Zeolite Numericals ll With Short Trick ll Numericals on Zeolite Process ll Engineering Chemistry
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- Опубликовано: 1 окт 2024
- Zeolite Numericals ll With Short Trick ll Numericals on Zeolite Process ll Engineering Chemistry
Hello viewers,
Welcome to my channel EASY ENGINEERING CHEMISTRY. This channel aims to make chemistry easy for Engineering students.
ABOUT THIS VIDEO
In this video I am going discuss Numericals based on Zeolite or Permutit process of water softening . Zeolite/Permutit method is an External method of water treatment. In exams Numericals based on Water softening methods are frequently asked and numericals are always marks scoring if you do correctly. In this this video zeolite process based numericals are explained in three very easy steps with short trick to solve this type of numericals.
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In Short trick we take weight of NaCl in mg for one litre. So you write unit of W mg/l instead of mg.
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Mam i watch your all playlist of water softening method . And i understand word to word 😮 mam u r fabulous ❤ .. plzz make new videos 😊
Thank you for appreciation. Keep watching and sharing😊
512.8ppm. 600ppm
GOOD JOB. Keep watching and do subscribe to my channel.
Thank you ma'am! Your explanation was very good!!
Thanks for appreciation. Keep watching.
Ma'am Nacl kaa too molecular factor hii nhi hota naa
NaCl Hardness me contribute nahi karta hai lekin multiplication factor kisi bhi salt ka nikal sakte hai . Hope you got it. If not feel free to ask.
Keep watching and sharing😊
Thanku mam. Very helpful mam🙂
Keep watching and sharing😊
Such a Nice explanation tomorrow is my exam and at midnight this is the biggest stress relifer
Thank you for appreciation. Keep watching and sharing😊
Tomorrow is my engineering chemistry semester exam. I had a lot of doubts before RUclips suggested me this video. Thanks for the perfect explanation. Keep it up, until you make yourself loss by you.❤
Keep watching and sharing😊
Please complete the syllabus of engineering chemistry in diploma
I will try till than Keep watching and sharing😊
Thank you Mam. You explained very nicely and make it easy to understand.
Thanks for appreciation. Keep watching.
512.82051ppm , 600ppm
👍Keep watching and sharing😊
Ma'am plz solve this question
Which one ?
@@easyengineeringchemistry3057 ma'am is video me jo question aapne diya tha last two questions
Ma'am agar me 200*3*100*1000/117*100*10000=5.128 mg/l
200*3*100/117*100=5218.20513
5128.20513*1000/10000=512.82 mg/l
@@shivangiagrahari181 3% means 30 g/l so
{30*1000*200*(100/117)}/10000.
your answer is correct.
Keep watching.
Second question ka answer 512.82mg/L
Third question ka 3mg/L
Kya shi answer aaya h madam ?
Please reply
Third question ka answer 600ppm
512.82 mg/l and 600 mg/l sahi answer hai.
Good going. Keep watching and subscribe my channel.
@@easyengineeringchemistry3057 mera bhi aa gya ma'am 😄
@@ApurvPriyanshLuka Very nice Apurv.
512 ppm
👍Keep watching and sharing😊
Ma'am do we have to make CaCO3 equivalent in every numericals like this
Yes ,because we have to report hardness in CaCO3 eq.. To clear your concept watch video hardness and its units.
Keep watching and sharing😊
Thank you ma'am, you saved me from a back.
Keep watching and sharing☺
Q1) H = 512.82 mg/l
Q2) H = 600 mg/l
👍Keep watching and sharing😊
Ma'am can we do it through normality equation
yes. First we have to calculate normality of NaCl solution from given strength then we can apply N1V1=N2V2 for water and NaCl to get normality of water and finally calculate strength of CaCO3 in water then convert it in mg/l.
Hope you got it. Keep watching and sharing😊
Equivalent weight of calcium carbonate is 50 and mol wt is 100 so it means mam is making mistake at 9:01 in video multiplicating factor should be 100/58.5 because we are taking molecular wt of both compounds
No, there is no mistake actually it is misconception that multiplication factor is = Molar mass of CaCO3/ Molar mass of salt but
multiplication factor = 100/ 2x chemical equivalent of salt/substance. Here salt is NaCl and its equivalent weight is 58.5 (Molecular and equivalent weight are same for NaCl) So
M.F. = 100/2x 58.5 = 100/117.
To clear you concept of multiplication factor watch video "Hardness and its units".
ruclips.net/video/ggx6iVhNsLU/видео.html
Hope your doubt will be cleared if not feel free to ask.
Keep watching and sharing😊
Thankyou mam ☺️
Keep watching and sharing😊
Mazaa aa gayaa ma'am ji🙏
Thank you for appreciation. Please like and share videos. Keep watching,
512.8,600ppm
👍Keep watching☺
badiya mam aachi lagi video
Thank you Bhavy. Please share videos and subscribe my channel.
Well explained madam!!!
Thank you. Keep watching and sharing 😊
Q2 600*10-3 mg/l
Ans is 600 mg/l .Check calculation once again. Keep watching☺
excellent explination, god level explanitation
Thanks for appreciation. Keep watching.
Molecular wt of nacl is 58.5 why there put 117
Molecular weight and equivalent weight of nacl both are 58.5 and 100/117 is the multiplication factor of nacl to convert nacl into CaCO3 equivalent.
Formula for Multiplication factor is
=100 /( 2x chemical equivalent )
so for nacl 100/(2x58.5)
=100 /117.
You can also use 50/58.5 instead of 100/117.
For concept of multiplication factor watch video Hardness and its units on channel.
keep watching.
🥺 Jab 💗 short 😎 method 🥺 se 💗 batana 😎 tha 🥺 to 💗 pehele 😎 hi 🥺 bata 💗 dete 😎 mam 🥺 time 💗 waste 😎 kar 🥺 diya 🥺
Thank 💗 you 💗😎
Agar full marks ka question aata hai aur short trick se karoge to may be marks bhi short ho jaye aur waise bhi concept to sikhana hi chahiye. Anyway keep watching and sharing🙂
Lekin second method se answer galat aata hai... Agar Nacl ka wt. mg mein lena hai aur concentration w/v mein diya hai toh formula ke wajah se volume of Nacl do baar aa jaayega... Plz explain it
Ma'am, hardness wrong h aapne jo question solve Kiya h uska, it should be 256.41 ppm
No, It should be 2564.10 ppm. Try to solve again.
Is still there any confusion regarding answer.
@@easyengineeringchemistry3057 no ma'am, all clear... There was a calculation error from my side...
@@ApurvPriyanshLuka KEEP WATCHING🙏
@@easyengineeringchemistry3057 ma'am, pls complete the playlist of the chapter fuels and combustion 🙏
Mam I had doubt in one question can you plz solve my question on zeolite?
Please ask your question. I will try my best.
Thank you mam your explanation is nice
Thank you for appreciation. Keep watching and sharing☺
Mam kya aap pura engineering chemistry of aktu University ko padhaiye gi
I'm in 1st semester
I will try. Please drop me your syllabus on easyengineeringchemistry@gmail.com
Keep watching.
@@easyengineeringchemistry3057 mam i have sent syllabus on your mail id please provide the videos as soon as possible mam
I will try my best.
@@easyengineeringchemistry3057 ok mam
Q2) 512.8205 ×10³ mg/g
Q3) 600×10-³ mg/l
is it correct.
Correct answers are 512.8 mg/l or ppm and 600 mg/l.
Keep watching,
@@easyengineeringchemistry3057
Yes mam.
@@anuplande2121 Keep learning.
Yes
Mam in most of the books ans is 569.8 mg because they use 90% zeolite
Mam which one is correct?@@easyengineeringchemistry3057
Mam plz is question ka solution dijiya na plz
Which one??
@@easyengineeringchemistry3057 mam edta method ka ans kaise likhe paper me exam he mam 26 ko plzzz
@Dhruv Gujar Please check videos based on EDTA method. Answer hamesha point wise likhe jis se content valuer ko clearly visible ho.
Channel ke community tab par EDTA method short hai aap use bhi dekh sakte hai.
Phir bhi kahi koi doubt ho to aap msg kar de.
Keep watching and please like ,share my videos.
Aapko kis numerical ka solution chahiye?
@@easyengineeringchemistry3057 nhi mam muje bs edta ka ans chahiye tha thanks mam ❤️🙏🙏
Ma'am demineralization method bhi cover kariye na
Please check links below. Keep watching.
Ion exchange process or demineralization of water
ruclips.net/video/3KNPHkfb2Qk/видео.html
Mixed Bed Ion Exchange ll Mixed Bed Deionization ll Mixed Bed Demineralization ll Water softening
ruclips.net/video/Huo15psNdxw/видео.html