Thank you so much for your lecture.. I was almost crazy since I kept failed to find right CEF. Now I can finally finish my assignment after watching your video. Thank you so much😭😭😭😭😭😭😭😭😭love from Korea💙💙
You are a lifesaver, Especially the part about conditional expectations and their dependence. Question: At 6:20, why is the integral over dy and not dx?
might be wrong but we set X = x, so X is constant and Y is "variable" - which makes sense since we are dealing with how Y depends on the value of X = x here. if u meant the top integral then that's just the definition of the expectation of Y for the continuous case
Last part about f_z(z)...I'm not sure about my step 0 2 step procedure: 1)find CDF of Z. 2)differentiate to get PDF of Z -1) find f_X. Just integrate the joint (f(x,y) = x+y) with respect to y...or, by symmetry it's similar to the f_Y in the video. f_X = x +1/2 0) finding the inverse From (3X+2)/(6X+3)
Thank you so much for your lecture.. I was almost crazy since I kept failed to find right CEF. Now
I can finally finish my assignment after watching your video. Thank you so much😭😭😭😭😭😭😭😭😭love from
Korea💙💙
You are a lifesaver, Especially the part about conditional expectations and their dependence.
Question: At 6:20, why is the integral over dy and not dx?
might be wrong but we set X = x, so X is constant and Y is "variable" - which makes sense since we are dealing with how Y depends on the value of X = x here. if u meant the top integral then that's just the definition of the expectation of Y for the continuous case
Last part about f_z(z)...I'm not sure about my step 0
2 step procedure: 1)find CDF of Z. 2)differentiate to get PDF of Z
-1) find f_X. Just integrate the joint (f(x,y) = x+y) with respect to y...or, by symmetry it's similar to the f_Y in the video. f_X = x +1/2
0) finding the inverse
From (3X+2)/(6X+3)
Thank you so much