Example of Functions where Limits does not exist
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- Опубликовано: 8 фев 2025
- Limits Lesson: • Calculus First Lesson ...
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This was very helpful, thanks! Also your voice is really relaxing.
Thanks. Here is related Test: ruclips.net/video/oQjjdPowWXE/видео.html
Thaks❤
thank u so much sir
Good work! why we say a function is undefined? A function is not a function if its all domain members are not uniquely mapped. It means a function is not a function if it is undefined because undefined my one of its domain members is undefined.
Every function has its domain in which it is defined. Example: Square-root function is defined for values greater than or equal to zero. Hope that helps. Thanks
Thanks a million !!
For example a, I was unsure how to explain how there is no limit, since you cannot say the left and right hand limits differ due to the fact that infinity and negative infinity are not limits. Since it is a vertical asymptote, it approaches an undefined value, which you explained perfectly. Thank you.
Perfect. Limit does not exist is a better term in the above case which you described. Thanks
thank you for this sir
If a function is undefined at a point is it necessary that the limit will always not exist at that point?
@svnspell6709 function is undefined at a hole but the limit exits. Hope that helps. Thanks
Thanks I love your voice, it is very soothing.
thank u sir
Can you please solve this question:
Show that limit of function exist:
Y = (3^n + (-3)^n)/ 4^n
so as long as it has a denominator of zero, it is considered as DNE? how about when it is an imaginary number such as i or 3i, is it not considered as DNE?
Hello Anil Sir, can you explain some functions for which limit exists when x tends to a but the function is not defined at point a, limit exists when x tends to a but not equal to f(a)? That will be very helpful.
Thanks in advance
Yes you can see the example of one devided by mod x
For the first example, the limit does not fail to exist. Substitution does not work for that value true but the idea of a limit is to approach a value so even if it is undefined for the value x tends to. That does not mean that the limit does not exist
but that limit is undefined, because if you approach from the righ side you get a positive value, whereas if you approach from the left side you get a negative value. Imagine you could use x=0.0001 and x=-0.0001. You'd get different values for f(x) and that is why is undefined (I can't prove it more formally than that, sry).
I appreciate
Please reply fast i am in exam hall
LMAO
😂😂😂
😂5 years
Did you pass that exam ??? Just curious.
love from BD
i am sorry sir but you should have mentioned that you used 0 for the value of x on number d. i got confused as the limit was 1 but i was getting 0 as answer.
for no.d y is always 1. graph for further reference...
00:(1)7 Correct
this was extremely helpful!
Why is Mean Girls the first video that comes up when you search for this?
Just randomly wanted to know
Are you still alive?
@@SidhantVaibhav Lmao, yes
I hope you are my teacher. My other teacher is a same indian as you but her accent is terrible that I can literally learn nothing
I love you hope you all the best in your life
How did he get( x>=3) in question (b)?
because x is greater or equal to 3?
you need to find the domain which is x-3>=0 and u have to move 3 to the right side so x>=3
Sir thoda fast bola kriye. 2X me bhi slow lg rha h
Hi Sir, Why we're not applying L' hospital's rule in the third question ?
Most of the students here (US and Canada) do not learn about L' hospital's rule in High School.
Anil Kumar Sir,but won't the answer actually vary when the rule is applied ?!
No, You cannot apply it second time since it is 1/0. L' hospital's rule cannot be applied for 1/0 situation.
It is important to understand. Hope this example helps you to figure that out. Thing about limit x approaches zero for 1/x.
M Maneesh Kumar L’hopital’s rule I believe can only be applied by taking the derivative only in a 0/0 or infinity/infinity situation
I thought it could be used in every condition of the form a/0 (a € R) ! Thanks for that clarification.
After sex somebody got sick and he was locked up in side a 18 wheeler screaming with the aligator why? What happened?
Shouldn't we use L'Hosipitals on a????
It is not and indeterminant, and so you cannot use. Here is the video on this rule application: ruclips.net/video/hMdMHIXw2R0/видео.html
Thanks
To date, I'm still looking for this pen. Anyone please send me a link to name 🙏
Name of the pen is Trimax, very popular pen, I used it a lot in my high school..
@@Shrreyy wow thank you so much I have been waiting for this for 5 Months 🤣🤣🤣🤣
@@geoquerry oh, my pleasure 🙃
This is completely wrong, In the third question you have to differentiate with x in both numerator and denominator in the polynomial x-1/x+1 and the answer will be 1, not doesn't exist. And also in second question if left limit doesn't exist ,then we just have to take right limit and limit does exist and it is 0. Please don't tell students mistakes, I am the teacher from kkr gowtham school,ramireddy
You are right🙏🏼
Waitt, you can have a limit that is 0?
For the second example, f(x) = sqrt(x-3), most CAS's returns 0, why is that?
You cannot approach 3 from the left side. That is the reason. Thanks
Isn't there specific conditions that the limit does not exist?
Rather than examples😁sir
I really don't believe part b to be right? more explanation please
As a matter of pedagogy, throwing up a screen of equations already written is nowhere near as effective as writing them out while explaining them. Students' ability to copy and comprehend matches closely the speed of an instructors handwriting. Four equations posted with the speed of video is just too fast.
What about when applying limit rules (sum, subtract ...) for limits that don't exist? (what are special cases that despite the limit for each separate function DNE when operating on them together the limit will exist? )
Interesting to make a video. Will take this soon. Thanks
X-y/x+y exist or not when limit x andytends to 0
The squareroot of x-3 made me more confuse. In other example we can substitute the limit but for this we cant. :( WTF.
Since the square root of anything less than 3 in number b would turn out to be an imaginary number, the left side of the limit as x approaches 3 would not be real, thus it does not exist in the real number system. And finally, if one side of the limit as x approaches 3 for f(x)=sqrt of (x-3) does not exist, the whole limit would thus not exist as well.
I came because of mean girls xd
Thumbs down. You know when you are a teacher do not assumed that we already know what your are doing. Hayyysssss wtf! I wasted my time!
To get to this point you should already know certain things. It’s not a waste of time. It’s very helpful.