How to solve manometer problems
HTML-код
- Опубликовано: 16 мар 2014
- Check out www.engineer4free.com for more free engineering tutorials and math lessons!
Fluid Mechanics Tutorial: How to solve manometer problems.
Please support my work:
PATREON | / engineer4free
Every dollar is seriously appreciated and enables me to continue making more tutorials
"As you go deeper into the liquor, the more pressure you should have". Funny, as the university work piles up, the more pressure I have and the deeper into the liquor I sink
Directly proportional
😂😂😂
a U-tube on youtube
LMAO
Lol
Thank you so much for all your work. You helped me in mechanics of materials and now in thermo💪
I always had problems with the manometer,but you explained it in such an easy way that I don't think I'll ever get it wrong again haha! Thank you again so much for your help♡
That's awesome!!! Glad to hear it =). I have a few other videos on fluids that you might like to check out as well, the playlist is here: ruclips.net/p/PLOAuB8dR35oeOIPMOBH6hjwobuIJHPKSN ♡♡
Pretty helpful for my Civil Engineering fluid mechanics course
Glad to hear it!
Are you an Engineer now?
@@pokeman316 Yes but Civil is a broad field. I got into Estimating/Project coordinating side lol. I would like to go more into designing but let's see.
@@erazlle yooo that’s dope man! I’m currently doing my 2nd year in civil and hope to get into structural engineering. I wish you luck man, may the good blood guide your way!
@@pokeman316 Have a lot of fun as you can during your years in Civil. Once you get into Real world ... you wish you could go back to simpler times. You will be dealing with a lot of assholes, ego narcissists in construction industry.
My advice would be learn as much as you can and start building networking/find internships during summer and have fun.
thank you so much, simple and clear to understand
I definitely won’t forget now since you said “the deeper you go in a liquor..” 😂
😂 Whoops!!
I have a physics exam tommorow, btw thank u so much really helped a lot
Well explained. Thank you!
You're welcome! Thanks for watching!
thank you so much for makling such helpful video
nice teaching sir soooooo thanks
Your fluid mechanics videos are amazing. Big thanks from Türkiye.
so useful, thank you. ❤
nice video ! Thanks for share your knowledge !
Thanks for watching!
LOL "The deeper you go in a liquor"
🍻
high school chem is not easy!! so thanks so much! :)
Definitely is not, thanks for watching!!
thank u so much
Thanks, with love
great video thanks!
Glad you liked it!! Make sure to check out the full Fluid Mechanics playlist here: ruclips.net/p/PLOAuB8dR35oeOIPMOBH6hjwobuIJHPKSN =)
thank you for this video it really helps me understand somethings for my physics exam tomorrow
Glad it helped!! Hope the exam went well =)
@@Engineer4Free yes it did it was easy now I'm just waiting till I can get to the next grade
Nicely Explained 🙏
Thanks Ashutosh!! =)
Does Pgas exert a pressure against Patm????
Sir love your explaination
Thanks!! Glad you liked it. There are some more examples here too: ruclips.net/p/PLOAuB8dR35oeOIPMOBH6hjwobuIJHPKSN =)
Thank you! Could you tell which program you using for this tutorial?
Yeah, take a look at engineer4free.com/tools where I list all of the hardware and software that I use in the videos!
thanks a ton..!😊
Your welcome :D thanks for watching!!
What about closed one
Bit confused here, on your example problem video you did the opposite of what you showed here with the minus and add signs.
Thank you
You're welcome!
If we exchange the gas with a liquid, will it be the same as all the dots have the same pressure or it will vary ?
I think it will vary since the weight of the fluid will add more pressure than the weight of the gas!
I thought being a software engineer that I wouldn't have to go through this shit, oh well.
hahaha yeah I know at least at my school, software engineering students had to still take a general 1st year of engineering =/
Its helpful...
Thanks for watching and commenting!
Great chanel + website
Thanks!! =) =)
so much more useful than my stupid notes
^_^
We had a problem like this on an exam except the fluid was of "unknown density." Any ideas?
You can just rearrange the formula P = Po (+ or -) rho * g * h to solve for rho, which is the fluid density! Remembering that pressure increases the deeper you go down in a fluid. It's worth checking out my other fluids tutorials here just to get more familiar with the formulas: ruclips.net/p/PLOAuB8dR35oeOIPMOBH6hjwobuIJHPKSN
What if h is missing?
Then h is the unknown and you must be given all other quantities. Just rearrange for h and solve. At most you can have 1 unknown, so the question can be framed in a few different ways such that you must determine whatever the unknown is.
thx
You're welcome, thx for watching!
IT IS HELPFULL FOR WATER ENGINEER
When do we add Patm to pgh
When you want to know the pressure in a fluid that is at depth of h below the surface of the fluid that is in contact with the atmosphere. Sometimes with manometers due to the U shaped bend there can be a location in the fluid column that is higher than the boundary with the atmosphere. In that case you subtract ρgh from Patm.
Engineer4Free thank u so much and it was very help full
Awesome, thanks for watching!
Sir when you add P(atm) + P(gage) is equal to = P(absolute) ?
👍
✌️
Sir one think i did not understand that what is Po
Po is just a known pressure. Usually in problems like this you start with Patm as Po, and then you will add ρgh to determine the pressure at the deeper depth. In compound manometer problems you will then repeat the same equation, but you will use P from the last iteration as Po in the new iteration. If you go deeper into the column in the next iteration, you add ρgh and if you go up higher into the column you subtract ρgh.