarify for my understanding. Which is, in method of joints we refer to if the joint is under compression or tension. However in your example you refer to the beam being in compression or tension. I think you must have meant the joint as the forces were acting opposite to what you said when you referred to the beam. Example - You said beam AC was under tension but you have the forces acting towards each other, which would be compression, leaving the corresponding joints in tension. I hope you can understand, I just want to make sure my understanding is good. Thanks v much for the example it's very useful and exactly what I was trying to solve at work.
In working through trusses there is some ambiguity surrounding convention. Do we show the forces acting BY the beams ON the joints, or do we show the forces acting ON the beams BY the joints. In the two cases the forces will be shown with equal magnitude, yet opposite direction.
I typically show forces BY beams / members ON joints, since it is the net force ON the joint that must be zero in any axis to keep things nice and static; but not everyone does things my way...
Thanks, in the UK we state whether the joint is in compression or tension. 👍
Right.I think the load in the member becomes the opposite type load at the web!!! A web in tension puts a compressive load at the web.
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Thanks! I appreciate the input.
Right.I think the load in the member becomes the opposite type load at the web!!! A web in tension puts a compressive load at the web.
Its almost like getting something for nothing when the force acting through BC is more than double the load applied ios this how scissor jacks work
Only thing worthy of my understanding rn
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What happens if B is also a hinge, not a roller
If B is a pin, the member AB can be removed; The other two beams will be unaffected.
What happens if B is fixed and is not a roller?
You can get rid of member AB... The loads in the other two members do not change , and B supports the vertical load that used to be in AB.
Can't understand!😢
The best way to figure this out is with a model.