Speed of bus = 10m/s Distance b/w bus and scooter = 1km Distance covered by bus in 100 sec = s=d/t =D=s×t =10×100 =1000m or 1km Total distance = 1km + 1km = 2km Speed needed to cover the total distance = s=d/t =S=2000/100 =S=20m/s Ans = 20m/s
the bus is travelling with the speed of 10 m/s and the time in which the scooter has to overtake the bus is 100s s=vt => s=10x100 => s=1000m so the distance scooter has to travel to overtake the bus in 100s will be s=1000+1000 => 2000m so the speed required to cover 2000m in 100s is v=2000/100 => 20 m/s
Bus after 100 seconds with velocity 10 metre per second then distance travelled =10 *100=1000 m means 1 km Then scooter have to travel 2 kilometre in 100 second so the speed scooter is is 2000m/100s Then the speed is 20 m/s
amazingly explained...I found many parts that we have already studied in 9std soo I was getting bored waitching all those 2hours and 4 hours lectures...but this helped me alot to save time..Thank you soo much❤❤
Great explanation in a short time....it ll really helpful for all the students...I m honestly nt good in numericals bt aftr watching dis 2 times I solvd a lot of examples....A big thanks to this young teacher
Thank you so much bro . This was really helpful, we were in search of such short videos where in different topics will be covered within less time n this was the best .
Bhaiya pls make more videos for questions because questions are important.. firstly important formula then questions... Assa lecture.. rest this for really amazing.... Maine sarre questions krliye thae solve all were right... ❤❤ Because I am your junior...
Accidentally discovered you... Fabbb u won't get such amazing crystal clear explanation in such very few time.. Throughout the whole video I was like wow. Proud of myself that i clicked on your vedio. And things which I didn't knew and got to know by you... St those moments I was like GODAMMM thanks man.. Just PHENOMENAL! thankkss for these.. Btw for some secs.. I realize that I'm just watching u speak and not heard or understood a single of ur words Lol i skipp back and get it...yep.. UrCharmingg
Speed required for the 🛵 to chase the 🚌== Speed of 🚌 + 1000/100 [ 1km=1000m & time =100s] = 10m/s + 10m/s =20 m/s 🏠 work question answer bhaiya🙈🙂🙃. Me Cares:+
Speed of bus = 10m/s
Distance b/w bus and
scooter = 1km
Distance covered by bus in 100 sec = s=d/t
=D=s×t
=10×100
=1000m or 1km
Total distance = 1km + 1km
= 2km
Speed needed to cover the total distance = s=d/t
=S=2000/100
=S=20m/s
Ans = 20m/s
He's like the one friend who teaches us the whole chapter one hour before the exam 😂😂
Yesss😅
Bhi exam kaise Gaya? Let me know because I am also watching 1 day before exam😨
@@PemaGurung-p6ebhai mash gya
15/100 😂
Passs hote² bash gya
@@roshangetnosleep lgta h vo 15 no. Bhi practical file ke honge 😂
the bus is travelling with the speed of 10 m/s and the time in which the scooter has to overtake the bus is 100s
s=vt => s=10x100 => s=1000m
so the distance scooter has to travel to overtake the bus in 100s will be
s=1000+1000 => 2000m
so the speed required to cover 2000m in 100s is
v=2000/100 => 20 m/s
Same Answer
And nicely explained🤝
1km=1000m
Speed of bus + 1000/100s
10+10
,=20 ms -1
👍👍
Correct 👍🏻
Correct to yahi hai bhai but 100 secs me wo bus ke barabar phnch jayega is speed se
But overtake nahin kar payega.
😂😂
Ajeeb hai.
@@mr.nobody.2809 Chase the bus bro
Bhai vo relative velocity ka concept hai minus wala vo alg hai . Do not mess it up
PLEASE make 20 minute rivision SERIES for class 11th chemistry
Hello abhinav
Yes it's will help us a lot 😌
Ys
@@Anshika-ij7ii ja na chapri
Lwd chemistry to simple he
Bus after 100 seconds with velocity 10 metre per second then distance travelled =10 *100=1000 m means 1 km
Then scooter have to travel 2 kilometre in 100 second so the speed scooter is is 2000m/100s
Then the speed is 20 m/s
amazingly explained...I found many parts that we have already studied in 9std soo I was getting bored waitching all those 2hours and 4 hours lectures...but this helped me alot to save time..Thank you soo much❤❤
Amazing series for physics revision 🙌🏻 thank you
Speed of bus +speed of scooter..
1000/100=10.(scooty wala)
10+10 =20ms.. answer😅
Bro plz do more videos on 11 th
I am new subscriber 😁
Your explanation was simply superb 😍
Great explanation in a short time....it ll really helpful for all the students...I m honestly nt good in numericals bt aftr watching dis 2 times I solvd a lot of examples....A big thanks to this young teacher
Thank you❤
Kl hi 11th ka pehla test aur ye video bahut help kiya kai video ko dekhe lekin ye video sirf aache se samajh me aaya h.
Thank You 😄
Please make 20 minute revision series of chemistry class 11
👍
Wow what is a Revision superb
Tq..👍😊
The answer of last Question is20m/s
Option is (d)
Thank you so much bro . This was really helpful, we were in search of such short videos where in different topics will be covered within less time n this was the best .
Bro u r god for me thnk uuu so much ❤❤❤❤❤❤❤❤❤
Apke lecture krke hmne physics me 160 scored kiya whole syllabus of 11th and 12th 😇 bhaiya thanku so much u r superb mindblowing 😍🤗
Hello noob
It's for time pass
Sister
Kal mera Physics ka exam h !! And this video is wooow 💯🔥 for my Revision...Nice explanation 👍
Btw New subscriber 🤩😊
Nice
Kya tum Sach ma 11th ma hi ho.🤔🤨
Mera bhi
@@starklinkville8423 jiiii
@@atharvchaudhari1755 ohhh
14:40 option D is also incorrect, negative velocity..?
20m/s ans...... thank you for this amazing video
Bhaiya please continue this numerical series
Please make Rev video for class 11 chem also...(equilibrium).
I'm a new subscriber, best video in few minutes. I understood well in short time. Thanks for this video. Time saving video
Brooo after watching your video MOTION IN STRAIGHT LINE become very easy ❤❤❤
Thank you soo much bhaiya for numericals...I literally wanted this ❤️
Omgg you made it soo easy,thank you so much 🥺❤️
20 ms
Very good explanation,😊😊
bhaiya this video was super amzing ....thank u so much for it💞💞💞💕💕💕😍😍❤️❤️
Excellent bro....
Jaha physics Nam sunke bore hota tha
Apka video deke to najar araha hai. Bas itnahi hai physics..👍
❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️
Thanks a lot bhaiya.....🥰🥰🥰 you did a great job...God bless you bro😘
Sir amazing chapter hai sir friends say very chapter but this my best chapter
Aap bhaut Achhe short video banate ho for revision. Please aur bhi question laao
20m/s ans hai ??plzz answer sir
Newly subscribed....
Keep doing a lot of numericals....!
Bhaiya pls make more videos for questions because questions are important.. firstly important formula then questions... Assa lecture.. rest this for really amazing.... Maine sarre questions krliye thae solve all were right... ❤❤ Because I am your junior...
Accidentally discovered you... Fabbb u won't get such amazing crystal clear explanation in such very few time.. Throughout the whole video I was like wow. Proud of myself that i clicked on your vedio. And things which I didn't knew and got to know by you... St those moments I was like GODAMMM thanks man..
Just PHENOMENAL!
thankkss for these..
Btw for some secs.. I realize that I'm just watching u speak and not heard or understood a single of ur words Lol i skipp back and get it...yep.. UrCharmingg
Aap bhut cutee ho❤❤❤❤❤
the answer of last question should be 20 m\s. option D
No1 bhai, love you 👍
Appreciate ❤️ ur videos..thnks
Bruh im from Assam. State board 2022 march se start ho rha h nov se start karke kse 98% score kar sakte h plzz make a vdo
Speed required for the 🛵 to chase the 🚌== Speed of 🚌 + 1000/100 [ 1km=1000m & time =100s]
= 10m/s + 10m/s
=20 m/s
🏠 work question answer bhaiya🙈🙂🙃.
Me Cares:+
one day after is my exam and today I'm watching this video and this is amazing🙌🙌 thank u so much bhaiya
New subscriber 😃
The last question answer is 20 m/s❤️✌️✅.
BHAIYA ANSWER TO THE QUESTION ASKED BY YOU IS: D) 20 M/S
Very nicely explained bro ... please make chemistry one shot vedio of class 11th we have term 1 exam from 11th November onwards
And first exam is of chemistry only
1:45 begin the 1st question
Thanku so much bhaiya for your quick revision series
Bhai last wale question me proportionality lagana tha
relative velocity 20 m/s
Thanku so much bro 🤘 your all videos osm
20m/s?
is this right?
Bhaiya thanku
Your videos are for decades
vaiya.....iss tarah ke aur numerical korau...plz..
Very amazing explanation bro
Thanks a lot bhaiyya 😊
2oms^-1
Sir option d is ans
Very nice ☺️
Thanks a lot sir super explanation you are amazing sir 😊😃😍👧❤❤👌👌👌👍
This is also
=80²-20²/10²
=300
Easy 🙃
Thanks a lot bhaiya for such an amazing and interesting explanation🤗♥️🙏
Nice explaintion bro I love your class
1:46 video starts
Thanks a lot ❤
Thanks a lot ❤️ such a amazing
is the answer 20m/s before i got 10m/s then i added the speed of bus and scooter so i got 20m/s
i wanna if its correct especially the last step
Correct answer is 20m/s since u have to apply concepts of relative motion. All these questions are neet pyqs..
@@nishapandey6359 thanks for telling :)
2000(d)÷100sec=20m/s
Distance 2000 kaise hogi
Thank you brother 😊😊
S=d/t
1000/100=10m/s,
this time taken by scooter to reach near the bus
So it wants more speed to overtake the bus
Yes plz chemistry ke s and p block ka short revision video bnaiye
Please make videos for class 11th chemistry
Hey hii
I think you are also not perfect in chemistry like me 😅😅
Do you had instagram can we exchange our exam question papers so that we can practice
@@hellohi2190 tharki🤦🏻🤦🏻😂
@@AyushPatel-hw2sw true😂
I ❤ed ur explanation
Nice explanation bro👌
Atomic structure class11 20 min revision video .
20ms^-1
Thanks u bhaiya g 🙏🙏👍❤🤩🤩🥰🥰😘😘
Please make video on JEE/NEET motion in a plane numerical video and Unit and measurement numericals because my exams is going on....🙏🏻
Ans bro plse give contact no. Question papae chahiye
Thank you bhaiya 😊
Tomorrow is my physics board exam ... And I'm here... Really helpful 💖thanks bhaiya saare chapter revision ho jayega
All the best👍💯
thanks you so much brother😍
Bro if i othing learn about this chp so this is helfful or not for exam ??
1:48
strts at 1:50
I watched your all videos and veryyy veryy helpful for me my chemistry exam done best because of you thank you sooooo muchhhh.....🙏🏻🙏🏻🙏🏻🙏🏻❤️
Last ka question common sense ka bhi tha 20ms-1
Bhaiya aap ka upar Dil aah gaya
last question answer is 20 m/s
Bhaiya plz make the video on 11th chemistry lesson number 11 isomerism and reaction mechanism plz bhaiya fast as fast upload that video 🙏🏻
Is this good for neet ???????
Please chemistry also
What is the answer of last question.?????
Please make new videos for new pattern 2022-23 ...
20
Thank you Bhaiya
Answer is 20m/s²
20m/s is the answer of last question
thanks bro nice explanation and you are very handsome🥰🥰
Thank u shivbaba bless u