Angle of twist due to torsion in a shaft with varying cross section
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- Опубликовано: 15 май 2017
- This mechanics of materials tutorial goes over an example of finding the angle of twist due to torsion in a shaft with varying cross-section.
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Thanks for watching, I hope it helps!
you did an awesome job. I am very thankful for your video!!!
Thanks!! 😊
Love your work! Thank you so much.
Wow thanks Sadaqat!!! 🙌
thank you!!! this helped so much
Glad it helped! You can find the rest of the playlist here: engineer4free.com/mechanics-of-materials =)
Thanks!
You're welcome!
And u r doing good job
Thanks Siffat =)
Hi, what would change if one was asked to calculate the angle of twist for the wider part of the shaft, i.e, 0.4m from the wall?
what will be the maximum shear stress?
If both ends are fixed and we have a statically indeterminate shaft, will phi at the intersection of the two cross sections be equal, even though we have varying J?
Hi Sir!
What would be the new condition of Φ if we also have the same small dia. shaft with the same clockwise torque (0.5kNm) on the other side of the big hollow shaft?? What would be the changes in Φ?
Hi! Great video,just a doubt, how will the internal torque at section 2 be the same?
It must be the same for static equilibrium. What’s not the same is the stress and strain in regions 1 and 2, as they have varying cross sections.
I need mini project this model
Great video. What software are you using?
Thanks! Ive got a list of all the hardware and software that I use at engineer4free.com/tools 👌
Perfect
Thanks!!
@@Engineer4Free my structural exam is in 1 day, wish me luck :D
@@user-qm8dz8dn7h ahh, good luck!!
what is relation between length and angle of twist
Linear relationship φ = TL / JG Watch this video: www.engineer4free.com/4/torques-and-angle-of-twist and then check out all videos that I did on this topic, videos 14-21 here: www.engineer4free.com/mechanics-of-materials.html
what if the length says.. 1000 ft, those torque would reach that point if different diameter / cross section, since we need minimum torque allowing the torque transfered to the end of the pipe
I need mini project
What if both ends are free ? How to calculate the angle of twist ? The torques are at the both ends.
No difference. If both ends are free the torques need to be equal and opposite for the member to be in static equilibrium. The reaction torque in this video is equal and opposite to the applied torque, so whether you draw the wall or not, it will be the same method to solve.
you start on the end of the shape, and once you get to the other end, you would add the torques if they are in the same direction or subtract the torques if they are in opposing positions. Once the torque is calculated you complete the problem as in the video. Thank you very much for your question.
If for the stepped shaft(ABC) the twist is T at the free end C and the Length of AB is 100cm and Dia AB is 4cm and Length of BC is 50cm and dia BC is 2cm what will be the angular twist at c. Given angular twist at A is q
At A the shaft is fixed and at C it's free
The angle of twist at the fixed connection will be zero. Follow the exact same formula I use in this video phi_=sigma(TL/JG)_i . phi = angle of twist at free end c. Do TL/JG for section AB and also section BC, add them up, and you will get phi.You'll need to know the G, which depends on the material too.
@@Engineer4Free Thanks for the reply bro
@@Engineer4Free but don't we use sign convection , do we just add them up , as counterclockwise moment is positive and clockwise is negative?
Namaber
G= 77GPa , that steel is as soft as aluminum ;)
Eyyyy I think your thinking of E not G 🙃. Check em out: www.google.com/amp/s/www.engineeringtoolbox.com/amp/young-modulus-d_417.html - www.google.com/amp/s/www.engineeringtoolbox.com/amp/young-modulus-d_417.html
wrong formula for polar moment of inertia
Bro i think you did a wrong solution because section 2 must be negative torque