Thank you so much! I was really struggling to understand how to read the chi square distribution since the last 3 or so videos and articles I watched and read kept glossing over it and in turn I had a hard time understanding how to get the chi-square critical value using the chi-square table. But this was SUPER helpful!
Hello Sir, There is a question in your CRE preparation test in Udemy. I am not able to understand this question. There is a mention of both Weibull distribution(2P) and Chi-Square statistics. Can you please help to solve this question? Data of time to repair machines is collected. Average is found to be 95 minutes with standard deviation of 20 minutes. To assess whether data fits in 2-parameter Weibull distribution, data is divided in to 10 class intervals. Critical value of the chi-square statistic at 0.01 level of significance is...
My apologies for late response! This is based on goodness of fit testing. As the data is divided in to 10 class intervals, degrees of freedom would be (10-1-2)-7. The -2 is for the two Weibull parameters as these are also estimated from the same data. This is always a right tail test and the right tail critical value of Chi-sq distribution at 0.01 alpha risk would be would be 18.475.
Thank you so much! I was really struggling to understand how to read the chi square distribution since the last 3 or so videos and articles I watched and read kept glossing over it and in turn I had a hard time understanding how to get the chi-square critical value using the chi-square table. But this was SUPER helpful!
You're very welcome! I am glad you found it helpful!
very good explanation
Glad you think so! Keep watching!🎉
A very clear explanation. Thanks
Thanks! I am glad to see your feedback!
precise and concise
Thank you!
Very useful and informative sir.
Thanks and welcome
Hello Sir,
There is a question in your CRE preparation test in Udemy. I am not able to understand this question. There is a mention of both Weibull distribution(2P) and Chi-Square statistics. Can you please help to solve this question?
Data of time to repair machines is collected. Average is found to be 95 minutes with standard deviation of 20 minutes. To assess whether data fits in 2-parameter Weibull distribution, data is divided in to 10 class intervals. Critical value of the chi-square statistic at 0.01 level of significance is...
My apologies for late response!
This is based on goodness of fit testing. As the data is divided in to 10 class intervals, degrees of freedom would be (10-1-2)-7. The -2 is for the two Weibull parameters as these are also estimated from the same data. This is always a right tail test and the right tail critical value of Chi-sq distribution at 0.01 alpha risk would be would be 18.475.
y its good
Thank you!