E/Z Isomerism Explained

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  • Опубликовано: 17 окт 2024
  • Professor Davis goes over a quick introduction to E/Z isomerism in alkenes, including an explanation of the Cahn-Ingold-Prelog ranking convention.

Комментарии • 50

  • @davros1996
    @davros1996 10 лет назад +7

    As someone who is currently studying in France, this is an absolute life-saver for my exams next week. Thank you!

    • @ChemSurvival
      @ChemSurvival  10 лет назад +2

      I am so glad that you found the video useful. Please subscribe to the channel, share with your classmates and come back for more videos!

  • @Anna-wt7je
    @Anna-wt7je 9 лет назад +7

    thankyou so much i thought this was way harder than it actually is

  • @ChemSurvival
    @ChemSurvival  11 лет назад +1

    Thanks, Hasan. Don't forget to subscribe, tell your friends and keep coming back! New videos are going up all the time!

  • @MiltRodgers
    @MiltRodgers 11 лет назад

    Thank you so much. Yours is the most systematic and the clearest explanation I've seen.

  • @tresenpartychef1891
    @tresenpartychef1891 9 лет назад +1

    I'm german and I have learned so much more than from all the videos that exist in german. Thanks for that^^

    • @ChemSurvival
      @ChemSurvival  9 лет назад

      +Tess Partschev I'm so glad it helped!

  • @Davidlee-ps5nx
    @Davidlee-ps5nx 10 лет назад +1

    Cannot be more clear; this is much better than Khan academy.

  • @7D7N7A7
    @7D7N7A7 8 лет назад +3

    Thank you very much... This Video helped a lot... Using animation helps the student to understand better... Thanks a lot again

  • @ChemSurvival
    @ChemSurvival  11 лет назад +2

    Hi Milt. I'm glad you found the video useful! You know the drill... please subscribe, like and pass the channel on!

    • @ZAsym
      @ZAsym 4 года назад

      semen of a male fish

  • @DavideousIII
    @DavideousIII 10 лет назад +1

    What if your 2 higher priority groups were both on the left side (or right) of the double bond? Would it still be Z, the same?

    • @ChemSurvival
      @ChemSurvival  10 лет назад

      Hi David. This simply isn't possible. We only consider one carbon at a time. So you are finding the higher priority substituent of the two on a carbon, then the higher priority of the two on the other side. We do not compare groups one on carbon with another for prioritization.

  • @zakicadde1
    @zakicadde1 10 лет назад +2

    Good video, at 7:46 why would two carbons count from the double bond.

    • @ChemSurvival
      @ChemSurvival  10 лет назад +2

      Hi zakicadde1. This is by convention. Cahn, Ingold and Prelog made that call nearly a century ago and we have stuck to it ever since. Any time a double or triple bond is analyzed in the CIP scheme, the connected atom always counts as two or three, respectively. Thanks for the question!

  • @7amido12
    @7amido12 9 лет назад

    Very helpful, I didn't understand the concept before. Thank you for your effort :)

    • @fddvdh5949
      @fddvdh5949 8 лет назад

      زين اشرحهه الي بالعربي اني ما فهمت عليه لو سمحت 😟

    • @fddvdh5949
      @fddvdh5949 8 лет назад

      زين اشرحهه الي بالعربي اني ما فهمت عليه لو سمحت 😟

    • @fddvdh5949
      @fddvdh5949 8 лет назад

      زين اشرحهه الي بالعربي اني ما فهمت عليه لو سمحت 😟

    • @fddvdh5949
      @fddvdh5949 8 лет назад

      زين اشرحهه الي بالعربي اني ما فهمت عليه لو سمحت

    • @fddvdh5949
      @fddvdh5949 8 лет назад

      زين اشرحهه الي بالعربي لأن ما فهمت عليه لو سمحت😟

  • @bixstar1469
    @bixstar1469 5 лет назад

    very coherent explanation

  • @7D7N7A7
    @7D7N7A7 8 лет назад +1

    You made the E-Z easy :)

  • @tarunjudepereira6231
    @tarunjudepereira6231 7 лет назад

    ohhh dude this was just what i needed.thx

  • @fj19981
    @fj19981 8 лет назад

    Great tutorial by the way the systematic name for the compound in 6:56 is E-4ethyl,3,5dimethyl, hex-3-ene is it?

    • @ChemSurvival
      @ChemSurvival  8 лет назад

      +Dr. Fhood That looks right to me! Lowest number to the functional group and lowest set for substituents!

    • @fj19981
      @fj19981 8 лет назад

      ChemSurvival
      ok thanks
      :)

  • @TheMedavia
    @TheMedavia 10 лет назад

    YOU SAVE MY LIFE THANK YOUUUUUU

  • @stsfoxfacel9171
    @stsfoxfacel9171 10 лет назад

    At 0:54, aren't the bottom two molecules supposed to be enantiomers? (you say they are the same)

    • @ChemSurvival
      @ChemSurvival  10 лет назад

      not sure I understand the question. There are three examples on that slide. The top two pairs are identical. The bottom pair is a set of stereoisomers.

  • @saraemad6292
    @saraemad6292 4 года назад

    Excellent 👌

  • @akshitagupta4938
    @akshitagupta4938 4 года назад

    this was amazing. thanks alot!!!

  • @TrollinJoker
    @TrollinJoker 9 лет назад

    This is great!

  • @JS-ls5mh
    @JS-ls5mh 8 лет назад

    thank you soooo much finally i got it! i wish if my lecturer was like you lol

    • @ChemSurvival
      @ChemSurvival  8 лет назад

      +Rohan Ullah I'm so glad it helped you, Rohan! Thanks for watching and please subscribe to the channel and checkout my Foundations of Organic Chemistry course with The Great Courses at www.thegreatcourses.com

  • @bartieberthrapp6362
    @bartieberthrapp6362 5 лет назад +1

    Thanks 🙏

  • @miguelgalarza5742
    @miguelgalarza5742 10 лет назад +1

    Perfect!

  • @rimeln6443
    @rimeln6443 10 лет назад

    thankss! :) ur a life saver

  • @thunchan14
    @thunchan14 10 лет назад

    Thank u soo much 🙌😃

  • @lolabella3555
    @lolabella3555 10 лет назад +3

    Thaaaaank UUUUU!!

  • @WhoaBoost
    @WhoaBoost 10 лет назад +1

    ty

  • @28.mdareeb73
    @28.mdareeb73 6 месяцев назад +1

    In India we call it cis and trans insomers

  • @rassimsimou1594
    @rassimsimou1594 Год назад +1

    Good

  • @shabnamansari3826
    @shabnamansari3826 6 лет назад

    Thanx

  • @KineticReef
    @KineticReef 11 лет назад +1

    Hello TCS students!

  • @ZAsym
    @ZAsym 4 года назад

    E

  • @hasan23452345
    @hasan23452345 11 лет назад

    good