What I like is how you've left yourself vulnerable to making mistakes. Practically everything you got wrong, I got wrong too and was forced back to the training materials to fill in the holes in the knowledge. Thank you for allowing yourself to be not only this helpful, but also this open. My upcoming Network+ exam now seems more like a storm wave rather than a tsunami at this point.
Passed my Network+ exam in part because of your videos. At least a dozen questions were accompanied by your visage and voice and as a very visual learner I'm grateful I picked you! thank you!
Hey z!! I'm so glad it helped out 😂 I'm not sure I'd wish my visage upon anyone's mind during a test, but that was funny. Thanks for watching!! I'm planning to make more videos soon.
1.st step: take 1100 0100 divide it in nibbles and under each nibble write 8421 8421 8421 2nd step: All numbers under 0 you ignore so you are left with this 1100 0100 84 - - -4 - - 3rd step: For each nibble SEPARATE add those lower numbers and you will get 12 on 1 side and 4 on other. in hex: 1=1 8=8 15=F 2=2 9=9 3=3 10=A 4=4 11=B So basically you got 12 that is "C" in hex and 4 that is 4.... aka C4 5=5 12=C 6=6 13=D 7=7 14=E
Ivan, you have the right idea on this. I have worked to memorize the hexadecimal values above, and the values of the first 8 bits at least -- 2^0 (1) to 2^7 (128), which total to one power higher minus 1 (for instance, the 8th bit equals 128 or 2^7, but all 8 bits with values of 1 have a total value of 2^8-1 or 255) -- and then I moved on to playing with subnetting, borrowing binary digits from the host address to add to the network address. (I studied from Mike Meyers' text and lab book.) Manipulate these numbers until you can do it in your sleep. You will become more fluent in binary (base 2) and hexadecimal (base 16), like you are now in base 10. Then I think you will have no problem with the math and conversions on the test.
Also... Although the current exam focuses mainly on IPv4, IPv6 IS THE FUTURE, SO GET USED TO IT! That means hexadecimals. Hexadecimal is also used for memory addresses, and will be annotated with "0x" before the digits.
Thank you, however it’s a poorly worded question because normally when put next to each other you continue the powers of 2, so it would be 1100 0100, first set representing 192, second set being 4, meaning it would be 192 and 192, very poor written question
I wanted to write about question 13. Binary System = 128 +64 +32 + 16 + 8 + 4 + 2 +1 = 255 We are looking at which numbers we can use to reach the number 196. I need one 128 for this. Then I need 64 and one 4 e. 128 + 64 + 4 = 196. Then I distribute it as 8 digits and divide it by two. 1100 0100 Then I add the first part and find the letter C as decimal 12 and hexadecimal. If I then add 0100 for the second part, I get 4. So our answer would be C4. Thank you for this fine skill.
Thank you Damlaya! That is a good explanation. 196 becomes 11000100 in binary. 1100 becomes 12 in decimal which becomes C in hex. 0100 becomes 4 in decimal which is still 4 in hex. Thank you for clarifying!
Q13. I noticed that the binary and decimal were both saying 196 decimal, so then divided the 196 by 16 (hex) and that gave me 12 remainder 4. The 12 when counting in hex = C (0123456789AB 'C' DEF) and the remainder of 4 gave me a hex value of '4' so the answer was C4. ..seems dividing by 16 and doing it this way is relatively uncomplicated and 'should' work every time ..My Network+ is coming up as soon as I can find the courage and spare the cash to sit it! Great content btw!!!!!!
Thanks for this. This convinced me to pay for practice tests, cause now I see why they're valuable. As an aside, while the test writers know a lot a networking, they definitely could work on their sentence structure. Edit: I was trying to be nice, but sweet lord, I'm starting to think they just learned English. I can't read a quarter of these on the first try.
On question 13, the Hex is only there for a shortcut. Each four digits in binary convert to one digit in Hex. This way you can work with smaller numbers: 1100 = 12 (0xC) and 0100 = 4 (0x4), so 1100 0100 = C4. That trick doesn't work with decimal. This is because 16 is a power of 2 (2^4 = 16), but 10 is not a power of 2 (2 raised to any power will not equal 10).
For question 30, in a class C subnet, you usually have 254 possible host addresses. To set up subnets within that host section, you have to borrow bits from the last octet of the address. Look up "calculating subnets." TLDR, you have to borrow 4 bits from the final octet. So instead of 11111111 (255), it is 11100000 (224).
You are doing great! I'm going to school for cyber security and information assurance through WGU and I like to expose myself to all learning, as in watching, listening, and doing. You're doing great work and bring amazing character into it! Much respect for what you're doing!
Finished a college class and am taking a week to cram and get rdy for my tests watching this video in the car while I travel and studying at home. 5 days left wish me luck! Also I subscribed 🎉
@@vincenthumble sadly not well. I sat down and got everything set up, and when I finally got the test in front of me, it was in Spanish. I told them it was in the incorrect language and they said that they would have to cancel the test. They gave me a customer service number and a ticket number to give them. I called the next day as they are closed on weekends and they said they would look into it and to expect an email over the next few days. 4 days later I got an email saying their is nothing they can do . They whole thing left me feeling very sour about it all. I am for sure unmotivated to try and take this test again and I am especially upset at this company. I am sure I will take it again, but it’s gonna have to wait a while as I had to dish about money and time to make it work this one time. Anyways, thanks for the help.
@@budddmj8191I had a run of bad experiences with Pearson when I took my A+ exams recently. Just one terrible thing after another that made me want to quit and their customer service was no help at all, but I found a way to move past it all. Don't let the bumps in the road stop you from getting where you're going.
Awesome video! Appreciate your use of the binary 1s and 0s to get the subnet mask or CIDR, it made that part of subnetting really easy for me. Didn't think of it that way. Thank you Vincent!
Q30 requires the borrowing of bits in the last octet. Therefore it cannot be A or E. B,C,and D are the decimal values for 1,2 0r 3 bits borrowed. If you look up how many bits are required to subnet a class c address you will see it require 3 bits can create a maximum of 8 subnets and that you can calculate the decimal value of three bits to total 224, eg 128+96+32.
For anyone who was stuck on the binary and decimal part here are a few things I like to keep in mind that may help. My understanding portion Hexadecimal = Hex(6), decimal (10), six over ten, so keep in mind there are 16 digits we have to pay attention to. From 0 - 9, we can count it normally, the only difference is in 10 we convert to A and keep going to 15. For example 0,1, 2, 3, 4, 5, 6, 7, 8, 9 ---> (Alphabet now) 10(A), 11(B), 12(C), 13(D), 14 (E), 15(F), we don't go up to 16 because we started at zero. From this we now understand two things, the numbering system in hexadecimals (1) and it being 16(2). Hence, we use this understanding of it having a base 16, to our advantage in decimals. Meaning if we want to convert a decimal to hexadecimal we need to divide it by 16. Binary = Binary (0 or 1), keep in mind for decimals they use the power of 2, because it's base 2. This is all the information we need to start our conversions. Solving portion Binary part: 1100 0100 Since we're using base 2, we'll use the powers of 2 to solve this (respectfully for each part). 2^0 = 1 2^1 = 2 2^2 = 4 2^3 = 8 (This is all we need to solve this problem here, and keep in mind if there are more numbers you keep on going: for example if it was 111100, you'd go up to 2^5) 0's mean off, so we don't need to add those parts in, only the parts that have a one to it. Because of this, we get 4 + 8 = 12. So lets organize all of this together. Binary : 1100 0100 (Go from right - left, not left to right) 1100 = 4 + 8 = 12 0100 = 4 Now to convert it to hexadecimal we keep in mind what we learned earlier, 12 = C, so we put C. 4 isn't that high so we keep it 4 (only converting pass 9). Giving us: C4 Decimal part This part requires less work and if you've ever programmed you'd notice it's quite similar to the % operator (remainder). Since we understand that hexadecimal is base 16, we divide whatever the decimal is by 16, here in this case it was 196. 196/16 = 12.25 16 * 12 = 192, meaning we're left with a remainder of 4. So out of this, we have two important numbers the 12 which we got from dividing, and the 4. We convert the 12 to hexadecimal which is C and leave the 4 alone getting C4 lets do another problem, lets say it was 230. 230/16 = 14.375 16 * 14 = 224, we need six more to get to 230, meaning the remainder is 6. We have two important numbers the 14 and the 6 giving us: E6
Someone has probably already said this here but for anyone confused about NIC Teaming, most Net+ courses call NIC Teaming "Link Aggregation". It seems like CompTIA wants you to call it NIC Teaming but its essentially the same thing or at least the same general concept as Link Aggregation. Always look up terms you don't recognize because more than likely its something you DO know but under a different naming convention. Classic CompTIA.
Hey Lucy! Thanks for watching, and good luck! Unfortunately, I only have time to upload about the tests I am currently studying for (Security+). There are a couple hours of content for the Net+ and I hope it serves you well :)
27 is iffy. The correct answer is port or link aggregation. It's basically the same as nic teaming, but for a switch. I have never heard anyone call it that. 44 is also wrong. It's at least 10km.
For question 13, you have 12, 1-9 a is 10, b is 11, c is 12. So that gives you C for 1100 in hex. 0100 is four so the hex for 1100 0100 is C4. The decimal is all of the ones added together so 128+64+4 or 196.
You have probably figured this out yourself, but for others potentially wondering why that Hex answer was C4.. That's cause you start counting from 0 instead of 1. So 0123456789ABCDEF.
I wish you luck on taking your exam, I will be taking me shortly as well. Whoever made this practice test did a horrible job, I would look at other means of practice tests to better prepare for the exam
already subscribed, humble Mr.Humble....thanks for your efforts...this questions are sometimes difficult to answer, this is why are watching your review...have a nice life! :-)
you are awesome. You are so funny. Please leave the question visible while you are reading it. you are doing very well though. I hope to test out in 2 weeks also.
he spent so long on the binary to hexadecimal portion, i feel so bad for that homies need to know that you group binary numbers by 4s (which the question already did), convert each 4 into 1 hex, then concatentate them to get the hex. you can get really good at this once you practice your binary to hex table
Failed it …. Rescheduled for this Friday been studying all the things I needed to touch up on …. Barely failed it makes it even more frustrating for me
Glad to hear it!! Thank you for watching! I'll be releasing my last couple of videos regarding the Sec+ soon. If you plan on taking that test as well, check out the playlist 🙂 I have put more effort into the editing and setup since this video was released.
I appreciate you making this video, studying now for this. But I have to say, as handsome as you are, ever since I saw your cat I found myself wishing your camera was on your cat. XD
q25 - portscanner will tell you what is listening, not what is being used, OTDR is for testing fiberoptics, Multimeter aint gonna measure network activity at all, and the cable tester will only tell you how good your cable is ... C is the only thing left
wait you have to know hexadecimal conversion? O_O none of the material i went throguh even mentioned hex conversion, only decimal to binary and binary to decimal
For question 3 for any1 still studying, you look at all the answers you pick 3 that are the most accurate, so even like he said he wouldnt think A would be one of the correct answers, you need to look at other, if the question says pick 3 out of the 5 and the other 2 are completely wrrong, you would still pick A, because C is incorrect, and E is incorrect, so answers A has to be a part of the answer
I’m using professor messer videos and his notes, and interactive hands on labs. Also reading Michael meyers book, and practice tests. Is this an adequate study method ?
I think this is adequate. But I would definitely recommend taking Jason Dion's practice tests on Udemy to get a better idea of where you're at. Not every question he puts on his exams is relevant to the actual exam, but your aim should be to score at least 80% or higher on his tests. If you can, you will most likely pass. If you don't, just go back and review the questions you missed and study those sections until you can score 80% higher. This is basically the strategy I use for each of the three exams.
Compared to this one they were a bit harder. I also do material from CompTI certmaster learn in some of my other videos and I would say the test was easier than those questions in general.
Those questions they give you with the voucher are really poor. However, the discount voucher is certainly a deal without the free pdf that was put together in short order. Thanks for sharing.
Yes, I agree. The questions I go over in other videos from Certmaster Learn by CompTIA are much higher quality. These questions were much easier, but they had many typos and errors. Thanks for watching!
I started watching without much attention, but after 30min watching and studying with you help me a lot in some points I thought I knew! Will follow you up, thanks! Got a subscriber here
Hi! Thanks for watching! You could have many certificates and still into get a cybersecurity job. What employers care most about is experience. Can you do what they need you to do within the cybersecurity job? I would recommend getting an entry level job in a related position such as IT helpdesk first. However, if you have the means and the time and your dead set on cybersecurity then you need to learn the hands on keyboard skills through labs and exercises such as TryHackMe and HackTheBox. Maybe compete in some CTFs. If you get to that skill level I believe you could jump straight into CyberSec
I took the A+ 1001 exam twice (630,710) and the 1002 exam once (708). I’m considering getting my network certification. Is the network exam one single exam or a two part exam?
@@vincenthumble I have already taken 3 other CompTIA exams and I am not really a fan of how they ask their questions. Is this the difficult part that you are speaking of?
Yes, certainly. They push your confidence down by wording the questions in a very difficult way. I think the purpose is to truly test your knowledge, which I think is effective, but it can also be very disheartening
@@vincenthumble With the other tests I feel like if I had known which category the question was about, then I knew the answer. It was the guessing which category a question belonged in.
Just for practice 🙂 posting actual exam questions or studying actual exam questions is not allowed by CompTIA and will get you barred from taking any CompTI certification exams.
@@vincenthumble couple of questions, how many performance based questions did you get? Were they difficult? Also do did you take the test in person or online ? I have my test scheduled in person I don't know if I should change that
I honestly can't remember how many performance-based questions I got. I think it was two or three. However, since you're the second person to ask about this, I've decided to make a video about the performance-based questions. I took the test online, I am grateful that I did because I was able to change the time at the last minute to give myself four extra hours to cram. I think in person would be nice too because you can write on the whiteboard.
2^3=8 not 6. I feel like some people get confused and do 2*3. Anyways the question is just a bit misleading or possibly badly written. 255.255.255.224 makes a /27 cidr notation and creates 8 subnets. So it is correct since it would be the lowest number of subnets you could create while still encompassing the 6 the question states were created. I could be wrong but I think this is what they had in mind.
Cool man! Kudos. I literally just use my camera phone with a generic Amazon tripod. Formerly pixel 5a, currently pixel 7. Screen record & audio through OBS, editing is DaVinci Resolve 18 (free version), generic Amazon green screen hung from wall or ceiling for the self without background overlayed onto screen. Good luck with your content! 🙂
Apologies, but this test is NOT good. Its very base level knowledge and doesn't even really detail the answers well. That's not even mentioning the strange wording that sounds like it was likely compiled by AI. I don't say this to be arrogant, I'm only commenting to say that you should not rely on this resource alone and walk into that exam. The Net+ exam will not be a word association/vocabulary test, it's going to require a basic understanding of how these resources interconnect and function in a network. Personally I would recommend Boson exams. I used them for SEC+ and NET+, and the in depth explanation on every question of the right and wrong answers, makes it worth the price of admission alone. You could honestly get a good portion of your studies just from taking the quizzes over and over, and reading the explanations. Of course, you should always use a variety of resources, so I would also recommend Professor Messer's video course.
a website called getcertified has extremely cheap like $180, so i tried to buy it but my credit card company blocked my card and said it was suspicious so it freaked me out, i ended up using getcertified but it was a little bit more than $180.
What I like is how you've left yourself vulnerable to making mistakes. Practically everything you got wrong, I got wrong too and was forced back to the training materials to fill in the holes in the knowledge. Thank you for allowing yourself to be not only this helpful, but also this open. My upcoming Network+ exam now seems more like a storm wave rather than a tsunami at this point.
Passed my Network+ exam in part because of your videos. At least a dozen questions were accompanied by your visage and voice and as a very visual learner I'm grateful I picked you! thank you!
Hey z!! I'm so glad it helped out 😂 I'm not sure I'd wish my visage upon anyone's mind during a test, but that was funny. Thanks for watching!! I'm planning to make more videos soon.
How did you get your hands on practice
1.st step: take 1100 0100 divide it in nibbles and under each nibble write 8421
8421 8421
2nd step: All numbers under 0 you ignore so you are left with this
1100 0100
84 - - -4 - -
3rd step: For each nibble SEPARATE add those lower numbers and you will get 12 on 1 side and 4 on other.
in hex:
1=1 8=8 15=F
2=2 9=9
3=3 10=A
4=4 11=B So basically you got 12 that is "C" in hex and 4 that is 4.... aka C4
5=5 12=C
6=6 13=D
7=7 14=E
Ivan, you have the right idea on this.
I have worked to memorize the hexadecimal values above, and the values of the first 8 bits at least -- 2^0 (1) to 2^7 (128), which total to one power higher minus 1 (for instance, the 8th bit equals 128 or 2^7, but all 8 bits with values of 1 have a total value of 2^8-1 or 255) -- and then I moved on to playing with subnetting, borrowing binary digits from the host address to add to the network address. (I studied from Mike Meyers' text and lab book.)
Manipulate these numbers until you can do it in your sleep. You will become more fluent in binary (base 2) and hexadecimal (base 16), like you are now in base 10. Then I think you will have no problem with the math and conversions on the test.
Also...
Although the current exam focuses mainly on IPv4,
IPv6 IS THE FUTURE, SO GET USED TO IT!
That means hexadecimals. Hexadecimal is also used for memory addresses, and will be annotated with "0x" before the digits.
Thank you for this!! I knew there was an easy way haha
Thank you, however it’s a poorly worded question because normally when put next to each other you continue the powers of 2, so it would be 1100 0100, first set representing 192, second set being 4, meaning it would be 192 and 192, very poor written question
I wanted to write about question 13.
Binary System = 128 +64 +32 + 16 + 8 + 4 + 2 +1 = 255
We are looking at which numbers we can use to reach the number 196. I need one 128 for this. Then I need 64 and one 4 e. 128 + 64 + 4 = 196.
Then I distribute it as 8 digits and divide it by two.
1100 0100
Then I add the first part and find the letter C as decimal 12 and hexadecimal. If I then add 0100 for the second part, I get 4. So our answer would be C4.
Thank you for this fine skill.
Thank you Damlaya! That is a good explanation. 196 becomes 11000100 in binary. 1100 becomes 12 in decimal which becomes C in hex. 0100 becomes 4 in decimal which is still 4 in hex. Thank you for clarifying!
Q13. I noticed that the binary and decimal were both saying 196 decimal, so then divided the 196 by 16 (hex) and that gave me 12 remainder 4. The 12 when counting in hex = C (0123456789AB 'C' DEF) and the remainder of 4 gave me a hex value of '4' so the answer was C4. ..seems dividing by 16 and doing it this way is relatively uncomplicated and 'should' work every time ..My Network+ is coming up as soon as I can find the courage and spare the cash to sit it! Great content btw!!!!!!
Thanks for this. This convinced me to pay for practice tests, cause now I see why they're valuable.
As an aside, while the test writers know a lot a networking, they definitely could work on their sentence structure.
Edit: I was trying to be nice, but sweet lord, I'm starting to think they just learned English. I can't read a quarter of these on the first try.
Lol you're welcome! Glad to be of service.
@vincenthumble
On question 13, the Hex is only there for a shortcut. Each four digits in binary convert to one digit in Hex. This way you can work with smaller numbers: 1100 = 12 (0xC) and 0100 = 4 (0x4), so 1100 0100 = C4. That trick doesn't work with decimal. This is because 16 is a power of 2 (2^4 = 16), but 10 is not a power of 2 (2 raised to any power will not equal 10).
For question 30, in a class C subnet, you usually have 254 possible host addresses. To set up subnets within that host section, you have to borrow bits from the last octet of the address. Look up "calculating subnets." TLDR, you have to borrow 4 bits from the final octet. So instead of 11111111 (255), it is 11100000 (224).
Nice explanation!
made 0 sense to me.
You are doing great! I'm going to school for cyber security and information assurance through WGU and I like to expose myself to all learning, as in watching, listening, and doing. You're doing great work and bring amazing character into it! Much respect for what you're doing!
Your Videos are amazing , Its good for revision and boost up my confidence for the exam
Finished a college class and am taking a week to cram and get rdy for my tests watching this video in the car while I travel and studying at home. 5 days left wish me luck! Also I subscribed 🎉
Hey! How did it go?
@@vincenthumble sadly not well. I sat down and got everything set up, and when I finally got the test in front of me, it was in Spanish. I told them it was in the incorrect language and they said that they would have to cancel the test. They gave me a customer service number and a ticket number to give them. I called the next day as they are closed on weekends and they said they would look into it and to expect an email over the next few days. 4 days later I got an email saying their is nothing they can do .
They whole thing left me feeling very sour about it all. I am for sure unmotivated to try and take this test again and I am especially upset at this company. I am sure I will take it again, but it’s gonna have to wait a while as I had to dish about money and time to make it work this one time.
Anyways, thanks for the help.
@@budddmj8191I had a run of bad experiences with Pearson when I took my A+ exams recently. Just one terrible thing after another that made me want to quit and their customer service was no help at all, but I found a way to move past it all. Don't let the bumps in the road stop you from getting where you're going.
@@JustinAZ thanks man. You are right, next month I’m gonna start to study again and give myself a little more time this time.
@@budddmj8191 I really hope you stuck with it and passed your test. Keep pushing forward! You got this..
Awesome video! Appreciate your use of the binary 1s and 0s to get the subnet mask or CIDR, it made that part of subnetting really easy for me. Didn't think of it that way. Thank you Vincent!
Q30 requires the borrowing of bits in the last octet. Therefore it cannot be A or E. B,C,and D are the decimal values for 1,2 0r 3 bits borrowed. If you look up how many bits are required to subnet a class c address you will see it require 3 bits can create a maximum of 8 subnets and that you can calculate the decimal value of three bits to total 224, eg 128+96+32.
Thanks, Im taking the exam tomorrow and I got almost a perfect score on these questions, so thats a good sign.
Great job Jose! Best of luck to you brother
Did you pass?
@@musagoud4884 yes
Q37 easy fast calculation> /26 means there is two bits borrowed for subnetting and 6 bits for host. Two bits decimal value = 192 eg 128+64
For anyone who was stuck on the binary and decimal part here are a few things I like to keep in mind that may help.
My understanding portion
Hexadecimal = Hex(6), decimal (10), six over ten, so keep in mind there are 16 digits we have to pay attention to. From 0 - 9, we can count it normally, the only difference is in 10 we convert to A and keep going to 15. For example 0,1, 2, 3, 4, 5, 6, 7, 8, 9 ---> (Alphabet now) 10(A), 11(B), 12(C), 13(D), 14 (E), 15(F), we don't go up to 16 because we started at zero.
From this we now understand two things, the numbering system in hexadecimals (1) and it being 16(2).
Hence, we use this understanding of it having a base 16, to our advantage in decimals. Meaning if we want to convert a decimal to hexadecimal we need to divide it by 16.
Binary = Binary (0 or 1), keep in mind for decimals they use the power of 2, because it's base 2. This is all the information we need to start our conversions.
Solving portion
Binary part: 1100 0100
Since we're using base 2, we'll use the powers of 2 to solve this (respectfully for each part).
2^0 = 1
2^1 = 2
2^2 = 4
2^3 = 8
(This is all we need to solve this problem here, and keep in mind if there are more numbers you keep on going: for example if it was 111100, you'd go up to 2^5)
0's mean off, so we don't need to add those parts in, only the parts that have a one to it. Because of this, we get 4 + 8 = 12. So lets organize all of this together.
Binary : 1100 0100 (Go from right - left, not left to right)
1100 = 4 + 8 = 12
0100 = 4
Now to convert it to hexadecimal we keep in mind what we learned earlier, 12 = C, so we put C. 4 isn't that high so we keep it 4 (only converting pass 9). Giving us: C4
Decimal part
This part requires less work and if you've ever programmed you'd notice it's quite similar to the % operator (remainder).
Since we understand that hexadecimal is base 16, we divide whatever the decimal is by 16, here in this case it was 196.
196/16 = 12.25
16 * 12 = 192, meaning we're left with a remainder of 4.
So out of this, we have two important numbers the 12 which we got from dividing, and the 4. We convert the 12 to hexadecimal which is C and leave the 4 alone getting
C4
lets do another problem, lets say it was 230.
230/16 = 14.375
16 * 14 = 224, we need six more to get to 230, meaning the remainder is 6.
We have two important numbers the 14 and the 6 giving us:
E6
Someone has probably already said this here but for anyone confused about NIC Teaming, most Net+ courses call NIC Teaming "Link Aggregation". It seems like CompTIA wants you to call it NIC Teaming but its essentially the same thing or at least the same general concept as Link Aggregation. Always look up terms you don't recognize because more than likely its something you DO know but under a different naming convention. Classic CompTIA.
i love your personality 😂 got me laughing when im stressing about this test
Thank you so much for these videos Vincent, they helped me so much during my studies!
Hey Ulysses! Thanks for watching! I'm glad these videos helped you 🙂
how accurate are these questions for the exam?
For the most part, they cover the same material, but they are less difficult
taking this test in the spring, please up load as much as you can on this test....
Hey Lucy! Thanks for watching, and good luck! Unfortunately, I only have time to upload about the tests I am currently studying for (Security+). There are a couple hours of content for the Net+ and I hope it serves you well :)
Gonna take the test tomorrow
how'd it go??
Do you think a net+ is enough to get a job? Or should we also get something like A+ or Sec+ before applying?
27 is iffy.
The correct answer is port or link aggregation. It's basically the same as nic teaming, but for a switch. I have never heard anyone call it that.
44 is also wrong. It's at least 10km.
Thanks so much trying to prepare for my test! Thanks!!!
For question 13, you have 12, 1-9 a is 10, b is 11, c is 12. So that gives you C for 1100 in hex. 0100 is four so the hex for 1100 0100 is C4. The decimal is all of the ones added together so 128+64+4 or 196.
Well-played Mr. Brock
You have probably figured this out yourself, but for others potentially wondering why that Hex answer was C4.. That's cause you start counting from 0 instead of 1. So 0123456789ABCDEF.
Thank you your pointing that out
I wish you luck on taking your exam, I will be taking me shortly as well. Whoever made this practice test did a horrible job, I would look at other means of practice tests to better prepare for the exam
Lazer Cablezzzzz lmao. Thanks for the practice questions man.
Haha! You're welcome. Thanks for watching!
already subscribed, humble Mr.Humble....thanks for your efforts...this questions are sometimes difficult to answer, this is why are watching your review...have a nice life! :-)
Helpful video! One request, would it possible for you to explain your thinking or reasoning to an answer. That would be very helpful!
Yes! I believe I do that better in some of my other videos. Thank you for watching!
you are awesome. You are so funny. Please leave the question visible while you are reading it. you are doing very well though. I hope to test out in 2 weeks also.
Thank you for your kind words! Good luck on your test!
he spent so long on the binary to hexadecimal portion, i feel so bad for that
homies need to know that you group binary numbers by 4s (which the question already did), convert each 4 into 1 hex, then concatentate them to get the hex. you can get really good at this once you practice your binary to hex table
im taking my test tomorrow and ive been using your videos to study thanks for the help
Awesome! Good luck and thanks for watching!
How’d it go?
Failed it …. Rescheduled for this Friday been studying all the things I needed to touch up on …. Barely failed it makes it even more frustrating for me
Ok took it again today and passed thank you for all the help
@@thehighofmusic82 good for you, I would like to ask you question pls
Did you pass the test? I am preparing for the test.heard scary rourmors😰😱
Yes, I did pass. It was not as bad as I thought 🙂
@@vincenthumble what other resources did you use?
Jason Dions practice exams, Professor Messers videos and notes, and Mike Meyers Udemy courses.
hahah, man this inspires me. I went to school and my teachers couldnt even keep me this entertained!
Glad to hear it!! Thank you for watching! I'll be releasing my last couple of videos regarding the Sec+ soon. If you plan on taking that test as well, check out the playlist 🙂 I have put more effort into the editing and setup since this video was released.
I appreciate you making this video, studying now for this.
But I have to say, as handsome as you are, ever since I saw your cat I found myself wishing your camera was on your cat. XD
q25 - portscanner will tell you what is listening, not what is being used, OTDR is for testing fiberoptics, Multimeter aint gonna measure network activity at all, and the cable tester will only tell you how good your cable is ... C is the only thing left
Where are these practice tests located?
Thanks
“It hurts” lmao! I felt that too
Help me, i am studying N+, will this questions help me to pass my Exam? Thanks in advance
Comptia also gives discounts for Students on their website
VERY EXELLENT EXPLANATION, I SUBSCRIBED
THANK YOU BROTHER
LOL 4:40 “C! Pick letter C my lord!!”
I was your 200th like you have achieved greatness now
Thank you, bestower of greatness. I have achieved.
Thank you for all the great info.
👍
in the video question 13 is 1100 0100 = 128+64+8=194 == HEX is C4 1100 = C - 13
wait you have to know hexadecimal conversion? O_O none of the material i went throguh even mentioned hex conversion, only decimal to binary and binary to decimal
Thanks. Great effort and detailed information shared.
Glad it was helpful!
@22:19 thank you!! 😊
For question 3 for any1 still studying, you look at all the answers you pick 3 that are the most accurate, so even like he said he wouldnt think A would be one of the correct answers, you need to look at other, if the question says pick 3 out of the 5 and the other 2 are completely wrrong, you would still pick A, because C is incorrect, and E is incorrect, so answers A has to be a part of the answer
I’m using professor messer videos and his notes, and interactive hands on labs. Also reading Michael meyers book, and practice tests. Is this an adequate study method ?
I think this is adequate. But I would definitely recommend taking Jason Dion's practice tests on Udemy to get a better idea of where you're at. Not every question he puts on his exams is relevant to the actual exam, but your aim should be to score at least 80% or higher on his tests. If you can, you will most likely pass. If you don't, just go back and review the questions you missed and study those sections until you can score 80% higher. This is basically the strategy I use for each of the three exams.
Thank you for this, good video!
Thanks for watching!
thanks for the video. question for you, were the questions on the test on the same level of difficulty as these or harder?
Compared to this one they were a bit harder. I also do material from CompTI certmaster learn in some of my other videos and I would say the test was easier than those questions in general.
Those questions they give you with the voucher are really poor. However, the discount voucher is certainly a deal without the free pdf that was put together in short order. Thanks for sharing.
Yes, I agree. The questions I go over in other videos from Certmaster Learn by CompTIA are much higher quality. These questions were much easier, but they had many typos and errors. Thanks for watching!
Where do I get this practice test? Also are there any free ones?
I started watching without much attention, but after 30min watching and studying with you help me a lot in some points I thought I knew! Will follow you up, thanks! Got a subscriber here
Thanks man, that means a lot
8+4 is 12 and in hex A is 10 B 11 and C is 12
And the other is just 4 so C4
I would edit out the burp. Thank you for making the videos.
Yes, that is a bit of advice that I have implemented in my videos posted since then 😁 thanks for watching!
the preactice test shown hree in this video how can I access?
The books and google said that the wifi ac only operate in 5 ghz so question 6 I suppose is d wifi n that in some case has both
27 is Port Aggregation
aka nic teaming
Hi, Vincent thanks for all videos about exam or certificate. How many certificates do we need to get for find cyber security job? Thanks.
Hi! Thanks for watching! You could have many certificates and still into get a cybersecurity job. What employers care most about is experience. Can you do what they need you to do within the cybersecurity job? I would recommend getting an entry level job in a related position such as IT helpdesk first. However, if you have the means and the time and your dead set on cybersecurity then you need to learn the hands on keyboard skills through labs and exercises such as TryHackMe and HackTheBox. Maybe compete in some CTFs. If you get to that skill level I believe you could jump straight into CyberSec
I took the A+ 1001 exam twice (630,710) and the 1002 exam once (708). I’m considering getting my network certification. Is the network exam one single exam or a two part exam?
One exam, friend
can't you do part 3 please
Vincent when they talk about subnets and network
IP ranges how do you know if it’s private or public
IP range ?
You just have to memorize the ranges.
Were these questions close to the actual exam?
Same material, but the exam is a bit more difficult
@@vincenthumble I have already taken 3 other CompTIA exams and I am not really a fan of how they ask their questions. Is this the difficult part that you are speaking of?
Yes, certainly. They push your confidence down by wording the questions in a very difficult way. I think the purpose is to truly test your knowledge, which I think is effective, but it can also be very disheartening
@@vincenthumble With the other tests I feel like if I had known which category the question was about, then I knew the answer. It was the guessing which category a question belonged in.
Very helpful God bless
Trash test all around but i really appreciate your efforts my man. i test tomorrow at 10am
I'm sorry but these questions are horribly written in terms of grammar which makes it harder to understand
I'll just Google it.
Question 22 should have said Link State not Ste Link
13 answer is C
Where did you get the flash cards from?
I just made them out of 3x5 notecards
these questions are the one asked in exam or it just for practice?
Just for practice 🙂 posting actual exam questions or studying actual exam questions is not allowed by CompTIA and will get you barred from taking any CompTI certification exams.
where did you get this exams from, can you share the link?
It comes free with purchase of the exam voucher from getcertified4less
@@vincenthumble thanks!
I used the same website for my A+ Certificate. Can co-sign :) I appreciate the content!
Nice, thank you! And thank you for co-signing. I passed the Net+ yesterday! I'll have a video out for it soon ☺️
@@vincenthumble couple of questions, how many performance based questions did you get? Were they difficult?
Also do did you take the test in person or online ? I have my test scheduled in person I don't know if I should change that
I honestly can't remember how many performance-based questions I got. I think it was two or three. However, since you're the second person to ask about this, I've decided to make a video about the performance-based questions. I took the test online, I am grateful that I did because I was able to change the time at the last minute to give myself four extra hours to cram. I think in person would be nice too because you can write on the whiteboard.
For question# 30: There 6 subnet > 2^3 = 6 > 255.255.(128+64+32 = 224) 000.00000000
Nice explanation!!
2^3=8 not 6. I feel like some people get confused and do 2*3. Anyways the question is just a bit misleading or possibly badly written. 255.255.255.224 makes a /27 cidr notation and creates 8 subnets. So it is correct since it would be the lowest number of subnets you could create while still encompassing the 6 the question states were created. I could be wrong but I think this is what they had in mind.
@@drewsuski1825 You're right and it's actually one of the better worded questions on this practice exam, imo.
34:48
What camera and program do you use to put your face in the corner? I want to make similar content 😝
Cool man! Kudos. I literally just use my camera phone with a generic Amazon tripod. Formerly pixel 5a, currently pixel 7. Screen record & audio through OBS, editing is DaVinci Resolve 18 (free version), generic Amazon green screen hung from wall or ceiling for the self without background overlayed onto screen. Good luck with your content! 🙂
I'm saving up for a "real" camera but my budget is whatever I make on YT, so it'll take a while 😅
you missed some answers and did not credit yourself with the loss on the notepad... just saying
Yeah, I'm sure you're right. Every mistake is a learning opportunity. The important thing is, I passed the exam 🙂
23:10
"Create a several DMZ"
what
How scary is the test for real it has me really nervous
Not as bad as you think :D
Apologies, but this test is NOT good. Its very base level knowledge and doesn't even really detail the answers well. That's not even mentioning the strange wording that sounds like it was likely compiled by AI. I don't say this to be arrogant, I'm only commenting to say that you should not rely on this resource alone and walk into that exam. The Net+ exam will not be a word association/vocabulary test, it's going to require a basic understanding of how these resources interconnect and function in a network. Personally I would recommend Boson exams. I used them for SEC+ and NET+, and the in depth explanation on every question of the right and wrong answers, makes it worth the price of admission alone. You could honestly get a good portion of your studies just from taking the quizzes over and over, and reading the explanations. Of course, you should always use a variety of resources, so I would also recommend Professor Messer's video course.
Well said Tom! This is definitely the lowest quality exam on my channel. I also recommend studying with a variety of resources! Solid advice
Did you pass?
Yes!
This practice test is awful bro so horribly written
Lol that's the comedic relief I guess. It was free sort of
Whoever wrote that test needs work on their spelling
Yes. I definately agree
a website called getcertified has extremely cheap like $180, so i tried to buy it but my credit card company blocked my card and said it was suspicious so it freaked me out, i ended up using getcertified but it was a little bit more than $180.
Oh not a bad price! Were you able to schedule the exam with that code and verify that it is legitimate?
@@vincenthumble yes i was able to get a+ certified with it