Why is the acceleration same (negative) when a body rises and then falls under gravity freely?

This video tries to explain why the acceleration of a body is same (negative) when it is thrown upwards, rises to a height and falls back on its own.
The stress is mainly on the fact that the acceleration is due to constant force, which is simply equal to the force of gravity between them.

[@ginaassi9967]

Sir a lot of thanks to you.you just solved the complicated misunderstanding in my mind
Thanks a lot. Please keep uploading such videos so every body will benefit from your knowledge.

[@sajitchandrashakya]

Thank you, I will!!!

[@subhashmandal9455]

Very well explained......... The point which u have told "the force remain constant"" ........ Is amazing point to student

[@sajitchandrashakya]

Yes, Mr. Subhash. Stressing an important point causes great pleasure. It is a source of great adrenaline rush!!

[@bharathirajkumar205]

Thanks a lot for this video sir. This was one doubt that I was stuck with. U cleared this now. thanks a lot sir.

[@derrickngambi9973]

Thank so much sir
You've cleared everything 😍✌️

[@heneryze5805]

Thank u sir, u just refreshed my mind of thinking the wrong way for Gravity.

[@abulmoiz9830]

Well the force is constant but the thing is we are not talking about magnitude,we are talking about direction.the minus sign.

[@princesejwal8730]

Thanks sir for a great explaination i am from delhi and your lecture help me a lot.

[@shreyaskumbhar6519]

Very nic explanation we our nation need more dedicated teacher like you a grand salute to you sir keep it up

[@shreyaskumbhar6519]

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[@kaiserwani3143]

In depth and well explanation

[@jyostnamayeesatapathy3355]

Best explanation sir

[@Drolo]

Wonderful sirr

[@flora9112]

Thanks a lot sir

[@sajitchandrashakya]

Most welcome!!

[@complexcat5049]

If an apple fall from our hand in the downward direction what will be the acceleration - positive or negative

[@sajitchandrashakya]

In this case, a will be positive, because v increases. The increase is from zero to some non zero value!!

[@user-sc5wo7yy4k]

Thank you for this sir!!

[@ImranKhan-zt4qj]

Nice sir.. Grt want more videos like this

[@sajitchandrashakya]

Sure 👍

[@Johairali]

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[@sajitchandrashakya]

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[@nepalgorkha8665]

I finished my alevel still I.love your video.You are truly passionate physician .insalllah god strength you always

[@nepalgorkha8665]

@@sajitchandrashakya Always Welcome Sir,

[@utj9559]

Great work sir keep it up sir

[@MAJHAIL.STATUS]

Thank u so much
U explained very well...

[@bhumikadas6068]

Thank you sir . You have discussed very clearly

[@bernardo6329]

great video

[@maimoonaqamar6937]

You didn’t explain why it’s negative. You just said that it’s always negative g

[@divyayadav6748]

Please tell me when we take negative gravity in potential energy formula (mgh)
I am very confused🤔 sometimes we use positive on some times negative

[@sajitchandrashakya]

Mr. Dibya, g is always positive. The issue is whether a is positive or negative. If velocity increases, a is positive. If it decreases, a is negative.

[@wizard.01]

,g is always -ve in motion..hope I'm not wrong

[@sajitchandrashakya]

You are!!!! Sorry for that!!!

[@sciencespectrum3855]

Thank you sir 🙏🙏🙏🙏

[@sajitchandrashakya]

Most welcome!!!! Too indebted!!!

[@sohamsokashi7566]

Thanks sir

[@yuneshussien5426]

Thank you so much sir :))

[@sajitchandrashakya]

All the best!!

[@dhirajjambukar9719]

Thanks 👍

[@harshitabhardwaj9844]

Thank you so much 👏👏

[@KusumLata-ob3rk]

Thank you so much sir 🙏

[@sajitchandrashakya]

Most welcome!!

[@murtymn1921]

Om Sairam swamy. God bless you. Sukhibhava

[@sajitchandrashakya]

Thanks for the blessings!! My prayers for you!!!

[@neonninja4634]

You are an Angel

[@manojthakurgour]

Sir but the direction of ball has been changed ,as applying vacter law, direction change means sign is also changed

[@sajitchandrashakya]

"Direction of ball" means you are concerned with the direction of velocity. But the question is about direction of acceleration, which is always downward (towards earth's centre), and is the direct result of the gravitational force, which is always downward.

[@shamamanizamani]

Sir thankss alot you cleared the mystery. sir but tell what if projectile drops from a height what will be its a? positive or negative?

[@sajitchandrashakya]

The answer is straight forward. If it drops from a height after initially firing horizontally, the vertical velocity increases, so, a = g; i.e. positive. As has been stated in the explanation, if v increases, a is positive; and if decreases, a is negative.

[@shamamanizamani]

@@sajitchandrashakya Okay sir thanks alot.

[@GyanamTuition]

So when g will be positive?

[@revanthalexkumar7597]

Example like skydiving

[@revanthalexkumar7597]

Example like skydiving

[@sohamsokashi7566]

Sir what will be the sign of 'g' when a bullet is fired from a mountain?? It goes in downward direction in projectile motion, so i think it should be positive. M i right??

[@sohamsokashi7566]

I saw in one answer that they took g as negative, and put -g in formula of s=ut -1/2 gt^2..... but i think that it should be s=ut + 1/2 gt^2..plz reply

[@sohamsokashi7566]

@@sajitchandrashakya thanks sir, but plz tell, if i shot a bullet horizontally from a mountain, i goes down from mountain in projectile motion. so, if i want to find displacement, should i put g as negative or positive in equation i.e s=ut+1/2(-gt^2) or s=ut+1/2gt^2

[@sohamsokashi7566]

i have doubt in 1 que. i.e, 2 guns situated on the top of a high hill fire a shot each at some interval of time with the same speed 5 root3 m/s. One gun fires horizontally and other fires upwards at an angle of 60 degree with the horizontal. The shots collide in air at point P. Find i) the time interval between the firing ii) the coordinates of P, taking top of the hill as the origin.
sir plz tell me how to take g in this question

[@classytechboy3583]

Sir, If a projectile is thrown from a height(horizontal motion projectile) what will be its g.

[@sajitchandrashakya]

g is always positive because g = GM/R^2. In no way that g can be negative. The issue is whether a is positive or not. If v increases, a = g and so positive. If v decreases, a = - g and so negative.

[@faheemullahkhattak5202]

@@sajitchandrashakya in projectile motion when the projectile is moving upward v decrease so a will be negative. But when the projectile start downward motion v increase so a must be positive. But this concept is against to your video concept. Need some explanation

[@sapnasharma2823]

Sir if in case of projectile motion a body is thrown from some height and that body takes projectile path
What is the value of g

[@sapnasharma2823]

@@sajitchandrashakya thanks for clarifying my concept

[@Saicharan-dt7fw]

same doubt on this concept to me
object thrown from some height and that takes projectile motion the what is the value of g upwards and downwards? please clarify @ sapna sharma

[@goodguy8622]

But initially why did we take a=(-g)

[@sajitchandrashakya]

When velocity decreases, a is negative. This happens right from initial moments, so a = -g.

[@Johairali]

if i would be your student,then i think i would be best physicst.

[@sajitchandrashakya]

Haha!! I still expect you to be, even if you are not my student!!!

[@yipyiphooray339]

Tyyyyy sirrrrr

[@naveedsyed2917]

Terrible explanation didn’t even explain why just told ki ye line rata Marlo

[@lewismwanza3120]

Thank you sir....