Simple answer: Al is bigger than B (including electronegativity), and thus the distance btw Al-H is longer than that of btw B-H. The similar concept is the acidity of H-I vs H-Cl.
Jeremy Samuels Thanks Jeremy! True, I guess the bloops don't teach anything, but sometimes I like to include bloops to show that no ones perfect, and to make the video a little more relaxed? lol I try to not make them too long though.
thanks sir.... Ur video proves very beneficial for me .. I have totally mess up BTW nabh4 and lialh4 but ur concept was amazing and now I am totally clear abt the difference.. hope u could tell me and reply my ques --- Optically active 2- iodooctane when treated with radioactive NaI128 in dry acetone rate of loss of optical activity is twice the rate of isotopic exchange... plz explain it...????
Great video explanation, but LiAlH4 does not reduce carboxylic acids by nucleophilic addition/attack. Because a carboxylic acid (unlike ketones or aldehydes) has an acidic proton, LAH will instead act as a base in excess, and then do another nucleophilic addition when it is made into the aldehyde further on in the mechanism. :)
You’re totes right! I realized this in 2016 after I made the vid 😅. Most schools though don’t require students to know the full mech/aren’t tested on it. So luckily this explanation is simpler/still sort of works!
in C=O double bond. Oxygen is very electronegative and pulls all the electrons away from Carbon making Carbon partially +. In LiAlH4 or NaBH4, Hydrogen is more electronegative than Aluminum and Boron and both are more stable with 3 bonds not 4 (full at 6 e- not 8). So H can take 2 electrons from B or Al and become H-. C is electrophilic with PARTIAL + and H- is nucleophilic with FULL -, so the H- can attack C(+) and electrons in C=O double bond can move to the electronegative Oxygen. C still has 4 bonds, C=O becomes C-O. Watch his previous video or check out Khan Academy, to see this visually.
Biblo Hudson sometimes you have a Ketone and a Carboxylic Acid on your molecule but you only want to reduce the Ketone down to a Alcohol but not the Carboxylic Acid. 😉
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Simple answer: Al is bigger than B (including electronegativity), and thus the distance btw Al-H is longer than that of btw B-H. The similar concept is the acidity of H-I vs H-Cl.
Nice... a concept explained with clarity is better than covering 10 concepts with no clear explanation. Btw, I am a chem teacher.
Do you teach in US or in UK? Thanks😁
Quite a niche topic for YT, but pretty nice for any Chemistry student, or Chemist (who tries to refresh his knowledge, like me).
Thanks! 😃 Cool stuff right?
So when H+attacking Oxygen i mean if oxygen has already "bond" with li or na.@@OrgoMadeEasy
@@OrgoMadeEasyso H+ is better counter ion rather than li and na? I mean i want reduce keton to an alcohol by adding h3o+ molecul
this guy is a legend
I think your videos are great. You have a very relaxed way of presenting, you don't try to be fancy or perfect, keep it up.
You gave me the correct direction of thinking over this concept... thank you so much sir...
can you post videos on many important reagents of organic chemistry.you are simply superb thank you so much sir.
U're the best teacher!!! I love your videos!
Thanks, you explained this concept very clearly. I think that the video would be better without including the bloops though...
Jeremy Samuels Thanks Jeremy! True, I guess the bloops don't teach anything, but sometimes I like to include bloops to show that no ones perfect, and to make the video a little more relaxed? lol I try to not make them too long though.
Amazing explanation. Thank you.
No problem Ali! I'm glad it made sense to you! :D I was so excited when I learned this, and knew I had to share it with everyone.
thanks sir.... Ur video proves very beneficial for me .. I have totally mess up BTW nabh4 and lialh4 but ur concept was amazing and now I am totally clear abt the difference.. hope u could tell me and reply my ques --- Optically active 2- iodooctane when treated with radioactive NaI128 in dry acetone rate of loss of optical activity is twice the rate of isotopic exchange... plz explain it...????
Enlightening!! Yes dude!!! Thanks a lot
Great video explanation, but LiAlH4 does not reduce carboxylic acids by nucleophilic addition/attack. Because a carboxylic acid (unlike ketones or aldehydes) has an acidic proton, LAH will instead act as a base in excess, and then do another nucleophilic addition when it is made into the aldehyde further on in the mechanism. :)
You’re totes right! I realized this in 2016 after I made the vid 😅. Most schools though don’t require students to know the full mech/aren’t tested on it. So luckily this explanation is simpler/still sort of works!
nicely explained bro..keep it up
Wowwww thanks for such a good explanation
Thank you!! No point of ambiguity I know it's funny but your explanation and behaviour was also cute😎😁
Li+ is smaller than Na+, making the + charge more concentrated/stronger to better stabilize O- and keep C+ more available for H- nucleophilic attack.
So H+ is more stonger right? Smaller orbit so its make ketone to alcohol by adding nabh4 + h3o++
Do the actual video please how to make Lialh4
thanks
Really nice.
it was a good explanation
Amazing✌️✌️
@ 2:36 how did the hydrogen attach the carbon where it already has 4 bonds around it??????
It wont happen, this step is wrong
in C=O double bond. Oxygen is very electronegative and pulls all the electrons away from Carbon making Carbon partially +. In LiAlH4 or NaBH4, Hydrogen is more electronegative than Aluminum and Boron and both are more stable with 3 bonds not 4 (full at 6 e- not 8). So H can take 2 electrons from B or Al and become H-. C is electrophilic with PARTIAL + and H- is nucleophilic with FULL -, so the H- can attack C(+) and electrons in C=O double bond can move to the electronegative Oxygen. C still has 4 bonds, C=O becomes C-O.
Watch his previous video or check out Khan Academy, to see this visually.
Good job :)
Ty
Tysm sir 💖
You’re very welcome Lalita! 😄
Great vid thx
Frank let's go
Launch all Hydrides on my mark… Mark! 🚀
It was definitely helpful but I liked it even more bcz u're so cute !!
Why not use LiAlH4 all the time?
Biblo Hudson sometimes you have a Ketone and a Carboxylic Acid on your molecule but you only want to reduce the Ketone down to a Alcohol but not the Carboxylic Acid. 😉
I am from india 🇮🇳🇮🇳🇮🇳
LiBH4 ?
waww