Calorimetry: Using q=mΔTc to find Temperature + Example
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- Опубликовано: 31 окт 2012
- Hot Iron Bar + Cold Water = Final Temperature?
Use the formula mΔTc = -mΔTc to show that heat gained = heat lost and solve for whatever "x" is. In this case, it's the final temperature.
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HI - larious.
ty this 7min video helped me more than my 2hour long class U________U
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Absolutely. You can carry units throughout the whole thing if you like. I find some students get lost when there are units floating around the linear equation though.
Once more, you've taken an equation that my textbook hopelessly overcomplicated and made it simple, and once more you have my thanks.
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Me
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The way this video just saved my life!! Thank you chemistNate!!!
Cant thank you enough for doing this example. My prof made this question WAY more difficult than it needed to be and you simplified it making it painless and easy to solve. THANK YOU!!
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thank you! this was way more helpful than my physics teachers lecture
This helped so much you have no idea. Thank you so much!
FANTASTIC. what a great explanation and thanks for breaking down the steps. Explained it a LOT better than my Physics guide did, that's for sure!!! Thanks again!!!
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this is awesome thank you Nate!! A way more simplified version to what I learned.
You're the man... I finally understand this!!! Thank you for making this!
OMG! Thank you so much! You helped me so much. I have been struggling with this concept for days!!!!!
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Very well presented. Kudos to your teaching technique. You also anticipated student's questions as you went along. Well done!
Very very helpful!!! Thank you so much for taking the time to do this!
This video was the only one that solved my question...thanks!
Haha I never realized how weird it is until now, but my chemistry teacher writes the formula as q=mc🔺t and she pronounces it like "q equals mcat" 😂
Same with me, I find it easier to remember
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haha wow that’s so funny man 😂
9 equals mcat is a good mnemonic if you are studying for the MCAT exam, which requires you to know this equation ;)
lol
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Thanks alot man, been around this equation for an hour ...
BOOM! Nicely done best of luck
This just made a lot click for me. Thank you ChemistNate!
Thanks for posting this. I found it helpful and will use it with my students.
Thanks man you're a lifesaver!
Thank you so much for posting this video! I have a test on this in two days and this helped me so much!!!! Thank you.
This was so helpful . I am forever grateful.
Thanks so much! That was really helpful!
Thank you !!! I used this for a two part equation were the initial for the second part was the final for from my first part !!! Work out perfectly!!
Thank you! SO much easier than I thought
finally figured it out now that's it's 12:30 am thanks to your video! Thank you!
This was extremely helpful!! Thank you very much!!
thank you so much, I am reviewing for a final exam and this is helping me out.
Thanks a ton. This was pretty helpful!
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Thank you so much! I was so confused with my chem homework until I watched your video.
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Thank you! I tried this tonight but the Chem text was making the math so difficult to solve! You make it much easier!
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idk why but this hella made me laugh. but thanks I needed a memory refresher on this before my test tomorrow
Thank you so much for this video. I've just spent 3 hours trying to solve a problem that you made simple in 6 minutes. Completely different than all the other examples out there but finally, logic I can understand!
+ch r I've been spending roughly 6 hours on mine!
omg i have a test on this tomorrow! youre amazing haha, i know ill do better now
Very helpful. Thank you so much!!
I just wanted to say thank you so much for this video. My teacher gave the worst clues on how to solve a problem like this one so I am truly grateful to you.
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Thank you so much this video was a life saver
Good video. Thanks. I'd suggest dividing both sides of the linear equation by -4.6 as a second step though. It makes the numbers more manageable with only 'x-80' remaining on the right side.
Extremely helpful 🙏
thanks for uploading, really helped alot
SAVED MY LIFE! i have been trying to figure this out for ages and my text book is shit!. Sir, you earned yourself a sub! ily
10/10 Would solve again
Thank you so much! So helpful
Thank you! You explained this perfectly! :)
How do you know what should be - and + for the initial plugging in of information? Is water endothermic?? Not quite sure what is going on with this part.
Great! this helped drastically in my chemistry II class.
Really helpful!!!
:D
chemistNATE
Good job 👏 this video really helps
Do you have other examples of these types of Calorimetry problems? If so, can you direct me to the link? I would greatly appreciate viewing a few more of these.
helped me soo much bro thanks
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Well said!! Thank you
Literally just saved my life!!! yessss Thank youu
very helpful, thank you!
amazingly explained
Thank you for making
At 2:12-2:15 did you mean 70mL or what you wrote??
Amazing! Thanks !
THANKS A TON! This helped a lot. :)
Why isn't the Ms 80g? I thought you're supposed to add both masses?
Wouldnt the units cancel? So you would have joules?
Thank you, sir!!!
Thank you so much!
Sir I have question I want to mixed one gallon water at 10 degree how much can I add hot water at 40 degree to get water at 30 degree ?
How would you solve an more complex problem involving 3 masses and 3 specific heat capacities asking for mass? e.g ice dropped in a glass of water
Did you ever find out how to complete these? I'd appreciate some resources on how these are done.
Thanks! CHEM 121 final tomorrow. This looks way harder in my textbook when you are casually glancing through; lol.
is the x in the answer the final temperature to the iron to the water?
I'm just starting a youtube channel to help my students. I love your explanation. What do I tell them about dropping the units during the workup? Do they actually cancel out as it progresses?
Thank you thank you thank you thank you!
if you combined like terms why is there only one x in the end?
How would you do this if there were three components? But two of them have the same change in temp.
EX. 80 degree Copper dropped into 30 degree Celsius water held in 30 degree Celsius cup
Thank you so much.
thank you so much for making this video and making it so simple ive been trying to learn this the whole day and with your video i can finally understand it thx a lot
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How can u find mass with this formula.....I really need it plz help
Thank you much for helping people like me :)
Does it matter which - sign you put, either on iron or water? for q=-q... Either way result is the same, but is there any actual assignment of the negative sign?
Thank You!
thank you sir!
Thank you!
THANK YOU!
compute the amount of heat needed to drop the temperature of 100cans of milk from 32c to 25c , assume specific weight of milk to be .99kg/L. specific heat of milk is .93 BTU/lb F. can you help me with this
Thanks a lot very helpful
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