Degree of a Face in a Plane Graph | Graph Theory

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  • Опубликовано: 28 окт 2024

Комментарии • 20

  • @nunu.g
    @nunu.g 9 месяцев назад +2

    I have discrete exam tommorow and you have no idea you just saved my life God bless u sir🙏🙏

  • @PunmasterSTP
    @PunmasterSTP 5 месяцев назад

    Those outros are so intense 😮

  • @gnagyusa
    @gnagyusa Год назад

    Cool explanation. Thanks! I've written a polygon mesh 3D boolean operation tool for my 3D software, and I'm always looking for new insights related to the field that might help me improve it.

    • @WrathofMath
      @WrathofMath  Год назад

      That's awesome! Thanks for watching and good luck with your work~

  • @SHASHANKRUSTAGII
    @SHASHANKRUSTAGII 3 года назад +1

    This is second handshaking lemma.
    watched NPTEL IISER PURE GRAPH THEORY LECTURES on this.

  • @emoprogramador8453
    @emoprogramador8453 Год назад

    You saved me, thanks for the video!!

  • @leolyo7
    @leolyo7 4 года назад +3

    Could you do a lesson on Chromatic Polynomials perhaps?

    • @WrathofMath
      @WrathofMath  4 года назад +4

      Thanks for watching and for the request! Some lessons on chromatic polynomials are in the works, I've got to do a bit more studying myself though, so they won't be out for a little longer.

  • @morganjones7428
    @morganjones7428 7 месяцев назад

    Thank you!!!

    • @WrathofMath
      @WrathofMath  7 месяцев назад +1

      You're very welcome! Thank you for the donation!

  • @divyatailor8269
    @divyatailor8269 4 года назад +2

    I have a doubt from sets:
    Given that if A is a subset of B, then C-B is a subset of C-A. Is the reverse proof true?

    • @WrathofMath
      @WrathofMath  4 года назад

      Thanks for watching and for the question! I might do a quick lesson on both statements. Like you said, if A, B, and C are sets, and A is a subset of B, then C - B is indeed a subset of C - A.
      The converse is, for sets A, B, and C, if C-B is a subset of C-A then A is a subset of B. This statement is not true because C-B being a subset of C-A, basically just means that B has more elements of C than A does. But it does not forbid A from having a bunch of other elements that C doesn't have. So B could equal C, for example, in which case C-B is the empty set and is thus certainly a subset of C-A, and A could be anything at all - it doesn't have to be a subset of B. Does that make sense?

    • @divyatailor8269
      @divyatailor8269 4 года назад

      @@WrathofMath Thank you sir

  • @tusharbarman1924
    @tusharbarman1924 3 года назад

    Great explanation.

    • @WrathofMath
      @WrathofMath  3 года назад +1

      Thank you! If you are looking for more graph theory, check out my graph theory playlist: ruclips.net/p/PLztBpqftvzxXBhbYxoaZJmnZF6AUQr1mH
      Let me know if you ever have any questions!

  • @gabrielpereiramendes3463
    @gabrielpereiramendes3463 4 года назад

    #Excelent!

  • @stevenshi9012
    @stevenshi9012 2 года назад +1

    shouldn't the deg(r2) = 6?

    • @WrathofMath
      @WrathofMath  2 года назад

      Correct, that's what I say in the video, but not at first. First I use the wrong definition of a region, to illustrate this common error in the definition and why the definition should be slightly different.