Hi! I love your videos and they have taught me soooo much, thank you☺️ I have one question: if midpoint is just half the distance, then why is it (x1+x2)/2 when distance is x1-x2 in the other formula? Or have I misunderstood something😅
Midpoint is the MIDDLE value, so we can use the average. That's why for midpoint we say (x1+x2)/2. An average is the sum of the values, divided by the number of terms. **However, the distance formula needs to know the DIFFERENCE between two values, so that's why we have the subtraction there. Hope that helps, and keep on working hard! Cheers, Mitch
![Radians and the unit circle [IB Maths AA SL/HL]](http://i.ytimg.com/vi/d4XlggA3f9g/mqdefault.jpg)
![Radians and the unit circle [IB Maths AA SL/HL]](/img/tr.png)
![Distance and midpoint in 3D [IB Maths AI SL/HL]](http://i.ytimg.com/vi/e6WCqar3jHM/mqdefault.jpg)
![Exponent Laws & Solving Equations [IB Math AA SL/HL]](http://i.ytimg.com/vi/lelY241PySM/mqdefault.jpg)
You're a lifesaver man, thank you!!!!
You are most welcome! :)
Hi! I love your videos and they have taught me soooo much, thank you☺️ I have one question: if midpoint is just half the distance, then why is it (x1+x2)/2 when distance is x1-x2 in the other formula? Or have I misunderstood something😅
Midpoint is the MIDDLE value, so we can use the average. That's why for midpoint we say (x1+x2)/2. An average is the sum of the values, divided by the number of terms. **However, the distance formula needs to know the DIFFERENCE between two values, so that's why we have the subtraction there. Hope that helps, and keep on working hard! Cheers, Mitch
Will you upload HL videos? These ones are so good!
I'm so glad you like the videos! I will upload HL videos eventually, but they take time to develop :)
7:26 same
haha