Parallel plates's questions seems to be very difficult to me but now I am very confident that I can solve any type of question on this topic..... Thanku so much Sir
Ye karke bata 😂😂 Consider a parallel plate capacitor system consisting of three parallel plates: A, B, and C. The plates are separated by distances 'd1' and 'd2' as shown in the diagram. Plate A has a positive charge 'Q_A', plate B has a negative charge 'Q_B', and plate C is uncharged. ``` [A] [B] [C] ``` At time 't = 0', the plates are connected to an external circuit. Plate A starts losing its charge at a constant rate 'dQ_A/dt = -k', while plate B's charge increases at the same rate 'dQ_B/dt = k'. Simultaneously, plate C is pulled towards plate B by an external force with acceleration 'a'. a) Derive an expression for the electric field 'E' between plates A and B as a function of the distance 'x' from plate A, during the time the charges are changing. b) Calculate the initial acceleration of plate C and its initial velocity when 't = 0'. c) Find an expression for the electric potential difference between plates A and B as a function of time 't'. d) Determine the position of plate C as a function of time 't' considering its initial displacement, velocity, and the external force. e) Calculate the power delivered by the battery that maintains the potential difference between plates A and B, as a function of time 't'. f) As plate C moves towards plate B, the distance 'd2' between plates B and C decreases linearly with time at a rate 'v'. Explain how this affects the capacitance between plates B and C and the rate of change of electric potential energy stored in the capacitor system.
From many months I was troubling to solve these kind of questions but really this video has cleared all my doubts 🥰 May you get more and more love 😊 Thank you sir💗
sir in this 26:45 : -4c hona chaiye tha, as 12 x -4= -48 and 12+(-4)=8 in middle term splitting. in that question answer would be 4 x 10^-6 Farads. Thank you so much sir, for making this video 🙏
Thank you sir so much, just today i was doing these sums from S.L. Arora by sitting next to my teachwr and i was unable to do it and was explaining me the structure of the circuits. I couldn't understand. But sir your video helped me a lot and you've cleared all the doubts. Genuinely grateful 🥰
@@raveenasahu6131C1 and C2 ARE IN PARALLEL SO IT WILL BECOME 2C BY CAPACITANCE IN PARALLE FORMULA THEN C3 AND C4 ARE IN SERIES THEN IT WILL BECOME C/2 BY FORMULA AND THEN BOTH WILL COME IN PARALLE SO ADD THEM IT WILL COME OUT TO BE 5/2 C WHICH IS 2.5 C
2nd Wale k answer hai 5c/2....& Thank you so much sir ab ki video mein 1St time dekha...aur clearly sab kuch samajh aaya sir thank you sir once again!🙏🏻
Consider a parallel plate capacitor system consisting of three parallel plates: A, B, and C. The plates are separated by distances 'd1' and 'd2' as shown in the diagram. Plate A has a positive charge 'Q_A', plate B has a negative charge 'Q_B', and plate C is uncharged. ``` [A] [B] [C] ``` At time 't = 0', the plates are connected to an external circuit. Plate A starts losing its charge at a constant rate 'dQ_A/dt = -k', while plate B's charge increases at the same rate 'dQ_B/dt = k'. Simultaneously, plate C is pulled towards plate B by an external force with acceleration 'a'. a) Derive an expression for the electric field 'E' between plates A and B as a function of the distance 'x' from plate A, during the time the charges are changing. b) Calculate the initial acceleration of plate C and its initial velocity when 't = 0'. c) Find an expression for the electric potential difference between plates A and B as a function of time 't'. d) Determine the position of plate C as a function of time 't' considering its initial displacement, velocity, and the external force. e) Calculate the power delivered by the battery that maintains the potential difference between plates A and B, as a function of time 't'. f) As plate C moves towards plate B, the distance 'd2' between plates B and C decreases linearly with time at a rate 'v'. Explain how this affects the capacitance between plates B and C and the rate of change of electric potential energy stored in the capacitor system.
Sir 26:25 minutes pa apne -12c+8c kiye h . Galat h .. q ki 12×8=96 aata h .. isliye waha pa -12c×4c=48 aana chaiye . Or -12c+4c=8c aaye ga .. I am right sir
Watch this - ruclips.net/video/FKBAhSUlXTE/видео.html
5c/2 is the answer
5C/2 is the answer sir 🙏
@@rudranarayanranasingh bhi kese aya bta na?
9:46
Batch:2024-2025
2025 me
Bro just casually cleared all my doubts in a single video 😭❤️
😮
chup
9:38 5c/2 is correct 💯
Kese
@@Error.occurred000 vhi to
🤔🤔🤔🤔🤔🤔
@@harshprajapat-qc6fs bhi pta chla ?
Kese aya ?
Yes uh are right 👍
Thank you sir,
I was finding difficulties to solve the first two types. Your video helped me a lot!
best video on capacitor problems so far, covered every type of questions on infinite ladder. Thank you!!
Undoubtedly Best video on this topic... ❤ Thank you so much sir
itna aram se pdhate ho ap , sab samajh me aya varna aur to jaldee karte hai . thanks for such nice video
26:28 the factorisation was wrong
yup
Ya... It should be c²-12c+4c-48=0
@@anishyaanil3989exactly
Yaah Bro Mujhe laga ki hum dono ne ek he kitab padhi thi but ye to maine nahi padha
Galat hai
Parallel plates's questions seems to be very difficult to me but now I am very confident that I can solve any type of question on this topic..... Thanku so much Sir
Kam faak bhai 😂😂
Happy for you bro :)
Ye karke bata 😂😂
Consider a parallel plate capacitor system consisting of three parallel plates: A, B, and C. The plates are separated by distances 'd1' and 'd2' as shown in the diagram. Plate A has a positive charge 'Q_A', plate B has a negative charge 'Q_B', and plate C is uncharged.
```
[A] [B] [C]
```
At time 't = 0', the plates are connected to an external circuit. Plate A starts losing its charge at a constant rate 'dQ_A/dt = -k', while plate B's charge increases at the same rate 'dQ_B/dt = k'. Simultaneously, plate C is pulled towards plate B by an external force with acceleration 'a'.
a) Derive an expression for the electric field 'E' between plates A and B as a function of the distance 'x' from plate A, during the time the charges are changing.
b) Calculate the initial acceleration of plate C and its initial velocity when 't = 0'.
c) Find an expression for the electric potential difference between plates A and B as a function of time 't'.
d) Determine the position of plate C as a function of time 't' considering its initial displacement, velocity, and the external force.
e) Calculate the power delivered by the battery that maintains the potential difference between plates A and B, as a function of time 't'.
f) As plate C moves towards plate B, the distance 'd2' between plates B and C decreases linearly with time at a rate 'v'. Explain how this affects the capacitance between plates B and C and the rate of change of electric potential energy stored in the capacitor system.
@@Ecstacyk 💀
One of the best teachers in my list 🙏
26:14 it will be (-12C+4C)
26:04 sir yaha par mistake h -12c+4c factor hoga but aap 4c ki jagah par 8c likh diye h but answer aa gya h 😅
But he factorized correctly, don't know how he wrote 8 still he treated correctly as 4! Just a magic
@@Truthlover4ever He already memorized the answer prior to class.
Sir I attended your lecture for the first and understood with so much clarity... thank you sir 🙏🙏
From many months I was troubling to solve these kind of questions but really this video has cleared all my doubts 🥰 May you get more and more love 😊 Thank you sir💗
sir in this 26:45 : -4c hona chaiye tha, as 12 x -4= -48 and 12+(-4)=8 in middle term splitting.
in that question answer would be 4 x 10^-6 Farads.
Thank you so much sir, for making this video 🙏
NO the factorisation is wrong but answer is correct.
I clearify all my doubts related capacitor! Thank you so much sir
Very clearly understood . Thank u so much sir! 🙏
5C/2 is the capacitance sir...Thank you very much. Namaste 🙏🙏🙏🌅
26:07 pr glt h sir -12c+8c = - 4 ayega app ke hisab se lekin lana toh -8 h
Right
He already memorized the answer prior to class.
Thank you sir so much, just today i was doing these sums from S.L. Arora by sitting next to my teachwr and i was unable to do it and was explaining me the structure of the circuits. I couldn't understand. But sir your video helped me a lot and you've cleared all the doubts.
Genuinely grateful 🥰
9:49 Ceq= 2.5C
Explain pls
@@raveenasahu6131C1 and C2 ARE IN PARALLEL SO IT WILL BECOME 2C BY CAPACITANCE IN PARALLE FORMULA THEN C3 AND C4 ARE IN SERIES THEN IT WILL BECOME C/2 BY FORMULA AND THEN BOTH WILL COME IN PARALLE SO ADD THEM IT WILL COME OUT TO BE 5/2 C WHICH IS 2.5 C
5/2 kaise aya
Sir kaya app mole concept class 11 par video dal sakte hae kaya....with numericals
2nd Wale k answer hai 5c/2....& Thank you so much sir ab ki video mein 1St time dekha...aur clearly sab kuch samajh aaya sir thank you sir once again!🙏🏻
nice
Thank you so much sir. It really helped a lot.
Sir the answer for the second question is. 5C/2
If u make videos on jee and neet instead of boards u can get more views. You r outstanding
25:50 -12C+4C
Correction.
Yes bro. I was searching for this comment
Yess right
How ...? Can u please explain
@@Yo_pinuswe want multiplication as -48 and addition as -8 so the two numbers are -12 and 4
Very good explanation thank you soo much ❤
Thank you !! Now these questions feel so easy to me
Begginers mistake : factorisation 😎
26:20 main c²-12c+4c-48=0 hoga sir...
26:05 sir factor wrong hai C2 - 12 c + 4C - 48 = 0
9:45 5c/2 is right ans
Consider a parallel plate capacitor system consisting of three parallel plates: A, B, and C. The plates are separated by distances 'd1' and 'd2' as shown in the diagram. Plate A has a positive charge 'Q_A', plate B has a negative charge 'Q_B', and plate C is uncharged.
```
[A] [B] [C]
```
At time 't = 0', the plates are connected to an external circuit. Plate A starts losing its charge at a constant rate 'dQ_A/dt = -k', while plate B's charge increases at the same rate 'dQ_B/dt = k'. Simultaneously, plate C is pulled towards plate B by an external force with acceleration 'a'.
a) Derive an expression for the electric field 'E' between plates A and B as a function of the distance 'x' from plate A, during the time the charges are changing.
b) Calculate the initial acceleration of plate C and its initial velocity when 't = 0'.
c) Find an expression for the electric potential difference between plates A and B as a function of time 't'.
d) Determine the position of plate C as a function of time 't' considering its initial displacement, velocity, and the external force.
e) Calculate the power delivered by the battery that maintains the potential difference between plates A and B, as a function of time 't'.
f) As plate C moves towards plate B, the distance 'd2' between plates B and C decreases linearly with time at a rate 'v'. Explain how this affects the capacitance between plates B and C and the rate of change of electric potential energy stored in the capacitor system.
I was getting trouble to solve this kind of questions,but finally this video helps me a lot 🤞 tqs sir ....
9:30 ans- 5c/2
answer is 5c/2 ....best explaination sir
how
Sir maja aa gaya thank you 👌👌
Sir current electricity ka bhi video lao na please 🙏🏻
Thnku so much sir 😊 it's very very very helpful ❤ seriously 😊
15:25 same this type of question in jee 2023
9:38
5C/2
Wow sir 🎉 kya samjhate hai AAP ❤
Is this enough for jee mains?
Sir 5C/2 ayga 2nd no. Questions ka
I also get the same answer
🎉
How u got answer tell me formula
@@sandhyar-zo4oi C¹ +C² = 2C
C⁴C⁵÷C⁴+C⁵ = C×C÷2C
2C+C×C÷2C = 5C×C÷2C ( C cancel out) 5C÷2
5C/2
Sir question no. 2 ka answer hai = 5c/2
5c/2 is answer for 37:48
Ko sir ke lecture se capacitor ke ques ko solve karne mai full confidence aa gaay
2c + c/2 = 5c/2
Kaise aaya
Good Explained❤🎉🎉🎉
Tq very much sir for making physics easier for me 🫡👌🙏
Legends watching one day before exam any legend here 😂🎉❤
Sir pure RUclips par koi itne achhe se circuit nhi smjaya thankyou sir ❣️
5/2 C is the answer 09:30
Wrong ❌
Ans2- 5c/2
Great teaching
Tq so much sir.apnai bhit axa samjhaya.
Thanku so much sir 😀😀
Nice explanation sir
At position of 4 ,8 is placed
Sir u r great thank u very much for your efforts
26:39 sir its -8 micro farad you did the wrong factorisation
26:19 sir yaha par galti h 8c -48 se 4 common lenge toe braket ke andar bhi toe 2c ayega
Tq bahut acha laga❤❤❤
9:44 currect answer is (5c)÷2
5C/2 is ans. Of 2nd question 💯
Thanks so much 🙏❤
Thank You Sir ❤
😮
thanks for this 💖
Answer - 5C/2
Kya content hai yr dil aur dimag khush ho gya ❤❤❤❤
ANS - Que 2 5c by 2 7:33
Right
Sir 2nd question me 5 capacitor kaha gya??
26:07 factorisation mistakes sirrrrr😅
Ya
yup
Kase
Amazing yaar ❤🤩
5C/2 answer of 2nd question
Nice sir ji
9:52 answer 5C/2
9:54-
5C/2
Super skills❤
5C /2
Tomorrow is my exam 😢 I watch this today 😅
Today is my exam😎
33:40 pr balanced wheat stone bridge bhi to h to phir ye same valtage diff. wala concept kyun?
9:43 answer: 2.5C
Sir 5c/2 hoga second bale ka amswer
Very good👍 imp
Concept clear sir jee😊😊
14:08 sir mera bhe same aarha he par mane apne tution wale teacher ke thrah se kra hei
Sir 5C/2 is the correct answer of question 😊
Very useful 😊😊😊
answer for 9:55 5C/2
Sir pls make a video on all formulas of class 11physics in one video .
Sir ap humasa bolta ho jo ap log bologa usi pa ayaga video lets check .
5C/2 equivalent capacitance of q. 2
9:38 Answer is 5c/2 thankyou soo much sir 😊
If 19.12 it is not wheatstone bridge??
9:53 5c/2
Sir 26:25 minutes pa apne -12c+8c kiye h . Galat h .. q ki 12×8=96 aata h .. isliye waha pa -12c×4c=48 aana chaiye . Or -12c+4c=8c aaye ga .. I am right sir
bhai tu kiss exam ke liye ye vid dekh rha?
Zabardast.superb explanation
Thank you sir...
Second question ka answer 1/2+1+1=5c/2 sir