In the first example the transitive closure of R appears to be not transitive because (6,8) and (8,10) are included in the relation but (6, 10) is not included.
Thanku sir❤.. Sir concept to clear ho jaa rha but appne question thoda kraya hai es liye prectice nhi ho paa rha ..😶 So sir can you please make one shot latest video of all unit , which you involve more practice questions...which we could make Good marks in the exam..😊
Sir aisa ho skata hai kya....ki w4 kai pehli hi w2 mai hi sab jagh par 1-1 aaye 0 ke badle...to bhi anwer correct hai na..mere ek problem mein aisa ho raha hai..plz reply
Sir ager W0= me 1st coloum me sare zero hai tho kya hum W1 solve ker sakta hai kya ? , Sir mera questions hai A{1,2,3,4} R{(1,4),(2,2),(2,3),(3,2),(4,3)} sir ye question hai fine the transitive closure using warshall algorithm
Sir Pi and Qi ke har value ke liye pair banega?? Suppose Pi ke under 3 elements hai and Qi ke under 2 to total 6 pairs banenge?? Pi ke under har element ka Qi ke under ke har element ke sth pair??
22:35 wrong positioning of (2,4)
@@vaibhavthakur9890 yes dear correct please
In the first example the transitive closure of R appears to be not transitive because (6,8) and (8,10) are included in the relation but (6, 10) is not included.
Yes because sir had by mistake taken 8 , 10 as 6, 10 while making matrix
yes sir (2,4) mistake but we understand
Yes, dear
There is mistake by me, sorry
Final ans of questions 1 is
{(4,4),(4,10),(6,6),(6,8),(6,10),(8,10)}
It was mistake by sir but its ok
Thank you very much sir
Yes dear
I did this mistake
wo mistake (2,4) ki position ko 1 karne me hui hai@@dr.anuj.fearlessinnocentmath
Good
Sir warshall's algorithm AKTU - 2023-24 Ke syllabus mai hai ya nahi ?
Hai dear
@@dr.anuj.fearlessinnocentmathok sir 😊
MISTAKE!!! you have to insert 1 at 2,4 in w3 but you inserted it at 3,4
Yes dear
Please correct it
Sir is this topic included in syllabus this year or it has been removed ? Please reply
Ye by name syllabus me nhi hota but ye syllabus me hai
Thanks a lot sir..✨🙏🏻😊.. amazing lecture..
Welcome dear
Thanks sir for amazing content 😊
Welcome dear
Sir w3 mai 2,4 position p 1 nhi h pehle se
Ok dear correct it
Thank you so much Sir!
Welcome dear
You are god for us aap nahin hote to kya hum log ka..... Agar jindagi mein kuchh ban gay tho milane jarur aayaga....🎉🎉🎉🎉🎉
Very nice dear
Best of luck
Sir kya ye topic aktu syllabus me hai
Yes
Sir yeh wala topic toh syllabus me mention nahi hai toh kya eese padu ke nahi 😢
Isse question aata hai
Last year bhi ye mention nhi tha
Ok sir
Sir, i think there is no warshall's algorithm in current syllabus
Ok dear
pi and Qi Row and column index h?
Notation
Please upload recursive relation🙏🙏🙏it is also the part of syllabus
Ok dear
Where is the 2,4 pair?
Time
Thanku sir❤..
Sir concept to clear ho jaa rha but appne question thoda kraya hai es liye prectice nhi ho paa rha ..😶
So sir can you please make one shot latest video of all unit , which you involve more practice questions...which we could make Good marks in the exam..😊
Welcome dear❤❤
Sir aisa ho skata hai kya....ki w4 kai pehli hi w2 mai hi sab jagh par 1-1 aaye 0 ke badle...to bhi anwer correct hai na..mere ek problem mein aisa ho raha hai..plz reply
Yes dear
Sir ager W0= me 1st coloum me sare zero hai tho kya hum W1 solve ker sakta hai kya ? , Sir mera questions hai A{1,2,3,4} R{(1,4),(2,2),(2,3),(3,2),(4,3)} sir ye question hai fine the transitive closure using warshall algorithm
Take w0=w1 in that case
Ye topic included h kya?
Yes dear
Sir in first q. For W3, '1' is not present at position (2,4)
Ohh my mistake
Please correct last step.
Second to thik hai na usme to koi error nhi.
@@dr.anuj.fearlessinnocentmath yes sir
Sir, I think 1st Example solution is Wrong🤔🤔
Yes I did mistake in one entry
Correct it dear
sir first question wrong he becouse 2,4 pr 1 hoga
Yes correct it
Sir Pi and Qi ke har value ke liye pair banega??
Suppose Pi ke under 3 elements hai and Qi ke under 2 to total 6 pairs banenge??
Pi ke under har element ka Qi ke under ke har element ke sth pair??
Yes dear❤
Recursive definition of relation
sir ye topic rah gya syllabus m de rkha h please bta dijiye ye kya hota h ???
Ha upload karta hu ise bhi jaldi
@@dr.anuj.fearlessinnocentmath sir 26th dec se st1 h unit 1 ka paper higa to unit 1 k jo topic rah gye h jldi upload kr dijiye sir please !!!!
@@genjiplayzzz6674
Unit 1 to complete hai
@@dr.anuj.fearlessinnocentmath recursive definition of relation unit 1 m hi h sir bo rah gya h
@@genjiplayzzz6674
Ok got it
I will upload soon
Nice content sir , but 1st example me apne galti se ek point miss kar diya 6,10
Yes dear
Correct it
@@dr.anuj.fearlessinnocentmath ok sir . Apke videos bhaut Jayda helpful hote h sir
Sir please
Syllabus jldi complete kra do 🙏🙏
Yes dear
loveyousir will you marryb me, fir i'm never gonna fail in my maths exam
😀
You are wrong in 1st question in W3 (2,4) position
Yes dear correct it