Kirchoff's Loop Rule

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  • Опубликовано: 4 фев 2025

Комментарии • 95

  • @batuhankaya2200
    @batuhankaya2200 8 лет назад +37

    You have probably made me pass the physics course, thanks a lot and I wish all the good things happen in your life !

  • @timmylindquist7704
    @timmylindquist7704 9 лет назад +3

    I’m currently an electrical engineering student, and it has come to my attention that students have trouble grasping the concept of Kirchhoff’s Voltage Law in many of the introductory courses. My colleagues and I set out to help these student by offering a technical description of the process to coincide with the course material. We discovered it was much easier to grasp this concept with analogies, as you did. We then provided a strategy for solving these problems by analyzing the circuit, choosing a loop, and finally applying Kirchhoff’s Law to solve for unknown variables. We hope this technical description will benefit struggling students.

  • @rawstarmusic
    @rawstarmusic 10 лет назад +5

    Truly amazing channel you have Paul. Leaving small pauses after conclusions would help to realize and remember before the next part.

  • @archerdev
    @archerdev 10 месяцев назад +1

    Thank you so much Mr. Andersen , you are the best.
    Physics bless us all

  • @willya6690
    @willya6690 8 лет назад +3

    Thanks for sharing your videos. They are wonderful and easy to understand. The best videos about electrical ever seen.

  • @Itskelss
    @Itskelss 4 года назад +2

    Thank you a lot! I struggle with physics and this made me understand better about Kirchhoff's law.

  • @astroash2697
    @astroash2697 9 лет назад +1

    Excellent description, very simple to grasp.

  • @fastdollar1
    @fastdollar1 7 лет назад +3

    thank you, I was so lost when we went over this in class. I'm grateful for this, I just needed a different look at it I guess.

  • @lukasherrmann2977
    @lukasherrmann2977 3 года назад

    you are the definition of a blessing my friend

  • @ProLeopardx1
    @ProLeopardx1 8 лет назад +2

    Wonderfully explained, thank you so much.

  • @vishaalshiva2009
    @vishaalshiva2009 9 лет назад +1

    Really helped me a lot. Thanks for doing this video

  • @jeremyjj3866
    @jeremyjj3866 2 года назад

    This analogy is phenomenal

  • @vanillapie8321
    @vanillapie8321 2 года назад

    great educators are great communicators.

  • @marium9592
    @marium9592 Год назад

    Thanks, u explained so smoothly

  • @Starship245
    @Starship245 8 лет назад +1

    Thank you for the Presentation !!! Very helpful

  • @francismannion7075
    @francismannion7075 8 лет назад +1

    Fantastic explanation, thank you.

  • @Livingbeing01
    @Livingbeing01 3 года назад

    YOU ARE AWESOME!! Thanks so much for uploading this video🤗

  • @swarnnabaranwal1210
    @swarnnabaranwal1210 7 лет назад

    you are the best!!! this is the easiest exanation I have ever heard. thank you thank you so much!!!!!

  • @arunkumardr3778
    @arunkumardr3778 9 лет назад +1

    Really helped me a lot, Thanks

  • @preethigrg
    @preethigrg 9 лет назад +2

    Wow very very helpful. Especially for 10 class students

  • @mianabdurrehmansohaib1429
    @mianabdurrehmansohaib1429 8 лет назад +4

    Amazing video.........extremely helpful

  • @seanspringer8204
    @seanspringer8204 2 года назад

    thank you Paul

  • @bluevery2317
    @bluevery2317 8 лет назад +1

    Thank you ,sir. you are a great help.neither my tutor nor my college was this much of a help.

  • @9NIAF
    @9NIAF 10 лет назад

    it's very clear thank you , please took about thevenin theorem and superposition because i don understand it and i'll be thankful ❤

  • @danielkwon3062
    @danielkwon3062 7 лет назад +1

    Thank you for helping me all the time, I use your videos a lot - you explanation is perfect!
    I had one question about Kirchoff's Rule,
    what happens if those 'loop' that we are working on has capacitor or Inductor?
    how does the equation change?
    Thank you very much~!

  • @TheFnasimi
    @TheFnasimi 9 лет назад +1

    Really helpful, Thanks.

  • @narsimha2564
    @narsimha2564 5 лет назад

    It's a wonderful video..... for the good learners...

  • @mangolover26
    @mangolover26 3 года назад

    you are AMAZIING. thnk you

  • @sohailrocz5285
    @sohailrocz5285 9 лет назад

    yeah...good one very help full

  • @aazuaj7935
    @aazuaj7935 Год назад

    thank you sir!

  • @edwinperez3689
    @edwinperez3689 9 лет назад +12

    first time watching n the best explanation that I have heard,I'm just a beginner hungry for knowledge..

  • @msuri247
    @msuri247 8 лет назад +1

    Also why would be there a potential drop across second capacitor, since the larger capacitor will store all the charge. unless the dielectric potential breaks.could you through some light

  • @ajtepal8596
    @ajtepal8596 8 лет назад

    that was awesome. very very helpful. I thank you so much!

  • @Tahassaleem
    @Tahassaleem 5 лет назад

    sir you are awesome thank you

  • @artdimensionallimited2578
    @artdimensionallimited2578 9 лет назад

    Copyright Notice* "1:43" and "3:36" display certain aspects that we feel could infringe our copyright used for learning.

    • @Ayayron_e3
      @Ayayron_e3 4 года назад

      lol.. get over yourself.

  • @seshachary5580
    @seshachary5580 7 лет назад

    very educative. thank you. regards.

  • @sangurai3789
    @sangurai3789 2 года назад

    We know that voltage drives the current around but at the end point of the source before entering is zero so does it mean no current there or current is in motion and only voltage drop?

  • @youknowooo
    @youknowooo 8 месяцев назад

    Can you please share whoch software you are using where you measure with the multimeter? Or is it just graphics?

  • @ravitanwani770
    @ravitanwani770 8 лет назад +1

    Great Video.Which software were you using?

  • @ivarsvanberg542
    @ivarsvanberg542 9 лет назад

    very hard 2 make this easier 2 understand. thx!

  • @bhanubhaktasapkota3836
    @bhanubhaktasapkota3836 2 года назад

    So battery is a elastic rubber band holding charge on it and it releases charge around circuit, when a load comes it lose energy just like friction cause to lose energy of body which causes to lose energy of charge. But how it regain it energy from battery?

  • @manasilimaye5144
    @manasilimaye5144 4 года назад

    THANK U SO MUCH

  • @davidoldscheuerman7045
    @davidoldscheuerman7045 8 лет назад

    Thank you.
    I do have a question.
    How is voltage (potential difference) stored in the moving electrons? What I mean by this is when a current of electrons goes through a battery, how does the voltage give them power to carry out their functions, (ex. light bulbs)? Should I think of it as like Amplitude in waves? because the current is same all through the circuit. I just want to know how energy is delivered from the battery to the resistor?

  • @Onneshawn
    @Onneshawn 9 лет назад +4

    what is the software you have used?? please give me the download link

  • @crease701
    @crease701 9 лет назад +2

    What's that program he used to simulate a circuit? Does anyone know other application like that? Thanks for the help :)

    • @crease701
      @crease701 8 лет назад

      +Himanshu Sharma
      Thank you 👍

  • @lotanangmphahlele5571
    @lotanangmphahlele5571 8 лет назад

    helpful , thanks a lot

  • @andrij13
    @andrij13 7 лет назад

    would be nice if you explained how its .6 and 6v and 3v.
    assume i know nothing. i just missed out on valuable info

  • @cphVlwYa
    @cphVlwYa 8 лет назад +1

    That works great as long as there isn't a changing magnetic field going through the loop ;)

  • @samanthamallen8999
    @samanthamallen8999 9 лет назад

    Thank you!

  • @rajatgupta000
    @rajatgupta000 9 лет назад +1

    thank you man, finally got it👍

  • @vedofficial326
    @vedofficial326 4 года назад

    Nice , i am from India (Delhi )

  • @DesertE1
    @DesertE1 6 лет назад

    What type of software do you use for the circuit simulations?

  • @age_of_reason
    @age_of_reason 8 лет назад

    Wouldn't the 9V be shared between the other circuit?

  • @ankursingh6952
    @ankursingh6952 6 лет назад

    Which circuit software are you using?

  • @JamesGriggProfile
    @JamesGriggProfile 10 лет назад

    Is there also a video for the rule in parallel circuits?

    • @salazsvg97
      @salazsvg97 10 лет назад

      Can you take a look at my video...am not sure if its series or parallel or both.

    • @JamesGriggProfile
      @JamesGriggProfile 10 лет назад +1

      salaz SVG that's parralel

    • @salazsvg97
      @salazsvg97 10 лет назад

      James Grigg thank you...how did you know.Can you briefly explain.

    • @JamesGriggProfile
      @JamesGriggProfile 10 лет назад

      A switch is series will cause all the lights to turn on/off at once

    • @salazsvg97
      @salazsvg97 10 лет назад

      I looped the common at the 2 gang switch.

  • @uzairmumtaz6180
    @uzairmumtaz6180 8 лет назад

    Thanks!

  • @stephenlarbi4608
    @stephenlarbi4608 8 месяцев назад

    How did he get the 6?

  • @emmanuelchungu1421
    @emmanuelchungu1421 6 лет назад

    so helpful

  • @PhilipKirkbride
    @PhilipKirkbride 8 лет назад +2

    What software are you using to simulate the circuit?

    • @ajtepal8596
      @ajtepal8596 8 лет назад

      yes I am asking for this too. I wish someone knows

    • @CutenessFUN
      @CutenessFUN 7 лет назад

      Philip Kirkbride 7

  • @wolfchrt
    @wolfchrt 11 месяцев назад

    Now i can actually pass my class

  • @amritakumari4306
    @amritakumari4306 9 лет назад

    I have a doubt
    You said that the sum of the voltage is zero then why did you subract them

    • @peterharris8846
      @peterharris8846 9 лет назад

      +amrita kumari Subtraction is the same thing as addition of a negative value. Losing potential (i.e. across a light bulb) is a negative value.

    • @thebassofmontecristo
      @thebassofmontecristo 9 лет назад

      +amrita kumari Think of it this way... suppose they ask you to sum 3 and negative 4. How would you write that? Even though they are asking you to add them, you would write them as 3 - 4 because of the negative sign that 4 has. It is the same thing here. When you sum up the voltages it is like adding with negative numbers because when you go through the resistors in the direction of the current there is a voltage drop or loss of potential energy. Therefore the voltage across that resistor is expressed with a negative. 9V + (-6V) + (-3V) = 9V - 6V - 3V = 0. Hope that helps.

  • @paulgoodier3777
    @paulgoodier3777 8 лет назад

    thx for the vid just a minor complaint "MR"?

  • @msuri247
    @msuri247 8 лет назад +1

    bigger caps means more charge storage, so why is the potential drop less? could you please explain the inverse property.

  • @ceemoore33
    @ceemoore33 Год назад

    CLASSIC!!!!!!

  • @konouzkartoumeh
    @konouzkartoumeh 8 лет назад

    great !

  • @tataraogummadi8628
    @tataraogummadi8628 6 лет назад

    'I' in the circuit is 9/15A but not 6A.please acknowledge.

  • @sarahvan3826
    @sarahvan3826 8 лет назад +1

    you're awesome :D

  • @lokeshthota7847
    @lokeshthota7847 7 лет назад +1

    why it is happening

  • @realtrickybilly
    @realtrickybilly 8 лет назад

    Nice. Subscribed :)

  • @PB32_Singh
    @PB32_Singh Год назад +1

    Kirchoff was a bastard 😂😂😂

  • @hodaali8463
    @hodaali8463 2 года назад

    كيف تحقق قانون كيرتشوف عمليا؟

  • @muhammadsalman8836
    @muhammadsalman8836 8 лет назад

    thnxs good

  • @Ratonbat
    @Ratonbat 10 лет назад

    Praaaaaaaaaa...

  • @Cooliofamily
    @Cooliofamily 9 лет назад +1

    Look up Lewin's response to this. You will realize that this is actually false. They do not = 0 after all!

  • @AnkurYadav-ut7xx
    @AnkurYadav-ut7xx 3 года назад

    Paada

  • @seingam5625
    @seingam5625 4 года назад

    what's the point of showing your face if no one is paying attention to your face. You get me unhard

  • @hannahalexis6741
    @hannahalexis6741 8 лет назад

    THANK YOU!

  • @robinskye4599
    @robinskye4599 8 месяцев назад

    Thank you!