16 - Kirchhoff's Current and Voltage Law (Concept and Solved Examples)

[@saxkreativehub]

This is the best Kirchhoff's law explanation I have ever received, thank you so much!

[@SkanCityAcademy_SirJohn]

Thanks so much

[@HanafiMdoka]

This is the best clear explanation I've ever had 😢God bless you 🙏

[@SkanCityAcademy_SirJohn]

Amen, and thanks so much

[@arnavhegde183]

I thank this man for teaching me something both my School and tution failed to do so

[@SkanCityAcademy_SirJohn]

Aww thanks so much

[@SawawaMkandawire]

Wow you are the good teacher,thank you

[@SkanCityAcademy_SirJohn]

Thank you very much

[@mctontoh4165]

The best explanation ever

[@SkanCityAcademy_SirJohn]

Thanks my brother

[@_WAYZZZFX]

Your explanations are so clear

[@SkanCityAcademy_SirJohn]

thanks so much

[@mafedilemashumu-up4bd]

Thanks sir u are the best 🎉🎉🥳🥳

[@SkanCityAcademy_SirJohn]

You are most welcome.
Where are you watching from?

[@megangibbs2627]

Thank you so much! This video was so helpful.

[@SkanCityAcademy_SirJohn]

You are most welcome

[@RichardFearGod]

I like your approach to teaching bro

[@SkanCityAcademy_SirJohn]

Aww thank you very much

[@emmanuelquarshie-yx8gz]

you nailed it bro! Thank you for this video

[@SkanCityAcademy_SirJohn]

You are most welcome.

[@ntukwasi]

This was so helpful! There was a part of these concepts that had confused me in the past, but you cleared it up so easily! Thank you!

[@SkanCityAcademy_SirJohn]

You are most welcome Agu

[@Paganini-Liszt]

I am going for Electrical Engineering, good luck to you all!

[@SkanCityAcademy_SirJohn]

Good luck

[@Paganini-Liszt]

ty! really helpful video

[@SkanCityAcademy_SirJohn]

@Paganini-Liszt thanks so much

[@FruHoseaTse]

thanks very much for your help today

[@SkanCityAcademy_SirJohn]

You are most welcome

[@adeharry4973]

Thanks my Ghanian brother

[@SkanCityAcademy_SirJohn]

You are most welcome Mr Ade

[@AlobwedeNehemiah-ff4mc]

Thanks for explaining

[@SkanCityAcademy_SirJohn]

You're welcome, thanks for watching

[@StephenBuah]

Please can you teach how to identify if a current is in series or parallel

[@LeoPetala-iv7bw]

Thank you very helpful

[@SkanCityAcademy_SirJohn]

You are most welcome

[@NontobekoNgidi-qb3eo]

❤🎉awesome sir thank you 😊you just saved me from drowning 😂😂😂

[@SkanCityAcademy_SirJohn]

Aww nice feeling for you. I'm really happy for you❤️🎉🎉😂😂😂
Where do you watch me from?

[@mkepler5861]

can you explain why you have current flow coming out of the left battery going to the right battery. isn't it impossible for a positive to be attracted to another positive. the 4 ohm resistor can only have current flowing through it from the right battery. your calculation is wrong!!! mike

[@SkanCityAcademy_SirJohn]

Great observation, we just considered the conventional flow of current which says that current leaves the positive terminal of a source, and considering the left battery 32v as reference. It doesn't mean the solution is wrong. You can ask well use a different approach. Thank you

[@DhammikaSiriwardhana]

Wery nice teach

[@SkanCityAcademy_SirJohn]

You are most welcome

[@tbkzinventor6371]

Nice vid helpful

[@SkanCityAcademy_SirJohn]

Thanks so so much

[@s.danboyigangs9736]

What is the full meaning of IR

[@SkanCityAcademy_SirJohn]

IR is current x resistance= Voltage

[@s.danboyigangs9736]

@@SkanCityAcademy_SirJohn thanks body

[@charlestoneoyoo]

Damn...you are goated..I just understood this thing or the first time in 2years. Thank you so much

[@SkanCityAcademy_SirJohn]

You are most welcome

[@osmankoroma6495]

Perfect 🥰

[@SkanCityAcademy_SirJohn]

Thanks so much Osman

[@TobilobaAkintujoye]

Your loop 1,why don't you have a negative sign for 2I and negative sign for 8(I-I1),since current flows from positive to negative

[@SkanCityAcademy_SirJohn]

No please, it's supposed to be +2I like you see in the video because we take the conventional flow which is same direction as current I

[@emmanuelchidera574]

I am little bit confused why there was a negative voltage drop between the I¹ & I²

[@SkanCityAcademy_SirJohn]

I don't get your question. Can you come back again

[@syafiqsalim3457]

brother the equation 2 why all devide by 8?

[@SkanCityAcademy_SirJohn]

Because we want to make I the subject

[@syafiqsalim3457]

@@SkanCityAcademy_SirJohn can we devide to any number?

[@SkanCityAcademy_SirJohn]

You can, but to make I stand alone you divide by the coefficient of I which is 8

[@emmanuelchidera574]

Yh
I'm confused there too

[@UnderratedGamer714]

​@@syafiqsalim3457 So Just don't divide by 8, instead take the 8 which is in multiple with I on the other side, so it will get divided there.
I hope you got the logic of what I meant here

[@Ocean-b7u]

But what if we have another resistance of 5ohms parallel to 2ohms ......how to do that

[@SkanCityAcademy_SirJohn]

Well it changes the nature of the question. You can either use resistance combination or current division at the effected area.

[@frownsmiley]

niceee

[@SkanCityAcademy_SirJohn]

Thank you very much.

[@hatdogxpandesal8168]

bro u are wrong
g

[@SkanCityAcademy_SirJohn]

Can you please specify the time and why you think I'm wrong?