KIRCHHOFF'S VOLTAGE LAW | SOLVED PROBLEMS IN KVL IN HINDI (PART-1)
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- Опубликовано: 9 ноя 2024
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TODAY WE WILL STUDY KIRCHHOFF'S VOLTAGE LAW (MESH ANALYSIS) PROBLEM NO.1.
👉 HOW TO SOLVE SIMULTANEOUS EQUATIONS IN CALCULATOR :
• HOW TO SOLVE SIMULTANE...
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I1=0.44, I2=2.33,I3=0 for the given problem Sir
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Shukriya.
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Sir in loop 3 , why we take i3 -i2 in positive. It should be negative according to your loop 1 explanation as we r taking voltage in positive?
in loop 3 the current is flowed into positive that why it Is postive
I HAVE ANSWER THIS QUESTION IN MY 7TH DOUBTS SESSION. PLEASE WATCH IT.
Correct brother
Sahi baat hai loop 3me clockwise or anticlockwise ka alag alag polarity sign hota hai same nhi hota
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Sir tell me how to solve a kcl rule if l use kl rule in kvl tell me l am Ansh from India jalandhar
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Video on Nodal analysis will come on Monday Morning..... please wait & keep in touch
I already uploaded 3 videos on KVL (Mesh analysis).
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03:36 Using Kirchhoff's voltage law to find current and power consumed in 3 ohm resistances by using mesh analysis.
07:12 Apply KVL in loop no.1 and write the algebraic sum of voltage across all elements equal to zero.
10:48 The voltage across the 2 ohm resistor is represented as 2 * I1.
14:24 There are two methods to solve the given circuit equations
18:00 Follow the method of writing voltage sources based on the direction of current entering
21:36 There are three simultaneous equations in the given text
25:12 To solve the problem using Cramer's rule, we need to find the current through the 3 ohm resistance (i2).
28:48 The current flowing through the 3 ohm resistance is 0.444 A and the power consumed is 0.591 W.
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