In order to separate the load from the utility ground. Like this you can create an ungrounded circuit. This is either done to reduce the risk of electric shock or to avoid short circuiting measurement setups.
Thank you for your explanations and I also like the software that you use, I am about to try that one, thank you for sharing the name for it. Everycircuit
It was mentioned that due to the frequency, f = 0 for DC supply, hence the net impedance of the circuit becomes merely resistance, R. However, since f = 0, isn't that the capacitive reactance that is inversely proportionate to f would become infinite and the resultant impedance, Z would become infinite also? Appreciate if someone could shed some light...
In a HVAC line,since there is only a resistance in the wire and there is no connection of capacitor and inductance,why your considering inductive reactance and capacitance?
Sir, First of all impedance is given by Z=R+j(Xl-Xc) not R+Xl+Xc(j denotes phasor and it is very important in AC quantities), and secondly the value of Xl i.e. leakage reactance is also very low, the transformer is designed such that it has less leakage flux so that the Voltage regulation value can be minimized. So, you cannot justify by saying that becuase in DC Xl=0 therefore current will increase, it is not the valid explanation. Explanation: Apply KVL in primary side u will get V=i(t)R+Ldi(t)/dt Where V is the supply voltage And L is the inductance of primary coil. Apply laplace and solve i(t) U will get i(t)=Vexp(-Rt/L) Now find flux, ¤=mmf/reluctance ¤=Ni(t)/R Therefore flux will come out to be decreasing exponential function of time. And eventually after 3 to 4 time constant flux will be equal to zero. Now apply Farady law and find induced emf in secondary. E2=N2 d¤/dt. Since flux is constant and it is equal to zero therefore induced emf E2=0 (short circuit, hence secondary side impedance is zero). Now refer the circuit to primary side u will get the following circuit elements: 1. Voltage source 2. Primary and secondary winding resistance. Rp and Rs 3. E2=0 therefore it will be replaced by short circuit wire. The impedance on secondary side becomes zero(because induced emf is zero) therefore by this logic u can say that current will increase drastically.
@@GauravJI was wondering this too. I want to design a dc motor that basically uses transformers to wirelessly excite the rotor and rather than using ac current and putting rectifiers on the secondary for the rotor I'm thinking it would be better to use a pwm DC source connected to the primary
great Job you make me understand easily.from Africa Zambia
Good to know!
Enjoyed this, please bring interview questions sir
Glad you liked it ☺️
I would highly appreciate Gaurav Ji,
sharing valuable things and knowledge.
Very good sir.Thanks
Fantastic explanation sir.
Please my question is, at what point in time do we need 1:1 transformer in power system?
In order to separate the load from the utility ground. Like this you can create an ungrounded circuit. This is either done to reduce the risk of electric shock or to avoid short circuiting measurement setups.
Wonderful video sir 👍🏻 💯 very informative yet easy to understand , thank you sir 😊
Glad it was helpful 😊 do share!!
🎉🎉🎉 good knowledge sir , may god bless you
Thanks 👍🏻 do share and subscribe 😇
What an awesome video sir 👍👍 truly 💎 keep making videos
Thank you 😊 do share and subscribe 😇
Really understandable.keep the good work and make videos about electrical generation in ships
Glad it was helpful 😊 do share 👍🏻
Our saviour, Gaurav J😊
Very informative. Thank you Sir.
Glad it was helpful!
This video was too good.....
Glad you liked it!!
Tq... Very helpful...
Welcome 😊
Great job
Thank you 😊
Thank you for your explanations and I also like the software that you use, I am about to try that one, thank you for sharing the name for it. Everycircuit
Glad it was helpful 😊 do share and subscribe
very lucid manner fine...
It was mentioned that due to the frequency, f = 0 for DC supply, hence the net impedance of the circuit becomes merely resistance, R. However, since f = 0, isn't that the capacitive reactance that is inversely proportionate to f would become infinite and the resultant impedance, Z would become infinite also? Appreciate if someone could shed some light...
You are right. The reason for higher current is the lack of back emf produced by the induction.
Capacitive resistance comes not in series with the winding. It is always bw the winding and ground. So it can not be considered
Crystal clear 🔥🙏
Glad it was helpful!! Do share 😊👍🏻
So we can change switch on and off continuous to get output for long time??
What software are you using to simulate circuits?
EveryCircuit
thank you
You're welcome
Sir but 1/2pifc if in dc f equal to zero means xc infinity in that R + Jxc maximum
In a HVAC line,since there is only a resistance in the wire and there is no connection of capacitor and inductance,why your considering inductive reactance and capacitance?
Sir is there any possibility that by using "variable DC supply" (i.e. Square Wave) as a source, the "transformer" can operate?
yes
i have a question why then are transformers used in amplifiers? if the circuit is in DC how does the transformer amplify the input to the speaker?
Pl send the link for basics of transformer
Sir, First of all impedance is given by Z=R+j(Xl-Xc) not R+Xl+Xc(j denotes phasor and it is very important in AC quantities), and secondly the value of Xl i.e. leakage reactance is also very low, the transformer is designed such that it has less leakage flux so that the Voltage regulation value can be minimized. So, you cannot justify by saying that becuase in DC Xl=0 therefore current will increase, it is not the valid explanation.
Explanation:
Apply KVL in primary side u will get
V=i(t)R+Ldi(t)/dt
Where V is the supply voltage
And L is the inductance of primary coil.
Apply laplace and solve i(t)
U will get i(t)=Vexp(-Rt/L)
Now find flux,
¤=mmf/reluctance
¤=Ni(t)/R
Therefore flux will come out to be decreasing exponential function of time. And eventually after 3 to 4 time constant flux will be equal to zero.
Now apply Farady law and find induced emf in secondary.
E2=N2 d¤/dt.
Since flux is constant and it is equal to zero therefore induced emf E2=0 (short circuit, hence secondary side impedance is zero).
Now refer the circuit to primary side u will get the following circuit elements:
1. Voltage source
2. Primary and secondary winding resistance. Rp and Rs
3. E2=0 therefore it will be replaced by short circuit wire.
The impedance on secondary side becomes zero(because induced emf is zero) therefore by this logic u can say that current will increase drastically.
Sir, what is Concept of leakage flux if RYB OF 3Phase transfomer operate commonly at one phase means no phase difference in RYB
yeah
What will happen if we supply pulsating DC in primary of transformer? will bulb starts glowing ? As we are giving change in supply
Yes. An output can be seen in that case.
@@GauravJI was wondering this too. I want to design a dc motor that basically uses transformers to wirelessly excite the rotor and rather than using ac current and putting rectifiers on the secondary for the rotor I'm thinking it would be better to use a pwm DC source connected to the primary
@@GauravJThat is what we call pulsating transformer in that case
What happened actually when we measured trf IR with 5 KV DC insulation resistant testor meggar
Megger only measures the insulation bw winding and ground
But we connected the megger the motor for insulation check what will happen and why not motor burnout
Sir which software it is
Everycircuit
👍👍
Promo_SM 😥
veeeedio