This is awesome! A lot of proofs just use the product rule and chain rule but you do it from the definition of a derivative, which is a lot more informative.
it's the same. He's using it to "add zero" to the equation, but in doing so, allows him to create the two difference quotients that become the g'(x) and f'(x) parts in the denominator.
This is awesome! A lot of proofs just use the product rule and chain rule but you do it from the definition of a derivative, which is a lot more informative.
Thank you!
Thank you so very much. Needed to know this proof for an upcoming exam. Your clarity really helped me so much.
your video is so awesome, i really like to go deeper in the way people have created formulas instead of just accepting and applying them only
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I can't thank videos like this enough.
Thank you.
But what happens if you write:
+ f(x)g(x) - f(x)g(x)
instead of: - f(x)g(x) + f(x)g(x)
Like why is the answer not equal?🤔
it's the same. He's using it to "add zero" to the equation, but in doing so, allows him to create the two difference quotients that become the g'(x) and f'(x) parts in the denominator.
Best explanation. You are a legend sir.
Absolutely excellent explanation, you are doing incredible work that helps a lot of people. Certainly a life goal.
Thank you for such a kind comment. It is greatly appreciated!
Soo neat and clear. Love it👌🏼
Thanks alot this really helped.
I found it very helpful. Thanks!
If we have to add and subtract to prove the Quotient Rule then how does this prove the equation works?
Where’d you get f(x)g(x)
Perfect.
Valeu!
Thank you very much for the super thanks! Your support is very much appreciated.
Ok but too many repetitive steps and gets rid of g(x).h in the final denominator by making h=0.
Very good explanation.
A loved your explanation thankssss
Thank you. Good work.
Thanks!,very well explained.
Thanks Professor.
amazing video
Thank you
thank you ✨
❤❤❤❤❤❤❤ keep going
Wonderful
Respect
thaaaaaaaanks
slappy mouth noises. im out....😖