Free-Body Diagrams
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- Опубликовано: 25 авг 2014
- 043 - Free-Body Diagrams
In this video Paul Andersen explains how free-body diagrams can be used to solve kinematics problems. The only two parts of a free-body diagram are the object and all external forces acting on the object. Numerous situations are presented and free-body diagrams for each are illustrated.
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I'm gonna stop going to class honestly I don't know why my professor couldn't just explain it like this
I concur
My teacher spent 1 semester teaching these things and you know what i understood 0% about free body diagram. This video taught me and gave the most crystal clear idea about free body diagrams. Thank you
you taught more in 6 mins than my actual teacher taught in a year thank you!!!
Good Job Anderson. Really appreciate the simplicity and checklist at the beginning!
Very concise and informative, great review to remove any ambiguity from the subject
Your doing amazing work. Keep it up!
Honestly i could get a 5 on the AP exam by just watching your videos not even going to class
Rohith Raman h
how much did you got?😁
hey! um a student from india..nd i find your videos reallyyy helpful!! its like they are super reliable ! i can count on your videos even 1 day before my final exams ! thankyou so much :) :D
another Indian joins the league! :)
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you are GREAT, man... seen many of your videos. thank you, thank you!!! ;-)
Thank you. This video was extremely helpful.
Excellent video on FBD. Thank you very much.
It was very helpful. Thank u so much. Keep making videos
amazing video... thanks a lot... this was one tough topic hampering me in physics... until now!!!
happy to see this video
All I can say is that you are a Brilliant teacher.
Thank you! This was very helpful!
You are a great teacher.
I think khan academy should also include pictures like this.
you make every thing so easy thank u so much you are a great teacher
thank you for this!
Yes it was helpful , thank you very much and keep doing it . I had forgot the tension force in the last 😅😅
I wish you were my teacher! So helpful and informative :)
Wow that is so true, he is a really good teacher of physics, very nice Bozeman very nice.
No he sucks
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Yes, absolutely perfect explanation
Love the gameplay!!
Thank you so much! Very helpful :)
Great lesson, Thank you!
revisiting statics trying to get well grounded. once I get to that point the math will be just plugging in. I've noticed unless I know a subject thoroughly I get side tracked. looking forward to viewing your videos.
Great helpful video!
Pretty good one, as always ( of course ).
Short request: A parachute would be a great example, in it's different stages...
Maybe next time.
Have a great day, Mr. Anderson !
thank you so much very helpful!!
Very helpful life saver thank you so much mean a lot!
that was really helpful, thanks!
nice video, please could you please enlighten me, on why the normal force of the inclined plane is perpendicular to the platform?
thank you
For the last example (motionless car with a rope), would there be a static friction force vector opposite of the tension force vector?
Great video
THE KING
I have always been told that the normal force acts from the where the object and the ground meet (contrary to your depiction with the normal force acting from the object centre), but that would that would make it difficult to decompose into x and y axes. It makes more sense to me that way however, as the normal force is a force acting from the ground on the object. Is one more corect than the other?
At 5:12 , since the car is in rest at the peak of its flight, don't we need an upward force to balance the car if only for that instance. If we take the frame where that car is in rest, don't we have to think about the upward force too?
very helpful! how do you know how long you should make the vector arrows? for example the tension arrow you drew for the last example was slightly longer than the one for the for the friction arrow where the car was rolling down the angled platform.
Angela Banda it’s based on the magnitude of the force
Anyone plz. 4:05 How is friction exerted by the ground on the car is to the left when the car is actually accelerating to the right.
very good lesson
Thank you!
amazing video , keep it up :)
I thought that this video was too short. I wish the explanations had been a little more thorough and terms defined. And, I am a great fan.
when the car is inclined at an angle as it accelerates downward, why is it that there was no label for acceleration which is the opposite of friction?
whats the difference between traction and kinetic friction?
thanks the clarity
Good vid helped a lot
Thank you
thank you
Thank you for helping the day before my mechanics exam. Nd i am india too
Love you
thank you.
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thank you! big help man :)
Thanks man
haha im watching this for my physics final less than 12 hours before my final thank you so much
I wish you taught at my school!!!
How about an object Suspended in the air. In this case a cable cars found in skiing areas
Thanks sir
thx
ily man
why is the force of friction on the car on the slope on the right? why isnt it to the back of the car since friction helps impede movement?
+Nicole friction always acts opposite to motion so if the car was moving right,friction would act to the left
thefunway123 Doesn't the wheels of the car roll backwards in orientation? So technically friction acts in the same orientation as the car?
3:59 hi i want to ask that why are F fraction the forced exerted to the car by the ground ? Following after Newton's third law, we all know about if an object exerts an any force to other object, it will be exerted the same magnitude force. So if the car exerts a force to the ground, the direction of the force must be perpendicular to the ground, or we can say that the forces exerted by the car have the same direction as the gravity, so if the ground exerts a force back to the car, this force must be the same magnitude but opposite in the direction. But if we follow what you were talking in the video, the F fraction ( the force that the car be exerted by ) will have the direction of the right, not opposite to the gravity anymore. So i rellay confused if i had any misunderstanding wrong or something, hope i will get your answer soon
awesome
At 4:05 you say "frictional forces of the ground". Please explain those forces.
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Thankyou
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What do you use to make you videos
A stationary car will have force of static friction, won't it?
Cool
Why is there no applied force or acceleration force in the second last example? Please answer asap I have a test on Monday..
how'd it go
killed him.
thank
3:56 What is F traction ?
F traction in this case would be acceleration. F just means force though, so force traction (movement) to the right.
COMIN IN CLUTCH
Epic
Co-ordinate system? No idea what it is/what is needed for?
Just to simply the understanding of which direction of all the opposing forces relative to each other. X-y axis graph directs itself to the direction of the surface where the object is based on. If upslope, picture the x-y axis graph upslope as well.
theory oni much..there should have been a calculation example so its easier to understand
but wouldnt the upward force action on the car thats in free fall be drag and not a frictional force.
they both cancel out
Can you label the Force of Gravity as Weight, or W?
UWBadgersfan28 no
u need to write mg there Because F(Force) = W(Work) = MA and here A = Gravitational acceleration(G) therefore we can write F = MG instead of gravity. hope it helped :)
Saksham Sahgal gravity is measured in Newtons so (N)
So the friction force disappears if there's tension?
No, frictional force comes from the resistance of two surfaces as one tries to go across the other. Since the tension force is in equilibrium with the normal force and the gravity force, the object is still, so there is no friction.
i have a doubt mr anderson
does weight depend on inclination?
weight is the force with which an object attracted towards the center of earth.
weight of an object w=mass*gravity
the only possible way to increase or decrease the weight is either change in mass or change in gravity. in the video showed weight of an object on inclined surface is less when compared to weight of an object on horizantal surface.can u explain me how weight of an object depends on inclination?
I think you might be right Vinod. I was thinking about this too, when I watched the video. I think that the NET FORCE on the object changes, because of the inclined plane, but not the actual force of gravity on the object. I might be wrong, but when I saw your comment, it helped me think I might be right. :) Thanks, for posting.
I have to say, though, these videos from Bozeman Science are good.
i've been watching alot of videos about free body diagrams and woa my teacher is actually explaining everything wrong that's why i couldn't understand her. i wish i had a better teacher because im always having a hard time in science.
good
When you're shooting the car into the air, there should be air friction, right? I'm not sure; this is my first time learning this.
I think in that example he's talking about the moment when the car is paused in the air at its peak, not shooting up through the air. When it's paused in the air and about to fall down, there is no air friction resisting its upward motion because it isn't traveling up. Hope that answered your question.
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Isn't traction an internal force?
No,he said it. As the car pushes on the ground , the ground pushes back on it. Here, we don't include the force exerted by the car on the ground cause it's an internal force but the equal and opposite force by the ground on the car is included because it's an external force. btw Sorry for late reply.
@@yalenagloria4547 Hello! How is traction (a force applied by the ground to the rotating wheels of the cars) an external force whereas the push force applied by the wheels to the ground an internal force? Aren't internal forces suppose to occur in pairs and cancel each other out?
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I stopped watching after I saw that you don't take your shoes off when you weigh yourself...10/10
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I do not understand
who else is off their seneca homework?
Who here is learning this for their 7th grade science test
me
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@@sioal 8th grade
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