Thank You! I'm a student in cairo university faculty of engineering and it's a rotted place that has crazy dense rooms (200-300 students) with unhelpful professors making very difficult exams. I don't recommend it for anyone
Uda and Udc are the unit vectors. so 4.5 and 3.5 are both magnitude of position vectors Rda and Rdc. sqrt of 3^2 + 1.5^2 + 3^2 = 4.5 and sqrt of 1.5^2 + 1^2 + 3^2 = 3.5. Hope it helps.
@@hizamshahrusmi still not making sense here. for Rda why is there two 3^2 ? it is 3 up and 1.5 to the left of D origin point, but then where does the other 3 come from?
@@matteovinci83 A(4.5, 0, 3) and D(1.5,1.5,0). Rda is the difference A-D (head - tail) , so (4.5-1.5, 0-1.5, 3-0) then u will get Rda is (3,-1.5,3), hope it helps.
Finally I found a worked out solution to a problem similar to the one I needed to solve. I'm an electrical engineering student in a Vector Analysis class where they gave one of these equilibrium problems. I haven't had physic in years so I can't exactly remember how to solve these static problems. Thanks for posting. I'm so glad EEs don't have to take statics. I hate this shit! Give me an electrical circuit any day!
the Ez equation you can solve for the unknowns. with the Ex equation you solve for DC in terms of DA. then you plug that value into the Ez equation. there fore you can solve for what DA is from the Z equation. Then you plug that back into the Ex equation and solve for DC, then you can solve for the last unknown.
Great last minute help for a static exam. Really the same as 2D with the whole extra layer of third dimension. Easy to overthink
Thank You! I'm a student in cairo university faculty of engineering and it's a rotted place that has crazy dense rooms (200-300 students) with unhelpful professors making very difficult exams. I don't recommend it for anyone
Why did you divide DA by 4.5 and DC by 3.5? What would you divide DB with?
Uda and Udc are the unit vectors. so 4.5 and 3.5 are both magnitude of position vectors Rda and Rdc.
sqrt of 3^2 + 1.5^2 + 3^2 = 4.5 and sqrt of 1.5^2 + 1^2 + 3^2 = 3.5. Hope it helps.
and for DB you can do the same steps and it will give 1. so it is just Fdb because it lies on y-axis
@@hizamshahrusmi still not making sense here.
for Rda why is there two 3^2 ?
it is 3 up and 1.5 to the left of D origin point, but then where does the other 3 come from?
@@matteovinci83 A(4.5, 0, 3) and D(1.5,1.5,0). Rda is the difference A-D (head - tail) , so (4.5-1.5, 0-1.5, 3-0) then u will get Rda is (3,-1.5,3), hope it helps.
Finally I found a worked out solution to a problem similar to the one I needed to solve. I'm an electrical engineering student in a Vector Analysis class where they gave one of these equilibrium problems. I haven't had physic in years so I can't exactly remember how to solve these static problems. Thanks for posting. I'm so glad EEs don't have to take statics. I hate this shit! Give me an electrical circuit any day!
slow down
But i think ive finally figured out this coordinate system stuff...thanks
Please can you explain or show how you substituted the equations to get the final results of FDA Fdc?
Thank you
Where did you get the 4.5? That would be the length of DA. How did you find that?
because uDB was therefore unit vector abbreviated to -j. its a cleaned up version to reader's benefit, he did mentioned it as he sums them up.
You really helped me in my Math project for my final year of high school. Thank you a lot, I needed this information, but could not find it easily.
you really should have done the last steps to show the whole process from start to finish
the Ez equation you can solve for the unknowns. with the Ex equation you solve for DC in terms of DA. then you plug that value into the Ez equation. there fore you can solve for what DA is from the Z equation. Then you plug that back into the Ex equation and solve for DC, then you can solve for the last unknown.
Yes, agreed
THANK YOU! You saved my day with this exercise. Thanks!
i only got here for the algebra part, still didn't got it hahah
How to solve equation? Using matrix?
all i am given in the problem is two angles and one force, i have been working on it for like 2 hours
where is the force of BD
+Chen D
at ( Sum Fy=0 ) and (sum Fz=) there are three forces have been affected on the mass
DA is 4.5i
yeah where is it?
+alhammam alsindi
at ( Sum Fy=0 ) and (sum Fz=) there are three forces have been affected on the mass
I really aint to understand how to get the vector Fda and Fdc ? But anyone may be to help me ?
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Why did you calculated force which emerged from bucket 20lb. This is mass so you need to multiply by 9.81 right?
terrible video!!! why the rush???
really helpful