indeed you are a good teacher to man. This is a good example my suggestion is you should use English the official language that most people understand Thank You Sir
When we are writing the changed equation for span CD, will the new equation is valid only for UDL Or any type of loading? Because I have seen in some other videos they are continuing with the same SD equation. Kindly answer.
Yes you can. But the solution getting lengthy. And i have used that equation due to hinged support at end not due to UDL and one thing more. The equation would have been the usual if there were fixed support at D. I hope you got my point if not then let me know. And dear, i have discussed about it in one of my video on same method which is in hindi. Check it in the link.
Asymmetrical load mean the load which is acting away from the center of span. And for that we have formula. Or, You can say that there are two different formula for the two different loading condition i.e. 1. Load acting at the center of span. 2. Load acting away from the center (asymmetrical). Hope you understood.
I didn't get one thing while drawing BMD you wrote the moment for Mba i.e 4.18 but you didn't write moment for Mbc i.e -4.176 at the same B point why is that so? Pls whoever reads my comment reply asap
Hum condition of equilibrium bich wale(intermediate) support pe lagate he. And us end k saath jo equation bana hua he step to me us ko add karte he. Jitna intermediate support hoga utna hi equations bane ga humra and finally un equations ko solve kar k hum slope ka value find kar lete he. And us k badh final moment ka slope ka value substitute kar k ( step 2 k equations me).
Diagram thik se dekhoge to pata chalega ki supports different he ek side fixed and dusri side hinged he so formula thoda fark he. Practice well. Best of luck.
@@903gaurav2 Bhai simply supported and hinged support dono same hi hota he. So aap koi bhi assume kar k solve kar sakte ho. Prepare well for your exam.
Thank you so much bro. you really helped my life with this. I am about to write SE exams in 2 hours time. this really helped thanks.
Best of luck dear 👍👍
You're really saved my day.... I wish dt you still grow more and achieve ❤️👍😁
Thank you
You're a life saver. Thank you, sir!
Means alot dear.
These comments motivates me to come with best contents.
I will be back with new topic soon.
Thank you.
Thank you sir 🙏 You are best teacher in India
Thanku so much slop deflection MTD k sath calculator m EQN solve Krna b sikha diya bhaiiiii love you 🤩🙏🤗
Welcome 😁
@@Civillearningonline syd apse ek choti si mistake ho gai jo step 5) final moment calculation h usme EI.ib hai usme /4 nahi aayega baki sb thik h...
indeed you are a good teacher to man. This is a good example
my suggestion is you should use English the official language that most people understand
Thank You Sir
Sure sir.
I am working on it.
There are 2 to 3 video in Hindi.
@@Civillearningonline thank you sir
Your vedio is very easy to understand and good explanation
Thank you
It's really a good concept i got. Thanks a lot.
for the slope deflection equation Mcd - Mdc/2 + 3EI ic/2 or should it be + 3EI ic/L as shown in your last video ?
@11.57
3/2 is ok.
We use this formula when we have hinged support at far end.
@@Civillearningonline so 3 EI/L is for fixed support ?
@@walldanwazeel7863 3/4 *EI/L for fixed support.
When we are writing the changed equation for span CD, will the new equation is valid only for UDL Or any type of loading? Because I have seen in some other videos they are continuing with the same SD equation.
Kindly answer.
Yes you can. But the solution getting lengthy.
And i have used that equation due to hinged support at end not due to UDL and one thing more.
The equation would have been the usual if there were fixed support at D.
I hope you got my point if not then let me know.
And dear, i have discussed about it in one of my video on same method which is in hindi. Check it in the link.
@@Civillearningonline yes, I understood and it was really helpful. I just saw the other video. Thank you once again.
Welcome dear ♥️
It is 3/2EI @b or 3EI/L @b
Kindly clarify
Thanks
If we have a roller support at D, then which slope deflection equation shall be used?
17:18
Can any one explain this part to me clearly. How to enter those values in calci , I’m unable to understand ??😭
Tq sir good explanation sir make more videos on movement deflection and kanis method also sir please
I have already made video on kani's rotation method and created a seperate playlist please visit channel.
Should I have to find Shear force for this??
Only if asked.
Why you divide 4 in final moment calculation step while the equation was (-1.5EI.iB)
Sir i need small clarification sir...sir we may have many spans but only at the end span if it is simply supported we should use that equation right??
Yes.
@@Civillearningonline thank you sir
Best of luck 👍
Sir M ab u got -1.54kNm so in bmd shouldn't we take it minus that is below line??
Sir is it 3/2 EI .ic or 3/L
EIib and EIic ki value kaise find kari
Pura karke btana tha na
Aur hnn mere find karne par EIib= -3.235 aur EIic= 9.33 aai hai
Thank you bhaiya.
Mab me 4 se divide kyun kiya 19:05
Tq bro accha samjhaye
Welcome bhai
brother how to solve the equation in MS calculator??
Sir please batao ei/4 A 4 ko kyu dala gaya hai final eqn me. 4 tao Ma-b eqn me nahi hai
Sorry bhai. 4 nai hoga waha pe.
Baki sab thik he
Is Mab correct sir?? It’s supposed to be -1.5-0.16=-1.66KNm
Yes this is right
@@soumya3661-7 what is right the one in the video or the one that this girl has commented
@@sanketbhandekar2165-1.66
@@sanketbhandekar2165tu hai kon🗣️
thank u soo much Thanz a lot
Sir, am Student of IIT Indore. Mujhe aapne aaj fail hone se bacha liya 😣
Sir, can u explain sinking model?
Yes
What is the difference between point load and asymmetrical I'm so confused at 1st you taken it as asymmetrical and next you taken it as point load
Asymmetrical load mean the load which is acting away from the center of span.
And for that we have formula.
Or,
You can say that there are two different formula for the two different loading condition i.e.
1. Load acting at the center of span.
2. Load acting away from the center (asymmetrical).
Hope you understood.
Thank you 💞 💞 very so much sir alwalys u souprt me
I didn't get one thing while drawing BMD you wrote the moment for Mba i.e 4.18 but you didn't write moment for Mbc i.e -4.176 at the same B point why is that so? Pls whoever reads my comment reply asap
4.176 ko 4.18 to likhi saqte hay na round off kar k. issliyea 4.18 likha hay.
@@bananimondal9389 nhi issue 4.18 mn nh hai issue is with -4.176 wo moment hmne nh use ki at joint B
B point me BMD same hay issliyea koi vi ek laykar BMD draw kiya hay
Thank u very much sirr
Bhai Thank You so much But Brother Step 5 ke First line me kuch Error hn mere According.
I will Thank full to You Dear Brother God Bless you
Welcome dear brother ❤️❤️
SFD?
Reaction bhi bta dete kaise calculate krte hai
Joint B ki value calci me kaise put kare
Thanks !
Vedio full screen pe kiu nai dikh rha h🙄😢😢😢😢😭
Dekha to rahahe
Well thanks tho it’s a good example
Veri good
Thanku tusi great
There is an example similar by civil learn online
They're using 3EI/L
Drop the link of that video. I will short it out
Sir please explain step 3 applying equilibrium condition I don't understand
Sure
@@Civillearningonline sir please explain how to solve step 3
Hum condition of equilibrium bich wale(intermediate) support pe lagate he. And us end k saath jo equation bana hua he step to me us ko add karte he. Jitna intermediate support hoga utna hi equations bane ga humra and finally un equations ko solve kar k hum slope ka value find kar lete he. And us k badh final moment ka slope ka value substitute kar k ( step 2 k equations me).
Let me know whether you have understood or not
@@Civillearningonline sir not clear this concept if any video related this please share
Sir jii meko PDF chaiye apki
From step two above when finding Mcd ... I think that (3/2)EIØc should be (3/Lcd)EIøc 🤔.... That 2 should be replaced by length of span CD
Exactly my point mann!!
Sir what about SFD ?
Can we draw sfd in this question? And if can then how ?
Yes we can draw SFD. Drop your email i will make it for you.
@@Civillearningonline osangtemjenjamir@gmail.com thank you so much sir.. 🔥 I have exams day after tomorrow .. will help alot
I will send you email tomorrow.
@@Civillearningonline ok sir thank you so much again 🙇♀️
Sir or bhi video bnao or bhi topic h plz
Sure
Span AB and Span BC ka फार्मूला alag ku h
Diagram thik se dekhoge to pata chalega ki supports different he ek side fixed and dusri side hinged he so formula thoda fark he. Practice well. Best of luck.
@@Civillearningonline thanks bro
Bhai joint c u done a mistake c nahi hai b hai
Ic hahi ib aata first word par
Kis duration ??
Timing?
Joint b and c dono he.
Overhang beam ka videos plzz
Please check playlist.
Bhai ea paper structural analysis paper 1 or paper 2..???
Structure analysis 2
@@Civillearningonline bhai b tech poora complete ek hy backlog lqggaya sa 1 plz support paper 1 videos chahiye merko
@@mohammadnaseeruddin7654 kuch video available. Maine seperate playlist create kar rakha he.
@@mohammadnaseeruddin7654 Structure analysis part 1: ruclips.net/p/PL513Y7_xBTnDgkdP8HXGXjbgz9hA5E7JU
This is gonna help you alot.
@@Civillearningonline thnq so much wa ek hogaya tho b tech complete hojaye ga
Sir ek sum ka doute he slove karavo ge
Sure. Mail kardo. civillearningon@gmail.com
What's the chapter name,
My teacher taught this but i don't know the chapter name 😶😶.
Analysis of indeterminate structure,
Using slope deflection method.
This will be sooo helpful if it was in English am jux following but dont really get it 😰😰😰😰
There are some other examples which are in English. Have a look. Please check out playlist.
Sf diagram nahi he
M,ab= -1.54 hi BMD me positive le liya
Diagram me agar value exceed karga to +ve otherwise -ve lena hota he.
Thanku sir
Welcome dear
Voice Me Awaj Aa rahi hai,, Irrrted ho raha Tha isiliye nhi dekha, plz use 🎤mic, not phone mic
Sorry bhai. Ye old video he us time idea nai tha. Aap playlist check karo.
Just when I started enjoying the moment distribution method in English...
You changed to Hindi and I'm totally lost😣
Sorry dear,
You can find video in English too.
Please check the playlist.
Structure analysis part 2: ruclips.net/p/PL513Y7_xBTnAprzGbIpMFzGm-ju1ZiCuS
♥️
Sir joint c answer rong hai sir
MBC =-wl^2/8 hogga
Bhai simply supported end pr 0 aata hai bhai at moment Dc
Haa bhai.
0 aaye ga moment at hinged support DC.
Bhai kabhi kah raha h hinde kabhi siple support? Kahna kya jaata h explain kro
@@903gaurav2 Bhai simply supported and hinged support dono same hi hota he.
So aap koi bhi assume kar k solve kar sakte ho.
Prepare well for your exam.
P
?
jhor se bol bhai sunai nahi dera
Aur bhi video he playlist, his me sound achha he. Have a look.
Thanks u so much sir...