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Pls sir, the is a mix up somewhere,they told us that if the acceleration due to gravity is not given we should use the normal value which is"9.81"
It a constant value
@@ExcellentlinkAcademy but they said is only for O/L sir
Thank u so much sirAnswer =13.478
Thanks you sir.
You are welcome
R= 1353.16m Well underatood ... thank you so much sir ... God bless you
Correct
1353 thanks
You are welcome and correct
Mi answer for range is 1352.16m
Thanks Correct
What about trajectory
Consider much more later
Am answer is 1353.157
Good
Reply us please
I have
R=1353.160
1353.168
Time of flight is suppose to be 2usinx/g
No, check your Physics text book time of flight is usinx/g While Total Time of flight is 2usinx/g
R= 82.6m
R = 1353.16 m
@@ExcellentlinkAcademy thanks you
Time of flight is 2u sin tia/g
It is (u sin Tia/g) for time of flight For total time of flight it is 2u sin Tia/g
1353.6
0.09578 m
R = 1353.16m
Pls sir, the is a mix up somewhere,they told us that if the acceleration due to gravity is not given we should use the normal value which is"9.81"
It a constant value
@@ExcellentlinkAcademy but they said is only for O/L sir
Thank u so much sir
Answer =13.478
Thanks you sir.
You are welcome
R= 1353.16m
Well underatood ... thank you so much sir ... God bless you
Correct
1353 thanks
You are welcome and correct
Mi answer for range is 1352.16m
Thanks Correct
What about trajectory
Consider much more later
Am answer is 1353.157
Good
Correct
Reply us please
I have
R=1353.160
Correct
1353.168
Good
Time of flight is suppose to be 2usinx/g
No, check your Physics text book time of flight is usinx/g
While Total Time of flight is 2usinx/g
R= 82.6m
R = 1353.16 m
@@ExcellentlinkAcademy thanks you
Time of flight is 2u sin tia/g
It is (u sin Tia/g) for time of flight
For total time of flight it is 2u sin Tia/g
1353.6
Correct
0.09578 m
R = 1353.16m
R=1353.160
Correct