Correction: Please note this. At 4:48, for shunt regulator, the polarity of the inverting and non-inverting terminal should be reverse. That means the reference voltage should be connected to the inverting terminal (negative terminal) and voltage divider signal or feedback signal should be connected to the non-inverting terminal (positive terminal) Here is the link for the simulation: www.multisim.com/content/Hw2z9xwQRQwpTek2LesNqc/shunt-voltage-regulator/open/
ALL ABOUT ELECTRONICS Why don’t you put an annotation in the video ? If you have done it I wouldn’t be thinking to myself that the circuit was wrong the first time.
I wish I read the comment earlier. It took me a long time to prove that your explanation was wrong, not just your video, but most of the content online is incorrect!
@@ALLABOUTELECTRONICS , but when would you do it sir? Several months have spent and still nothing. I spent so much time figuring out that it was false and then I decided to read the comments and was happy to see that Iwas right... but many people may not look at the comments and will learn something wrong... you should modify it quickly sir.. But despite this, I enjoy your video and the nice details you give about the concept underneath component such as TL431 which appears to me as magical... I'm happy to at last understand it
You got the schematic wrong with the shunt regulator. If the circuit is constructed as is, it WILL NOT WORK. Let's say that R1=R2, the Zener diode is 3 volts, the output voltage is 5 volts, and the supply is 12 volts. The voltage on the inverting pin of the op-amp would be 2.5 volts and the non-inverting pin would be 3 volts. The op amp would turn the output on further, turning on the NPN transistor more and drawing the output even lower, which would reduce the voltage on the inverting input lower. The circuit as illustrated would be stable only at Vout=0 or Vout=Vin. Reverse + and - on the opamp to make the circuit actually work. (You got the series one right).
A voltage regulator is a circuit that maintains a constant voltage level. Linear regulators are a type of voltage regulator that use an op amp to maintain a constant voltage level. The op amp is connected as a comparator, and the reference voltage is divided by two and applied to the noninverting input. The output of the op amp is then connected to the inverting input, and the resistor R2 sets the output voltage.
The timestamps for the different topics covered in the video: 0:30 Why Voltage Regulator is Required (What is Load and Line Regulation ? ) 3:20 Basic block diagram of Series and Shunt Voltage Regulator 4:48 Design of Shunt Voltage Regulator using the op-amp 8:44 Design of Series Voltage Regulator using the op-amp 10:57 Simulation of Series Voltage Regulator using the op-amp
Your explanation resembles mere recital of what is written in text book. Can you explain why Vo= Vo'-Vbe in series voltage regulator? On what basis did you write that equation? HOW DOES the KVL APPLY IN THAT EQUATION?
The base current Ib is the current supplied by the op-amp. Since the op-amp is operating in the negative feedback, it will try to maintain the voltage at the inverting and non-inverting end. And accordingly, the op-amp will regulate the base current. I hope, it will clear your doubt.
Sir, I dont understand how 'the output voltage increases due to variation in load current'. Isnt it the otherway around. I thought it was current changes because potential difference changes. I also thought this way. Maybe load resistance can change (like we charge multiple phones using a junction box, we might remove some of them, so resistance of the entire load changes) leading to change in current acc. V=IR. But still, in that case V was constant. Kindly help with me with the *first line statement* .
The output voltage will change with the variation in the load. But when there is no load then output voltage will be maximum and as the load current increases, then voltage will reduce. And as I mentioned in the video, it is defined using the load regulation. As the load current demand increases, the current drawn from the source will also increase. And hence, there will be more drop across the series resistance of the source. That's why there is a drop in the voltage as the demand (load current) increases. I hope, it will clear your doubt.
Great video, an excellent circuit description, thankyou very much, just wondering i have built a few of these circuits and sometimes they appear to be unstable, would placing a pico farads capacitor between the op amps output and the non-inverting input help solve the problem, by slowing down the op amps bandwidth. Anyway thanks again, please keep it up.
sir, i have a doubt... you said to reverse the polarity and and feedback signal to be connected to postive terminal... then it will be positive feedback right?? then virtual short wont be there... isnt it??
Yes, there is positive feedback to the op-amp, but as an overall circuit( with transistor), there will be negative feedback. For example, as the output voltage increases, more voltage will be there at the non-inverting terminal at the op-amp. Which will drive the transistor harder (due to increased op-amp output). So, base current increases, and hence collector current increases. Now, as the collector increase, the voltage drop across Rs increases and output voltage reduces (And also the feedback voltage). So, as an overall circuit, there is negative feedback and won't drive the op-amp into saturation. And as far as op-amp is operated in the linear region, the concept of virtual short/ground is applicable. I hope it will clear your doubt. You can also check the simulation file I have provided in the pinned comment for more information.
Is the shunt regulator with the opamp considered "low noise"? Would this circuit have a lower noise output than a typical LM317 regulator circuit? I ask because I plan to use it for sensitive audio design.
Sir your video are great..... But as some off us are not from electronic filed and may some times visit your explanatory video just for a basic concept of the working principle of electronic and various components... Sometimes theory bounces off of our head..... While exploring about electronic i came cross a channel name RSD ACADEMY..... There he explain every concept in very very simple way as if he is explaining in to a 3 year old child..... I would like you to make videos in similar fashion.. So that concept nd the fundamental rules gets clear without scratching our damn head out....
@ALL ABOUT ELECTRONICS Is it possible to directly feed the AC supply voltage to the voltage regulator without passing it through the rectifier and filter? I'm asking this because I'm planning to generate a PWM signal through 555 timer and I want to feed the AC supply to the Vcc pin of the IC after passing it through the voltage regulator.
Sir please make videos on h parameter model , EMT uniform plane waves and transmission lines and ;7 layer architecture and digital communication noise topic.
Just because you don't understand the content, doesn't mean you gotta be rude about it. He learned a second language, you could at least meet him half way and learn to understand his accent.
Correction: Please note this.
At 4:48, for shunt regulator, the polarity of the inverting and non-inverting terminal should be reverse.
That means the reference voltage should be connected to the inverting terminal (negative terminal) and voltage divider signal or feedback signal should be connected to the non-inverting terminal (positive terminal)
Here is the link for the simulation: www.multisim.com/content/Hw2z9xwQRQwpTek2LesNqc/shunt-voltage-regulator/open/
ALL ABOUT ELECTRONICS Why don’t you put an annotation in the video ?
If you have done it I wouldn’t be thinking to myself that the circuit was wrong the first time.
@@justpaulo Yes, I will do it. In fact, that would be helpful to everyone.
No wonder I feel strange, ha ha
Will you make video on all kinds of logic gates circuit using opamps?
I wish I read the comment earlier. It took me a long time to prove that your explanation was wrong, not just your video, but most of the content online is incorrect!
@@ALLABOUTELECTRONICS , but when would you do it sir? Several months have spent and still nothing. I spent so much time figuring out that it was false and then I decided to read the comments and was happy to see that Iwas right... but many people may not look at the comments and will learn something wrong... you should modify it quickly sir..
But despite this, I enjoy your video and the nice details you give about the concept underneath component such as TL431 which appears to me as magical... I'm happy to at last understand it
You got the schematic wrong with the shunt regulator.
If the circuit is constructed as is, it WILL NOT WORK.
Let's say that R1=R2, the Zener diode is 3 volts, the output voltage is 5 volts, and the supply is 12 volts.
The voltage on the inverting pin of the op-amp would be 2.5 volts and the non-inverting pin would be 3 volts.
The op amp would turn the output on further, turning on the NPN transistor more and drawing the output even lower, which would reduce the voltage on the inverting input lower. The circuit as illustrated would be stable only at Vout=0 or Vout=Vin.
Reverse + and - on the opamp to make the circuit actually work. (You got the series one right).
Yes, that's true. Thanks for the correction.
Yes, exactly the schematic shown is incorrect.
Exactly bro....
Very helpful tutorial. I hope to see the video of regulators using opamp and MOSFET. Thanks
A voltage regulator is a circuit that maintains a constant voltage level. Linear regulators are a type of voltage regulator that use an op amp to maintain a constant voltage level. The op amp is connected as a comparator, and the reference voltage is divided by two and applied to the noninverting input. The output of the op amp is then connected to the inverting input, and the resistor R2 sets the output voltage.
The timestamps for the different topics covered in the video:
0:30 Why Voltage Regulator is Required (What is Load and Line Regulation ? )
3:20 Basic block diagram of Series and Shunt Voltage Regulator
4:48 Design of Shunt Voltage Regulator using the op-amp
8:44 Design of Series Voltage Regulator using the op-amp
10:57 Simulation of Series Voltage Regulator using the op-amp
Your explanation resembles mere recital of what is written in text book. Can you explain why Vo= Vo'-Vbe in series voltage regulator? On what basis did you write that equation? HOW DOES the KVL APPLY IN THAT EQUATION?
Nicely explained and the membership is also very useful 👌🏼👌🏼
your videos are very educational, been learning so much new from you. thank you for sharing the knowledge
Yes bro, he is explaining well....
really really great way to teach sir
Really helpful for RRB JE Exam... thanks Sirji...
Very beutefull thank you but some disadvantages is that the op amp it need external power supply
Nice video for interested
I really want to know more about ICs and regulatirs
Your videos and explanation are very helpful! Just only one feedback is to increase the cursor size. It is a bit difficult to spot it
Thanks for the suggestion. It has been considered and has been increased in the recent videos.
Can you explain why if the voltage output increases then the Ib will also increases ?
Sir thanks for the great video !
The base current Ib is the current supplied by the op-amp. Since the op-amp is operating in the negative feedback, it will try to maintain the voltage at the inverting and non-inverting end. And accordingly, the op-amp will regulate the base current. I hope, it will clear your doubt.
Sir, I dont understand how 'the output voltage increases due to variation in load current'.
Isnt it the otherway around. I thought it was current changes because potential difference changes.
I also thought this way. Maybe load resistance can change (like we charge multiple phones using a junction box, we might remove some of them, so resistance of the entire load changes) leading to change in current acc. V=IR.
But still, in that case V was constant. Kindly help with me with the *first line statement* .
The output voltage will change with the variation in the load. But when there is no load then output voltage will be maximum and as the load current increases, then voltage will reduce. And as I mentioned in the video, it is defined using the load regulation. As the load current demand increases, the current drawn from the source will also increase. And hence, there will be more drop across the series resistance of the source. That's why there is a drop in the voltage as the demand (load current) increases. I hope, it will clear your doubt.
thank you, sir, for this séries of op-amp I learned a lot of things about op-amp
You videos are awesome! Can you also make a video on zero crossing detector?
PLEASE UPLOAD THE ENTIRE COURSE VIDEOS .
Great video, an excellent circuit description, thankyou very much, just wondering i have built a few of these circuits and sometimes they appear to be unstable, would placing a pico farads capacitor between the op amps output and the non-inverting input help solve the problem, by slowing down the op amps bandwidth. Anyway thanks again, please keep it up.
Thanks for sharing ur knowledge sir....the priceless one
Absolutely Superb 👌 👌
for the series regulator, why do we need the transistor?
sir, i have a doubt... you said to reverse the polarity and and feedback signal to be connected to postive terminal... then it will be positive feedback right?? then virtual short wont be there... isnt it??
Yes, there is positive feedback to the op-amp, but as an overall circuit( with transistor), there will be negative feedback. For example, as the output voltage increases, more voltage will be there at the non-inverting terminal at the op-amp. Which will drive the transistor harder (due to increased op-amp output). So, base current increases, and hence collector current increases. Now, as the collector increase, the voltage drop across Rs increases and output voltage reduces (And also the feedback voltage). So, as an overall circuit, there is negative feedback and won't drive the op-amp into saturation. And as far as op-amp is operated in the linear region, the concept of virtual short/ground is applicable.
I hope it will clear your doubt. You can also check the simulation file I have provided in the pinned comment for more information.
@@ALLABOUTELECTRONICS thank you for clearing my doubt. thank you so much sir
Exactly ....
What happens when Vin increases in a shunt voltage regulator
Thanks for Sharing 👌
hello sir, need to be add current regulator link in description box
Is the shunt regulator with the opamp considered "low noise"? Would this circuit have a lower noise output than a typical LM317 regulator circuit? I ask because I plan to use it for sensitive audio design.
What is the power requirement ? I mean how much current the load is going to draw ??
@@ALLABOUTELECTRONICS It is a preamplifier for a microphone. It draws 24 Volts and a constant current of 150mA.
Thank you. Great video.
Sir your video are great..... But as some off us are not from electronic filed and may some times visit your explanatory video just for a basic concept of the working principle of electronic and various components... Sometimes theory bounces off of our head..... While exploring about electronic i came cross a channel name RSD ACADEMY..... There he explain every concept in very very simple way as if he is explaining in to a 3 year old child..... I would like you to make videos in similar fashion.. So that concept nd the fundamental rules gets clear without scratching our damn head out....
What is the name of application used in the Simulation part?
Multisim
I have a confusion. In shunt topology the output sampled voltage or V- should be provided to the non inverting input of the op amp.
Superb video Sir. Keep on the great work. I do not regret subscribing. 😃
Thank you Sir
Ty
Sir,have u done any videos on communication engineering like modulation techniques and about antennas
No it is yet to be covered.
@ALL ABOUT ELECTRONICS Is it possible to directly feed the AC supply voltage to the voltage regulator without passing it through the rectifier and filter? I'm asking this because I'm planning to generate a PWM signal through 555 timer and I want to feed the AC supply to the Vcc pin of the IC after passing it through the voltage regulator.
No, it will not work, you can try a triac, with gate fed with a square wave signal (not a pulse)....
thanks sensie
Nice😃
Do you have the link for the simulation of series voltage regulator?
Hey, please make video on ic 317,337,723
Sir please make videos on h parameter model , EMT uniform plane waves and transmission lines and ;7 layer architecture and digital communication noise topic.
PLEASE MAKE VIDEOS ON PLL, ACTIVE FILTERS, DAC, TIMERS ...
I have already made videos on ADC/DAC, active filters and 555 timers and oscillator. You can check the playlist on channel page.
Hello Shristi, I had uploaded all these videos in my channel...
superb sir
The circuit can oscillate. It depends on the capacitors of the input and output voltage. Use a little capcitor between C and B of the transistor.
Simulation kaise kia...plz provide a video. Vay,yeh project kar rhe hlp us.
Plz simulation design k video provide kro.
Can anybody please explain to me what is Rs? Is this a resistor or is it the nomenclate for the shunt regulator?
It’s a series resistor.
Hello sir How to find Vrpp at load ?
You mean practically how to find it ??
Thanks❤🎉🎉🎉
Thanks
name of simulator? looks good to practice
Its multisim live. It's online free version of the multisim.
The first circuit confused the heck out of me...there are other way better regular designs and the OP AMP probably cost more money.
Please make video in Hindi
it would be better if we could understand what he's saying!
realty in this not working..
Which opamp and bjt you have used in your design ? Can you share the details?
can you do this video in English please?
Are you deaf? It is in English. The man just has an accent, troll
Just because you don't understand the content, doesn't mean you gotta be rude about it. He learned a second language, you could at least meet him half way and learn to understand his accent.