To be really very honest, The initial music is very harsh Sir, basically before watching the lecture I personally get annoyed please change this it should be positive and pleasant to the ears, otherwise your videos are very informative and I always visit to your channel for conceptual clarity. Hope it is conveyed to you in the positive way.
In Q3 where we know area =1/2(ab)(sin ¤) Thus area =3_/3 So cant we put in our old formula 1/2(base*height) =area Thus , 3_/3 = 1/2 * ( 4+3 ) * height Thus final height is (6_/3)/7 *** i got that 7 by doing 4+3 becoz of the concept of angle bisector So why cant this be the answer 🤔
Trigonometry is not there in the vedios or even in play list also and some of the vedios are missing can you please tell me where can i get those vedios
I don't think sir has taken trigonometry..I saw the videos on unacademy as wel..he has started from here only..probably he was mentioning the introduction vedio. But go through MAss Point Geometry..Very Helpful.
If i am getting in to the B school i desire to get i will definitely thank you sir because that's what all i can do if i can do anything better i will definitely do so sir
Sir, what if I apply the heron's formula as you did in order to compute the area and then use the formula A=r*s in order to find the radius? Is that the right procedure coz the answers are different. I am telling you about the last sum in the video.
No i think u cant because thats inradius from incentre point here its radius from centre of semicircle and u can also verify by solving u will get wrong radius i.e 3
No i think u cant because thats inradius from incentre point here its radius from centre of semicircle and u can also verify by solving u will get wrong radius i.e 3
i tried solving the /_a=60 and AD =? sum in a different approach , according to the diagram sin 30=BD/4; so BD= sin30*4= 2; now tan 30= BD/AD; so AD= BD/Tan 30 ; AD= 2/root(3) but the answers are not tallying y? where did i do wrong?
trigonometric ratios are applicable only for right angle triangle now check in ur approach whether it is right angle triangle...actaually i too made the same mistake.then realised later.
thanks man i also got stuck at the same part. and was looking in comment section if anyone had given solution to it,thanks again @@devarapallivamsi7064
To be really very honest, The initial music is very harsh Sir, basically before watching the lecture I personally get annoyed please change this it should be positive and pleasant to the ears, otherwise your videos are very informative and I always visit to your channel for conceptual clarity. Hope it is conveyed to you in the positive way.
Skip the music part 🙂
External bisector theorem was interesting in particular!
Sir can you please give me the link for the TRIGONOMETRY LECTURES you are talking about.. I can't find the playlist. Kindly reply.. thank you
did u find it?
Did you ? 😅
@@namansharma2721did you?
Did you?
@@chiragsharma5267 are you preparing for cat?
Better content than CL.
⭐️⭐️⭐️⭐️⭐️⭐️⭐️
5:50 Questions from previous lectures
Last wala question A=r*s
Ye formula se kare to answer 66/22=3. Aa raha hai.......sir ky ye sahi hoga
r*s, where r is the inradius not the radius
I can't believe my eyes.. your content is such high-quality.
Thank You Sir. The way you explain the concept's is Awesome. Thank you once again:)
Thanks
@@Rodha sir perpendicular ko height kyu liye
Smjh gya sir ji😂
@@syedahmad4466 tera to pakka clear nai hua hoga
In Q3 where we know area =1/2(ab)(sin ¤)
Thus area =3_/3
So cant we put in our old formula
1/2(base*height) =area
Thus , 3_/3 = 1/2 * ( 4+3 ) * height
Thus final height is (6_/3)/7
*** i got that 7 by doing 4+3 becoz of the concept of angle bisector
So why cant this be the answer 🤔
you can,t take AD as perpendicular height
we cannot assume AD, as the height as AD has not been mentioned
Are these videos sufficient or you have to do 8-10 ncert maths if ur basics are weak
Did you give CAT?
Trigonometry is not there in the vedios or even in play list also and some of the vedios are missing can you please tell me where can i get those vedios
I don't think sir has taken trigonometry..I saw the videos on unacademy as wel..he has started from here only..probably he was mentioning the introduction vedio. But go through MAss Point Geometry..Very Helpful.
Thank You Sir
15.3 pe mistake hai
In circumsribing sum 11:13 what happened to 4 after cutting BC???
4*3/2= 6
great for revision of all concepts thank you Ravi sir
Thank you sir ji great explanation ❤
SIr in the AD wala question,Why cant we use trigno to find it??
The explanation and the concept based question of yours are magnificent ..!!!
Sir at 21:32, yes the radius can be the same, but how d will be the center ? It is not necessary that BD=DC right ?
D is the centre of semicircle
D is not centre of BC, it is centre of the diameter of semicircle
in the last question can't we use the formula Area is equal to r.s????
no Sangeeta it'll be contradicting
If i am getting in to the B school i desire to get i will definitely thank you sir because that's what all i can do if i can do anything better i will definitely do so sir
Angle bisector theorem
Can't thank enough for these lectures ❤❤ thank you sir
thankyou sir........
Thank you sir for the concepts and tricks !!
Sir, what if I apply the heron's formula as you did in order to compute the area and then use the formula A=r*s in order to find the radius? Is that the right procedure coz the answers are different. I am telling you about the last sum in the video.
Thanks yaar getting the same question in my mind.... 😃but the answer is different in that case🤔
because 'r' in that case is not in-radius.
it applies in inradius which have a whole circel but it is a semicircle in a full triangle
@@sanjayk1286 can't we just divide the r by 2 in that case?
@@rishimukherjee2118 no rishi
your just awesome sir.... thank you so much....
Amazing video. Thank you!
Sir for the last question can we use the formulae for Area = Inradius * S
No i think u cant because thats inradius from incentre point here its radius from centre of semicircle and u can also verify by solving u will get wrong radius i.e 3
Waah bhai badiya padha diya apne
Sir please upload trigonometry series 🙏
done
at 11:38 how can bc cut bc as its in bracket
sir in last question can we use A=r*s formula after finding area of triangle
From that we will get only the area not the radius.
In last question, after finding area(ABC) as 66 cm2. Why we can't use formula A= r.s which gives r= 66/22 = 3 cm.
small r in this formula is inradius
radius of the semi circle is not the inradius
Sir ye 7AD kese hua ye nahi samjha
Thank you sir ⭐
Do you have any book for questions?
excellent stuff 👍
Your lectures are very helpful. Thank you sir :)
Thankyou soo much sir . It was really helpful
4:40 someone please explain
Thank you so much sir.❤❤
1
jw amazing session
Thank you sir 🙏
15:03......can't i assume the third side to be 5 units considering the triplet scenario of (3 ,4 and 5) and then solve the problem .
in that case answer is 24/7
this is not..a assuming question...you need to prove your point
@piyush noo answer is right.. 2 can be divided by 6
6:00
when did we study that???? 9:55
In the previous one.
Thanku sir
thank you sir
answers bhi kar diya karo sir
What's wrong if we approach by A=r.s
Answer is coming as 3 by that method.
Please reply
Kyuki r one ke liye hai na ki 1/4th part of circle ke liye think about it
Ye btaye mujhe ye perpendicular ko height kyu liye🤔
@@syedahmad4466 read circle tangent angle property in previous lectures.
No i think u cant because thats inradius from incentre point here its radius from centre of semicircle and u can also verify by solving u will get wrong radius i.e 3
Humara jo centre hai wo incentre hona chiye ye formala use krne ko , lekin is q mein we can't say the centre is incentre .
Thank you sir!!
i tried solving the /_a=60 and AD =? sum in a different approach ,
according to the diagram
sin 30=BD/4;
so BD= sin30*4= 2;
now tan 30= BD/AD;
so AD= BD/Tan 30 ;
AD= 2/root(3)
but the answers are not tallying y? where did i do wrong?
trigonometric ratios are applicable only for right angle triangle now check in ur approach whether it is right angle triangle...actaually i too made the same mistake.then realised later.
thanks man i also got stuck at the same part. and was looking in comment section if anyone had given solution to it,thanks again
@@devarapallivamsi7064
Can i put AREA= r X s
Where s = a+b+c/2
No since radius and in radius is different stuff
11:47 we can find the length of angle bisector with this formula as well: d = (2ab cos θ )/ (a+b)
I think in place of cos ,sin should be there..or if that is cos, angle is bisected angle
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Bro but this much quality teaching very hard to get
Free me lectures bhi chaiye aur woh bhi without ads, aisa thodi hota hai, samaj seva karne thodi bethe hai ye log. Jo mil rha hai ussi me khush raho.
@@Rahulbajaj561 you dumb ass I mentioned many so better to ready it properly. Thats the reason channel reach is very low
Upgrade to premium simple 😅