Thank you for this! You really explained it well! I am really at loss on the internal torque, but you explained it clearly with the fbd and td. Thanks again!
Hello Teacher , Thanks for your helpful videos and it’s help me a lot . I really appreciate your efforts that you are putting to help students who are have some difficulties like me :( . I’m sorry for my English ,it’s my second language . Thanks a lot Prof ❤️❤️❤️❤️❤️❤️ The words aren’t helping me to describe to you how I appreciate it :( I’m going to share the videos with my colleagues that all what can I do to thank you 🙏
Hi, Could you please explain the use of the right-hand rule? Can we simply decide the direction of the x-axis as we want? Additionally, can we define the thumb’s direction (inwards or outwards) as positive based on our preference? I’m a bit uncertain about how we establish these definitions and under what conditions they apply. Thank you.
From about 2.20 I talked about the sign convention I applied. To be honest it doesn't really matter which way you apply the signs just as long as you're consistent.
@@theryderproject5053 my apologies in advance if I sound ridiculous... my concern here is that you have defined clockwise torque @B as positive. In that case, how is torque @ section BC defined as positive again? Is that not inconsistency given the sign convention you defined? Another concern would be if torque @BC is determined as positive, the final answer for angle of twist is affected hence i wanna be sure? Thank you for your prompt response.
@@shannaidu6645 The torque diagram at 4.40 is where the torque in each section comes from. I have continued the sign convention here (the one discussed earlier) where the torque applied at B is positive. Does that answer your question?
@@theryderproject5053 ur torque diagram makes complete sense. but im using the sectioning method . having a tough time tryin to relate the both of them.
@@shannaidu6645 is the sectioning method where you take a cut through a section and then calculate the internal torque at that point? If so, it should be equivalent - just apply the process of drawing a FBD with the internal unknown and then use equilibrium to solve for it.
The diameter d=100mm, The diameter of BC d2=100mm. Me = 3.14 kN·m, The allowable shear stress [] = 60MPa. Draw the internal torque diagram and point out the dangerous section ； Try to determine and check strength condition; Check stiffness condition.
You would need to be asked the angle of twist relative to some other point. For example, twist at D relative to A. Then you would just look to calculate the twist in the sections between the two points. (In the existing wording of the question, it infers to look relative to the fixed point).
Hello Teacher , Thanks for your helpful videos and it’s help me a lot . I really appreciate your efforts that you are putting to help students who are have some difficulties like me :( . I’m sorry for my English ,it’s my second language . Thanks a lot Prof ❤️❤️❤️❤️❤️❤️ The words aren’t helping me to describe to you how I appreciate it :( I’m going to share the videos with my colleagues that all what can I do to thank you 🙏
![[311] TORSION: Angle of twist of Shaft with multiple segment](/img/1.gif)
Best explanations on shafts so far. Thanks so much!
Thank you for this! You really explained it well! I am really at loss on the internal torque, but you explained it clearly with the fbd and td. Thanks again!
GREAT VIDEO. You taught me in 12 mins what my lecturer couldnt teach in 2 hours.
Thousands of gratitude. Actually you helped me to achieve 2$ in 12 min
I'm glad that this kind of video exist, compared to my prof, it easy to understand
madam - excellent - excellent - excellent = concepts cleared - thank u -india
Hello Teacher , Thanks for your helpful videos and it’s help me a lot . I really appreciate your efforts that you are putting to help students who are have some difficulties like me :( . I’m sorry for my English ,it’s my second language . Thanks a lot Prof ❤️❤️❤️❤️❤️❤️ The words aren’t helping me to describe to you how I appreciate it :(
I’m going to share the videos with my colleagues that all what can I do to thank you 🙏
Hi,
Could you please explain the use of the right-hand rule? Can we simply decide the direction of the x-axis as we want? Additionally, can we define the thumb’s direction (inwards or outwards) as positive based on our preference? I’m a bit uncertain about how we establish these definitions and under what conditions they apply.
Thank you.
THANK YOU MAAM .LOVE FROM INDIA 🇮🇳🇮🇳
That was really helpful, thank you.
The torque @ TBC is to be negative 20N.m since you defined clockwise torque as positive. Right?
From about 2.20 I talked about the sign convention I applied. To be honest it doesn't really matter which way you apply the signs just as long as you're consistent.
@@theryderproject5053 my apologies in advance if I sound ridiculous... my concern here is that you have defined clockwise torque @B as positive. In that case, how is torque @ section BC defined as positive again? Is that not inconsistency given the sign convention you defined? Another concern would be if torque @BC is determined as positive, the final answer for angle of twist is affected hence i wanna be sure? Thank you for your prompt response.
@@shannaidu6645 The torque diagram at 4.40 is where the torque in each section comes from. I have continued the sign convention here (the one discussed earlier) where the torque applied at B is positive. Does that answer your question?
@@theryderproject5053 ur torque diagram makes complete sense. but im using the sectioning method . having a tough time tryin to relate the both of them.
@@shannaidu6645 is the sectioning method where you take a cut through a section and then calculate the internal torque at that point? If so, it should be equivalent - just apply the process of drawing a FBD with the internal unknown and then use equilibrium to solve for it.
The diameter d=100mm, The diameter of BC d2=100mm.
Me = 3.14 kN·m, The allowable shear stress [] = 60MPa.
Draw the internal torque diagram and point out the dangerous section ；
Try to determine and check strength condition;
Check stiffness condition.
what if problem asked to find the angle of twist on D
You would need to be asked the angle of twist relative to some other point. For example, twist at D relative to A. Then you would just look to calculate the twist in the sections between the two points. (In the existing wording of the question, it infers to look relative to the fixed point).
Amazing. Thanks .
thank you
thanks .
How we will find Angle if G isn't given
Coz the question with I'm dealing now is without value of shear modulus 😊
If you're given the material the shaft is made from then you can look it up (eg. In textbook or Google)
❤❤❤
Good
Hello Teacher , Thanks for your helpful videos and it’s help me a lot . I really appreciate your efforts that you are putting to help students who are have some difficulties like me :( . I’m sorry for my English ,it’s my second language . Thanks a lot Prof ❤️❤️❤️❤️❤️❤️ The words aren’t helping me to describe to you how I appreciate it :(
I’m going to share the videos with my colleagues that all what can I do to thank you 🙏