Equations of Motion | Easy to Difficult Questions | Grade 9 | SHIKHAR 2024 |
HTML-код
- Опубликовано: 3 окт 2024
- Hello Students!!!
Get ready to ace every subject with BYJU’S Classes 9&10, a comprehensive education platform exclusively for Classes 9 and 10 Students. The channel covers subjects like maths, science, social studies and English for CBSE, ICSE and State Boards; with dedicated classes, experiments and quizzes.
______
📢Join our Telegram Channel:
t.me/byjusclas... 🔔
👉SUBSCRIBE here & don’t forget to turn on your notifications 🔔-
/ @byjusclass910
🚀 *IMPORTANT PLAYLISTS & SESSIONS:*
✔📚 SHIKHAR Class 10 Series Playlist for Boards 2024
www.youtube.co...
✔📚 SHIKHAR Class 9 Series Playlist for Annual Exams
www.youtube.co...
📢 Have you tried BYJU's Mini Learning Program yet 🔔
Key Features:
• 3 live classes with 2 teacher advantage
• 15 days Free access to unlimited content on Think and Learn Premium App
• One on One Mentor Support
👉 Link: byjus.com/mlp-...
Do not miss this chance ⚠️
📢Signup and watch more exciting videos for FREE:
byjus.com/lear...
➡️ Download the BYJU'S App Now:
btla-androidk1...
🔷Speak English like an expert, join our spoken English classes for 2 months in just 999, register here:
byjus.com/spok...
#BYJU'S #BYJU'S 9&10
![KSI - Thick Of It (feat. Trippie Redd) [Official Music Video]](http://i.ytimg.com/vi/At8v_Yc044Y/mqdefault.jpg)
It is so helpful guys for those who all are preparing for examination then must watch
I was not avlble to attend it live..but watched it later..Thank You Sir For this session 😊😊
Homework..
1. B.1km/h
2. 7.5 secs
1km kaise solution please
Thanks for the session sir!! 😄 Please bring some more sessions on numericals because this chapter needs more practice😅😃
🔴 HOMEWORK:-
QUESTION-1:03:19
ANSWER: For police officer=
U= 0, V=15, A=2,T=?
T= v-u/a
Or, 15-0/2
Or, 15/2= 7.5 seconds(answer)
Question 8 ( 48:02 )
Solution-
For first 4sec,
T=4 , s=24 , acceleration= a, initial velocity= u
We can use 2nd eq. In this condition.....
2nd eq. = UT+1/2at²=s
Or, Ux4+1/2xax4²
Or, 4u+1/2xax16
Or, 4u+8a=24
Or, u= (24-8a)/4....... (First part)
For next 4 seconds,
T= 4+4= 8sec.
S=24+64=88
Acceleration=a
Initial velocity= u
We can use 2nd eq.
S=ut+1/2at²
Or, RHS= 8u+1/2xax8²
Or, 8u+1/2xax64
Or, 8u+8a= 88
Or, u= (88-32a)/8...... (Part 2)
NOW, IF WE NOTICE... WE HAVE PART 1 AND 2 WITH SAME L. H. S...
By comparing,
Part 1=part 2
Or, (24-8a)/4=(88-32a)/8
After solving it, we will get a=2.5km/s²
WE HAVE A=2.5
NOW, WE CAN PUT IT IN ANY EQUATION, BECAUSE WE DON'T HAVE TO FIND ACCELERATION, QUESTION IS ASKING FOR INITIAL VELOCITY....
after putting it in any of two equations ( 4u+8(2.5)=24 or in 8u+32(2.5)=88)
We will get the same answer .... That is 1...
Thus, answer is option b...1
How can we solve 1st H.W question pls tell me it's little confusing 😐 48:08
And BTW you have written T = v-u/t instead of v-u/a 😀
@@M.LifeE.2007 hey, thanks for correcting my mistake 😃
Answer-
For first 4sec,
T=4 , s=24 , acceleration= a, initial velocity= u
We can use 2nd eq. In this condition.....
2nd eq. = UT+1/2at²=s
Or, Ux4+1/2xax4²
Or, 4u+1/2xax16
Or, 4u+8a=24
Or, u= (24-8a)/4....... (First part)
For next 4 seconds,
T= 4+4= 8sec.
S=24+64=88
Acceleration=a
Initial velocity= u
We can use 2nd eq.
S=ut+1/2at²
Or, RHS= 8u+1/2xax8²
Or, 8u+1/2xax64
Or, 8u+8a= 88
Or, u= (88-32a)/8...... (Part 2)
NOW, IF YOU NOTICE... WE HAVE PART 1 AND 2 WITH SAME L. H. S...
By comparing,
Part 1=part 2
Or, (24-8a)/4=(88-32a)/8
Now you just have to solve equation....
After solving it, you will get a=2.5km/s²
WE HAVE A=2.5
NOW, YOU CAN PUT IT IN ANY EQUATION, BECAUSE WE DON'T HAVE TO FIND ACCELERATION, QUESTION IS ASKING FOR INITIAL VELOCITY....
after putting it in any of two equations ( 4u+8(2.5)=24 or in 8u+32(2.5)=88)
You will get the same answer .... That is 1...
Thus, answer is option b...1km/s
You will not get this question untill you try😃 so , try this once yourself:)
@@astha-- thank you 😊 so much that you solve and convence me, ʘ‿ʘ
Thank you 😊 again 🤗
@@M.LifeE.2007 that's my pleasure ☺️
Thanks for the solution astha🤜🏻🤛🏻
We can do the 4th question with only one equation
S=Vt-1/2atsquare
By substuting values
S=(0)t - (-3) x 16/2
S= 24 m
Those who did by using this 😅
👇
@@LONELYLEGEND-xj1hg I Did It By using this and felling like Genius!!!😄😂
Homework Answers:-
1) option b 1km/s
2) final v=15ms-¹ , intial velocity=0 and time =2ms-²
Since acceleration= change in velocity or time (a=(u-v)/t
By putting all the values 2= (15-0)/t
t= 15/2=7.5 seconds Hence , Police officer will match the speed of motorist in 7.5seconds
I couldn't come in yesterday's class 😔
@@afraa76 don't be sad you can watch recorded session too 😊
What is the short method to solve question number 7?
Final velocity v = 15 m s − 1 Initial velocity u = 0 m s − 1 Acceleration a = 2 m s − 2 Since, acceleration = change in velocity/time a = ( v − u ) / t Substituting values 2 = ( 15 − 0 ) / t t = 15 / 2 = 7.5 s e c o n d s
2:20
⭐Homework
1. 1m/s
2.7.5second
By Jagdeep Singh Sidhu
😊😊
Thankyou sir for taking a session on numericals 😃
It's so helpful for our practice ✨
Sir please gave solution the solution of questions 8 48:07
Home work ans
Sorry i didn't understand the first one i will try after some time meanwhile the second one is u=0 a=2m/s sq v= 15m/s so using equation one we can solve it
V=u+at
15=0+2×t
15=2t
t=15/2
t=7.5 seconds
-Meenu raj ❤😊
I hadn’t understood 😢
TYSM SOO MUCH SIR, NOW I'VE GAINED CONFIDENCE IN DOING NUMERICALS MUCH AND EVERRR... 💯
Sir mujhe kuchh smjh nhi aya mai kya karu??
Can anyone give me the explanation of the question 8
sir , I can't understand the 4th question in medium level
Thank you Saurabh sir for this amazing practice session!😃😃😃
Homework Question Answer:
(1) 1km/s
(2) The police will match the motorcyclist's speed in 7.5s
1km kaise ?? Solution please
@@kiran_198 First use the Second equation of motion where s=24km, t=4s
You will get an equation: 24=4u+8a...(i)
Again use the Second equation of motion
for the total distance and total time (s=88km and t=8s)
You will get an equation: 8u+32a...(ii)
On solving (i) and (ii) we get
u=1m/s
Thus, initial velocity is 1km/s
@@Avni-447 thanks sis ❤️
Thanks for this amazing session.🙂
I am not able to attend the classes live as I have my tuitions during the same time. 🙁
📖HW-
1) I am not able to solve this till now.🤔
2) v for motorcyclist= 15m/s
u for police= 0
a for police= 2m/s²
required v by police= 15m/s
Applying 1st equation
t= (v-u)/a =>t= (15-0)/2
t=7.5sec😇
Please bring more sessions on equations of motion, please🙏
Thank you for the session sir,I need a bit practice to clear my understanding
Hw)
1)1m/s
2)7.5sec🎉🎉
Amazing session
Hw
v=u+at
0=15+2×t
t=15/2
t=7.5seconds
Can we take g=9.8m/s also?
Yes
Hey had mentioned it in question 10m/s (it’s a condition) so not 9.8
@@GowthamprakashRajanawe can’t (for this question) -_-
48:19
24:31 Bro how are you getting 24 wthhh
If you use the second equation you see there is plus after UT but in retadation it’s minus because it’s a negative force (now try it) 😊
2:40 2:41 2:42
😊 11:17
For 5th question we can use. S=(u+v÷2)×t one try sir
😂😂😂😂😂😮😂😮😂😮😂😮😂😮😂😮😂😮😂😮😂😮😂😮😂😮😂😮😂😮😢😂😢😂😢😂😢😂😢😂😢😂😢😂🎉😂🎉😂🎉😂🎉😂🎉😂❤😅❤❤😊😅😂e😮😂😮😂😮❤😮😂😮😮😂😅❤😮😂😅❤😮😅😮😅😮🎉❤😂😅❤😮😂😅❤😮😂😅❤😮😮😢😮😢😢❤😮
Sir Can u please tell that in medium level Q5 in Second equation why u not write 10 as the equation is s=ut+1/2at² so the value will place is o ×10+1/2×10²but u wrote o×1/2×2×10²...sir please tell where i m doing Mistake...its helpful session thank you byjus for such an amazing teacher 👍
0×10=0 na
Sir I can't understand medium level question no.4
please change the class time
hi sir i am saileyi
I think u all searched the question from Google and just typed here to make urself homework superstar i don't think so that this question was easy
Sir 48:08 question number 8
Sir mujhe difficult part nhi aa rha h..
Homework 7.5 sec ans
1. 1km/sec
2. 7.5sec
H. W
5.question in minti I found it difficult
48m
d
sir 4 question to bina u find ke hi agaya
20 m/s
😮
Bohot accha tha sir
Omg main aaisa hi kuch dondh rahi thi
C
A) 1 km/ hr or 1km / sec 😢(CONFUSED) 😢
B) 7.5sec
😀 🎉
1m/s
hw question
given
u=0m/s
t=?
a=2m/s square
v=15m/s [ as the police officer want reach the speed of motorist ]
using- v=u+at
15=0+2*t
15=2*t
t=15/2
=7.5 sec
thanks a lot for the session sir .
Motta punda sunny miru
Sir why are you explaining the answers in speed not clearly . Its hard to understand😭😭😭😭
Bahyt ghatiaa padhatee hoo thode dhiree padhaya karo hamko bhi tum joo samjhaa rahe ho voo aahi nahi raha hai pahale aap achaa padhanaa sikho fir padhanaa ulllu teacher
Kuch respect karo vo teacher hai 😡 theme samaj nahi aya Baki logo ok aya you hai ullu 😡
You are wrong