What if [B] wasn't zero order? The rate would be different, do you just take away 11.52^-3 from the rate and from that could you work out the order of [B]?
"What if [B] wasn't zero order? The rate would be different, do you just take away 11.52^-3 from the rate and from that could you work out the order of [B]?" Please answer this question!
Yes, u go from 11.52 to whatever the rate is in exp 3 in this case. If the difference is by the same factor so doubles then its first order. If quadrupled then 2nd order.
Usman Mahmood There is no point in the table where A's concentration is constant. This means we have to go the longer route of working out how A is affecting the rate before we work out B. We already know A was second order from measurements 1 and 2, so from measurements 2 to 3, where the concentrations of A was doubled, we would expect a quadruple of the rate. Anything else ON TOP of that from B would cause the rate to increase even further, but we don't find that. We find from 2 - 3 rate is quadrupled, meaning only A is impacting rate and thus B is zero order with no affect on rate despite doubling its concentration. Hope that helps.
""What if [B] wasn't zero order? The rate would be different, do you just take away 11.52^-3 from the rate and from that could you work out the order of [B]?" Please answer this question!"
If B was first order the rate would double again from the doubling of [B] so you'd need to multiply the 11.52 X 10^-3 by 2 to get the new rate. Hope that helps
Faseeh Ahmed Nope, because A's concentration was also doubled at the same time, and we know that A is second order already from measurements 1 to 2, so this means that the quadruple in rate (2 squared) is all because of the double in A's concentration, meaning B has no effect on rate (zero order). Otherwise, it would have increased rate further ON TOP of what A was doing as second order (2 squared affect on rate). Hope that helps.
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ohmygosh helped so much. I've been working on this for 3 days straight and havent seemed to get it. Finally do now!! tysm ❤
What if [B] wasn't zero order? The rate would be different, do you just take away 11.52^-3 from the rate and from that could you work out the order of [B]?
standard form police. haha brilliant!
"What if [B] wasn't zero order? The rate would be different, do you just take away 11.52^-3 from the rate and from that could you work out the order of [B]?" Please answer this question!
Yes, u go from 11.52 to whatever the rate is in exp 3 in this case. If the difference is by the same factor so doubles then its first order. If quadrupled then 2nd order.
+Machemguy If the exam question is set out like the first question, do we assume we use the method shown in the first question??
Exactly
Hi James, erm I actually don't understand how you actually got zero order for B, I couldnt quite get how you explained it.
Usman Mahmood There is no point in the table where A's concentration is constant. This means we have to go the longer route of working out how A is affecting the rate before we work out B. We already know A was second order from measurements 1 and 2, so from measurements 2 to 3, where the concentrations of A was doubled, we would expect a quadruple of the rate. Anything else ON TOP of that from B would cause the rate to increase even further, but we don't find that. We find from 2 - 3 rate is quadrupled, meaning only A is impacting rate and thus B is zero order with no affect on rate despite doubling its concentration. Hope that helps.
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""What if [B] wasn't zero order? The rate would be different, do you just take away 11.52^-3 from the rate and from that could you work out the order of [B]?" Please answer this question!"
If B was first order the rate would double again from the doubling of [B] so you'd need to multiply the 11.52 X 10^-3 by 2 to get the new rate. Hope that helps
Why is B zero order. The concentration is x2 and the rate experiment 2 to 3 is 2 squared. So wouldn't it be second order.
Faseeh Ahmed Nope, because A's concentration was also doubled at the same time, and we know that A is second order already from measurements 1 to 2, so this means that the quadruple in rate (2 squared) is all because of the double in A's concentration, meaning B has no effect on rate (zero order). Otherwise, it would have increased rate further ON TOP of what A was doing as second order (2 squared affect on rate). Hope that helps.
You could use an equation and log to find the orders.
Hi, how can does this work when non of the concentrations stay constant and changing at the same time