Fantastic solve as always by Simon! I'm so glad you found all of the core logic involved (with the 10 and 20 sums), and especially pleased you found the intended Sudoku near the end (the 5/7 pair in row 4). The concept for this puzzle started as I was thinking about other duality-type puzzles that may be possible (insert shameless plug for the recent Skunkworks puzzle pack here), and the thought of the number of a cage being both the sum and a look-and-say clue came to mind. As I thought about it, I realized all the points you discussed while solving, and started wondering if I could take that concept and make it so the actual total was initially unknown for every cage. I was incredibly delighted when I found that this was, in fact, possible!
@@arkadeusz91 The original title was actually "Look, A Killer!", but Chameleon came up with the final name, so I'm actually not sure if it's specifically an AC reference 😅
@@Ytterbio Well, that would fit as well, as one of the best AC and Rock Album,s ever is Kiiller. (And I did construct a sudoku that I named Halo of Flies which is a tune on that album, and if I ever manage to figure out how to solve it, I will submit it to CtC, I would love to see Simon cut his teeth on it)
If I encountered this puzzle anywhere else, say a newspaper or a puzzle magazine, I'd have simply written it off as "stupid fools, they've not printed it correctly". It being CtC, instead I go "ok, no given digits, no cage totals - let's get cracking!"
28:50 A 4-cell cage in a single house consists of two low digits, a high digit, and a whatever digit, where the whatever digit is not limited to being a second high digit.
That's true, but it thankfully ended up not mattering. When Simon did get to that 4 cell cage in box 9, he pointed out there could only be 1 small digit in the row 9 part. Which then makes the 3 small digits option he overlooked be impossible.
Usually I can follow along with your logic, and see how it is working as you explain it in real time, but something about this one kept breaking my brain. I had to pause and back up several times, and ask myself how you made the deductions. Well done. I am pretty sure I would have taken days to solve it by myself.
Really great puzzle. Got stuck and had to scroll through the video to get a hint of where to be looking (the top right, of course). I'm happy to say that I at least found the logic for the break-in myself after that --- of course you can "move around the X" to make the 20 sum however you need to. 1:46:44
51:59 There was a much easier way to prove that r8c9 was 1. In fact, it had been clear for about 15 minutes (as soon as you put the 1 in r3c7). The reasoning goes- if you don't have the 1 in the cage, the digits that add up to 10 must be 2, 3, 5 and now you don't have enough digits in the *adjacent* vertical 4 cell cage to put the 2, 3 and 5 it needs.
I got held up coming to this by the monthly reward pack - which is really great this month: loved it. Now an intriguing puzzle without time to try it myself, but I can see some nice things already.
Oh my, that was a hard one I think, it pays to know all sum combinations by heart. The ruleset was very elegant indeed, and somehow the puzzle kept resisting until the very end. Nicely done!
Holy Toledo, that was hard. I had a thicket of pencil marks, letters, and colors. Took me 3 hours but I never really felt stuck and the logic was a joy.
I finished in 137 minutes. This was a tough one, but it was so fun to solve. I had a great time figuring out the meta of the puzzle and rewired my brain to think about them adding up to 10 or 20 plus the end digit. That made things very clear in my mind. I think my favorite part was seeing that r8c1 couldn't be 234 as this would force the cage in the bottom right of box 9 to not have any partners for 1 that add to 10. I was a little slow on this one, but it was so fun to solve. Great Puzzle!
Well, I don't know yet about the puzzle, but the ruleset is magnificent❗I am looking forward to solving this puzzle before watching the video. Thank you for featuring it. 😏👍👍👍
Even though I watched you solve it, it still looked like an impossible puzzle to me. Mind you I’ve never ventured outside of normal sudoku rules. And the fact that solving it seems so impossible to me. I can’t even wrap my head around how one would even make such a puzzle.. absolute masterpiece!
I was planning on racing you to solve this, but man, this was not the puzzle for me, lol. I couldn't even see where you were going most of the time. I gave up and decided to just enjoy the ride of your solve.
Very dificuult, especiall if you're solving on a few different moments as I had to. Yet you're constantly on the feeling that you're not completely stuck
Well Simon and Mark have a lot to answer for. Was just at the bar ordering a coke and Losing my religion came on. Absent mindedly I sang “That’s 3 in the corner, that’s 3 in the spotlight proving it’s position” The lady serving me said “I takeit you do know those aren’t the correct lyrics “ To which I replied I take it you don’t do Sudoku or watch @CrackingTheCryptic”
Took me over an hour until I realized I messed it up, and then it still took me 1:17:57 and some small clues from the video afterwards. Dang, that was hard.
EDIT: Oh wait, I see my mistake. I think. You correctly note that column 1 will have four low digits so R4C2 and R7C3 cannot be repeated low digits. But I still think looking at the 4 cell cage in box 1 is the right answer. 11:40 Aren't you looking at the wrong cage now Simon? If R2C1 and R3C1 need to be high digits in a 4 cell cage that is constricted to box 1. Then the minimal that cage can be is 11 with a [56] pair. But that is before you consider the other two cells in the cage. If they were [12] then the minimum of the cage is now 14. That cage could, for the sake of not getting to a 20 sum or higher, take one more high digit, but only just. It could take 5, 6 and 7 to make 18 and then a 1 digit to get to 19. But then you don't have a 9 in it. Point is, that 4 cell cage in box 1 can't have more high digits so R2C2 and R3C2 are from low digits only. This makes R2C3 and R3C3 high digits. NOW you can look at column 2 if you want. Because you can only have one more low digit in that column, the rest have to be high digits. So the cage you are looking at is going to have four of the digits from [56789] and will be a minimum of 26, and so there will be repeated digits in the cage and those are R4C2 and R7C3. There's not enough room to make those repeated digits high digits. I.E, if you used high digits as the repeated digit, the cage would be a 30+ cage and would need three repeated digits. EDIT: Ah right, there will be THREE high digits in column 2 in that L shaped cage. Let's use [567] which is 18. Of course R3C2 and R7C3 repeat but they can be high digits without a problem as long as you don't add more than 11 in total. I.E, you can reach a 29 sum in the cage just fine. Well, since R3C2 and R7C3 can't be low digits, there still has to be a low digit in that cage. Going forwards, I think it's worth noting that none of the cages in the grid seem to allow for three repeated digits. So all cages are less than 30.
me, being familiar with the look-and-say sequence: yes, of course, one of these will turn out to be one two and one one, in a cage adding to one thousand two hundred and eleven
There are a couple cages that can't have a repeating number by sudoku, so they must sum to a number in the teens, and yet they do not have a 1 in them. How is this possible with the given rule set? I am so confused!
@@Landee 90% of all the movies she reviews are "best movie ever", so it looked to quite similar. (Dawn is a pretty blond Scottish woman, and often quite fun in her reviews and actually kind of smart also. Wonder how she would do on sudoku.)
Omg this never happens! (Me being early and also what I am about to say). For the first time I can remember I found a different path to Simon! Now, I am an enjoyer of sudoku, but I watch these videos just for fun and don't usually try to learn anything or do them myself first. Every once in a while, there will be something obvious that Simon misses because he's thinking too hard (lol) but this time I actually thought of a way to find a digit differently than Simon did, and before him as well. Now if you are still reading, I will be going into detail. At around 44:34 Simon was struggling to figure out where to go next, and I automatically thought about the 1st Column. Why? I don't know. Now, he had proven that the five digit cage in Row 1 had to have 1234 and whatever number was in the unit digit in the cage sum. (At this point I paused the video so I could continue my train of thought without listening to Simon). And with the extra info we have now, I was able to figure out Oh, no, I just realized my logic is flawed, dang it. I'll continue. I THOUGHT that in that cage in Column 1 the digit accompanying the 1234 quadruple had to be a 6 or 8 because I was thinking it was in the bottom two cells, in the same box as the 79 pair (it totally doesn't have to be). Now this led to 8 being ruled out in Box 1, and the 2 by 2 cage having a 57 pair. And this leads to the other two cells in the box being a 68 pair, which makes the blue cell 5. Once I "figured" this out, I pushed play on the video and watched Simon do something else entirely while I was sooooo smug at figuring it out before him. Then he got the 5 in a completely different way, and I wanted to see if anyone else thought of the same thing I did and came down here to type this comment out. Halfway through I realized the flaw and now I'm just surprised it was right. Edit: Turns out all of my logic was correct because Simon ended up doing a lot of the same stuff, my problem was just in correctly guessing where the high digit was in that cage!
Isn't this puzzle broken? There is a 4 cell cage in box one with four different digits none of which is a 1. How does the look see work there? Could someone explain?
You can think of the cage totals like spoken phrases, so a 17 total means "there is one 7 [in the cage]." A 24 total would mean "there are two 4s [in the cage]." Etc.
I'm so confused, doesn't every teenage cage need a 1 in it? it feels like he could place lots of ones for a while now, i feel like I'm missing something 27:52
64:58 for my time. That was a rather difficult but beautiful puzzle, there was a constant difficulty but a very natural flow and the kind of logic it involves is very neat (though I think Simon made a mistake a 4-cells teenage cage must always include 2 lows and 2 highs, as the unit number could very well be a low one). Plus a classical Xwing of 2s and a hidden 5-7 pair in the end to finish it, lovely!
Fantastic solve as always by Simon! I'm so glad you found all of the core logic involved (with the 10 and 20 sums), and especially pleased you found the intended Sudoku near the end (the 5/7 pair in row 4). The concept for this puzzle started as I was thinking about other duality-type puzzles that may be possible (insert shameless plug for the recent Skunkworks puzzle pack here), and the thought of the number of a cage being both the sum and a look-and-say clue came to mind. As I thought about it, I realized all the points you discussed while solving, and started wondering if I could take that concept and make it so the actual total was initially unknown for every cage. I was incredibly delighted when I found that this was, in fact, possible!
I was wandering - is the title of the puzzle reference to Alice Cooper song or is it just coincidence?
@@arkadeusz91 Didn't think about that, but now I wonder too. (Long term AC fan)
@@arkadeusz91 The original title was actually "Look, A Killer!", but Chameleon came up with the final name, so I'm actually not sure if it's specifically an AC reference 😅
This puzzle is pure *magic‼*
@@Ytterbio Well, that would fit as well, as one of the best AC and Rock Album,s ever is Kiiller. (And I did construct a sudoku that I named Halo of Flies which is a tune on that album, and if I ever manage to figure out how to solve it, I will submit it to CtC, I would love to see Simon cut his teeth on it)
If I encountered this puzzle anywhere else, say a newspaper or a puzzle magazine, I'd have simply written it off as "stupid fools, they've not printed it correctly". It being CtC, instead I go "ok, no given digits, no cage totals - let's get cracking!"
«All of the shenanigans involving the nonsense» 😊
Simon is nothing if not eloquent 8^)
Rasmus from denmark here - what a pleasant surprise! Many thanks for the birthday wishes 😊
Happy birthday!
28:50 A 4-cell cage in a single house consists of two low digits, a high digit, and a whatever digit, where the whatever digit is not limited to being a second high digit.
I believe the only fact Simon ended up using is that there must be (at least) two digits in the bottom-right cage
Just to be concrete, the combination 1-2-3-6 adds to 12, and contains (exactly) one 2.
@@MasterHigure other combinations that also work with 3 low digits are 1-2-3-5, 1-2-3-7, 1-2-4-7, 1-3-4-6, and 2-3-4-5
That's true, but it thankfully ended up not mattering. When Simon did get to that 4 cell cage in box 9, he pointed out there could only be 1 small digit in the row 9 part. Which then makes the 3 small digits option he overlooked be impossible.
Usually I can follow along with your logic, and see how it is working as you explain it in real time, but something about this one kept breaking my brain. I had to pause and back up several times, and ask myself how you made the deductions. Well done. I am pretty sure I would have taken days to solve it by myself.
Rules: 06:05
Let's Get Cracking: 08:22
Simon's time: 1h2m47s
Puzzle Solved: 1:11:09
What about this video's Top Tier Simarkisms?!
The Secret: 4x (18:10, 18:16, 18:19, 38:57)
Bobbins: 2x (50:55, 1:07:26)
Knowledge Bomb: 1x (25:29)
And how about this video's Simarkisms?!
Ah: 22x (10:19, 13:33, 16:20, 19:01, 20:51, 22:42, 25:44, 29:28, 32:44, 34:24, 34:24, 36:09, 39:23, 40:33, 43:01, 43:01, 49:37, 52:34, 54:25, 56:21, 1:00:56, 1:05:11)
Beautiful: 11x (17:30, 40:51, 46:43, 58:06, 1:00:56, 1:00:56, 1:03:23, 1:05:21, 1:08:55, 1:11:05, 1:12:28)
Cake!: 10x (03:16, 03:18, 03:34, 03:40, 03:46, 03:58, 04:00, 04:12, 04:37, 05:25)
By Sudoku: 9x (27:07, 29:16, 40:57, 42:27, 45:25, 52:12, 1:00:41, 1:09:49, 1:10:29)
Sorry: 7x (18:41, 19:55, 21:13, 26:11, 27:16, 45:36, 46:22)
Hang On: 6x (03:37, 13:33, 15:24, 22:33, 26:59, 31:49)
Obviously: 5x (11:58, 15:14, 29:56, 1:00:15, 1:12:18)
Nonsense: 4x (56:49, 56:51, 1:02:46, 1:10:35)
Ridiculous: 4x (17:33, 46:47, 57:45, 1:04:59)
I've Got It!: 4x (34:24, 34:32, 34:32, 58:12)
In Fact: 4x (09:12, 29:58, 37:26, 1:02:55)
Nature: 4x (14:04, 50:40, 50:43, 1:11:42)
Come on Simon: 3x (44:40, 47:49, 1:07:26)
What Does This Mean?: 3x (39:12, 41:04, 59:34)
Naughty: 2x (26:16, 54:29)
Brilliant: 2x (40:54, 43:01)
Gorgeous: 2x (1:05:15, 1:12:14)
Magnificent: 2x (04:07, 34:39)
Uniqueness: 2x (1:03:41, 1:03:44)
Weird: 2x (32:32, 1:02:16)
The Answer is: 1x (59:15)
I Have no Clue: 1x (53:55)
Lovely: 1x (1:09:10)
Hypothecate: 1x (37:33)
Take a Bow: 1x (1:12:35)
Shouting: 1x (05:24)
Shenanigans: 1x (1:10:33)
Surely: 1x (1:03:58)
Phone is Buzzing: 1x (1:07:02)
That's Huge: 1x (46:20)
Pencil Mark/mark: 1x (11:15)
Triangular Number: 1x (09:01)
Most popular number(>9), digit and colour this video:
Twenty (45 mentions)
Two (129 mentions)
Blue (6 mentions)
Antithesis Battles:
Low (39) - High (20)
Even (4) - Odd (1)
Column (16) - Row (13)
FAQ:
Q1: You missed something!
A1: That could very well be the case! Human speech can be hard to understand for computers like me! Point out the ones that I missed and maybe I'll learn!
Q2: Can you do this for another channel?
A2: I've been thinking about that and wrote some code to make that possible. Let me know which channel you think would be a good fit!
I'd love to see a "teenage" count on this one, otherwise love these counters
The cake was enjoyed, although i now fear we'll never sleep! Thank you for the birthday shout-out 😊
Really great puzzle. Got stuck and had to scroll through the video to get a hint of where to be looking (the top right, of course). I'm happy to say that I at least found the logic for the break-in myself after that --- of course you can "move around the X" to make the 20 sum however you need to. 1:46:44
51:59 There was a much easier way to prove that r8c9 was 1. In fact, it had been clear for about 15 minutes (as soon as you put the 1 in r3c7).
The reasoning goes- if you don't have the 1 in the cage, the digits that add up to 10 must be 2, 3, 5 and now you don't have enough digits in the *adjacent* vertical 4 cell cage to put the 2, 3 and 5 it needs.
I got held up coming to this by the monthly reward pack - which is really great this month: loved it. Now an intriguing puzzle without time to try it myself, but I can see some nice things already.
Fantastic puzzle! The maths is sublime! Thanks Simon and yttrio!
Oh my, that was a hard one I think, it pays to know all sum combinations by heart. The ruleset was very elegant indeed, and somehow the puzzle kept resisting until the very end. Nicely done!
My copy doesn't include cage totals :(
that's because the puzzle doesn't have cage totals lol
Thats correct, the puzzle does not show cage totals
Like in the video
Yes, I know that's the challenge. I was going for the humorous comment
It's a new Sudoku type , invisible ink Sudoku , pretty much a variant of fog Sudoku.
@@donaldsnyder1543 C'mon, don't be giving people ideas! The minute Sven or Chameleon sees this, we are all doomed!
Holy Toledo, that was hard. I had a thicket of pencil marks, letters, and colors. Took me 3 hours but I never really felt stuck and the logic was a joy.
I feel like that title can be applied to at least half of the Sudokus that appear on this channel!
You're pencil marking [1,2,3,4] as opposed to using a colour for low digits?
WHO ARE YOU, AND WHAT HAVE YOU DONE WITH SIMON??
This was fun. Unravelled surprisingly easy after understanding some stuff early on, but it kept being always interesting.
The title of this video is spot on. Indeed, one of the best sudoku of the year.
28:45 Why couldn't it have 3 low digits like 1-2-3-5 totaling 11?
I thought the same, luckily that conclusion didn't reflect afterwards
23:40 for me. Fantastic puzzle!!
I finished in 137 minutes. This was a tough one, but it was so fun to solve. I had a great time figuring out the meta of the puzzle and rewired my brain to think about them adding up to 10 or 20 plus the end digit. That made things very clear in my mind. I think my favorite part was seeing that r8c1 couldn't be 234 as this would force the cage in the bottom right of box 9 to not have any partners for 1 that add to 10. I was a little slow on this one, but it was so fun to solve. Great Puzzle!
Ohhhhhh that cake! That will be a very happy birthday!
Well, I don't know yet about the puzzle, but the ruleset is magnificent❗I am looking forward to solving this puzzle before watching the video. Thank you for featuring it.
😏👍👍👍
It's a very good one, indeed! 😄
68:20, with a little help with the 26 cage (I wasn't thinking about the repeat digit being in r1c6). Impressed by the logic I had to use.
Thank you for the birthday wishes Simon!!!!!!!
Happy birthday
Even though I watched you solve it, it still looked like an impossible puzzle to me. Mind you I’ve never ventured outside of normal sudoku rules.
And the fact that solving it seems so impossible to me. I can’t even wrap my head around how one would even make such a puzzle.. absolute masterpiece!
This was a REALLY hard one for me, so you're definitely not alone on that!
I was planning on racing you to solve this, but man, this was not the puzzle for me, lol. I couldn't even see where you were going most of the time. I gave up and decided to just enjoy the ride of your solve.
Kept misinterpreting the rule and thought both numbers were required in the cage.
Allways perfect timing simon :)
This one gets you well-acquainted with Base 10. You’re just enveloped in the arithmetic!
Very dificuult, especiall if you're solving on a few different moments as I had to.
Yet you're constantly on the feeling that you're not completely stuck
This Is One Of The Best Sudoku Puzzles Of 2024 with The Best Sudoku Puzzle Solver of All Times
Looking forward to this video.
Well Simon and Mark have a lot to answer for.
Was just at the bar ordering a coke and Losing my religion came on.
Absent mindedly I sang “That’s 3 in the corner, that’s 3 in the spotlight proving it’s position” The lady serving me said “I takeit you do know those aren’t the correct lyrics “ To which I replied I take it you don’t do Sudoku or watch @CrackingTheCryptic”
is there a sudoku advent calendar like there was last year?
Took me over an hour until I realized I messed it up, and then it still took me 1:17:57 and some small clues from the video afterwards. Dang, that was hard.
1:10:23 for me this time, but I did it much better on my own.
I just don't understand how anyone can come up with a puzzle like that
EDIT: Oh wait, I see my mistake. I think.
You correctly note that column 1 will have four low digits so R4C2 and R7C3 cannot be repeated low digits.
But I still think looking at the 4 cell cage in box 1 is the right answer.
11:40 Aren't you looking at the wrong cage now Simon?
If R2C1 and R3C1 need to be high digits in a 4 cell cage that is constricted to box 1. Then the minimal that cage can be is 11 with a [56] pair.
But that is before you consider the other two cells in the cage. If they were [12] then the minimum of the cage is now 14.
That cage could, for the sake of not getting to a 20 sum or higher, take one more high digit, but only just. It could take 5, 6 and 7 to make 18 and then a 1 digit to get to 19. But then you don't have a 9 in it.
Point is, that 4 cell cage in box 1 can't have more high digits so R2C2 and R3C2 are from low digits only.
This makes R2C3 and R3C3 high digits.
NOW you can look at column 2 if you want. Because you can only have one more low digit in that column, the rest have to be high digits.
So the cage you are looking at is going to have four of the digits from [56789] and will be a minimum of 26, and so there will be repeated digits in the cage and those are R4C2 and R7C3.
There's not enough room to make those repeated digits high digits. I.E, if you used high digits as the repeated digit, the cage would be a 30+ cage and would need three repeated digits.
EDIT: Ah right, there will be THREE high digits in column 2 in that L shaped cage. Let's use [567] which is 18. Of course R3C2 and R7C3 repeat but they can be high digits without a problem as long as you don't add more than 11 in total. I.E, you can reach a 29 sum in the cage just fine. Well, since R3C2 and R7C3 can't be low digits, there still has to be a low digit in that cage.
Going forwards, I think it's worth noting that none of the cages in the grid seem to allow for three repeated digits. So all cages are less than 30.
me, being familiar with the look-and-say sequence: yes, of course, one of these will turn out to be one two and one one, in a cage adding to one thousand two hundred and eleven
I got diabetes from seeing that cake.
Add to 10 the puzzle
What a wonderful cake!!!
Dubious, but what about a 3 cell cage summing to 06? 😉
Yesterday’s puzzle was great, looking forwards to this!
There are a couple cages that can't have a repeating number by sudoku, so they must sum to a number in the teens, and yet they do not have a 1 in them. How is this possible with the given rule set? I am so confused!
Every new video be like : The Best puzzle
You aren't by any chance watching Dawn Marie's movie reactions?
@dolf370 uh don't think so
@@Landee 90% of all the movies she reviews are "best movie ever", so it looked to quite similar. (Dawn is a pretty blond Scottish woman, and often quite fun in her reviews and actually kind of smart also. Wonder how she would do on sudoku.)
@@dolf370 oh okay, thanks for the info 🫶
You should work for MI6! You could break any code!
Omg this never happens! (Me being early and also what I am about to say). For the first time I can remember I found a different path to Simon! Now, I am an enjoyer of sudoku, but I watch these videos just for fun and don't usually try to learn anything or do them myself first. Every once in a while, there will be something obvious that Simon misses because he's thinking too hard (lol) but this time I actually thought of a way to find a digit differently than Simon did, and before him as well.
Now if you are still reading, I will be going into detail.
At around 44:34 Simon was struggling to figure out where to go next, and I automatically thought about the 1st Column. Why? I don't know. Now, he had proven that the five digit cage in Row 1 had to have 1234 and whatever number was in the unit digit in the cage sum. (At this point I paused the video so I could continue my train of thought without listening to Simon). And with the extra info we have now, I was able to figure out
Oh, no, I just realized my logic is flawed, dang it.
I'll continue. I THOUGHT that in that cage in Column 1 the digit accompanying the 1234 quadruple had to be a 6 or 8 because I was thinking it was in the bottom two cells, in the same box as the 79 pair (it totally doesn't have to be). Now this led to 8 being ruled out in Box 1, and the 2 by 2 cage having a 57 pair. And this leads to the other two cells in the box being a 68 pair, which makes the blue cell 5.
Once I "figured" this out, I pushed play on the video and watched Simon do something else entirely while I was sooooo smug at figuring it out before him. Then he got the 5 in a completely different way, and I wanted to see if anyone else thought of the same thing I did and came down here to type this comment out. Halfway through I realized the flaw and now I'm just surprised it was right.
Edit: Turns out all of my logic was correct because Simon ended up doing a lot of the same stuff, my problem was just in correctly guessing where the high digit was in that cage!
Isn't this puzzle broken? There is a 4 cell cage in box one with four different digits none of which is a 1. How does the look see work there? Could someone explain?
The numbers are 2,3,5,7. 5+3+2 are 10, plus one 7 makes 17. You don't need a 1 in the cage, only there is just one 7.
You can think of the cage totals like spoken phrases, so a 17 total means "there is one 7 [in the cage]." A 24 total would mean "there are two 4s [in the cage]." Etc.
I'm so confused, doesn't every teenage cage need a 1 in it? it feels like he could place lots of ones for a while now, i feel like I'm missing something 27:52
That was my thought
1:17:58 for me.
Simon really should get back to sudoku origins... But like REALLY.
By the way, Liverpool won by 2-0 😁😁🏆🏆
and were a class above City throughout. Love this Belgian!
@@arandamei2189Belgian? Kevin De Bruyne?? What?
70:03 for me
What football?
Cunning little puzzle
Naughty brain. Haha. I have a naughty brain, but it has absolutely nothing to do with sudoku.
64:58 for my time. That was a rather difficult but beautiful puzzle, there was a constant difficulty but a very natural flow and the kind of logic it involves is very neat (though I think Simon made a mistake a 4-cells teenage cage must always include 2 lows and 2 highs, as the unit number could very well be a low one).
Plus a classical Xwing of 2s and a hidden 5-7 pair in the end to finish it, lovely!
Yes, no, err, yes. Delicious.