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Much appreciated sir😊
Thank you, Prof!
3.25: V_l=(10V_i-1800)/211, you have sign mistake here it must be V_l=(10V_i + 1800)/211, i.e., plus sign
I was also thinking about that for a couple of minutes.
Can we think that the Zener knee current is the same as the breakdown current of the Zener diode ?
Much appreciated sir😊
Thank you, Prof!
3.25: V_l=(10V_i-1800)/211, you have sign mistake here it must be V_l=(10V_i + 1800)/211, i.e., plus sign
I was also thinking about that for a couple of minutes.
Can we think that the Zener knee current is the same as the breakdown current of the Zener diode ?