Solving Exponential Inequalities (TAGALOG) | GENERAL MATHEMATICS

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  • Опубликовано: 22 окт 2024

Комментарии • 19

  • @shukurenai3545
    @shukurenai3545 Год назад +1

    Salamat Lodi!! Maraming kang matutulungan hanggang future

  • @keanvincentquisado1124
    @keanvincentquisado1124 Год назад +2

    Sir pano po nakuha yung -2x -26 sa both side?

  • @mauriceelola7332
    @mauriceelola7332 2 года назад +1

    hi po pano po kung 1 ang common base?irretain po ba or ireverse ang inequality?

  • @alemanburp8615
    @alemanburp8615 3 года назад +1

    hello, can i ask po what if ung isang side lang ang fraction and it is also less than 1 but more than 0. for example: 3^x-4 < 1/27, will it be reversed po?

    • @TEACHMATHPH
      @TEACHMATHPH  3 года назад

      Hello Aleman :) Actually yung decision about reverse or retain the indicated inequality symbol ay naka depende lang sa base :) So if th eproblem is 3^x-4 < 1/27 , most probably ang base ay 3 so magiging x-4 < -3 ang set of exponents :) te answer is x

    • @stepbystep4267
      @stepbystep4267 3 года назад

      paano po yan, any fraction pwede nadin gawing whole number. example po ung 1/10 pwede sya irewrite as 10^-1 and ung 1/100 ay pwede irewrite as 10^-2. ano po and gagawin.. ireretain po ba talaga ang direction ng inequality symbol or hindi?
      PS. just asking for clarification, medyo nalilito din po kasi ako hahaha..

  • @nctenthusiast2697
    @nctenthusiast2697 3 года назад +1

    sir what if po fraction siya both side pero seems like hindi po siya pwede I raise sa iba pang power
    example po (1/27)^2x+1 < (1/243)^3x-2
    what will be the process?

    • @TEACHMATHPH
      @TEACHMATHPH  3 года назад +2

      Hello NTC :) If that is the case , need na imodify or itransform ang dalawang Base mo (1/27) and (1/243) then iaaapply lang ang power rule for exponents , so magiging 1/3^3 ang 1/27 ----- then 1/3^5 naman ang 1/243 ---- bale ang new base mo ay 1/3 so need ireverse ang inequality symbol :) Then simplify lang
      (1/27)^2x+1 < (1/243)^3x-2
      (1/3^3)^2x+1 < (1/3^5)^3x-2
      (1/3)^3(2x+1) < (1/3)^5(3x-2) (power rule of exponents)
      3(2x+1) > 5(3x-2) reverse the inequality symbol (bec base is less than 1)
      6x+3 > 15x-10 Distributive Property, Then APE lang or Solve for the value of x
      3 + 10 > 15x - 6x
      13 > 9x Divide both side by 9
      13/9 > x or x

  • @trishmarcellana4582
    @trishmarcellana4582 2 года назад +1

    Thank you sir!

  • @eughoo4705
    @eughoo4705 3 года назад +2

    hi! your videos helped me a lot with our current lessons and i'm very thankful for that. this means a lot to us students^^ have a good day and stay safe po!
    p.s. i hope you also make a video about answering word problems involving exponential expressions or conic sections, of course, only if you want to hehe

  • @melrynkhatesasana4972
    @melrynkhatesasana4972 2 года назад +1

    thank you po!

  • @shahedshahrear3918
    @shahedshahrear3918 Год назад +1

    < 4

  • @johneduarddextremercader3882
    @johneduarddextremercader3882 3 года назад +1

    paano po ba ung solution set?

  • @shahedshahrear3918
    @shahedshahrear3918 Год назад +1

    x < 4
    ( - infinity, 4)

  • @autumnhiraya1725
    @autumnhiraya1725 4 года назад +1

    tysm ❤️

  • @shahedshahrear3918
    @shahedshahrear3918 Год назад +1

    x>2

  • @shahedshahrear3918
    @shahedshahrear3918 Год назад +1

    > or = 4

  • @samtalosig-j1z
    @samtalosig-j1z 8 дней назад

    pogi ng boses mo kuya hahaha

  • @shahedshahrear3918
    @shahedshahrear3918 Год назад +1

    that tryna only grows harder over