Every Planar Graph has a Vertex of Degree 5 or Less | Graph Theory

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  • Опубликовано: 25 авг 2024
  • Every planar graph has a vertex of degree 5 or less! We'll be proving this result in today's graph theory lesson. This is a result which follows quickly from the upper bound for the size of planar graphs - which is a corollary of Euler's formula for plane graphs. Links to proofs below.
    Our proof today will use the contrapositive - we'll assume a graph doesn't have a vertex of degree 5 or less - thus all of its vertices have degree at least 6. Then, using the first theorem of graph theory, we'll easily show such a graph must exceed the upper bound for the size of planar graphs - and thus is nonplanar. Hence, if a graph is planar, it must have a vertex of degree 5 or less.
    What are Planar Graphs: • What are Planar Graphs...
    Proof of Euler's formula: • Proof: Euler's Formula...
    Upper Bound for Size of Planar Graphs: • Proof: Upper Bound for...
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Комментарии • 33

  • @WrathofMath
    @WrathofMath  Час назад

    Support the production of this course by joining Wrath of Math as a Channel Member for exclusive and early videos, original music, and upcoming lecture notes for the graph theory series! Plus your comments will be highlighted for me so it is more likely I'll answer your questions!
    ruclips.net/channel/UCyEKvaxi8mt9FMc62MHcliwjoin
    Graph Theory course: ruclips.net/p/PLztBpqftvzxXBhbYxoaZJmnZF6AUQr1mH
    Graph Theory exercises: ruclips.net/p/PLztBpqftvzxXtYASoshtU3yEKqEmo1o1L

  • @teqnify63
    @teqnify63 3 месяца назад +3

    Dude that shirt is absolute fire

  • @PunmasterSTP
    @PunmasterSTP 2 месяца назад

    Initially I thought the way to prove this would be with contradiction, but I see how nicely contraposition works out here!

  • @shinelee4
    @shinelee4 3 года назад +4

    thank you so much for your videos! I want to kindly request a video on how to easily find (and draw) K33 or K5 configuration in the nonplanar graphs ! :) hope you have a good day!

  • @shizheli5344
    @shizheli5344 3 года назад +4

    literally the best math videos on youtude

    • @WrathofMath
      @WrathofMath  3 года назад

      Thanks so much, Shizhe - I do my best! Let me know if you ever have any questions!

  • @learnhome9659
    @learnhome9659 2 года назад +2

    Great lesson, Can we prove the same using Contrdiction

  • @gade28934
    @gade28934 3 года назад +1

    It's easy to understand! Thx so much!

    • @WrathofMath
      @WrathofMath  3 года назад +1

      No problem, glad to help! Thanks for watching and let me know if you ever have any questions. Check out my graph theory playlist if you haven't! ruclips.net/p/PLztBpqftvzxXBhbYxoaZJmnZF6AUQr1mH

    • @gade28934
      @gade28934 3 года назад

      @@WrathofMath Thx a lot !

  • @juancarlosgarciaaltamirano1305
    @juancarlosgarciaaltamirano1305 3 года назад

    Hello my friend, I need cite this result. Which article is the correct? Thank you.

  • @athenkosimagada
    @athenkosimagada 3 года назад

    Answered my question, thank you🙏🙏

    • @WrathofMath
      @WrathofMath  3 года назад

      You're welcome, I am glad it helped and thanks for watching!

  • @VinodKumar-ye7ii
    @VinodKumar-ye7ii 3 года назад

    Great video.

    • @WrathofMath
      @WrathofMath  3 года назад

      Thank you! Check out my graph theory playlist if you're looking for more! ruclips.net/p/PLztBpqftvzxXBhbYxoaZJmnZF6AUQr1mH
      Let me know if you ever have any video requests!

  • @karthiksiruvalam169
    @karthiksiruvalam169 3 года назад

    suppose , i will draw a regular hexagon and a vertex in the middle and join all the vertices to the middle one , now i have a vertex with degree 6, and planar .. can u please explain this ?

    • @WrathofMath
      @WrathofMath  3 года назад +3

      Thanks for watching and for your question! We have to be careful to make sure we understand the result correctly. We haven't proved that all vertices of any planar graph have degree five or less - that is not true, as your example shows. We proved that every planar graph HAS a vertex of degree 5 or less. In the example you gave, every vertex has degree 5 or less except for the one in the middle. Does that help?

    • @karthiksiruvalam169
      @karthiksiruvalam169 3 года назад

      thanks dude ❤️

  • @anujnarode3315
    @anujnarode3315 3 года назад

    how to prove this result for if G has k connected components?

    • @WrathofMath
      @WrathofMath  3 года назад +1

      Thanks for watching and if G is planar, then this result applies to each of G's components, so in fact such a graph would have at least k vertices of degree 5 or less.

    • @anujnarode3315
      @anujnarode3315 3 года назад

      @@WrathofMath Thanks a lot.

  • @joaovictorferreira3950
    @joaovictorferreira3950 Год назад +1

    Does this just only prove that you cannot have a graph with delta>=6; but at the same time, don't prove that a graph must have a vertex of degree 5 or less. I mean, the same logic could be used to prove that you can't have a graph with delta>=7 but this dont prove that you can have a planar graph with minimun degree of 6

    • @LearningCS-jp4cb
      @LearningCS-jp4cb 21 день назад

      this is exactly what i want to ask too, @WrathOfMath can you shed some light on this? We just said graph cannot have minimum degree >=6, nowhere its said 6 is least minimum degree from which graphs become non-planar.

  • @jayanthikamaraj7295
    @jayanthikamaraj7295 3 года назад

    Sir,Can u draw a graph for the degree of vertices is 5...

    • @WrathofMath
      @WrathofMath  3 года назад

      Thanks for watching and I am not sure what your question is. Are you asking for a graph whose vertices all have degree 5? A complete graph on 6 vertices fits that condition.

    • @jayanthikamaraj7295
      @jayanthikamaraj7295 3 года назад

      @@WrathofMath thanks for ur reply sir.

  • @light.236
    @light.236 3 года назад

    But there still some cases in which some vertices have degree greater than 5 and some have less than 5

    • @WrathofMath
      @WrathofMath  3 года назад +1

      Thanks for watching and indeed, every planar graph has a vertex of degree 5 or less, but there is nothing stopping them from having other vertices with a degree greater than 5. Consider a star graph with one center vertex that is adjacent to 100 other vertices!

  • @andrewnolan5958
    @andrewnolan5958 3 года назад

    Legend

  • @chelseafener1064
    @chelseafener1064 Год назад

    Sean baba kral video

  • @jahzeelreid5572
    @jahzeelreid5572 2 года назад

    draw it!!!!!!!!