Размер видео: 1280 X 720853 X 480640 X 360
Показать панель управления
Автовоспроизведение
Автоповтор
2.10 2.2^5 1.2^1 2^1 (m ➖ 2m+1).
m= 1-1/3 ? 10 seconds.
64/27=(64/27)e^{i2jπ}, j any integer & i=√(-1); ∛(64/27)=∛(64/27)∛e^{i2jπ}=(4/3)e^{i2jπ/3}=(4/3)[cos(2jπ/3)+i*sin(2jπ/3)],j=0,1,2For m^3=(64/27), m_j=(4/3)[cos(2jπ/3)+i*sin(2jπ/3)],j=0,1,2
Thankyou
2.10 2.2^5 1.2^1 2^1 (m ➖ 2m+1).
m= 1-1/3 ? 10 seconds.
64/27=(64/27)e^{i2jπ}, j any integer & i=√(-1); ∛(64/27)=∛(64/27)∛e^{i2jπ}=(4/3)e^{i2jπ/3}=(4/3)[cos(2jπ/3)+i*sin(2jπ/3)],j=0,1,2
For m^3=(64/27), m_j=(4/3)[cos(2jπ/3)+i*sin(2jπ/3)],j=0,1,2
Thankyou