Equations of Projectile Motion in Physics Explained - [1-4-6]
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- Опубликовано: 16 авг 2022
- More Lessons: www.MathAndScience.com
Twitter: / jasongibsonmath
In this lesson, you will learn what the equations of projectile motion are and how to use them in physics. Projectile motion refers to an object moving in two dimensions (vertically and horizontally) under the effect of a gravitational force. Projectile covers the motion of balls and rockets flying in space or in the atmosphere, as well as the motion of a thrown rock or other object. The equations of projectile motion allow is to predict the position and velocity of an object at an point in the future along its trajectory after the motion begins..
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As someone who is learning both mathematics and physics on my own at 39 years old, your instruction is by far, my favorite. Thank you for your passion to teaching and creating these videos.
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Ja sam ovo učio pre 50 godina (osnovna , srednja, faks)... i dan danas sam u ovim sferama nauke... I studied this 50 years ago (primary, high school, college...)... and to this day I am in these spheres of science... Very well video! Thanks
As a former active duty USMC artillery officer, you just made my year by publishing this video. I studied physics at the Naval Academy before I was commissioned and then attended the Field Artillery Officers' Basic Course at Fort Sill after I graduated from The Basic School for Marine officers at Quantico. This video brings back a lot of memories and is inspiring me to relearn trigonometry and calculus. Thank you!!!!!!
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He answers the part that the books do not reveal at all . I love watching these lectures. Thankyou sir
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Excellent lesson. I have always been interested in the motion of an object in a gravitational force field since my college days of studying orbital mechanics.
Thank you for making this video, I really don't like math that much but when I am watching your videos is making me start liking math again. Cause I use to like math but I don't like it anymore even though we use it every day! I bet your students likes you for teaching them! Thanks a lot for the videos man!. You are a very good teacher, God bless you
Honestly Thank You so much!! Best teacher to explain it simply to me.
Out of all videos that Ive watched, this one's the only one that made me understand this topic😭
Most videos are leaned into the 'memorizing' part and never the 'understanding' part. Which is why I really loved your video more💕
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Super! Outstanding teaching skills. It's amazing to see how physics, trig and calculus are connected together to understand/interpret a physical phenomena
Hi '
This is helping me to explain to my Grandson of projectile in his physics class. Keep up the good work there are a lot of people out there that wish you were their teacher in school.
Thank you sir , it was crystal clear but can u cover the other equations like 'time of flight' , 'range' , 'maximum height' and 'equation of trajectory' ?
Well another helpful lesson, helping me fill the gaps in my distance learning degree material in engineering. Don't suppose you have any books you'd recommend for someone studying engineering ?
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Great video, very clear, thank you.
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Wow ! That's is amazing . So If I shoot a high power bullet velocity, at say 4000fps the bullet will hit the ground at the same time as if I was to just drop it from the same height at 0 velocity. That is difficult to understand. But this is true .however, you would have to drop the bullet from the top of the arch hieght. Excellent teaching. I've purchased 2 of your DVDs about 6 years ago. Great to see that your still teaching
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Mr. Jayson, from your videos on resolution of forces and trigonometry, I had sensed what might be happening in projectile motion before I watched your this video. Anyways I would like to genuinely thank you for your commitment!
I do have a question in my mind regarding the acceleration in the x direction that why the acceleration in the x direction was not included or mentioned in the video that was applied in the first place by the person hurling the object in projectile motion. I mean there has to be an acceleration because a force was applied otherwise there wouldn't be any motion in the x direction, or was it so negligible that we ditched it completely?
I don't know enough English, but I understood you better than my professor who speak the same language than me.
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This man lecture is funny and at the same time very understanding
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Enjoyable lecture
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Thank you so much enlightening
You are so welcome
I have a comment you should tell the students, that the Sign of G, depende on your frame of reference, or datum. If your on top of a platform throwing kicking or dropping a ball, you could use G as positive, but if it's on the ground then you could use Y as positive up and then G will be negative, so it all depends on your frame of reference, and the equations as well will change. Gravity always points down, so if you choose your frame of reference for Y positive up, your G will be negative, if you use your frame of reference for Y positive down, your G will be positive as well. But you put such passion in what you are doing, thar you are truly a great professor. I congratulate you. I wish I had while I was in College professor like you.
Can you please create videos for BioChemistry. I am not able to find a good video for Biochem. Math and Physis chemistry you are best. Please create biochem also.
2nd equation is confusing cus the equations of motion I w know are
V = U + at
V² = U² + 2aS
S = Ut + ½at²
S = ½(U+V)t
Where S is the distance
V is final velocity
U is initial velocity
a is acceleration
❓
You are right, but this is where you have missed it.
S=ut+1/2at^2.
S in the above equation is change in displacement, which can be replaced as Xf-Xi.
Substituting the above for S you will now have
Xf-Xi=ut+1/2at^2 (making Xf the subject of the formula you will now have)
Xf=Xi+ut+1/2at^2.💯💯💯
Thank you! C:
Thank you. Please allow the cc, the auto subtitle.
32 feet per second per second.
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Sir, why is the acceleration negative?
Thank you so much for this amazing video😊 I've been struggling and your explanation really helped💙 Thank you very very much
Billy Mays did physics?
I love you
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It is nice to hear a US tutor use the metric system of measurements as opposed to imperial system of measurements 😀
What's the imperial system
@@akinyelemorounfoluabdurahm5005 it is the older system of measurements, uses feet, yards, miles, gallons, pounds and so on. For a comprensive explanation, Google for the answer.
How are you
I’m good how are you doing?
Hello
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Zoooooper
What language are you typing in?
te pup 😘
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we all know that a projectile trajectory (on earth) is never a parabola
Realno, zato što postoji otpor kretanju projektila (trenje u vazduhu), stoga je trajektorija modufikovana faktorom e^-kt, (k zavisi od otpora sredine). Realistically, because there is resistance to the movement of the projectile (friction in the air), therefore the trajectory is modified by the factor e^-kt, (k depends on the resistance of the medium).
@@josip.harasic The "resistance of air" depends on a lot of parameters including the form of the projectile, its bearing, on the velocity itself (supersonic or not)... In any case it can't be neglected, we never assume that a trajectory is parabolic, unless you do not care about killing people far from your target.
@@gide5489 That´s right, absolutely...👍
What language are you typing in?
@@YujiuWang-qc8bn Bosnian ?
As usual the diagram is grossly misleading. Firearms books use this almost exact demo to explain the path of a projectile from a firearm. The correct path is a drooping arc with the droop rapidly steepening as it gets further form the gun. Books show the projectile traveling through the path described here and much of the firearms community believe a projectile leaves the muzzle and rises above the "line of departure". This is not so.
I’m not sure what you’re going on about but I never mentioned firearms in this lesson. The diagram is not misleading, the diagram is that of throwing an object up from the ground at an angle that is why it rises up and then comes down.
@@MathAndScience Firearms publications are full of misconceptions concerning the path of a projectile after leaving the barrel. Most people believe the projectile rises---when it does not and it is because of diagrams as we see here. All firearms publications use this same diagram to explain the behavior of a projectile. The original path of the projectile would be "line of departure" which it never gets above. Would you discuss this and clarify the confusion?
@@MathAndScience Understood. This is a good explanation.
Abdul is learing
What language are you typing in?
The word "parabola" comes from the Arabic language.
Parabola comes from the Arabic language.
he should explain gailei transformations