As a side note, by using the point to point mode of calculation, in the third circuit we can determine Vo only by using the silicon diode voltage barrier, 0,7 V, and the -10V point. Therefore, starting from Vo and going towards -10V, we have : Vo - 0.7V = -10V; Vo = -10V + 0.7V; Vo = -9.3V. In this way, we have reached the same answer without having to determine current Id! I understood the point to point calculation in this way : You start the equation with the node you're leaving from, writing it into the equation with the polarity that it has. Then, you follow whichever branch you want, as long as you reach to another point ( either another potential or ground ). You type in the equation the voltage drops you meet taking into account : The voltage drops which are headed towards the destination point will be written with minus ( minus sign of the voltage drop is near the destination, plus sign is far from it ), the ones which are headed in the opposite direction will be written with plus sign ( minus sign of the voltage drop is far from the destination, plus sign is near it ). Finally, after you reached the destination potential, you write the potential on the other side of the equal sign. Also, to keep in mind is that first you have to make sure that you write into the circuit the direction of where the currents are going, in which current always goes towards the lowest potential, which is minus rather than ground. This has been illustrated in circuit number one, where current seems to go from ground towards -5V ! ! !
yes the explanation at start was going from 1 point to other. but then he suddenly started going from ground (I know it can be considered as a point potential of 0V) but still it was confusing. not keeping the methods consistent or I should say not using the branch with two non ground point potential made it a little more difficult to understand. He should've given another example where he take Point A as ground instead of some arbitrary point A to be more clear in what he did in example 2 and 3.
Hello sir. In third case while finding current through the diode in that equation why didn't we wrote Vo in the equation like as we have assumed it nil there, why is it so?
Good day, sir! I was just confuse where to really start if you're getting the V_0. Both 1 & 3 equates to V_0. However, in #2 you start from V_0. Thank you!
Start from the higher potential. In first 0V is higher than -4.3V so we start from there while in 2nd question V0 is 4.75V so we start from there as it is higher than 0V.
Why have we considered -5v to Vo while calculating Vo in the first case, while we have considered +20V to 0v for second case, instead of considering till Vo?
the direction of voltage does not matter or what? because on the first example you started from ground to vnot , but the second example you stared from vo to ground does that differ?
you can start calculations from any side but final answer will be with some sign like positive or negative so if calculated i is positive then the current direction that you have assumed is correct , if it is negative then the direction of current will be opposite to what you have assumed
at 3:51. If we write Va+5V-6V-8V+15V-Vb=0 is this a wrong way of notation because I consider when current is entering at positive terminal then assign plus to the voltage.
8:20 2nd sum U have considered the current direction in a way that both diode will be FORWARD BIAS,,,,,,,but the negative terminal of silicon diode is connected to positive???? Then it shouldn't be forward right... Please helppp
My guess would be Vo is just a point. We are calculating the potential at that point. It is not a voltage source, so taking Vo into account is not needed. @Shruti
I have a question on the second model of the three.I think the equation should be like this:20V-0.7V-0.3V-2I-0.5*2I=0. Because the main current in the combined should equal to the sum of the two separate wires. As the voltage of the two powers on both sides should be equal. to each other. the current in both wires should be the same. could u pls try to explain t me.thx
1A becuase the two diode has no effect becuase even if the one is forward bias the other one neglects or I should say reverse so that it is open circuit not only the 10 volts and 10 ohms are there then use ohms law 10V/10R=1A
in 1st example how u can say the current going through thr resistor and the diode is same ???? i mean there can be some current coming from Vo potrntial
Vo potential point not potential difference and it is somewhere between resistor and diode. This is basicly a close circuit started from -5V and ended on ground. Also there is only one current which flows from resistor to diode because he picked up the direction of current that way and the result of current was positive. that means his first choice is correct.
@@tuna5653 Do not fool yourself and people. He made a mistake. The correct answer is that he should have considered a current 2Id instead of Id through the resistor.
At the last math to get Vo here 20 V,6.8 kohm and Vo - this combination has been applied. If i apply 6.8 kohm,Vo and diode and -10V then i get different ans.What is the right way of choosing combination for finding the voltage for a random point in circuit?
Because we don't take the point-potential value into account between the other two point-potentials. All we take is the potential drops or the potential differences between two potential points.
+Neso Academy In the last example why did not you consider taking Vnot in the KVL to calculate Id? u took all the voltage differences between 10v to 20 v right? Vnot is betn 10-20 v.
jayati saxena please learn the concept of making pn junction diode...you find the better idea.....if not...then I will explain you....in detail...I am not explain this time...bcz I don't want writing.....more..
why does he considers same current Id in example 2 and example 1 won't it be different?? it should be different when going through diode and resistance they are not connected in series are they?
Zhen Wang, I think he drew the circuit wrong. We have no idea how the two voltage points are connected to ground. They could be through resistors, batteries, even very complex circuits. They should be considered volt meter readings relative to ground only. In other words, the points in question do not affect the circuit. It's like they are connected to ground through very large resistors (i.e. they are volt meter readings).
Hello sir. I need your quick response, Would 10kv pass through the first 1kv diode in forward biased? in series of 10. 1kv diode. And Would 10kv block by the first 1kv diode in reverse biased?
I have a question in which there are two batteries and negative of one is connected to p side while negative of other is connected to n side. So is the diode on or off?
How come is the diode forward biased in the 1st example? The diode is connected to -ve terminal of Vo and to ground. Where from is +ve voltage obtained inorder to overcome the barrier potential? Please expain.
dead line I agree about current flowing from ground to -ve terminal but there's still some doubt regarding how potential barrier is overcome...Thanks anyway
Brother in3rd example 20+10-0.7÷6.8 Do not understand when 0.7 move from left to rigth it becom positive you write this negative. Please clear that point i don't understand??
Sir press help me with the 2 model My answer is not matching with yours..I solved the problem in alternate method..Like 20+0.7+0.3+2I+2I=0..Is it right..
the point Vo is in between the resistor and the diode. Hence, the equation you asked about is wrong. If we consider the other equation, it will be like: Vo - 0.7 = -10 , => Vo= -10+0.7 = -9.3
don't get confused buddy ..he messed up in the last video of series diode configuration...actually if the diode is in the ON state , the direction of the direction of the barrier potential will be in such way that it lowers the voltage drop further...that is why it is barrier potential.
Thank you for explaining this better 😌 my uni ain't got nothing on u 😍 ur the best
As a side note, by using the point to point mode of calculation, in the third circuit we can determine Vo only by using the silicon diode voltage barrier, 0,7 V, and the -10V point.
Therefore, starting from Vo and going towards -10V, we have :
Vo - 0.7V = -10V;
Vo = -10V + 0.7V;
Vo = -9.3V.
In this way, we have reached the same answer without having to determine current Id!
I understood the point to point calculation in this way :
You start the equation with the node you're leaving from, writing it into the equation with the polarity that it has.
Then, you follow whichever branch you want, as long as you reach to another point ( either another potential or ground ).
You type in the equation the voltage drops you meet taking into account : The voltage drops which are headed towards the destination point will be written with minus ( minus sign of the voltage drop is near the destination, plus sign is far from it ), the ones which are headed in the opposite direction will be written with plus sign ( minus sign of the voltage drop is far from the destination, plus sign is near it ).
Finally, after you reached the destination potential, you write the potential on the other side of the equal sign.
Also, to keep in mind is that first you have to make sure that you write into the circuit the direction of where the currents are going, in which current always goes towards the lowest potential, which is minus rather than ground. This has been illustrated in circuit number one, where current seems to go from ground towards -5V ! ! !
yes the explanation at start was going from 1 point to other. but then he suddenly started going from ground (I know it can be considered as a point potential of 0V) but still it was confusing. not keeping the methods consistent or I should say not using the branch with two non ground point potential made it a little more difficult to understand. He should've given another example where he take Point A as ground instead of some arbitrary point A to be more clear in what he did in example 2 and 3.
In question 3 , why he did not take Vo in the first case ?
Sir provided video in such a way that we clear our doubt thank you and we are very helpful
I have no words to express my thanks!
thank you so much sir you helped me a lot 😇⚘
thankyou so much ,you teach very well,i am very must satisfied with your videos
Amazing Sir. Please complete the playlist
I am very glad to see your channel. Many thanks for these useful information.
Hello sir. In third case while finding current through the diode in that equation why didn't we wrote Vo in the equation like as we have assumed it nil there, why is it so?
Thank you sir❤❤❤❤❤❤
May ALLAH bless you!!! it's really helpful
Thanks sir you help understanding all the concepts
Good day, sir! I was just confuse where to really start if you're getting the V_0. Both 1 & 3 equates to V_0. However, in #2 you start from V_0. Thank you!
Start from the higher potential.
In first 0V is higher than -4.3V so we start from there while in 2nd question V0 is 4.75V so we start from there as it is higher than 0V.
Awesome videos. Thank you so much👍
sir if we want to calculate Vd by using ohm law then the answer is 29.4... why?
Bro..danqu very much..😅😅
Why have we considered -5v to Vo while calculating Vo in the first case, while we have considered +20V to 0v for second case, instead of considering till Vo?
most probably because V0 was asked in third problem ,for your own convenience you can replace V0 by a point P and then can find potential at point P
I believe it is because 0v is at a higher potential than -5v maybe? Not totally sure. Current flows from high to low.
In 3rd case if we have Vo on 6.8k resistor how should we calculate Vo?
the direction of voltage does not matter or what? because on the first example you started from ground to vnot , but the second example you stared from vo to ground
does that differ?
you can start calculations from any side but final answer will be with some sign like positive or negative so if calculated i is positive then the current direction that you have assumed is correct , if it is negative then the direction of current will be opposite to what you have assumed
at 3:51. If we write Va+5V-6V-8V+15V-Vb=0 is this a wrong way of notation because I consider when current is entering at positive terminal then assign plus to the voltage.
8:20
2nd sum
U have considered the current direction in a way that both diode will be FORWARD BIAS,,,,,,,but the negative terminal of silicon diode is connected to positive????
Then it shouldn't be forward right...
Please helppp
is voltage across resistor always -ve ? and how to solve 2 diodes in series when one is off
In ex 3 you have left v0 and calculated value of Id ,I can't understand Lyk how could we leave a voltage point and take the next potential?
did u get the ans?
Same question!
My guess would be Vo is just a point. We are calculating the potential at that point. It is not a voltage source, so taking Vo into account is not needed. @Shruti
Sir 1st sums V0=5.7 and Id=2.59......please correct me if m wrong.
I have a question on the second model of the three.I think the equation should be like this:20V-0.7V-0.3V-2I-0.5*2I=0. Because the main current in the combined should equal to the sum of the two separate wires. As the voltage of the two powers on both sides should be equal. to each other. the current in both wires should be the same. could u pls try to explain t me.thx
the circuit is not parallel, the resistors are actually in series. Therefore the same current passes through both
Their are no two separate wires their is actually two loops out of which we have considered the first one
Why dont we consider current in both the loops to be different?
1A becuase the two diode has no effect becuase even if the one is forward bias the other one neglects or I should say reverse so that it is open circuit not only the 10 volts and 10 ohms are there then use ohms law 10V/10R=1A
Thank you!
in 1st example how u can say the current going through thr resistor and the diode is same ???? i mean there can be some current coming from Vo potrntial
Vo potential point not potential difference and it is somewhere between resistor and diode. This is basicly a close circuit started from -5V and ended on ground. Also there is only one current which flows from resistor to diode because he picked up the direction of current that way and the result of current was positive. that means his first choice is correct.
@@tuna5653 Do not fool yourself and people. He made a mistake. The correct answer is that he should have considered a current 2Id instead of Id through the resistor.
@@sarthakgirdhar2833 u r wrong.... Tuna is right
@@sarthakgirdhar2833 konse college ke ho ? .......
I think he made a mistake cause the circuit is connected
in question 1. incoming current equal to out going current(by kcl),so Ir=Id
Is the answer 1A?
At the last math to get Vo here 20 V,6.8 kohm and Vo - this combination has been applied. If i apply 6.8 kohm,Vo and diode and -10V then i get different ans.What is the right way of choosing combination for finding the voltage for a random point in circuit?
Thanks It IS the best
why was Vo not included in the equation used to find Id in the 3rd example?
Because we don't take the point-potential value into account between the other two point-potentials. All we take is the potential drops or the potential differences between two potential points.
+Neso Academy In the last example why did not you consider taking Vnot in the KVL to calculate Id? u took all the voltage differences between 10v to 20 v right? Vnot is betn 10-20 v.
Understood. Ur lectures are real gems. Thank you
in last eg why didn't you consider taking v not in kvl theorem??
+nishita sagta he already f**king answered the question.
how do u decide the polarity of diode when u replace it with a potential difference?
jayati saxena please learn the concept of making pn junction diode...you find the better idea.....if not...then I will explain you....in detail...I am not explain this time...bcz I don't want writing.....more..
@@sandeeptiwari3655 chutiye jab batahe nahi hai toh reply kyu kar rha hai
In the first example what is the difference from ID and the The darker green current you drew on top of the diode
why does he considers same current Id in example 2 and example 1
won't it be different?? it should be different when going through diode and resistance they are not connected in series are they?
Zhen Wang, I think he drew the circuit wrong. We have no idea how the two voltage points are connected to ground. They could be through resistors, batteries, even very complex circuits. They should be considered volt meter readings relative to ground only. In other words, the points in question do not affect the circuit. It's like they are connected to ground through very large resistors (i.e. they are volt meter readings).
you are right, but he is right too
In question3 , why did you not take Vo in the first case ??
In a question if direction of current is not given then how to figure out whether the diode is on?
You assume that the diode is on, otherwise stated in the problem.
Hello sir. I need your quick response,
Would 10kv pass through the first 1kv diode in forward biased? in series of 10. 1kv diode.
And Would 10kv block by the first 1kv diode in reverse biased?
Nice
Plzzz make videos on cmos
Thanks
Sir please redraw 3rd example by converting points to potential difference
I have a question in which there are two batteries and negative of one is connected to p side while negative of other is connected to n side. So is the diode on or off?
Depends upon which battery produces a higher voltage .
+Anees Muzaffar they have same emf
In that case , the potential across the diode is zero , hence no current flows .
sir thank u
How come is the diode forward biased in the 1st example? The diode is connected to -ve terminal of Vo and to ground. Where from is +ve voltage obtained inorder to overcome the barrier potential? Please expain.
I think the direction of current mentioned is somewhat incorrect.
dead line I agree about current flowing from ground to -ve terminal but there's still some doubt regarding how potential barrier is overcome...Thanks anyway
first example its a forward bias or reverse bias diode?
Forward biassed diode ..Because negative terminal of 5v is attached to the n type of diode...
If current across diode is not given how we will match with the arrow of the diode and check it is on or off
Sir so we can take any path for finding current n voltage acc to our convenience,can't we?
In the second problem, you substracted Amperes from Volts. How does that work?
in 2nd problem why did u considered the resistor which is also grounded
Same query
How did you solve it? Will you please explain it properly?
sir how can current flow through resistance as the circuit is incomplete?
Brother in3rd example 20+10-0.7÷6.8
Do not understand when 0.7 move from left to rigth it becom positive you write this negative.
Please clear that point i don't understand??
MULTIVIBRATORS USING IC-555 please upload
1st solution is wrong ....
Vo=4.3V
In the first question I think you are take wrong sketch current and voltage are in opposite directions..??
sir how will u get the ID? i try to solve dis on calculator 20v - 0.7 - 0.3 -2 -2 = 15? help please SOS asap
erick bongalon it's
20v-0.7-03-2Id-2Id=0
=>19-4Id=0
=>Id=19/4
=4.75
Nice teaching but fail to beat ekeeda teaching
Sir press help me with the 2 model My answer is not matching with yours..I solved the problem in alternate method..Like 20+0.7+0.3+2I+2I=0..Is it right..
it's voltage drop across the diodes -0.7 and -0.3
You take entering sign right....so you get -20+0.7+0.3+2I+2I
Now you will get the same answer...
there is no lecture in solving diode circuit using thevnin theorm please give a lecture on that plz
just awsome...
In the potential difference and potential at point why you use + signs between 5v, 6v and 8v in kvl except - sign.??? I do not understand this point.
Point - To - Ponder from position to negative it is a lost
from negative to positive it is a gain
i understand in that way
sir thanks for such a nice lectures,,May i contact you by phone ?
@@nesoacademy why dont the current divided at the nodes..........will the entire current goes in to ground
my question is how we will fix the polarity of the diode equivalent potential barrier
1.65 A
Sir,2kiloohm should be equal to 2*10to the power of 3 but you wrote it 2 ohm how is it possible?
Nice 👍 catching
For the last example how come we can't fin Vo like this Vo=6.8ID+.7-10 ???
the point Vo is in between the resistor and the diode. Hence, the equation you asked about is wrong. If we consider the other equation, it will be like: Vo - 0.7 = -10 , => Vo= -10+0.7 = -9.3
I am getting confused on how to draw the polarities of the barrier potential, its now different from how it was done in the previous presentation.
don't get confused buddy ..he messed up in the last video of series diode configuration...actually if the diode is in the ON state , the direction of the direction of the barrier potential will be in such way that it lowers the voltage drop further...that is why it is barrier potential.
@@anuraggadaria9408 Thank you
+Neso Academy In the second problem what if we replace the ground with a voltage +5 V ? does it make a difference aside from numbers ?
nah
@@SaminCrypted لو بكرت عليا اربع سنين كنت لساتي طالب و عندي مستقبل
@@r0n1n- eng please
in 1st example, why didn't the resistor affect the Vo if the current went at the resistor's way
(im in highschool btw)
I too have the same doubt
why negative to ground???
7:19
in your last question you din not consider silicon diode to calculate V0 this is wrong way.
Id in the first example must be negative
IN 3RD PROBLEM I=2.94mA
How
1amp ?
I think he made a mistake in case one he should also consider the current coming from Vo
Thanks