Ive taken calc 1,2,3, linear algebra, intro to differential equations, and am now in complex vector analysis and somehow avoided learning about hyperbolic functions. This was great explanation and just what I needed for this class. Thank you :)
Bruh I'm a fucking engineering 1st year student and this is the first time I'm hearing about hyperbolic functions. I dont recommended walking on any bridges i make in the future
Professor Dave, you continue to deliver on the kicks in the discovery. Learning that Hyperbolic geometry is literally geometry with Hyperbolas has warmed my soul
It was the best . I liked your video very much. I was so confused about these h functions but your amazing video helped me a lot. Thank you very much sir.
Great video Dave. Enjoy all your uploaded material. You truly have mastered the art of distilling a topic to it bare essence. Your fan following is very lucky to have you. Just missed one small point though in this particular video. You forgot to explicitly describe the relationship between these trigonometric hyperbolic functions to an actual graphical hyperbola. That I think would have made the video just a tiny bit more complete.
I Had a calculus class this morning about this exact hyperbolic functions, and it took 90minuts, and professor dave finished it in 7 minutes. Thank you professor dave
The graph of the system y = (1/2)e^x y = -(1/2)e^x is clearly not a hyperbola. On a hyperbola with no vertical asymptotes, the limit of dy/dx as x approaches plus or minus infinity should be finite (it should approach a line). For y = (1/2)e^x , dy/dx = (1/2)e^x which increases without bound as x approaches infinity (the graph does not approach a line).
Agreed! i'm not taking anything away from Professor Daye, but the grapth of Ae^x is the graph of the exponential function, not the graph of the hyperbola. The easy equation of a hyperbola is y=1/x. the area under that curve is ln. the inverse function of ln is e. so there's ur connection b/n e and hyperbolas. A rotated hyperbola has the equation y^2-y^2=R^2
The hyperbolic functions do come from a hyperbola, Dave's explanation is not how it works. Sal Khan has the right idea. "Hyperbolic functions and the unit hyperbola | Hyperbolic functions | Precalculus | Khan Academy." Dave is generally very good, but he's wrong about this.
Because when multiplying 2 exponent functions, you can add the exponents to each other. So e^y . e^-y = e^y-y = e^0 = 1. I hope you understand it. If not, feel free to ask questions.
I'm disappointed in this vid. Professor Dave is my favorite for math videos to assign to my students, because the vids are professionally made, clear, understandable, and have good graphics. Some math vids are just unwatchably bad. I need a good vid on hyperbolic functions, but this one has a glaring error. Dave says that 1/2 e^x and -1/2 e^(-x) form a hyperbola. They do not. Hyperbolas have linear asymptotes. Exponentials do not. The hyperbolic functions do come from a hyperbola, but that's not how it works. Sal Khan has the right idea. "Hyperbolic functions and the unit hyperbola | Hyperbolic functions | Precalculus | Khan Academy" I want a vid with the production values of Professor Dave Explains, but with a correct explanation of how the hyperbolic functions relate to the unit hyperbola, and there isn't one. I'm bummed.
He's not saying that it makes a hyperbola. It makes a function called a hyperbolic sine. It is related to hyperbolas in a similar way that sine and cosine are related to the circle, but it isn't a hyperbola itself. It also has a lot of properties in common with sine and cosine, but it isn't either of those functions either.
@@carultch I know what the hyperbolic sine function is. That is not the point. Listen to the vid from 1:20 to 1:35, where he says: "Now what does this mean graphically? Well, let’s take this expression and break it up into two terms: one-half e to the x, minus one-half e to the negative x. If we sketch these two curves, we get a hyperbola." That is incorrect. Sketching those two curves does not create a hyperbola.
Curse you Texas Instruments users. Casio is standard for us Aussies :) I just bought an FX-82AU plus II for $12 (Co-op Bookshop on campus had a 70% off clearout on everything), but I kinda have strong feelings for my decade old FX-100AU. Can't have enough calculators.
nope. the signs are different. that change in sign made all that huge difference. example: d[tanh^-1 x] = 1/(1-x2) d[tan^-1 x] = 1/(1+x2) and no you cant multiply the other by negative to get the other. they are completely different.
Ive taken calc 1,2,3, linear algebra, intro to differential equations, and am now in complex vector analysis and somehow avoided learning about hyperbolic functions. This was great explanation and just what I needed for this class. Thank you :)
Same....
bruh im taking hyperbolic functions in calc 2
Bruh I'm a fucking engineering 1st year student and this is the first time I'm hearing about hyperbolic functions. I dont recommended walking on any bridges i make in the future
@@mayankjain04 lmao same
I'm a second-year math major and I'm just learning about them now on my own. Why do they skip these?
Professor Dave, you continue to deliver on the kicks in the discovery.
Learning that Hyperbolic geometry is literally geometry with Hyperbolas has warmed my soul
Thank you, Jesus.
Fu ck you don't mocking
@@hunterz3163 aww is hunter mad abt some dead dude
@@hunterz3163 cope
@@sfl928 bruh you get 0 women
@@carmen_13 bro has 💅 in his bio 💀
It was the best . I liked your video very much. I was so confused about these h functions but your amazing video helped me a lot. Thank you very much sir.
I never learned hyperbolic functions in Calc 2, this is a great help in calc 3
Great video Dave. Enjoy all your uploaded material. You truly have mastered the art of distilling a topic to it bare essence. Your fan following is very lucky to have you. Just missed one small point though in this particular video. You forgot to explicitly describe the relationship between these trigonometric hyperbolic functions to an actual graphical hyperbola. That I think would have made the video just a tiny bit more complete.
what is that relationship?
Caranya.seorang.seni.bangunan.
I Had a calculus class this morning about this exact hyperbolic functions, and it took 90minuts, and professor dave finished it in 7 minutes.
Thank you professor dave
Might have mentioned that y=cosh x makes a catenary.
I am from india but
I understand thes explain easily
So I want to tell you
Thank you very much
Brilliant. Truly short and poignant, thank you for making this and uploading it.
I have been roaming for so long
But finally i have found him 🙏
His name is Professor Dave
Sameee😭🤭
Wish you were my face to face teacher!!
Wish you were my face
@@nyksiex 🤣🤣🤣
The video I was searching for..,is Finally found👍. Very well explained
Thankyou sir , your lecture helped me from a horrible maths class .
Very good and conceptually clear explanations.
thanks professor jesus, helps a lot
Just amazing, way better than our teacher in Universities.
Awesome and lucid explanation
Thank you father
Umm... Thank you. Will help me alot for my exam.
If I pass Calc it’ll be because of you 💕
The graph of the system
y = (1/2)e^x
y = -(1/2)e^x
is clearly not a hyperbola. On a hyperbola with no vertical asymptotes, the limit of dy/dx as x approaches plus or minus infinity should be finite (it should approach a line). For y = (1/2)e^x , dy/dx = (1/2)e^x which increases without bound as x approaches infinity (the graph does not approach a line).
Agreed! i'm not taking anything away from Professor Daye, but the grapth of Ae^x is the graph of the exponential function, not the graph of the hyperbola. The easy equation of a hyperbola is y=1/x. the area under that curve is ln. the inverse function of ln is e. so there's ur connection b/n e and hyperbolas. A rotated hyperbola has the equation y^2-y^2=R^2
@@MrWill2714 But those are really hyperbola.
The hyperbolic functions do come from a hyperbola, Dave's explanation is not how it works. Sal Khan has the right idea. "Hyperbolic functions and the unit hyperbola | Hyperbolic functions | Precalculus | Khan Academy."
Dave is generally very good, but he's wrong about this.
blessings to professor dave
Thank you, sir
Thanks prof Dave
What has my life come to
No*x^3
Yes*x^2
No*x
Yes
@@chemicallystimulated476 No*x^-1
Very comprehensive thank you sir.
well explained sir dave.
Thanx for explaining
My perfect tutor you and chatGPT. I hate my actual tutor never explained well
You're so good at teaching, sir!
Happy teacher's day sir ❤🎉
That's exactly what I needed. Thanks.
Thanks
Amazing explanation sir! Keep doing.. great work!
THANK YOU SIR
GOD BLESS YOU
Simple and to the point thanks a lot
Thankyou😊
It's amazing how similar they are to normal trignometric functions!
Thanks, Dave! God bless you, brother!
Taking this in high school
Super.... It was very easy for understand
Really helped thank you
Happy Birthday Danae Bertoli from Arkadiko Dramas in Greece. #happy18#zoom#Panagiotis#Efthimis#corona
Happy birthday darling, we still love you, even if you didn't come to the first computer class
Thank you so much, this was very helpful!!
Very good
Amazing video and epic intro !!!
Hi buddy
Am happy fr this
thank you so much
Sir..you are simply superb!!!
تشکر از شما استاد بزرگ👍
Thank you so much. Helping me a lot!
So nice sir
Please explain Taylor's theorem for differentiability of function..
Thank u sir
Superb sir
I love this man
Thanks a lot for the amazing explanation sir
That was helpful
You're the man
Thanks sir.u are best
Hi dave
i loved the intro
Wait..I don't get it!
Why (e pwer y) Times (e bower -y) is equal to 1???
I need to understand.
Because when multiplying 2 exponent functions, you can add the exponents to each other. So e^y . e^-y = e^y-y = e^0 = 1. I hope you understand it. If not, feel free to ask questions.
Thank you math jesus
Sir pls explain about Spintronics .....
Thanks for the translation, it was amazing information❤
Tq so much but one suggestion that subtitles in this vedio disturb to see the equations
Turn off caption in your settings
well done good explanation , thank you
Genius
!
Anyone noticed that cut at 3:20?
يخي انقذتنا،،شكرا
thank you, calculus jesus
Omg you are a life saver 😱
Sir plz solve this problem,
Cosh1/2x=√1/2(1+coshx)
Amazing
legend
Nice
Due to the subtitles can't able to see the lower portion plz do something to solve its an earnest request🙏
just turn off subtitles for those sections
What math class do you learn this in?
I'm disappointed in this vid. Professor Dave is my favorite for math videos to assign to my students, because the vids are professionally made, clear, understandable, and have good graphics. Some math vids are just unwatchably bad.
I need a good vid on hyperbolic functions, but this one has a glaring error. Dave says that 1/2 e^x and -1/2 e^(-x) form a hyperbola. They do not. Hyperbolas have linear asymptotes. Exponentials do not.
The hyperbolic functions do come from a hyperbola, but that's not how it works. Sal Khan has the right idea. "Hyperbolic functions and the unit hyperbola | Hyperbolic functions | Precalculus | Khan Academy"
I want a vid with the production values of Professor Dave Explains, but with a correct explanation of how the hyperbolic functions relate to the unit hyperbola, and there isn't one. I'm bummed.
Then make it lazy teacher
@@ConceptualCalculus You might not struggle so much with your job if you could depend on your teaching instead of other people's videos
Weird flex but ok
He's not saying that it makes a hyperbola. It makes a function called a hyperbolic sine. It is related to hyperbolas in a similar way that sine and cosine are related to the circle, but it isn't a hyperbola itself. It also has a lot of properties in common with sine and cosine, but it isn't either of those functions either.
@@carultch I know what the hyperbolic sine function is. That is not the point. Listen to the vid from 1:20 to 1:35, where he says:
"Now what does this mean graphically? Well, let’s take this expression and break it up into two terms: one-half e to the x, minus one-half e to the negative x. If we sketch these two curves, we get a hyperbola."
That is incorrect. Sketching those two curves does not create a hyperbola.
"I don't always drink hyperbolic functions. But when I do, I prefer Dos Hyperbolas - The most interesting function in the world."
Nice TY
Curse you Texas Instruments users. Casio is standard for us Aussies :)
I just bought an FX-82AU plus II for $12 (Co-op Bookshop on campus had a 70% off clearout on everything), but I kinda have strong feelings for my decade old FX-100AU. Can't have enough calculators.
I'm pretty sure 90% of the people on the planet use casio calculators
Jesus. You are genius! 🤯🙏
Which country you have live
You didn't give the derivative of inverse of cosech , sech and coth
I watched the intro 10+ times
Hello , What is the range of sin h when y=0
the range of function has nothing to do with the coordinates, the range still same which is all real numbers
is their anti derivative the same as the ones with trigonometric functions too?
nope. the signs are different. that change in sign made all that huge difference.
example:
d[tanh^-1 x] = 1/(1-x2)
d[tan^-1 x] = 1/(1+x2)
and no you cant multiply the other by negative to get the other. they are completely different.
thanks sir .But electricity vedios may i get ur playlist ?
all my playlists are on my home page, try classical physics.
Jesus himself is on our rescue.
Also, we now officially call sech "SHREK".
Great Sirrrr... You are superstar... I understood the whole... B)
Which app you use to edit
Adobe after effects
❤❤❤️ from 🇱🇰
This is like the homily of engineering my dudes
I NEED PROBLEMS OF INTER 1ST YEAR PLZZZZ
Sir rice attracting chemicals nema
Thx jesus
thankyou Jesus